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# Test: Divergence

## 10 Questions MCQ Test Electromagnetic Theory | Test: Divergence

Description
This mock test of Test: Divergence for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Divergence (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Divergence quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Divergence exercise for a better result in the exam. You can find other Test: Divergence extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### The divergence of a vector is a scalar. State True/False.

Solution:

Explanation: Divergence can be computed only for a vector. Since it is the measure of outward flow of flux from a small closed surface as the volume shrinks to zero, the result will be directionless (scalar).

QUESTION: 2

### The divergence concept can be illustrated using Pascal’s law. State True/False.

Solution:

Explanation: Consider the illustration of Pascal’s law, wherein a ball is pricked with holes all over its body. After water is filled in it and pressure is applied on it, the water flows out the holes uniformly. This is analogous to the flux flowing outside a closed surface as the volume reduces.

QUESTION: 3

### Compute the divergence of the vector xi + yj + zk.

Solution:

Explanation: The vector given is a position vector. The divergence of any position vector is always 3.

QUESTION: 4

Find the divergence of the vector yi + zj + xk.

Solution:

Explanation: Div (yi + zj + xk) = Dx(y) + Dy(z) + Dz(x), which is zero. Here D refers to partial differentiation.

QUESTION: 5

Given D = e-xsin y i – e-xcos y j
Find divergence of D.

Solution:

Explanation: Div (D) = Dx(e-xsin y) + Dy(-e-xcos y ) = -e-xsin y + e-xsin y = 0.

QUESTION: 6

Find the divergence of the vector F= xe-x i + y j – xz k

Solution:

Explanation: Div(F) = Dx(xe-x) + Dy(y)+Dz(-xz) = -xe-x + e-x + 1 – x =
e-x(1 – x) + (1 – x) = (1 – x)(1 + e-x).

QUESTION: 7

Determine the divergence of F = 30 i + 2xy j + 5xz2 k at (1,1,-0.2) and state the nature of the field.

Solution:

Explanation: Div(F) = Dx(30) + Dy(2xy) + Dz(5xz2) = 0 + 2x + 10xz = 2x + 10xz
Divergence at (1,1,-0.2) will give zero. As the divergence is zero, field is solenoidal.
Alternate/Shortcut: Without calculation, we can easily choose option b, as by theory when the divergence is zero, the vector is solenoidal. Option b is the only one which is satisfying this condition.

QUESTION: 8

Find whether the vector is solenoidal, E = yz i + xz j + xy k

Solution:

Explanation: Div(E) = Dx(yz) + Dy(xz) + Dz(xy) = 0. The divergence is zero, thus vector is divergentless or solenoidal.

QUESTION: 9

Find the divergence of the field, P = x2yz i + xz k

Solution: