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Test: Dielectric Vs Conductor Wave Propagation


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Dielectric Vs Conductor Wave Propagation

Test: Dielectric Vs Conductor Wave Propagation for Electrical Engineering (EE) 2023 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Dielectric Vs Conductor Wave Propagation questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Dielectric Vs Conductor Wave Propagation MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Dielectric Vs Conductor Wave Propagation below.
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Test: Dielectric Vs Conductor Wave Propagation - Question 1

In conductors, which condition will be true?

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 1

Answer: a
Explanation: For conductors, the conductivity will be maximum. Thus the loss tangent is greater than unity. This is given by σ/ωε >1.

Test: Dielectric Vs Conductor Wave Propagation - Question 2

For metals, the conductivity will be

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 2

Answer: d
Explanation: Metals are pure conductors. Examples are iron, copper etc. Their conductivity will be very high. Thus the metal conductivity will be infinity. Practically the conductivity of conductors will be maximum.

Test: Dielectric Vs Conductor Wave Propagation - Question 3

In conductors, which two parameters are same?

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 3

Answer: b
Explanation: In conductors, which are considered to be lossy, the attenuation and the phase constant are the same. It is given by α=β= √(ωμσ/2).

Test: Dielectric Vs Conductor Wave Propagation - Question 4

Calculate the velocity of wave propagation in a conductor with frequency 5 x 108 rad/s and phase constant of 3 x 108 units. 

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 4

Answer: c
Explanation: The velocity of wave propagation is the ratio of the frequency to the phase constant. It is given by V = ω/β. On substituting the given values, we get V = 5/3 units.

Test: Dielectric Vs Conductor Wave Propagation - Question 5

Calculate the wavelength of the wave with phase constant of 3.14 units.

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 5

Answer: b
Explanation: The wavelength is the ratio of 2π to the phase constant β. On substituting for β = 3.14, we get λ = 2π/β = 2π/3.14 = 2 units.

Test: Dielectric Vs Conductor Wave Propagation - Question 6

For dielectrics, which two components will be in phase?

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 6

Answer: d
Explanation: In dielectrics, the electric and magnetic components E and H will be in phase with each other. This is due the variation in the permittivities and the permeabilities of the dielectric surfaces. The phase difference between E and H will be 0.

Test: Dielectric Vs Conductor Wave Propagation - Question 7

In perfect conductors, the phase shift between the electric field and magnetic field will be

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 7

Answer: c
Explanation: For perfect conductors, the electric and magnetic field E and H respectively vary by a phase of 45 degree. This is due to the polarisation phenomenon in the conductors, unlike dielectrics.

Test: Dielectric Vs Conductor Wave Propagation - Question 8

The expression for phase constant is given by

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 8

Answer: c
Explanation: The phase constant is represented as β. It is a complex quantity representing the constant angle of the wave propagated. It is given by β = ω√(με).

Test: Dielectric Vs Conductor Wave Propagation - Question 9

In waveguides, which of the following conditions will be true?

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 9

Answer: a
Explanation: In waveguides, the phase velocity will always be greater than the speed of light. This enables the wave to propagate through the waveguide. Thus V > c is the required condition.

Test: Dielectric Vs Conductor Wave Propagation - Question 10

The attenuation constant in lossless dielectrics will be

Detailed Solution for Test: Dielectric Vs Conductor Wave Propagation - Question 10

Answer: a
Explanation: In lossless dielectrics, the attenuation constant will not be same as the phase constant, unlike conductors. Also, due to the lossless behaviour, the attenuation will be nearly zero. Practically, zero attenuation is not possible.

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