Test: Electrostatic Energy & Its Properties - Electrical Engineering (EE) MCQ

# Test: Electrostatic Energy & Its Properties - Electrical Engineering (EE) MCQ

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## 20 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Electrostatic Energy & Its Properties

Test: Electrostatic Energy & Its Properties for Electrical Engineering (EE) 2024 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Electrostatic Energy & Its Properties questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Electrostatic Energy & Its Properties MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Electrostatic Energy & Its Properties below.
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Test: Electrostatic Energy & Its Properties - Question 1

### The electrostatic energy in an electric field does not depend on which of the following?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 1

Explanation: The energy in an electric field directly magnitude of charges. Thus electric field and flux density are also dependent. But the applied field affects only the polarisation and it is independent of the energy in the field.

Test: Electrostatic Energy & Its Properties - Question 2

### Calculate the energy in an electric field with flux density 6 units and field intensity of 4 units.

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 2

Explanation: The energy in an electric field is given by, W = 0.5 x D x E, where D = 6 and E = 4. We get W = 0.5 x 6 x 4 = 12 units.

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Test: Electrostatic Energy & Its Properties - Question 3

### Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ)

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 3

Explanation: The energy in an electric field is given by, W = 0.5 x D x E. Since D = εE, we get W = 0.5 x ε x E2. On substituting the data, we get 3.16 microjoule.

Test: Electrostatic Energy & Its Properties - Question 4

Equipotential surface is a

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 4

Explanation: Equipotential surface is an imaginary surface in an electric field of a given charge distribution in which all the points on the surface are at the same electric potential.

Test: Electrostatic Energy & Its Properties - Question 5

The work done in moving a test charge from one point to another in an equipotential surface is zero. State True/False.

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 5

Explanation: Since the electric potential in the equipotential surface is the same, the work done will be zero.

Test: Electrostatic Energy & Its Properties - Question 6

When curl of a path is zero, the field is said to be conservative. State True/False.

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 6

Explanation: By Stoke’s theorem, when curl of a path becomes zero, then
∫ E.dl = 0. In other words the work done in a closed path will always be zero. Fields having this property is called conservative or lamellar fields.

Test: Electrostatic Energy & Its Properties - Question 7

If the electric potential is given, which of the following cannot be calculated?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 7

Explanation: Using potential, we can calculate electric field directly by gradient operation. From E, the flux density D can also be calculated. Thus it is not possible to calculate energy directly from potential.

Test: Electrostatic Energy & Its Properties - Question 8

Superconductors exhibit which of the following properties?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 8

Explanation: Since superconductors have very good conductivity at low temperatures (σ->∞), they have nearly zero resistivity and exhibit perfect diamagnetism.

Test: Electrostatic Energy & Its Properties - Question 9

Debye is the unit used to measure

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 9

Explanation: Debye is the standard unit for measurement of electric dipole moment. 1 Debye = 3.336 x 10-30 Coulomb-meter.

Test: Electrostatic Energy & Its Properties - Question 10

Ceramic materials possess which of the following properties?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 10

Explanation: Ceramic materials are generally brittle. Since these materials are used in capacitors, they have higher dielectric constant than polymer. With respect to energy, they possess high electrostatic energy due to very high dielectric constant (W α ε).

Test: Electrostatic Energy & Its Properties - Question 11

The permittivity is also called

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 11

Explanation: The term permittivity or dielectric constant is the measurement of electrostatic energy stored within it and therefore depends on the material.

Test: Electrostatic Energy & Its Properties - Question 12

Dielectric constant will be high in

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 12

Explanation: Materials that have very less conductivity like ceramics, plastics have higher dielectric constants. Due to their low conductivity, the dielectric materials are said to be good insulators.

Test: Electrostatic Energy & Its Properties - Question 13

Under the influence of electric field, the dielectric materials will get charged instantaneously. State True/False.

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 13

Explanation: The dielectrics have the ability of storing energy easily when an electric field is applied as their permittivity is relatively higher than any other materials.

Test: Electrostatic Energy & Its Properties - Question 14

Insulators perform which of the following functions?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 14

Explanation: Insulators is a non-conducting material which prevents the leakage of electric current in unwanted directions. Thus it is used to provide electrical insulation.

Test: Electrostatic Energy & Its Properties - Question 15

Which of the following properties distinguish a material as conductor, insulator and semiconductor?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 15

Explanation: The only parameter that classifies the material as conductor or insulator or semiconductor is the band gap energy. It is the energy required to make the electrons conduct. This is low of conductors, average for semiconductors and very high for insulators. This means it requires very high energy to make an insulator conduct.

Test: Electrostatic Energy & Its Properties - Question 16

Semiconductors possess which type of bonding?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 16

Explanation: Conductors exhibit metallic bonding. Insulators exhibit ionic bonding and semiconductors exhibit covalent bonding due to sharing of atoms.

Test: Electrostatic Energy & Its Properties - Question 17

Find the susceptibility of a material whose dielectric constant is 2.26.

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 17

Explanation: Electric susceptibility is the measure of ability of the material to get polarised. It is given by, χe = εr – 1.Thus we get 1.26.

Test: Electrostatic Energy & Its Properties - Question 18

The bound charge density and free charge density are 12 and 6 units respectively. Calculate the susceptibility.

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 18

Explanation: The electric susceptibility is given by, χe = Bound free density/Free charge density. χe = 12/6 = 2. It has no unit.

Test: Electrostatic Energy & Its Properties - Question 19

The susceptibility of free space is

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 19

Explanation: For free space/air, the relative permittivity is unity i.e, εr = 1. Thus χe = εr – 1 = 0. The susceptibility will become zero in air.

Test: Electrostatic Energy & Its Properties - Question 20

When the electric field becomes zero, which of the following relations hold good?

Detailed Solution for Test: Electrostatic Energy & Its Properties - Question 20

Explanation: The electric flux density of a field is the sum of εE and polarisation P. It gives D = εE + P. When electric field becomes zero, it is clear that D = P.

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## Electromagnetic Fields Theory (EMFT)

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