Test: Electric Dipole


10 Questions MCQ Test Electromagnetic Theory | Test: Electric Dipole


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This mock test of Test: Electric Dipole for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Electric Dipole (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Electric Dipole quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Electric Dipole exercise for a better result in the exam. You can find other Test: Electric Dipole extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

Choose the best definition of a dipole.

Solution:

Answer: c
Explanation: An electric dipole generally refers to two equal and unlike (opposite signs) charges separated by a small distance. It can be anywhere, not necessarily at origin.

QUESTION: 2

The potential due to a dipole at a point P from it is the

Solution:

Answer: b
Explanation: The total potential at the point P due to the dipole is given by the difference of the potentials of the individual charges.
V = V1 + (-V2), since both the charges are unlike. Thus V = V1 – V2.

QUESTION: 3

Calculate the dipole moment of a dipole with equal charges 2C and -2C separated by a distance of 2cm.

Solution:

Answer: b
Explanation: The dipole moment of charge 2C and distance 2cm will be,
M = Q x d. Thus, M = 2 x 0.02 = 0.04 C-m.

QUESTION: 4

Find the angle at which the potential due a dipole is measured, when the distance from one charge is 12cm and that due to other is 11cm, separated to each other by a distance of 2cm.

Solution:

Answer: d
Explanation: Here, the two charges are separated by d = 2cm.
The distance from one charge (say Q1) will be R1 = 11cm. The distance from another charge (say Q2) will be R2 = 12cm. If R1 and R2 is assumed to be parallel, then R2 – R1 = d cos θ. We get 1 = 2cos θ and cos θ = 0.5. Then θ =
cos-1(0.5) = 60.

QUESTION: 5

Find the potential due the dipole when the angle subtended by the two charges at the point P is perpendicular.

Solution:

Answer: a
Explanation: The potential due the dipole is given by, V = m cos θ/(4πεr2). When the angle becomes perpendicular (θ = 90). The potential becomes zero since cos 90 will become zero.

QUESTION: 6

For two charges 3C and -3C separated by 1cm and are located at distances 5cm and 7cm respectively from the point P, then the distance between their midpoint and the point P will be

Solution:

Answer: a
Explanation: For a distant point P, the R1 and R2 will approximately be equal.
R1 = R2 = r, where r is the distance between P and the midpoint of the two charges. Thus they are in geometric progression, R1R2=r2
Now, r2 = 5 x 7 = 35. We get r = 5.91cm.

QUESTION: 7

Calculate the distance between two charges of 4C forming a dipole, with a dipole moment of 6 units.

Solution:

Answer: b
Explanation: The dipole moment is given by, M = Q x d. To get d, we rearrange the formula d = M/Q = 6/4 = 1.5units.

QUESTION: 8

The potential due to the dipole on the midpoint of the two charges will be

Solution:

Answer: c
Explanation: The potential due a dipole at a point P will be V = m cos θ/(4πεr2).
Now it is given that potential on the midpoint, which means P is on midpoint, then the distance from midpoint and P will be zero. When r = 0 is put in the above equation, we get V = ∞. This shows that the potential of a dipole at its midpoint will be maximum/infinity.

QUESTION: 9

Dipoles in any electric field undergo

Solution:

Answer: d
Explanation: Dipoles in any pure electric field will undergo polarisation. It is the process of alignment of dipole moments in accordance with the electric field applied.

QUESTION: 10

Dipole moments are used to calculate the

Solution:

Answer: b
Explanation: Dipole moment implicates the strength of the dipole in the electric field. They are then used to compute the polarisation patterns based on the applied field. Once the polarisation is determined we can find its susceptibility. Though all options seem to be correct, the apt answer is to calculate polarisation, provided applied field is known.

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