Test: Electric Field Density


9 Questions MCQ Test Electromagnetic Theory | Test: Electric Field Density


Description
This mock test of Test: Electric Field Density for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 9 Multiple Choice Questions for Electrical Engineering (EE) Test: Electric Field Density (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Electric Field Density quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Electric Field Density exercise for a better result in the exam. You can find other Test: Electric Field Density extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

The lines of force are said to be

Solution:

Answer: c
Explanation: The lines drawn to trace the direction in which a positive test charge will experience force due to the main charge are called lines of force. They are not real but drawn for our interpretation.

QUESTION: 2

Which of the following correctly states Gauss law?

Solution:

Answer: d
Explanation: The electric flux passing through any closed surface is equal to the total charge enclosed by that surface. In other words, electric flux per unit volume leaving a point (vanishing small volume), is equal to the volume charge density.

QUESTION: 3

Find the flux density of a sheet of charge density 25 units in air.

Solution:

Answer: b
Explanation: Electric field intensity of infinite sheet of charge E = σ/2ε.
Thus D = εE = σ/2 = 25/2 = 12.5.

QUESTION: 4

The electric flux density is the

Solution:

Answer: a
Explanation: D= εE, where ε=εoεr is the permittivity of electric field and E is the electric field intensity. Thus electric flux density is the product of permittivity and electric field intensity.

QUESTION: 5

A uniform surface charge of σ = 2 μC/m2, is situated at z = 2 plane. What is the value of flux density at P(1,1,1)m? 

Solution:

Answer: b
Explanation: The flux density of any field is independent of the position (point). D = σ/2 = 2 X 10-6(-az)/2 = -10-6.

QUESTION: 6

Find the flux density of line charge of radius (cylinder is the Gaussian surface) 2m and charge density is 3.14 units?

Solution:

Answer: d
Explanation: The electric field of a line charge is given by, E = λ/(2περ), where ρ is the radius of cylinder, which is the Gaussian surface and λ is the charge density. The density D = εE = λ/(2πρ) = 3.14/(2π X 2) = 1/4 = 0.25.

QUESTION: 7

Find the electric field intensity of transformer oil (εr = 2 approx) with density 1/4π (in 109units) 

Solution:

Answer: c
Explanation: D = εE. E = (1/4π)/(2Xεo) = 4.5 X 109 units.

QUESTION: 8

Electric flux density in electric field is referred to as

Solution:

Answer: b
Explanation: Electric flux density is given by the ratio between number of flux lines crossing a surface normal to the lines and the surface area. The direction of D at a point is the direction of the flux lines at that point.

QUESTION: 9

If the radius of a sphere is 1/(4π)m and the electric flux density is 16π units, the total flux is given by,

Solution:

Answer: c
Explanation: Total flux leaving the entire surface is, ψ = 4πr2D from Gauss law. Ψ = 4π(1/16π2) X 16π = 4.

Related tests