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Test: Design of Joints Level - 2 - Mechanical Engineering MCQ


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20 Questions MCQ Test Design of Machine Elements - Test: Design of Joints Level - 2

Test: Design of Joints Level - 2 for Mechanical Engineering 2024 is part of Design of Machine Elements preparation. The Test: Design of Joints Level - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Design of Joints Level - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Design of Joints Level - 2 below.
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Test: Design of Joints Level - 2 - Question 1

A double fillet welded joint with parallel fillet weld of length L and leg B is subjected to a tensile force P. Assuming uniform stress distribution, the shear stress in the weld is given by

Detailed Solution for Test: Design of Joints Level - 2 - Question 1

Where

Le = Effective length

Le = 2L(Double fillet weld)

.

Test: Design of Joints Level - 2 - Question 2

A circular solid rod of diameter d welded to a rigid flat plate by a circular fillet weld of throat thickness t is subjected to a twisting moment T. The maximum shear stress induced in the weld is

Detailed Solution for Test: Design of Joints Level - 2 - Question 2

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Test: Design of Joints Level - 2 - Question 3

Pre loading of bolts in structural joints and pressure vessels subjected to fluctuating loads?

Detailed Solution for Test: Design of Joints Level - 2 - Question 3

Pre-loading of bolts will help in following

-Increasing the stiffness of the bolt

-Securely tightening the mating parts

-If above two things will be there, so it will also avoid leakage.

-So based upon the options, the most correct option is B.

Test: Design of Joints Level - 2 - Question 4

In transverse fillet weld, the size of the weld is equal to

Detailed Solution for Test: Design of Joints Level - 2 - Question 4

0.707S = t

S = 1.414 t

S = t

Where S = weld size

t = throat thicknes

Test: Design of Joints Level - 2 - Question 5

The permissible stress in a fillet weld is 100 N/mm2 . The fillet weld has equal leg lengths of 15 mm each. The allowable shearing load on weldment per cm length of the weld is

Detailed Solution for Test: Design of Joints Level - 2 - Question 5

Strength of weld P = 0.707 hlτper

= 10.6 kN/cm

Test: Design of Joints Level - 2 - Question 6

Tearing efficiency of a double riveted lap joint having a pitch of 60 mm and rivet hole diameter of 18 mm is

Detailed Solution for Test: Design of Joints Level - 2 - Question 6

Test: Design of Joints Level - 2 - Question 7

Two metal plates of thickness ‘t’ and width ‘w’ are joined by a fillet weld of as shown in given figure.

When subjected to a pulling force ‘F’, the stress induced in the weld will be

Detailed Solution for Test: Design of Joints Level - 2 - Question 7

Strength of a fillet weld is given by

Here width w = le

Sin 45o = 0.707

Test: Design of Joints Level - 2 - Question 8

In the welded joint shown in the given figure, if the weld at B has thicker fillets than that at A, then the load carrying capacity P, of the joint will

Detailed Solution for Test: Design of Joints Level - 2 - Question 8

The load carrying capacity means the maximum load which a member can sustain without a failure. So because of load P the weaker section will fail first. So thicker fillet at B will have no effect on the load carrying capacity

Test: Design of Joints Level - 2 - Question 9

A circular rod of diameter d is welded to a flat plate along its circumference by fillet weld of thickness t. Assuming as the allowable shear stress for the weld material, what is the value of the safe torque that can be transmitted?Options~

(A)

(B)

(C)

(D)


Detailed Solution for Test: Design of Joints Level - 2 - Question 9

Shear stress = τw

Shear force = τw x πdt

Test: Design of Joints Level - 2 - Question 10

A single parallel fillet weld of total length L and weld size h subjected to a tensile load P, will have what design stress?

Detailed Solution for Test: Design of Joints Level - 2 - Question 10

Test: Design of Joints Level - 2 - Question 11

How can shock absorbing capacity of a bolt be increased?

Detailed Solution for Test: Design of Joints Level - 2 - Question 11

Making shank diameter equal to the core diameter of thread will increase the strain energy stored in the bolt which will increase the shock absorbing capacity of a bolt.

Test: Design of Joints Level - 2 - Question 12

By reducing the shank diameter equal to the root diameter the impact strength of bolts

Detailed Solution for Test: Design of Joints Level - 2 - Question 12

Reducing shank diameter equal to the root diameter will increase the strain energy of the bolt. And increase in strain energy will improve the impact strength of the bolts.

*Answer can only contain numeric values
Test: Design of Joints Level - 2 - Question 13

Shown in the figure is a bracket attached to a channel by means of 5 identical rivets. The maximum load on most heavily stressed rivet is __________ kN


Detailed Solution for Test: Design of Joints Level - 2 - Question 13

Primary shear force on each rivet

Secondary shear force

Centre of gravity of all rivet lie at 3.

r3 = 0

r2 = r4 = 200

P1” = P5” = Cr1 = 0.278 x 223.6 = 62.11 kN

P2” = P4” = Cr2 = 0.278 x 200 = 55.56 kN

Maximum load on rivet 2 = P2’ + P2

= 20 + 55.56 = 75.56 kN

Maximum load on rivet 1

Here,

*Answer can only contain numeric values
Test: Design of Joints Level - 2 - Question 14

What is the diameter of the hole that must be drilled in a M50 (core diameter mm) bolt such the bolt becomes of uniform strengths is __________ mm?


Detailed Solution for Test: Design of Joints Level - 2 - Question 14

=

=

= 2 = 23.74

The roots can be guessed without the help of calculator:

*Answer can only contain numeric values
Test: Design of Joints Level - 2 - Question 15

A shaft of diameter D is welded to a plate as shown in figure. A torque T is applied at the free end. If the maximum shear stress produced is given by . Where h is the leg length of weld, then the value of n is __________


Detailed Solution for Test: Design of Joints Level - 2 - Question 15

J = lxx + Iyy

Therefore,n = 2

*Answer can only contain numeric values
Test: Design of Joints Level - 2 - Question 16

A component is attached to a horizontal column by means of three identical rivets as shown in figure. The maximum permissible shear stress for the rivets is N mm . The magnitude of maximum force is __________ kN.


Detailed Solution for Test: Design of Joints Level - 2 - Question 16

Primary direct force,

= 6666.67 N

Secondary shear force,

For maximum load,

P1” = P3” = c.r

= 125 x 80 = 10000N

Resultant shear force,

P = P1’ + P1” = 6666.67 + 10000

= 16666.67 N

= 16.7 kN

Test: Design of Joints Level - 2 - Question 17

A plate is attached using 4 rivets as shown in the figure

If the maximum allowable shear stress is 80 MPa, then what will be the minimum diameter of rivets required (in mm)?

Detailed Solution for Test: Design of Joints Level - 2 - Question 17

Direct shear force,

Due to moment, secondary shear force

F1r1 + F2r2 + F3r3 + F4r4 = P x e

F1 = 7.5 kN

Maximum shear force = F1 + FD\

= 7.5 + 12.5

= 20 kN

d = 17.84

d mm

Test: Design of Joints Level - 2 - Question 18

The circumferential joint of a boiler of diameter 1 m is made of lap joint with rivet diameter of 20 mm. If the allowable shear stress for the material of the rivet is 50 MPa and the boiler has to withstand an internal pressure of 2.5 MPa, then the minimum number of rivets required to prevent the failure of the joint is

Detailed Solution for Test: Design of Joints Level - 2 - Question 18

Test: Design of Joints Level - 2 - Question 19

A shaft of 100 mm diameter is welded to a flat plate by a fillet weld of weld size 16 mm as shown in figure. If the allowable shear stress for the weld material is 50 MPa, the maximum torque the shaft can withstand to avoid weld failure is

Detailed Solution for Test: Design of Joints Level - 2 - Question 19

= 2.8268π kNm

Test: Design of Joints Level - 2 - Question 20

Two plates are joined together by means of single transverse and double parallel fillet welds as shown in the figure given below. If the size of fillet is 5 mm and allowable shear load per mm is 300 N, what is the approximate length of each parallel fillet?

Detailed Solution for Test: Design of Joints Level - 2 - Question 20

300 x (100 + 2I) = 15000 or I = 200

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