Test: Types of Polarization


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12 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Types of Polarization

Test: Types of Polarization for Electrical Engineering (EE) 2023 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Types of Polarization questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Types of Polarization MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Types of Polarization below.
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Test: Types of Polarization - Question 1

When the phase angle between the Ex and Ey component is 00 or 1800, the polarisation is 

Detailed Solution for Test: Types of Polarization - Question 1

Answer: c
Explanation: The phase angle between the Ex and Ey component is 00 and 1800 for linearly polarised wave. The wave is assumed to be propagating in the z direction.

Test: Types of Polarization - Question 2

The magnitude of the Ex and Ey components are same in which type of polarisation?

Detailed Solution for Test: Types of Polarization - Question 2

Answer: b
Explanation: In circular polarisation, the magnitude of the Ex and Ey components are the same. This is a form of the elliptical polarisation in which the major and minor axis are the same.

Test: Types of Polarization - Question 3

When the Ex and Ey components of a wave are not same, the polarisation will be

Detailed Solution for Test: Types of Polarization - Question 3

Answer: b
Explanation: In elliptical polarisation, the magnitude of Ex and Ey components are not same. This is due to the variation in the major and minor axes of the waves representing its magnitude.

Test: Types of Polarization - Question 4

Identify the polarisation of the wave given, Ex = Exo cos wt and Ey = Eyo sin wt. The phase difference is +900.

Detailed Solution for Test: Types of Polarization - Question 4

Answer: c
Explanation: The magnitude of the Ex and Ey components are not same. Thus it is elliptical polarisation. For +90 phase difference, the polarisation is left handed. In other words, the rotation is in clockwise direction. Thus the polarisation is left hand elliptical.

Test: Types of Polarization - Question 5

Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -900

Detailed Solution for Test: Types of Polarization - Question 5

Answer: d
Explanation: The magnitude of the Ex and Ey components are not same. Thus it is elliptical polarisation. For -90 phase difference, the polarisation is right handed. In other words, the rotation is in anti-clockwise direction. Thus the polarisation is right hand elliptical.

Test: Types of Polarization - Question 6

Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = 2 sin wt. The phase difference is +900

Detailed Solution for Test: Types of Polarization - Question 6

Answer: a
Explanation: The magnitude of the Ex and Ey components are the same. Thus it is circular polarisation. For +90 phase difference, the polarisation is left handed. In other words, the rotation is in clockwise direction. Thus the polarisation is left hand circular.

Test: Types of Polarization - Question 7

Identify the polarisation of the wave given, Ex = cos wt and Ey = sin wt. The phase difference is -900

Detailed Solution for Test: Types of Polarization - Question 7

Answer: b
Explanation: The magnitude of the Ex and Ey components are the same. Thus it is circular polarisation. For -90 phase difference, the polarisation is right handed. In other words, the rotation is in anti-clockwise direction. Thus the polarisation is right hand circular.

Test: Types of Polarization - Question 8

For a non-zero Ex component and zero Ey component, the polarisation is

Detailed Solution for Test: Types of Polarization - Question 8

Answer: a
Explanation: When the Ex is non-zero and the Ey is zero, the polarisation is parallel. The parallel polarisation is classified under the linear polarisation type.

Test: Types of Polarization - Question 9

Identify the polarisation of the wave given that, Ex = 2 cos wt and Ey = cos wt.

Detailed Solution for Test: Types of Polarization - Question 9

Answer: d
Explanation: The magnitude of the Ex and Ey components are not the same. Thus it cannot be circular polarisation. For a phase difference of 0, the polarisation is linear. In other words, the waves are in phase. Thus the polarisation is linear.

Test: Types of Polarization - Question 10

The Snell law is applicable for perpendicular polarisation and the Brewster law is applicable for parallel polarisation. State True/False.

Detailed Solution for Test: Types of Polarization - Question 10

Answer: a
Explanation: The Snell law is calculated from the oblique incidence media. Thus it is applicable for perpendicular polarisation. The Brewster law is applicable for perpendicular polarisation.

Test: Types of Polarization - Question 11

When the polarisation of the receiving antenna is unknown, to ensure that it receives atleast half the power, the transmitted wave should be

Detailed Solution for Test: Types of Polarization - Question 11

Answer: c
Explanation: The polarisation of the transmitting and receiving antenna has to be the same. This is the condition for maximum power transfer to occur. This is possible only when the polarisation is circular.

Test: Types of Polarization - Question 12

Identify the polarisation of the wave given that, Ex = 2 sin wt and Ey = 3 sin wt.

Detailed Solution for Test: Types of Polarization - Question 12

Answer: a
Explanation: The magnitude of the Ex and Ey components are not the same. Thus it cannot be circular polarisation. For a phase difference of 0, the polarisation is linear. In other words, the waves are in phase. Thus the polarisation is linear.

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