Description

This mock test of Test: Transients for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam.
This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Transients (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Transients quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE)
students definitely take this Test: Transients exercise for a better result in the exam. You can find other Test: Transients extra questions,
long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.

QUESTION: 1

The resonant circuit in a waveguide refers to the

Solution:

Answer: a

Explanation: The resonant circuit refers to the tank circuit. It is parallel combination of an inductor and a capacitor.

QUESTION: 2

When a waveguide is terminated, the mode of the guided termination will be

Solution:

Answer: b

Explanation: A waveguide mode with a guided termination is represented by TEmnp and TMmnp. Here m and n are the orders of the waveguide and p is the order of the resonant cavity. It is always a non-zero value.

QUESTION: 3

The cut off frequency of a waveguide with resonant cavity is given by

Solution:

Answer: a

Explanation: The cut off frequency of the waveguide of dimensions a x b with the resonant cavity of dimension d is given by fc = √((m/a)^{2} + (n/b)^{2} + (p/d)^{2})/2. Here m and n are the orders of the waveguide, p is the order of the cavity and v is the velocity

QUESTION: 4

The power of a wave in a transmission line, when the current and the resistance are 5A and 120 ohm respectively is

Solution:

Answer: a

Explanation: The power of a line is given by P = I^{2}R. On substituting for I = 5 and R = 120, we get P = 5^{2} x 120 = 3000 units.

QUESTION: 5

The power of a wave having a magnetic field intensity of 2.5 units is

Solution:

Answer: a

Explanation: The power of a wave is given by P = 0.5 η H^{2}, where η is the intrinsic impedance and H is the magnetic field intensity. On substituting for η = 377 and H = 2.5, we get P = 0.5 x 377 x 2.5^{2} = 1.17 kilo watts.

QUESTION: 6

The power of a wave having an electric field strength of 12.8 units is

Solution:

Answer: a

Explanation: The power of a wave is given by P = 0.5 E^{2}/η, where E is the electric field intensity and η is the intrinsic impedance. On substituting for E = 12.8 and η = 377, we get P = 0.5 x 12.8^{2}/377 = 0.217 units.

QUESTION: 7

The form or mode of propagation is determined by which factors?

Solution:

Answer: c

Explanation: The form and the mode of propagation of the wave in a waveguide is determined by the type and location of the excitation device.

QUESTION: 8

The phase of the wave after the installation of the guided terminations will be

Solution:

Answer: a

Explanation: Using a guided termination, the guides serves as a reflector. If the distance between the exciter and the wall is properly adjusted, the transmitted and the reflected wave will be in phase.

QUESTION: 9

The exciter of the waveguide in a transmission line is the

Solution:

Answer: d

Explanation: The waveguide is usually excited by the antenna rod. The reflection depends on the phase of excitation and the antenna current

QUESTION: 10

A waveguide imitates which type of filter characteristics?

Solution:

Answer: b

Explanation: A waveguide passes only high frequency waves (in GHz range) and attenuates low frequencies. This is the characteristic of a high pass filter.

### Transients - Network Theory, GATE

Doc | 23 Pages

### Phasor Diagram of Transients

Video | 49:11 min

### Transients in Network System

Video | 63:00 min

### AC Transients - Network Theory, GATE

Doc | 25 Pages

- Test: Transients
Test | 10 questions | 10 min

- Test: Transients In LR Networks
Test | 10 questions | 10 min

- Test: Cloze Test- 5
Test | 5 questions | 10 min

- Test: Cloze Test- 1
Test | 15 questions | 15 min

- Divisibility Test - Practice Test
Test | 5 questions | 10 min