Test: Lossy & Lossless Dielectrics - Electrical Engineering (EE) MCQ

# Test: Lossy & Lossless Dielectrics - Electrical Engineering (EE) MCQ

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## 12 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Lossy & Lossless Dielectrics

Test: Lossy & Lossless Dielectrics for Electrical Engineering (EE) 2024 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Lossy & Lossless Dielectrics questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Lossy & Lossless Dielectrics MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Lossy & Lossless Dielectrics below.
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Test: Lossy & Lossless Dielectrics - Question 1

### For a dielectric, the condition to be satisfied is

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 1

Explanation: In a dielectric, the conductivity will be very less. Thus the loss tangent will be less than unity. This implies σ/ωε < 1 is true.

Test: Lossy & Lossless Dielectrics - Question 2

### For a perfect dielectric, which parameter will be zero?

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 2

Explanation: The conductivity will be minimum for a dielectric. For a perfect dielectric, the conductivity will be zero.

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Test: Lossy & Lossless Dielectrics - Question 3

### Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×108 m/s(in 10-8 order)

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 3

Explanation: The phase constant is given by β = ω√(με), where ω is the frequency in rad/s and 1/√(με) is the velocity of wave. On substituting √(με) = 3×108 and ω = 12, we get β = 12/(3×108) = 4 x 10-8m/s.

Test: Lossy & Lossless Dielectrics - Question 4

For a lossless dielectric, the attenuation will be

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 4

Explanation: The attenuation is the loss of power of the wave during its propagation. In a lossless dielectric, the loss of power will not occur. Thus the attenuation will be zero.

Test: Lossy & Lossless Dielectrics - Question 5

Calculate the velocity of a wave with frequency 2 x109 rad/s and phase constant of 4 x 108units.

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 5

Explanation: The velocity of a wave is the ratio of the frequency to the phase constant. Thus V = ω/β. On substituting the given values, we get V = 2 x109/ 4 x 108 = 5 units.

Test: Lossy & Lossless Dielectrics - Question 6

Which of the following is the correct relation between wavelength and the phase constant of a wave?

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 6

Explanation: The phase constant is the ratio of 2π to the wavelength λ. Thus β = 2π/λ is the correct relation

Test: Lossy & Lossless Dielectrics - Question 7

In lossy dielectric, the phase difference between the electric field E and the magnetic field H is

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 7

Explanation: In a lossy dielectric, the E and H component will be in phase. This implies that the phase difference between E and H will be 0.

Test: Lossy & Lossless Dielectrics - Question 8

The intrinsic impedance is the ratio of square root of

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 8

Explanation: The intrinsic impedance is the impedance of a particular material. It is the ratio of square root of the permeability to permittivity. For air, the intrinsic impedance is 377 ohm or 120π.

Test: Lossy & Lossless Dielectrics - Question 9

Calculate the skin depth of a material with attenuation constant of 2 units.

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 9

Explanation: The skin depth of a material is the reciprocal of the attenuation constant. Thus δ = 1/α. On substituting for α = 2, we get δ = ½ = 0.5 units.

Test: Lossy & Lossless Dielectrics - Question 10

Calculate the phase constant of a wave with skin depth of 2.5 units.

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 10

Explanation: The skin depth is the reciprocal of the phase constant and the attenuation constant too. Thus δ = 1/β. On substituting for δ = 2.5, we get β = 1/δ = 1/2.5 = 2/5 units.

Test: Lossy & Lossless Dielectrics - Question 11

An example for lossless propagation is

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 11

Explanation: There are many techniques employed to achieve zero attenuation or maximum propagation. But it is not achievable practically. Thus lossless propagation is not possible practically

Test: Lossy & Lossless Dielectrics - Question 12

Skin depth phenomenon is found in which materials?

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 12

Explanation: Skin depth is found in pure conductors. It the property of the conductor to allow a small amount of electromagnetic energy into its skin, but not completely. This is the reason why EM waves cannot travel inside a good conductor.

## Electromagnetic Fields Theory (EMFT)

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## Electromagnetic Fields Theory (EMFT)

11 videos|45 docs|73 tests