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Test: Concentration And Velocity - Chemical Engineering MCQ


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15 Questions MCQ Test Mass Transfer - Test: Concentration And Velocity

Test: Concentration And Velocity for Chemical Engineering 2024 is part of Mass Transfer preparation. The Test: Concentration And Velocity questions and answers have been prepared according to the Chemical Engineering exam syllabus.The Test: Concentration And Velocity MCQs are made for Chemical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Concentration And Velocity below.
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Test: Concentration And Velocity - Question 1

 In which of the following conditions mass transfer will occur spontaneously? C and z is concentration and distance respectively.

Detailed Solution for Test: Concentration And Velocity - Question 1

Explanation: Mass transfer occurs in the direction of decreasing concentration.

Test: Concentration And Velocity - Question 2

Which among the following is always true for mass transfer to occur?

Detailed Solution for Test: Concentration And Velocity - Question 2

Explanation: Mass transfer occurs to attain an equilibrium position or to minimize the energy of the system. Mass occur can occur even if there is no difference in concentration, pressure and temperature. Example: – A ball rolls down a slope to minimize its potential energy.

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Test: Concentration And Velocity - Question 3

A solution contains 0.3 moles of solute A, 0.2 moles of B and 0.5 moles of C. What will be the mole fraction of A in the mixture?

Detailed Solution for Test: Concentration And Velocity - Question 3

Explanation: Mole Fraction of A= Moles of A/Total moles

Test: Concentration And Velocity - Question 4

A gas mixture containing 21% O2 and 79% N2 flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2 is 0.04m/s and N2 is 0.035m/s.

Q. What is the value of molar average velocity (m/s) of the mixture?

Detailed Solution for Test: Concentration And Velocity - Question 4

Explanation: Molar average velocity= (C1u1+C2u2+……….)/C
=y1u1+y2u2…..
= 0.21*0.04+0.79*0.035
=0.036

Test: Concentration And Velocity - Question 5

A gas mixture containing 21% O2 and 79% N2 flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2 is 0.04m/s and N2 is 0.035m/s.

Q. What will be the value of mass average velocity (m/s)?

Detailed Solution for Test: Concentration And Velocity - Question 5

Explanation: Mass average velocity= (ρ1u12u2)/ ρ
ρ1= (p1*M1)/RT
ρ= (p*M)/RT.
Dividing these two equations
ρ1/ ρ = (p1*M1)/pM =(y1*M1)/M
M=y1*M1+y2*M2=0.79*28+0.21*32=28.84
Mass average velocity= (y1*M1*u1+y2*M2*u2)/M
= (0.21*32*0.04+0.79*0.035)/28.84
= 0.981

Test: Concentration And Velocity - Question 6

A gas mixture containing 21% O2 and 79% N2 flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2 is 0.04m/s and N2 is 0.035m/s.

Q. What is the value of Volume average velocity?

Detailed Solution for Test: Concentration And Velocity - Question 6

Explanation: Volume average velocity= Molar average velocity.

Test: Concentration And Velocity - Question 7

In a gas mixture if molecular weights of all the species are equal than which one will be more, Mass average velocity or Molar average velocity?

Detailed Solution for Test: Concentration And Velocity - Question 7

Explanation: Average molar mass of the mixture=M(x1+x2+………+ xn)=M
(x1+x2+………+ xn=1)
Mass average velocity=Σuiρi/ρ=uiPui/P
Molar average velocity=Σciui/c=ρuiPi/P (P=cRT).

Test: Concentration And Velocity - Question 8

The velocity of various components of mixture(21% A, 78% B and 1% C) are:
Velocity is in the form: v⃗=xi+yj+zk

Velocity of component A= (0.1, 0, 0)
Velocity of component B= (0, 0.1, 0)
Velocity of component B= (0, 0, 0.1)
Calculate the value of average molar velocity?

Detailed Solution for Test: Concentration And Velocity - Question 8

Explanation: Molar average velocity = (c1u1+c2u2+c3u3)/C.

Test: Concentration And Velocity - Question 9

Calculate the value of mass average velocity in the previous question?

Detailed Solution for Test: Concentration And Velocity - Question 9

Explanation: (y1*M1*u1+y2*M2*u2)/M.

Test: Concentration And Velocity - Question 10

For the calculation of Mass average velocity, which velocity of the molecule is used?

Detailed Solution for Test: Concentration And Velocity - Question 10

Explanation: None.

Test: Concentration And Velocity - Question 11

Which among the following can be the unit of Flux?

Detailed Solution for Test: Concentration And Velocity - Question 11

Explanation: Dimension analysis.
Flux= rate at which a species passes through a unit area, in unit time.

Test: Concentration And Velocity - Question 12

A molecule in a mixture moves with a velocity of 0.03m/s in (+x) direction. The concentration of the particle is 0.5 mol/liter. A observer is running in (-x) direction with a velocity of 2m/s. calculate the value of molar flux (mol/m2.s) relative to the observer.

Detailed Solution for Test: Concentration And Velocity - Question 12

Explanation: Molar flux with respect to observer= C(u-U)
(C=500mol/m3, u=0.03m/s, U= (-) 2m/s).

Test: Concentration And Velocity - Question 13

In the previous question what will be the value of flux (mol/m2.s) with respect to a stationary observer?

Detailed Solution for Test: Concentration And Velocity - Question 13

Explanation: Here U=0.

Test: Concentration And Velocity - Question 14

 Under which of the following conditions mass average velocity and molar average velocity are equal?

Detailed Solution for Test: Concentration And Velocity - Question 14

Explanation: None.

Test: Concentration And Velocity - Question 15

The mass flow rate of a component in a mixture in X-direction is 2kg/s. The area vector at a particular cross-section is (1.1, 3.2, 5.4) cm2. Calculate the value of flux (kg/cm2.s) through the cross-section. 

Detailed Solution for Test: Concentration And Velocity - Question 15

Explanation: For flux calculation area normal to the flow direction should be taken into account

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