Test: Curl

# Test: Curl

Test Description

## 10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Curl

Test: Curl for Electrical Engineering (EE) 2023 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Curl questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Curl MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Curl below.
Solutions of Test: Curl questions in English are available as part of our Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) & Test: Curl solutions in Hindi for Electromagnetic Fields Theory (EMFT) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Curl | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) Exam | Download free PDF with solutions
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Test: Curl - Question 1

### Curl is defined as the angular velocity at every point of the vector field. State True/False.

Detailed Solution for Test: Curl - Question 1

Explanation: Curl is defined as the circulation of a vector per unit area. It is the cross product of the del operator and any vector field. Circulation implies the angular at every point of the vector field. It is obtained by multiplying the component of the vector parallel to the specified closed path at each point along it, by the differential path length and summing the results.

Test: Curl - Question 2

### The curl of curl of a vector is given by,

Detailed Solution for Test: Curl - Question 2

Explanation: Curl (Curl V) = Grad (Div V) – (Del)2V is a standard result of the curl operation.

Test: Curl - Question 3

### Which of the following theorem use the curl operation?

Detailed Solution for Test: Curl - Question 3

Explanation: The Stoke’s theorem is given by ∫ A.dl = ∫Curl(A).ds, which uses the curl operation. There can be confusion with Maxwell equation also, but it uses curl in electromagnetics specifically, whereas the Stoke’s theorem uses it in a generalised manner. Thus the best option is c.

Test: Curl - Question 4

The curl of a curl of a vector gives a

Detailed Solution for Test: Curl - Question 4

Explanation: Curl is always defined for vectors only. The curl of a vector is a vector only. The curl of the resultant vector is also a vector only.

Test: Curl - Question 5

Find the curl of the vector and state its nature at (1,1,-0.2)F = 30 i + 2xy j + 5xz2 k

Detailed Solution for Test: Curl - Question 5

Explanation: Curl F = -5z2 j + 2y k. At (1,1,-0.2), Curl F = -0.2 j + 2 k. |Curl F| = √(-0.22+22) = √4.04.

Test: Curl - Question 6

Is the vector is irrotational. E = yz i + xz j + xy k

Detailed Solution for Test: Curl - Question 6

Explanation: Curl E = i(Dy(xy) – Dz(xz)) – j (Dx(xy) – Dz(yz)) + k(Dx(xz) – Dy(yz)) =
i(x – x) – j(y – y) + k(z – z) = 0
Since the curl is zero, the vector is irrotational or curl-free.

Test: Curl - Question 7

Find the curl of A = (y cos ax)i + (y + ex)k

Detailed Solution for Test: Curl - Question 7

Explanation: Curl A = i(Dy(y + ex)) – j (Dx(y + ex) – Dz(y cos ax)) + k(-Dy(y cos ax))
= 1.i – j(ex) – k cos ax = i – ex j – cos ax k.

Test: Curl - Question 8

Find the curl of the vector A = yz i + 4xy j + y k

Detailed Solution for Test: Curl - Question 8

Explanation: Curl A = i(Dy(y) – Dz(0)) – j (Dx(0) – Dz(yz)) + k(Dx(4xy) – Dy(yz)) =
i + y j + (4y – z)k, which is option d.

Test: Curl - Question 9

Curl cannot be employed in which one of the following?

Detailed Solution for Test: Curl - Question 9

Explanation: In the options a, b, c, the EM waves travel both in linear and angular motion, which involves curl too. But in waveguides, as the name suggests, only guided propagation occurs (no bending or curl of waves).

Test: Curl - Question 10

Which of the following Maxwell equations use curl operation?

Detailed Solution for Test: Curl - Question 10

Explanation: Maxwell 1st equation, Curl (H) = J (Ampere law)
Maxwell 2nd equation, Curl (E) = -D(B)/Dt (Faraday’s law)
Maxwell 3rd equation, Div (D) = Q (Gauss law for electric field)
Maxwell 4th equation, Div (B) = 0(Gauss law for magnetic field)
It is clear that only 1st and 2nd equations use the curl operation.

## Electromagnetic Fields Theory (EMFT)

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