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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Electromagnetic Fields Theory (EMFT)  >  Test: Dielectric Strength & Constant - Electrical Engineering (EE) MCQ

Test: Dielectric Strength & Constant - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Dielectric Strength & Constant

Test: Dielectric Strength & Constant for Electrical Engineering (EE) 2025 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Dielectric Strength & Constant questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Dielectric Strength & Constant MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Dielectric Strength & Constant below.
Solutions of Test: Dielectric Strength & Constant questions in English are available as part of our Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) & Test: Dielectric Strength & Constant solutions in Hindi for Electromagnetic Fields Theory (EMFT) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Dielectric Strength & Constant | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Dielectric Strength & Constant - Question 1
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Which of the following is not an example of elemental solid dielectric?

Detailed Solution for Test: Dielectric Strength & Constant - Question 1

Answer: c
Explanation: Elemental solid dielectrics are the materials consisting of single type of atoms. Such materials have neither ions nor permanent dipoles and possess only electronic polarisation. Its examples are diamond, sulphur and germanium.

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Ionic non polar solid dielectrics contain more than one type of atoms but no permanent dipoles. State True/False

Detailed Solution for Test: Dielectric Strength & Constant - Question 2

Answer: a
Explanation: In ionic crystals, the total polarisation is electronic and ionic in nature. Thus, it implies that it contains more than one type of atom and no permanent dipoles.

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Test: Dielectric Strength & Constant - Question 3
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Compute the refractive index when the dielectric constant is 256 in air.

Detailed Solution for Test: Dielectric Strength & Constant - Question 3

Answer: b
Explanation: By Maxwell relation, εr = n2, where εro is the dielectric constant at optical frequencies and n is the refractive index.For the given dielectric constant we get n = 16.

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Dielectric property impacts the behaviour of a material in the presence of electric field. State True/False.
Detailed Solution for Test: Dielectric Strength & Constant - Question 4

Answer: a
Explanation: Based on the dielectric property, a material can be classified as piezoelectric, ferroelectric, pyroelectric and anti-ferroelectric materials under the influence of electric field.

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Curie-Weiss law is applicable to which of the following materials?
Detailed Solution for Test: Dielectric Strength & Constant - Question 5

Answer: b
Explanation: Curie-Weiss law is given by χe = εr -1 = C/(T-θ), where C is the curie constant and θ is the characteristic temperature which is usually a few degrees higher than the curie temperature for ferromagnetic materials.

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Curie-Weiss law is used to calculate which one of the following?
Detailed Solution for Test: Dielectric Strength & Constant - Question 6

Answer: c
Explanation: Curie-Weiss law is given by χe = εr -1. Thus it is used to calculate the electric susceptibility of a material.

Test: Dielectric Strength & Constant - Question 7
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Calculate the loss tangent when the dielectric constant in AC field is given by 3 + 2j.
Detailed Solution for Test: Dielectric Strength & Constant - Question 7

Answer: d
Explanation: The AC dielectric constant is given by εr = ε` – jε“, where ε` is the real part of AC dielectric and ε“ is the imaginary part of AC dielectric. The loss tangent is given by tan δ = ε“/ε` = -2/3.

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When a dielectric loses its dielectric property, the phenomenon is called
Detailed Solution for Test: Dielectric Strength & Constant - Question 8

Answer: b
Explanation: Due to various treatments performed on the dielectric, in order to make it conduct, the dielectric reaches a state, where it loses its dielectric property and starts to conduct. This phenomenon is called as dielectric breakdown.

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Choose the best definition of dielectric loss.
Detailed Solution for Test: Dielectric Strength & Constant - Question 9

Answer: a
Explanation: In the scenario of an AC field, the absorption of electrical energy by a dielectric material is called as dielectric loss. This will result in dissipation of energy in the form of heat.

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Compute the loss factor when the loss tangent is 0.88 and the real part of dielectric is 24.
Detailed Solution for Test: Dielectric Strength & Constant - Question 10

Answer: d
Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.

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