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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  Fluid Mechanics for Mechanical Engineering  >  Test: Properties of Fluids - 2 - Mechanical Engineering MCQ

Test: Properties of Fluids - 2 - Mechanical Engineering MCQ


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15 Questions MCQ Test Fluid Mechanics for Mechanical Engineering - Test: Properties of Fluids - 2

Test: Properties of Fluids - 2 for Mechanical Engineering 2025 is part of Fluid Mechanics for Mechanical Engineering preparation. The Test: Properties of Fluids - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Properties of Fluids - 2 MCQs are made for Mechanical Engineering 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Properties of Fluids - 2 below.
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Test: Properties of Fluids - 2 - Question 1
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In a simple concentric shaft-bearing arrangement, the lubricant flows in the 2 mm gap between the shaft and the bearing. The flow may be assumed to be a plane couette flow with zero pressure gradients. The diameter of the shaft is 100 mm and its tangential speed is 10 m/s. The dynamic viscosity of the lubricant is 0.1 kg/m ∙ s. The frictional resisting force (in Newton) per 100 mm length of the bearing is _____(Give answer about 1 decimal place)


Detailed Solution for Test: Properties of Fluids - 2 - Question 1

D2 = 100 mm

V = 10 m/s

μ = 0.1 kg/m ∙ s

L = 100 mm (assume)

Frictional force = shear stress × surface area

Test: Properties of Fluids - 2 - Question 2
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Newton’s law of viscosity for a fluid states that the shear stress is

Detailed Solution for Test: Properties of Fluids - 2 - Question 2

According to Newton's law of viscosity, shear stress is directly proportional to the rate of angular deformation (shear strain) or velocity gradient across the flow.

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Test: Properties of Fluids - 2 - Question 3
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A flat plate of width L = 1 m is pushed down with a velocity U = 0.01 m/s towards a wall resulting in the drainage of the fluid between the plate and the wall as shown in the figure. Assume two-dimensional incompressible flow and that the plate remains parallel to the wall. The average velocity, Uavg of the fluid (in m/s) draining out at the instant shown in the figure is _______ (correct to three decimal places).


Detailed Solution for Test: Properties of Fluids - 2 - Question 3

Given Data:

  • Width of the plate L = 1 m

  • Velocity of the plate U = 0.01 m/s

  • Distance between the plate and the wall d = 0.1 m

Assumptions:

  • The flow is incompressible and two-dimensional.

  • The velocity profile between the plate and the wall is linear.

Step-by-Step Breakdown:

  1. Mass Displaced:

    • We assume the plate's length is Z, and the mass rate displaced between the plate and wall is calculated by:

    LZ × dh = 2 × uavg × d × Z × dt

    Where:

    • uavg is the average velocity.

    • dh is the differential change in height.

    • dt is the differential change in time.

  2. Rearranging the Equation:

    LZ × dh = 2 × uavg × d × Z × dt

    Simplifying, we get:

    LZ × dh = 2 × uavg × d × Z × dt

  3. Finding Average Velocity: From the given relationship:

    uavg = (L × U) / (2 × d)

    Substituting the values:

    uavg = (1 × 0.01) / (2 × 0.1) = 0.05 m/s

Conclusion:

The average velocity of the fluid draining out is 0.05 m/s, 

Test: Properties of Fluids - 2 - Question 4
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A real fluid is any fluid which
Detailed Solution for Test: Properties of Fluids - 2 - Question 4

The correct option is 4. A real fluid is a fluid that has viscosity, which means it resists shear or tensile stress and exhibits a continuous deformation when subjected to an external force. Real fluids may have variable viscosity and density, and they can also be compressible. Surface tension is a property of liquids and is not present in all fluids. Therefore, option 1 is incorrect. Zero shear stress is not a characteristic of real fluids, making option 2 incorrect. While real fluids may have constant viscosity and density under certain conditions, it is not a necessary characteristic, making option 3 incorrect.

Test: Properties of Fluids - 2 - Question 5
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When subjected to shear force, a fluid
Detailed Solution for Test: Properties of Fluids - 2 - Question 5

A fluid is a substance that deformed continuously when shear stress is applied to it irrespective of the magnitude of the shear stress. Because of the continuous deformation flow of the liquid can be seen. In other words, we can also tell that liquid can not sustain any shear load.

Test: Properties of Fluids - 2 - Question 6
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An Ideal Fluid
Detailed Solution for Test: Properties of Fluids - 2 - Question 6

Ideal Fluid: A fluid, which is incompressible and is having no viscosity is known as ideai fluid. Ideal fluid is only an imaginary fluid as all the fluids, which exists have some viscosity.

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Test: Properties of Fluids - 2 - Question 7
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A solid block of 2.0 kg mass slides steadily at a velocity V along a vertical wall as shown in the figure below. A thin oil film of thickness h = 0.15 mm provides lubrication between the block and the wall. The surface area of the face of the block in contact with the oil film is 0.04 m2. The velocity distribution within the oil film gap is linear as shown in the figure. Take dynamic viscosity of oil as 7*10–3 Pa-s and acceleration due to gravity as 10 ms2. Neglect weight of the oil. The terminal velocity V(in m s) of the block is ______ (correct to one decimal place).

Detailed Solution for Test: Properties of Fluids - 2 - Question 7

Mass m = 2 kg

Acceleration g = 10 m/s2

Height h = 15 mm

Terminal velocity V = ?
We know that terminal velocity is constant velocity, therefore net acceleration is zero.
Shear force due to oil film = weight of block

Hence, the correct answer is 10.714.
but upto 1 decimal place 10.7

Test: Properties of Fluids - 2 - Question 8
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Which one of the following is defined as force per unit length?
Detailed Solution for Test: Properties of Fluids - 2 - Question 8
  • Surface tension, in simple words, is defined as the force exerted on the fluid particles on a surface per unit length in the plane of the liquid surface perpendicular to either side of an imaginary line drawn to the surface.
  • Mathematically, surface tension is expressed as the ratio of force to length. It is the or type of behavior of the liquid surface to contract into a minimum surface area. The standard unit of surface tension is N m-1. 
Test: Properties of Fluids - 2 - Question 9
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Newton’s law of viscosity depends upon the
Detailed Solution for Test: Properties of Fluids - 2 - Question 9

Newton's law of viscosity:

  • Viscosity is a property of fluid by virtue of which they offer resistance to shear or angular deformation.
  • It is primarily due to cohesion and molecular momentum exchange between fluid layers, and as flow occurs, these effects appears as shearing stresses between the moving layers.
  • According to Newton's law of viscosity, shear stress is directly proportional to the rate of angular deformation (shear strain rate) or velocity gradient across the flow.

where, τ = shear stress

μ = absolute or dynamic viscosity

⇒  du/dy = velocity gradient 

⇒ dα/dt = rate of angular deformation (shear strain)

Test: Properties of Fluids - 2 - Question 10
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In incompressible fluid (kinematic viscosity = 7.4 × 10−7 m2/s, specific gravity, 0.88) is held between two parallel plates. If the top plate is moved with a velocity of 0.5 m/s while the bottom one is held stationary, the fluid attains a linear velocity profile in the gap of 0.5 mm between these plates; the shear stress in Pascal on the surface of bottom plate is
Detailed Solution for Test: Properties of Fluids - 2 - Question 10

γ = 7.4 × 10−7 m2/s

SG = 0.88
ρ = (SG) × ρwater = 0.88 × 1000

= 880 kg/m3

du = u2 – u = 0.5 m/s

μ = γρ

= 0.651 Pa

Hence, the correct option is (b).

Test: Properties of Fluids - 2 - Question 11
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The fluid which obey’s the Newton’s law of viscosity 
Detailed Solution for Test: Properties of Fluids - 2 - Question 11

The fluid which obeys the Newton’s law of viscosity is known as Newtonion fluid e.g.: Air, water, Kerosene.

Test: Properties of Fluids - 2 - Question 12
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The General relationship between shear stress (τ) and velocity Gradient  for a fluid can be written as

Then the fluid known as
Detailed Solution for Test: Properties of Fluids - 2 - Question 12

In the expression: 

If n < 1, B = 0
then it is known as pseudo plastic

Test: Properties of Fluids - 2 - Question 13
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Surface tension is due to
Detailed Solution for Test: Properties of Fluids - 2 - Question 13

Surface tension a line force caused by cohesion of fluid particle at the surface, the property of cohesion enables a liquid to resist tensile stress.

Test: Properties of Fluids - 2 - Question 14
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Which one of the following is correct dimension of surface tension?
Detailed Solution for Test: Properties of Fluids - 2 - Question 14

Test: Properties of Fluids - 2 - Question 15
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Kinematic viscosity of air at 20°C is given to be 1.6 × 10−5 m2/s. Its kinematic viscosity at 70°C will be varying approximately 
Detailed Solution for Test: Properties of Fluids - 2 - Question 15

The kinematic viscosity of air generally increases with temperature. To estimate the change in kinematic viscosity with temperature, we can use the following empirical relation:

nu₂ = nu₁ × (T₂ / T₁)ⁿ

Where:

  • nu₁ = kinematic viscosity at temperature T₁

  • nu₂ = kinematic viscosity at temperature T₂

  • T₁ and T₂ are the temperatures in Kelvin

  • n is an empirical constant, which for air is approximately 1.5

Given:

  • nu₁ = 1.6 × 10⁻⁵ m²/s

  • T₁ = 20°C = 293.15 K

  • T₂ = 70°C = 343.15 K

  • n = 1.5

Now, we can calculate nu₂:

nu₂ = (1.6 × 10⁻⁵) × (343.15 / 293.15)¹⁵

The kinematic viscosity of air at 70°C is approximately 2.03 × 10⁻⁵ m²/s.

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