Test: S & P Polarised Waves


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: S & P Polarised Waves

Test: S & P Polarised Waves for Electrical Engineering (EE) 2023 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: S & P Polarised Waves questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: S & P Polarised Waves MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: S & P Polarised Waves below.
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Test: S & P Polarised Waves - Question 1

The resultant electric field of a wave with Ex = 3 and Ey = 4 will be

Detailed Solution for Test: S & P Polarised Waves - Question 1

Answer: d
Explanation: The resultant electric field of two electric components Ex and Ey is E = √(Ex2 + Ey2). On substituting for Ex = 3 and Ey = 4, we get E = 5 units.

Test: S & P Polarised Waves - Question 2

In S polarisation, the electric field lies in the plane perpendicular to that of the interface. State True/False

Detailed Solution for Test: S & P Polarised Waves - Question 2

Answer: a
Explanation: In the EM wave propagation, the electric and magnetic fields are perpendicular to each other. The S polarised wave is similar to the transverse magnetic (TM) wave, the electric field lies in the plane perpendicular to that of the interface.

Test: S & P Polarised Waves - Question 3

In P polarisation, the electric field lies in the same plane as the interface. State True/False.

Detailed Solution for Test: S & P Polarised Waves - Question 3

Answer: a
Explanation: In the EM wave propagation, the electric and magnetic fields are perpendicular to each other. The P polarised wave is similar to the transverse electric (TE) wave, the magnetic field lies in the plane perpendicular to that of the interface or the electric field lies in the same plane as the interface.

Test: S & P Polarised Waves - Question 4

The group delay of a wave with phase constant 2.5 units and frequency of 1.2 radian/sec is

Detailed Solution for Test: S & P Polarised Waves - Question 4

Answer: d
Explanation: The group delay is given by td = β/ω. On substituting for β = 2.5 and ω = 1.2, we get the group delay as td = 2.5/1.2 = 2.08 units.

Test: S & P Polarised Waves - Question 5

The Brewster angle is valid for which type of polarisation?

Detailed Solution for Test: S & P Polarised Waves - Question 5

Answer: b
Explanation: The Brewster angle is valid for perpendicular polarisation. The P polarised wave is also a type of perpendicular polarisation. In P polarisation, the electric field lies in the plane of the interface.

Test: S & P Polarised Waves - Question 6

Find the reflection coefficient of a wave with an incident electric field of 5 units and reflected electric field of 2 units.

Detailed Solution for Test: S & P Polarised Waves - Question 6

Answer: b
Explanation: The reflection coefficient is the ratio of the reflected electric field to the incident electric field. Thus τ = Er/Ei. On substituting for Ei = 5 and Er = 2, we get τ = 2/5 = 0.4(no unit).

Test: S & P Polarised Waves - Question 7

The transmission coefficient of a wave with incident and transmitted electric field of 5 and 5 respectively is

Detailed Solution for Test: S & P Polarised Waves - Question 7

Answer: b
Explanation: The transmission coefficient is the ratio of the transmitted electric field to the incident electric field. Thus T = Et/Ei. On substituting for Et = 5 and Ei = 5, we get T = 5/5 = 1(no unit). Simply, when the incident and transmitted field are same, no reflection occurs and the transmission is unity.

Test: S & P Polarised Waves - Question 8

Find the relative permittivity of the medium having a refractive index of 1.6

Detailed Solution for Test: S & P Polarised Waves - Question 8

Answer: b
Explanation: The refractive index is the square root of the relative permittivity. It is given by n = √εr. To get εr, put n = 1.6. We get εr = n2 = 1.62 = 2.56(no unit).

Test: S & P Polarised Waves - Question 9

Calculate the transmission coefficient of a wave with a reflection coefficient of 0.6

Detailed Solution for Test: S & P Polarised Waves - Question 9

Answer: d
Explanation: The transmission coefficient is the reverse of the reflection coefficient. Thus T + τ = 1. On substituting for τ = 0.6, we get T = 0.4. It has no unit.

Test: S & P Polarised Waves - Question 10

The phase constant of a wave propagation with frequency of 35 radian/sec and time delay of 7.5 sec is

Detailed Solution for Test: S & P Polarised Waves - Question 10

Answer: b
Explanation: The group delay expression is td = β/ω. To get β, put ω = 35 and td = 7.5. Thus we get β = td x ω = 7.5 x 35 = 262.5 units.

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