Test: Frictional Forces On Screws - Civil Engineering (CE) MCQ

The screws are generally used as the fasteners. The main thing about the screws is that the friction helps the holding of the structures. Also screws help make the structure join fast and efficiently. Thus the name fasteners.

The square threaded screws are used in the machines. As the screws are generally used as the fasteners. The main thing about the screws is that the friction helps the holding of the structures. Also screws help make the structure join fast and efficiently

The square threaded screws are used in the machines. As these screws are generally used as the fasteners. The main thing about these screws is that the friction helps the holding of the structures. Also screws help make the structure join fast and efficiently. And in these screws forces act along the axis of screws.

The angle of the threading in the screw is determined by inverse tangent trigonometric function. This is the generalised form of the function which is being used so as to get the value of the angle. In wedges the same function is used so as to find the angle of wedge.

The angle of the threading in the screw is determined by inverse tangent trigonometric function. This is the generalised form of the function which is being used so as to get the value of the angle. In wedges the same function is used so as to find the angle of wedge. And in both the case the ratio is the vertical is to horizontal.

The angle of the threading in the screw is determined by inverse tangent trigonometric function. This is the generalised form of the function which is being used so as to get the value of the angle. In wedges the same function is used so as to find the angle of wedge. And thus the horizontal distance is called as lead.

The definition of the two force member only defines that the forces are being acted on the two points on the body. So does is the definition of the three forces members. The points of action of the three forces are three.

As we know that the moment is the cross product of the distance and the force we will try to apply the same here. We see that the perpendicular distance is 1.5 (3cos60). Thus we get the distance. And hence multiply it with the force, 75×1.5. Because the force component perpendicular to the distance need to be taken.

Simply, for the equilibrium the net force must be zero. That is the forces must be collinear if equilibrium is to be established. And they must be in the opposite directions. They also must be of same magnitude, cancelling each other.

The forces in the three force system are not always in the equilibrium. The equilibrium is established when the forces cancels out each other. Also when the net moment is zero. Then only the equilibrium is established in the three force system.

The couple moment depends only on the distance vector between the forces. The radius vector of the forces are not making the couple depended over it. But the distance vector is driven by subtracting the radius vectors of the forces. This means that, moment of the couple doesn’t directly depend on the radius vector of forces.

The forces are always in the opposite direction for the couple moment. But if they don’t act like the same that is they change their directions and align themselves in the same direction then the couple is not possible.

The equilibrium is only attained if the net force on the body tends to be equal to zero. Thus the forces cancel out. If this happens there is no motion of the body along any direction and hence the body is said to be in equilibrium. The body here is a rigid body.

The force system having all the forces emerging from a point is called the collinear system of force. This is a type of system of the force, which is easy in the simplification. This is because as the forces are the vector quantity, the vector math is applied and the simplification is done.

As we know that the moment is the cross product of the distance and the force we will try to apply the same here. We see that the perpendicular distance is 3m. Thus we get the distance. And hence multiply it with the force, the moment = 112.5Nm. Because the force component perpendicular to the distance need to be taken.