Test: Loss Tangent
10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Loss Tangent
| 1 Crore+ students have signed up on EduRev. Have you? |
Answer: a
Explanation: The loss tangent is the tangent angle formed by the plot of conduction current density vs displacement current density. It is the ratio of Jc by Jd. It represents the loss of power due to propagation in a dielectric, when compared to that in a conductor.
Calculate the conduction current density when the resistivity of a material with an electric field of 5 units is 4.5 units.
Answer: c
Explanation: The conduction current density is the product of the conductivity and the electric field. The resistivity is the reciprocal of the conductivity. Thus the required formula is Jc = σ E = E/ρ = 5/4.5 units.
Answer: b
Explanation: The conduction current occurs in metals and is independent of the frequency. The attenuation and phase constant highly depend on the varying frequency. The displacement current occurs due to dielectrics and is significant only at very high frequencies.
Find the loss tangent of a material with conduction current density of 5 units and displacement current density of 10 units.
Answer: b
Explanation: The loss tangent is the ratio of Jc by Jd. On substituting for Jc = 5 and Jd = 10, the loss tangent, tan δ = 5/10 = 0.5. It is to be noted that it is tangent angle, so that the maxima and minima lies between 1 and -1 respectively.
Answer: c
Explanation: The loss tangent is the measure of the loss of power due to propagation in a dielectric, when compared to that in a conductor. Hence it is also referred to as dissipation factor.
The loss tangent of a wave propagation with an intrinsic angle of 20 degree is
Answer: b
Explanation: The angle of the loss tangent δ is twice the intrinsic angle θn. Thus tan δ = tan 2θn = tan 2(20) = tan 40.
Answer: a
Explanation: The conduction current density is Jc = σ E and the displacement current density is Jd = jωεE. Its magnitude will be ωεE. Thus the loss tangent tan δ = Jc /Jd = σ/ωε is the required expression.
Answer: c
Explanation: The loss tangent is tan δ, where δ is the loss angle. Given that loss tangent tan δ = 1. Thus we get δ = tan-1(1) = 450.
The complex permittivity is given by 2-j. Find the loss tangent.
Answer: a
Explanation: The loss tangent for a given complex permittivity of ε = ε’ – jε’’ is given by tan δ = ε’’/ ε’. Thus the loss tangent is 1/2.
Answer: d
Explanation: The angle of the loss tangent δ is twice the intrinsic angle θn. Thus tan δ = tan 2θn. We get θn = δ/2 = 60/2 = 30 degrees.
|
11 videos|46 docs|62 tests
|
|
Use Code STAYHOME200 and get INR 200 additional OFF
|
Use Coupon Code |
|
11 videos|46 docs|62 tests
|
Download free EduRev App
Related content with Test: Loss Tangent
|
|
Related tests with Test: Loss Tangent
|
|
|
|
|
|
© EduRev
|
Education Revolution
|
Follow Us
|
