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Test: Magnetic Force & Lorentz Force


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Magnetic Force & Lorentz Force

Test: Magnetic Force & Lorentz Force for Electrical Engineering (EE) 2023 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Magnetic Force & Lorentz Force questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Magnetic Force & Lorentz Force MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Magnetic Force & Lorentz Force below.
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Test: Magnetic Force & Lorentz Force - Question 1

Find the electric force when the charge of 2C is subjected to an electric field of 6 units.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 1

Answer: c
Explanation: The electric force is given by F = qE, where q = 2C and E = 6 units. Thus we get F = 2 x 6 = 12 units.

Test: Magnetic Force & Lorentz Force - Question 2

Find the magnetic force when a charge 3.5C with flux density of 4 units is having a velocity of 2m/s.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 2

Answer: b
Explanation: The magnetic force is given by F = q(v x B), where q = 3.5C, v = 2m/s and B = 4 units. Thus we get F = 3.5(2 x 4) = 28 units.

Test: Magnetic Force & Lorentz Force - Question 3

Find the electric field when the velocity of the field is 12m/s and the flux density is 8.75 units.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 3

Answer: b
Explanation: The electric field intensity is the product of the velocity and the magnetic flux density ie, E = v x B = 12 x 8.75 = 105 units.

Test: Magnetic Force & Lorentz Force - Question 4

Find the Lorentz force of a charge 2.5C having an electric field of 5 units and magnetic field of 7.25 units with a velocity 1.5m/s.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 4

Answer: a
Explanation: The Lorentz force is given by F = qE + q(v x B), it is the sum of electric and magnetic force. On substituting q = 2.5, E = 5, v = 1.5 and B = 7.25, F = 2.5(5) + 2.5(1.5 x 7.25) = 39.68 units.

Test: Magnetic Force & Lorentz Force - Question 5

The force on a conductor of length 12cm having current 8A and flux density 3.75 units at an angle of 300 is

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 5

Answer: d
Explanation: The force on a conductor is given by F = BIL sin θ, where B = 3.75, I = 8, L = 0.12 and θ = 300. We get F = 3.75 x 8 x 0.12 sin 30 = 1.8 units.

Test: Magnetic Force & Lorentz Force - Question 6

The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10-6 order) 

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 6

Answer: a
Explanation: The force per unit length of two conductors is given by
F = μ I1xI2/2πD, where I1 = I2 = 5 and D = 0.2. Thus F = 4π x 10-7 x 52/ 2π x 0.2 = 25 x 10-6 units.

Test: Magnetic Force & Lorentz Force - Question 7

When currents are moving in the same direction in two conductors, then the force will be

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 7

Answer: a
Explanation: When two conductors are having currents moving in the same direction then the forces of the two conductors will be moving towards each other or attractive.

Test: Magnetic Force & Lorentz Force - Question 8

Find the flux density due to a conductor of length 6m and carrying a current of 3A(in 10-7order) 

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 8

Answer: a
Explanation: The flux density is B = μH, where H = I/2πR. Put I = 3 and R = 6, we get B = 4π x 10-7 x 3/2π x 6 = 1 x 10-7 units.

Test: Magnetic Force & Lorentz Force - Question 9

Find the maximum force of the conductor having length 60cm, current 2.75A and flux density of 9 units.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 9

Answer: a
Explanation: The force on a conductor is given by F = BIL sin θ, where B = 3.75, I = 8, L = 0.12 and θ = 90 for maximum force. We get F
= BIL= 9 x 2.75 x 0.6 sin 90 = 14.85 units.

Test: Magnetic Force & Lorentz Force - Question 10

The magnetic force impacts the energy of the field. State True/false. 

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 10

Answer: a
Explanation: The magnetic force depends on the flux density of a material and the flux density is in turn dependent on the energy of the material. It can be shown that F = q(v x B) and E = 0.5 x B2/μ. It is clear that B and F are related.

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