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# Test: Faraday Law, EMF And Lenz Law

## 10 Questions MCQ Test Electromagnetic Theory | Test: Faraday Law, EMF And Lenz Law

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This mock test of Test: Faraday Law, EMF And Lenz Law for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Faraday Law, EMF And Lenz Law (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Faraday Law, EMF And Lenz Law quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Faraday Law, EMF And Lenz Law exercise for a better result in the exam. You can find other Test: Faraday Law, EMF And Lenz Law extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### For time varying currents, the field or waves will be

Solution:

Explanation: For stationary charges, the field is electrostatic. For steady currents, the field is magneto static. But for time varying currents, the field or waves will be electromagnetic.

QUESTION: 2

### According to Faraday’s law, EMF stands for

Solution:

Explanation: The force in any closed circuit due to the change in the flux linkage of the circuit is called as electromotive force EMF. This phenomenon is called as Faraday’s law.

QUESTION: 3

### Calculate the emf when the flux is given by 3sin t + 5cos t

Solution:

Explanation: The electromotive force is given by Vemf = -dλ/dt. Thus Vemf = -dλ/dt = -(3cos t – 5sin t) = -3cos t + 5sin t.

QUESTION: 4

The induced voltage will oppose the flux producing it. State True/False.

Solution:

Explanation: According to Lenz law, the induced voltage acts in such a way that it opposes the flux producing it. This is indicated by a negative sign.

QUESTION: 5

Calculate the emf when a coil of 100 turns is subjected to a flux rate of 0.3 tesla/sec.

Solution:

Explanation: The induced emf is given by Vemf = -dλ/dt = -Ndψ/dt. Thus emf will be -100 x 0.3 = -30 units.

QUESTION: 6

Find the displacement current when the flux density is given by t3 at 2 seconds.

Solution:

Explanation: The displacement current is given by Jd = dD/dt. Thus Jd = 3t2. At time t = 2, we get Jd = 3(2)2= 12A.

QUESTION: 7

Find the force due to a current element of length 2cm and flux density of 12 tesla. The current through the element will be 5A.

Solution:

Explanation: The force due to a current element is given by F = BI x L. Thus F = 12 x 5 x 0.02 = 1.2 units.

QUESTION: 8

Which of the following statements is true?

Solution:

Explanation: The electric field is the cross product of the velocity and the magnetic field intensity. This is given by Lorentz equation

QUESTION: 9

The time varying electric field E is conservative. State True/False.

Solution: