Permutations And Combinations - MCQ 2

# Permutations And Combinations - MCQ 2

Test Description

## 20 Questions MCQ Test Quantitative Aptitude for Competitive Examinations | Permutations And Combinations - MCQ 2

Permutations And Combinations - MCQ 2 for Quant 2022 is part of Quantitative Aptitude for Competitive Examinations preparation. The Permutations And Combinations - MCQ 2 questions and answers have been prepared according to the Quant exam syllabus.The Permutations And Combinations - MCQ 2 MCQs are made for Quant 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Permutations And Combinations - MCQ 2 below.
Solutions of Permutations And Combinations - MCQ 2 questions in English are available as part of our Quantitative Aptitude for Competitive Examinations for Quant & Permutations And Combinations - MCQ 2 solutions in Hindi for Quantitative Aptitude for Competitive Examinations course. Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free. Attempt Permutations And Combinations - MCQ 2 | 20 questions in 15 minutes | Mock test for Quant preparation | Free important questions MCQ to study Quantitative Aptitude for Competitive Examinations for Quant Exam | Download free PDF with solutions
 1 Crore+ students have signed up on EduRev. Have you?
Permutations And Combinations - MCQ 2 - Question 1

### How many words of 4 letters with or without meaning be made from the letters of the word ‘NUMBER’, when repetition of letters is not allowed?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 1

D) 360
Explanation: NUMBER is 6 letters.
We have 4 places where letters are to be placed.
For first letter there are 6 choices, since repetition is not allowed, for second, third and fourth letter also we have 5, 4, and 3 choices resp., so total of 6*5*4*3 ways = 360 ways.

Permutations And Combinations - MCQ 2 - Question 2

### In how many ways the letters of the word ‘ALLIGATION’ be arranged taking all the letters?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 2

B) 453600
Explanation: ALLIGATION contains 10 letters, so total 10! ways. There are 2 As, 2 Ls, 2 Is So 10!/(2!*2!*2!)

Permutations And Combinations - MCQ 2 - Question 3

### In how many ways all the letters of the word ‘MINIMUM’ be arranged such that all vowels are together?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 3

A) 60
Explanation: Take vowels in a box together as one – IIU, M, N, M, M So there are 5 that to be placed for this 5!, now 3 Ms, so 5!/3!, so arrangement of vowels inside box gives 3!/2!
So total = 5!/3! * 3!/2!

Permutations And Combinations - MCQ 2 - Question 4

In how many ways a group of 4 men and 3 women be made out of a total of 8 men and 5 women?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 4

B) 140
Explanation: Total ways = 8C4 * 5C3

Permutations And Combinations - MCQ 2 - Question 5

How many 3 digit numbers are divisible by 4?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 5

B) 225
Explanation: A number is divisible by 4 when its last two digits are divisible by 4 For this the numbers should have their last two digits as 00, 04, 08, 12, 16, … 96 By the formula, a = a + (n-1)d 96 = 0 + (n-1)*4 n = 25 so there are 25 choices for last 2 digits and 9 choices (1-9) for the 1st digit so total 9*25

Permutations And Combinations - MCQ 2 - Question 6

How many 3 digits numbers have exactly one digit 2 in the number?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 6

A) 225
Explanation: 0 cannot be placed at first digit to make it a 3 digit number. 3 cases: Case 1: 2 is placed at first place 1 choice for the first place, 9 choices each for the 2nd and 3rd digit (0-9 except 2) So numbers = 1*9*9 = 81 Case 2: 2 is placed at second place 8 choices for the first place (1-9 except 2), 1 choice for the 2nd digit and 9 choices for the 3rd digit (0-9 except 2) So numbers = 8*1*9 = 72 Case 3: 2 is placed at third place 8 choices for the first place (1-9 except 2), 9 choices for the 2nd digit (0-9 except 2) and 1 choice for the 3rd digit So numbers = 8*9*1 = 72 So total numbers = 81+72+72 = 225

Permutations And Combinations - MCQ 2 - Question 7

There are 8 men and 7 women. In how many ways a group of 5 people can be made such that the particular woman is always to be included?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 7

C) 1001
Explanation: Total 15 people, and a particular woman is to be taken to form a group of 5, so choice is to be done from 14 people of 4 people Ways are 14C4 .

Permutations And Combinations - MCQ 2 - Question 8

There are 6 men and 7 women. In how many ways a committee of 4 members can be made such that a particular man is always to be excluded?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 8

D) 495
Explanation: There are total 13 people, a particular man is to be excluded, so now 12 people are left to chosen from and 4 members to be chosen. So ways are 12C4 .

Permutations And Combinations - MCQ 2 - Question 9

How many 4 digit words can be made from the digits 7, 8, 5, 0, and 4 without repetition?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 9

B) 96
Explanation: 0 cannot be on first place for it to be a 4 digit number, So for 1st digit 4choices, for second also 4 (because 0 can be placed here), then 3 for third place, 2 for fourth place Total numbers = 4*4*3*2

Permutations And Combinations - MCQ 2 - Question 10

In how many ways 8 students can be given 3 prizes such that no student receives more than 1 prize?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 10

D) 336
Explanation: For 1st prize there are 8 choices, for 2nd prize, 7 choices, and for 3rd prize – 6 choices left So total ways = 8*7*6

Permutations And Combinations - MCQ 2 - Question 11

In how many ways can 3 prizes be given away to 12 students when each student is eligible for all the prizes ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 11

Answer – B.1728 Explanation : 12^3 = 1728

Permutations And Combinations - MCQ 2 - Question 12

Total no of ways in which 30 sweets can be distributed among 6 persons ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 12

Answer – A. 35C5

30+6-1C6-1  = 35C5

Permutations And Combinations - MCQ 2 - Question 13

A bag contains 4 red balls and 5 black balls. In how many ways can i make a selection so as to take atleast 1 red ball and 1 black ball ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 13

Answer – C.465 Explanation : 24 -1 = 16 -1 = 15
25 - 1 = 32 -1 = 31
15*31 = 465

Permutations And Combinations - MCQ 2 - Question 14

In how many ways can 7 beads be strung into necklace ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 14

Answer – D.360 Explanation : No of way in Necklace = (n-1)!/2 = 6!/2 = 720/2 = 360

Permutations And Combinations - MCQ 2 - Question 15

Find the no of 3 digit numbers such that  atleast one of the digit is 6 (with repetitions) ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 15

Answer – A.252 Explanation : Total no of 3 digit number = 9*10*10 = 900 No of 3 digit number- none of the digit is 6 = 8*9*9 = 648 No of 3 digit number – atleast one digit is 6 = 900-648 = 252

Permutations And Combinations - MCQ 2 - Question 16

In how many ways  can 7 girls and 4 boys stand in a row so that no 2 boys are together ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 16

Answer – A. 8467200
Explanation : No of ways = 7!* 8P4
7! = 5040
8P4 = 8*7*6*5 = 1680
No of ways = 5040*1680 = 8467200

Permutations And Combinations - MCQ 2 - Question 17

In how many ways the letters of the word PERMUTATION be arranged ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 17

Answer – D. 11!/2!
Explanation : No of ways = 11!/2!

Permutations And Combinations - MCQ 2 - Question 18

How many numbers can be formed with the digits 1, 7, 2, 5 without repetition ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 18

Answer – C.64 Explanation : 1 digit number = 4 2 digit no = 4*3 = 12 3 digit no = 4*3*2 = 24 4 digit no = 4*3*2*1 = 24 Total = 4+12+24+24 = 64

Permutations And Combinations - MCQ 2 - Question 19

There are 3 boxes and 6 balls. In how many ways these balls can be distributed if all the balls and all the boxes are different?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 19

Answer – C.729 Explanation : 3^6 = 729

Permutations And Combinations - MCQ 2 - Question 20

In how many ways can 4 books be selected out of 10 books on different subjects ?

Detailed Solution for Permutations And Combinations - MCQ 2 - Question 20

Answer – A.210 Explanation : 16C4 =  10*9*8*7/4*3*2*1 = 5040/24 = 210

## Quantitative Aptitude for Competitive Examinations

33 videos|34 docs|140 tests
 Use Code STAYHOME200 and get INR 200 additional OFF Use Coupon Code
Information about Permutations And Combinations - MCQ 2 Page
In this test you can find the Exam questions for Permutations And Combinations - MCQ 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Permutations And Combinations - MCQ 2, EduRev gives you an ample number of Online tests for practice

## Quantitative Aptitude for Competitive Examinations

33 videos|34 docs|140 tests