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# Test: Maxwell Law - 2

## 20 Questions MCQ Test Electromagnetic Theory | Test: Maxwell Law - 2

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This mock test of Test: Maxwell Law - 2 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 20 Multiple Choice Questions for Electrical Engineering (EE) Test: Maxwell Law - 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Maxwell Law - 2 quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Maxwell Law - 2 exercise for a better result in the exam. You can find other Test: Maxwell Law - 2 extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### The charge density of a electrostatic field is given by

Solution:

Explanation: From the Gauss law for electric field, the volume charge density is the divergence of the electric flux density of the field. Thus Div(D) = ρv.

QUESTION: 2

### In the medium of free space, the divergence of the electric flux density will be

Solution:

Explanation: In free space or air, the charge density will be zero. In other words, the conduction is possible in mere air medium. By gauss law, since the charge density is same as the divergence of D, the Div(D) in air/free space will be zero.

QUESTION: 3

### In a medium other than air, the electric flux density will be

Solution:

Explanation: In any medium other than the air, the conduction is possible, due to the charge carriers. Thus charge density is also non-zero. We can write from Gauss law that Div(D) is non-zero. When the divergence is said to be non-zero, the field is not solenoidal or called as divergent field.

QUESTION: 4

For a solenoidal field, the surface integral of D will be,

Solution:

Explanation: For a solenoidal field, the divergence will be zero. By divergence theorem, the surface integral of D and the volume integral of Div(D) is same. So as the Div(D) is zero for a solenoidal field, the surface integral of D is also zero.

QUESTION: 5

In a dipole, the Gauss theorem value will be

Solution:

Explanation: The Gauss theorem for an electric field is given by Div(D)= ρ. In a dipole only static charge exists and the divergence will be zero. Thus the Gauss theorem value for the dipole will be zero.

QUESTION: 6

Find the electric flux density of a material whose charge density is given by 12 units in a volume region of 0.5 units.

Solution:

Explanation: By Gauss law, Div(D) = ρv. To get D, integrate the charge density given. Thus D = ∫ρv dv, where ρv = 12 and ∫dv = 0.5. We get, D = 12 x 0.5 = 6 units.

QUESTION: 7

From the Gauss law for electric field, we can compute which of the following parameters?

Solution:

Explanation: From the Gauss law for electric field, we can find the electric flux density directly. On substituting, D= ε E, the electric field intensity can be calculated.

QUESTION: 8

The charge density of a system with the position vector as electric flux density is

Solution:

Explanation: The divergence of the electric flux density is the charge density. For a position vector xi + yj + zk, the divergence will be 1 + 1 + 1 = 3. Thus by Gauss law, the charge density is also 3.

QUESTION: 9

The sequence for finding E when charge density is given is

Solution:

Explanation: From the given charge density ρv, we can compute the electric flux density by Gauss law. Since, D = εE, the electric field intensity can also be computed. Thus the sequence is E-D-ρv.

QUESTION: 10

The Gauss law employs which theorem for the calculation of charge density?

Solution:

Explanation: The Gauss divergence theorem is given by ∫ D.ds = ∫Div(D).dv. From the theorem value, we can compute the charge density. Thus Gauss law employs the Gauss divergence theorem.

QUESTION: 11

Which quantity is solenoidal in the electromagnetic theory?

Solution:

Explanation: The divergence of the magnetic flux density is zero. This is the Maxwell fourth equation. As the divergence is zero, the quantity will be solenoidal or divergent less.

QUESTION: 12

Which equation will be true, if the medium is considered to be air?

Solution:

Explanation: From the Gauss law for magnetic field, the divergence of the magnetic flux density is zero. Also B = μH. Thus divergence of H is also zero, i.e, Div(H) = 0 is true.

QUESTION: 13

Find the sequence to find B when E is given.

Solution:

Explanation: From E, D can be computed as D = εE. Using the Ampere law, H can be computed from D. Finally, B can be calculated from H by B = μH.

QUESTION: 14

The Gauss law for magnetic field is valid in

Solution:

Explanation: The Gauss law for magnetic field states that the divergence of B is always zero. This is valid for all cases like free space, dielectric medium etc.

QUESTION: 15

The sequence for finding H from E is

Solution:

Explanation: From E, we can compute B using the Maxwell first law. Using B, the parameter H can be found since B = μH. Thus the sequence is E-B-H is true.

QUESTION: 16

The reason for non existence of magnetic monopoles is

Solution:

Explanation: Practically monopoles do not exist, due to the connection between north and south poles. But theoretically, they exist. The reason for their non- existence practically is that, the magnetic field confined to two poles cannot be split or confined to a single pole.

QUESTION: 17

The non existence of the magnetic monopole is due to which operation?

Solution:

Explanation: The Maxwell fourth law or the Gauss law for magnetic field states that the divergence of B is zero, implies the non existence of magnetic monopoles. Thus the operation involved is divergence.

QUESTION: 18

Will dielectric breakdown lead to formation of magnetic monopole?

Solution:

Explanation: When dielectric breakdown occurs, the material loses its dielectric property and becomes a conductor. When it is subjected to a magnetic field, north and south flux lines coexists, giving magnetic force. Thus there exists magnetic dipole. Suppose if the conductor is broken into very small pieces, still there exist a magnetic dipole in every broken part. In other words, when a piece is broken into half, there cannot exist a north pole in one half and a south pole in the other. Thus monopoles never exist.

QUESTION: 19

Which equation will hold good for a magnetic material?

Solution: