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Test: Dielectric Vs Conductor Wave Propagation


10 Questions MCQ Test Electromagnetic Theory | Test: Dielectric Vs Conductor Wave Propagation


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This mock test of Test: Dielectric Vs Conductor Wave Propagation for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Dielectric Vs Conductor Wave Propagation (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Dielectric Vs Conductor Wave Propagation quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Dielectric Vs Conductor Wave Propagation exercise for a better result in the exam. You can find other Test: Dielectric Vs Conductor Wave Propagation extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

In conductors, which condition will be true?

Solution:

Answer: a
Explanation: For conductors, the conductivity will be maximum. Thus the loss tangent is greater than unity. This is given by σ/ωε >1.

QUESTION: 2

For metals, the conductivity will be

Solution:

Answer: d
Explanation: Metals are pure conductors. Examples are iron, copper etc. Their conductivity will be very high. Thus the metal conductivity will be infinity. Practically the conductivity of conductors will be maximum.

QUESTION: 3

In conductors, which two parameters are same?

Solution:

Answer: b
Explanation: In conductors, which are considered to be lossy, the attenuation and the phase constant are the same. It is given by α=β= √(ωμσ/2).

QUESTION: 4

Calculate the velocity of wave propagation in a conductor with frequency 5 x 108 rad/s and phase constant of 3 x 108 units. 
Solution:

Answer: c
Explanation: The velocity of wave propagation is the ratio of the frequency to the phase constant. It is given by V = ω/β. On substituting the given values, we get V = 5/3 units.

QUESTION: 5

Calculate the wavelength of the wave with phase constant of 3.14 units.
Solution:

Answer: b
Explanation: The wavelength is the ratio of 2π to the phase constant β. On substituting for β = 3.14, we get λ = 2π/β = 2π/3.14 = 2 units.

QUESTION: 6

For dielectrics, which two components will be in phase?
Solution:

Answer: d
Explanation: In dielectrics, the electric and magnetic components E and H will be in phase with each other. This is due the variation in the permittivities and the permeabilities of the dielectric surfaces. The phase difference between E and H will be 0.

QUESTION: 7

In perfect conductors, the phase shift between the electric field and magnetic field will be
Solution:

Answer: c
Explanation: For perfect conductors, the electric and magnetic field E and H respectively vary by a phase of 45 degree. This is due to the polarisation phenomenon in the conductors, unlike dielectrics.

QUESTION: 8

The expression for phase constant is given by
Solution:

Answer: c
Explanation: The phase constant is represented as β. It is a complex quantity representing the constant angle of the wave propagated. It is given by β = ω√(με).

QUESTION: 9

In waveguides, which of the following conditions will be true?
Solution:

Answer: a
Explanation: In waveguides, the phase velocity will always be greater than the speed of light. This enables the wave to propagate through the waveguide. Thus V > c is the required condition.

QUESTION: 10

The attenuation constant in lossless dielectrics will be
Solution:

Answer: a
Explanation: In lossless dielectrics, the attenuation constant will not be same as the phase constant, unlike conductors. Also, due to the lossless behaviour, the attenuation will be nearly zero. Practically, zero attenuation is not possible.

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