Test: Faraday Law, EMF & Lenz Law - Electrical Engineering (EE) MCQ

# Test: Faraday Law, EMF & Lenz Law - Electrical Engineering (EE) MCQ

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## 10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Faraday Law, EMF & Lenz Law

Test: Faraday Law, EMF & Lenz Law for Electrical Engineering (EE) 2024 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Faraday Law, EMF & Lenz Law questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Faraday Law, EMF & Lenz Law MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Faraday Law, EMF & Lenz Law below.
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Test: Faraday Law, EMF & Lenz Law - Question 1

### For time varying currents, the field or waves will be

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 1

Explanation: For stationary charges, the field is electrostatic. For steady currents, the field is magneto static. But for time varying currents, the field or waves will be electromagnetic.

Test: Faraday Law, EMF & Lenz Law - Question 2

### According to Faraday’s law, EMF stands for

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 2

Explanation: The force in any closed circuit due to the change in the flux linkage of the circuit is called as electromotive force EMF. This phenomenon is called as Faraday’s law.

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Test: Faraday Law, EMF & Lenz Law - Question 3

### Calculate the emf when the flux is given by 3sin t + 5cos t

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 3

Explanation: The electromotive force is given by Vemf = -dλ/dt. Thus Vemf = -dλ/dt = -(3cos t – 5sin t) = -3cos t + 5sin t.

Test: Faraday Law, EMF & Lenz Law - Question 4

The induced voltage will oppose the flux producing it. State True/False.

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 4

Explanation: According to Lenz law, the induced voltage acts in such a way that it opposes the flux producing it. This is indicated by a negative sign.

Test: Faraday Law, EMF & Lenz Law - Question 5

Calculate the emf when a coil of 100 turns is subjected to a flux rate of 0.3 tesla/sec.

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 5

Explanation: The induced emf is given by Vemf = -dλ/dt = -Ndψ/dt. Thus emf will be -100 x 0.3 = -30 units.

Test: Faraday Law, EMF & Lenz Law - Question 6

Find the displacement current when the flux density is given by t3 at 2 seconds.

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 6

Explanation: The displacement current is given by Jd = dD/dt. Thus Jd = 3t2. At time t = 2, we get Jd = 3(2)2= 12A.

Test: Faraday Law, EMF & Lenz Law - Question 7

Find the force due to a current element of length 2cm and flux density of 12 tesla. The current through the element will be 5A.

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 7

Explanation: The force due to a current element is given by F = BI x L. Thus F = 12 x 5 x 0.02 = 1.2 units.

Test: Faraday Law, EMF & Lenz Law - Question 8

Which of the following statements is true?

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 8

Explanation: The electric field is the cross product of the velocity and the magnetic field intensity. This is given by Lorentz equation

Test: Faraday Law, EMF & Lenz Law - Question 9

The time varying electric field E is conservative. State True/False.

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 9

Explanation: The time varying electric field E(t) is not a closed path. Thus the curl will be non-zero. This implies E(t) is not conservative and the statement is false.

Test: Faraday Law, EMF & Lenz Law - Question 10

When the conduction current density and displacement current density are same, the dissipation factor will be

Detailed Solution for Test: Faraday Law, EMF & Lenz Law - Question 10

Explanation: Dissipation factor refers to the tangent of loss angle. It is the ratio of conduction current density to displacement current density. When both are same, the loss tangent or the dissipation factor will be unity.

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