Courses

## 14 Questions MCQ Test Engineering Mechanics - Notes, Videos, MCQs & PPTs | Test: Reduction Of A Simple Distributed Loading

Description
QUESTION: 1

### The uniformly distributed load is having two different values of load per unit length on the ends of the distribution.

Solution:

The answer is no. The uniform distributed load is not having two different values of the load per unit meter on the corner. Rather the distribution is uniform. That is it is having the same value of the same on both of the corners.

QUESTION: 2

### There are two types of loading. The uniformly distributed and the non-uniformly distributed that is the one having two different values at corners.

Solution:

The two forms of the loading are the uniformly distributed and the non-uniformly distributed that is the one having two different values at corners. The uniform distributed load is not having two different values of the load per unit meter on the corner.

QUESTION: 3

### The type of reduction of the loading is different for the uniformly distributed and the non-uniformly.

Solution:

The methods for the reduction of the loadings is different for both uniformly distributed and the non-uniformly. In the latter the simplification uses the quadratic equation. The latter also uses the integration for the same purpose.

QUESTION: 4

Determine the magnitude of the resultant force acting on the shaft shown from left. Solution:

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

QUESTION: 5

Solution:

QUESTION: 6

Solution:

QUESTION: 7

Determine the magnitude of the resultant force acting on the shaft shown. The length is 2m. Solution:

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

QUESTION: 8

Solution:

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

QUESTION: 9

If any external force also is applied on the distributed loading then?

Solution:

The external forces are treated differently. They are not added by the force of the distributed loading. That is the force not only acts at the centroid always. It can be shifted also. Depending on the external forces.

QUESTION: 10

The resultant force acting, of the uniformly distributed loading is dependent on:

Solution:

The resultant force acting, of the uniformly distributed loading is dependent on the area that the distribution is covering. The more the area the more is the force. That is the more is the tension created over the structure on which loading is kept. Hence the answer.

QUESTION: 11

Solution:

The non-uniformly distributed loading is using the integration for getting the net force given by it. And the former only need the area or the linear distance of the loading. That is when the distance is multiplied by the uniformly distributed load the net force is obtained. But that is not so with the non-uniform one.

QUESTION: 12

Determine the location of the resultant force acting on the shaft shown from left. The length is 2m. Solution:

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

QUESTION: 13

Determine the location of the resultant force acting on the shaft shown from left. Solution:

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

QUESTION: 14

Determine the magnitude of the resultant force acting on the shaft shown from left. Solution:

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.