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Test: Vapour Liquid Equilibria - Chemical Engineering MCQ


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10 Questions MCQ Test Mass Transfer - Test: Vapour Liquid Equilibria

Test: Vapour Liquid Equilibria for Chemical Engineering 2024 is part of Mass Transfer preparation. The Test: Vapour Liquid Equilibria questions and answers have been prepared according to the Chemical Engineering exam syllabus.The Test: Vapour Liquid Equilibria MCQs are made for Chemical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Vapour Liquid Equilibria below.
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Test: Vapour Liquid Equilibria - Question 1

 A new phase is given for the separation by distillation.

Detailed Solution for Test: Vapour Liquid Equilibria - Question 1

Explanation: Here, the separation is done by vaporization.

Test: Vapour Liquid Equilibria - Question 2

Consider a sugar solution[ Sugar + Water]; On vaporization water only evaporate since sugar is________

Detailed Solution for Test: Vapour Liquid Equilibria - Question 2

Explanation: There is no boiling point for the Non-volatile compound. So the sugar has no vapour pressure.

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Test: Vapour Liquid Equilibria - Question 3

Distillation is possible only if the solution components are_____________

Detailed Solution for Test: Vapour Liquid Equilibria - Question 3

Explanation: Since the distillation is done by vaporization the components should be volatile for separation.

Test: Vapour Liquid Equilibria - Question 4

 No further process required for _____________

Detailed Solution for Test: Vapour Liquid Equilibria - Question 4

Explanation: Distillation is the only process gives the pure component separation.

Test: Vapour Liquid Equilibria - Question 5

In a solution (A and B); The vapour pressure of A is 260 mmHg and B is 360 mmHg; Find the relative volatility?

Detailed Solution for Test: Vapour Liquid Equilibria - Question 5

Explanation: Relative volatility= vapour pressure of A/ Vapour pressure of B
= 260/360
=0.72.

Test: Vapour Liquid Equilibria - Question 6

If the gas phase composition of a component A is 0.65 and its relative volatility is 2. Find the liquid phase composition.

Detailed Solution for Test: Vapour Liquid Equilibria - Question 6

Explanation: Relative volatility= 0.65/(1-0.65) * (1-x)/x
2= 1.85 * (1-x)/x ; x= 0.48.

Test: Vapour Liquid Equilibria - Question 7

The component A and B has the same boiling point. Can the separation is done by ordinary separation?

Detailed Solution for Test: Vapour Liquid Equilibria - Question 7

Explanation: Separation cannot be done if the two components have the same vapour pressure.

Test: Vapour Liquid Equilibria - Question 8

The possibility of separation will be more if the separation factor is greater than 1.

Detailed Solution for Test: Vapour Liquid Equilibria - Question 8

Explanation: Since if relative volatility is equals to 1. The separation is not possible since the boiling point of the two components will be same.

Test: Vapour Liquid Equilibria - Question 9

Find the vapour pressure of a component A in an ideal mixture, if its liquid composition and the partial pressure is 0.65 and 260 mmHg.

Detailed Solution for Test: Vapour Liquid Equilibria - Question 9

Explanation: For an ideal solution, Partial pressure = vapour pressure x mole fraction
Vapour pressure= (260/0.65)=400 mmHg.

Test: Vapour Liquid Equilibria - Question 10

Consider an ideal vapour-liquid binary mixture, find the total pressure if the vapour pressure of A is 260 mmHg and the vapour pressure of B is 520 mmHg and the composition of A in mole fraction is 0.55.

Detailed Solution for Test: Vapour Liquid Equilibria - Question 10

Explanation: Total pressure = (vapour pressure of A * mole fraction) + vapour pressure of B*( 1- mole fraction) = 377 mmHg.

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