Joint Admission Test for MSc (IIT JAM)
Subject wise Courses for Chemistry
Subject wise Courses for Physics
Subject wise Courses for Mathematics
Exam Name Indian Institute of technology Joint Admission Test for MSc | Mode Online | Exam Level All India level |
Exam Duration 3 hours | Exam Frequency Once in a Year | Conducted By IIT Kanpur |
Accepting Colleges 43 Colleges | Official Website |
Recommended Practice Quiz for IIT JAM
Recommended Documents for IIT JAM
- Nucleophile
- Lecture 2 - Principle of Mathematical Induction and Well Ordering Principle
- Realistic Representation Of Stereo Structures Of Molecules - Stereochemistry
- Nomenclature - Stereochemistry
- Bohr Model of the Hydrogen Atom - Atomic Structure
- Introduction to Atomic Structure - Atomic Structure
- Structural-isomerism and types - Coordination Chemistry, Inorganic Chemistry
- Preparation Books for IIT JAM Chemistry
- MCQ: States of Matter
- Drug Target Interaction
- FAQs regarding NEET 2017 Online Test Series
- General Organic Chemistry
- Concentration cells /Nernst equation / Electrochemistry/ class 12 chemistry
- Mole Concept and Stoichiometry - MCQ (Solved), M. Sc.
- The D-block elements - IIT JAM
What is IIT JAM
Joint Admission Test for MSc (JAM) is an all India level online entrance exam conducted by Indian Institute of Technology (IITs) every year on a rotational basis on behalf of ministry of human Resources development (MHRD), government of India. Candidates are informed that the biometric system of identification verification (finger - print) will be used for the JAM 2020exam as well as admission.
Till last year, the IIT JAM exam was conducted for seven subjects of science in order to provide admission to candidates in MSc and other post - bachelors courses offered at IITs and integrated Ph.D. courses offered at indian Institute of Science (IISc), Bangalore. Several National Institute of Technology (NITs) and centrally funded technical Institute (CFTIs) also accept JAM Score for MSc admission.
IIT JAM 2020 Exam dates and other events
Syllabus for Chemistry
Physical Chemistry- Basic Mathematical concepts, atomic and Molecular Structure, Theory of gases, Solid State, Chemical Thermodynamics, Chemical and phase equilibria, Electrochemistry, Chemical Kinetics, Adsorptions, Spectroscopy.
Organic Chemistry - Basic Concepts in Organic Chemistry and Stereochemistry, Organic Reaction Mechanism and synthetic Application, Qualitative Organic Analysis, Natural Product Chemistry, Aromatic and Heterocyclic Chemistry.
Inorganic Chemistry- Periodic table, Chemical Bonding and Shape of compounds, main groupsElements (s and p blocks), Transition Metals(d block), Bioinorganic Chemistry, Instrumental Method of Analysis, Analytical Chemistry.
Syllabus for Physics - Mathematical Methods, Mechanics and General Properties of Matter, Oscillations, Waves and Optic, Electricity and Magnetism, Kinetic theory, Thermodynamics, Modern Physics, Solid State Physics, Devices and Electronics
Syllabus for Mathematics - Sequences and Series of Real Numbers, Functions of One Real Variable, Functions of Two or Three Real Variables, Integral Calculus, Differential Equations, Vector Calculus, Group Theory, Linear Algebra, Real Analysis.
Syllabus for Geology -The Planet Earth, Geomorphology, Structural Geology, Paleontology, Stratography, Mineralogy, Petrology, Economic Geology, Applied Geology
Syllabus for Mathematics Statistics
Mathematics- Sequences and Series, Differential Calculus, Integral Calculus, Matrices.
Statistics- Probability, Random Variables, Standard Distributions, Joint Distributions, Sampling distributions, Limit Theorems, Estimation, Testing of Hypotheses
Syllabus for biotechnology
Biology (10 2 3 level) - General Biology, Biochemistry and Physiology, Basic Biotechnology, Molecular Biology, Cell Biology, Microbiology.
Chemistry(10 2 3 level)
Mathematics (10 2 level)
Physics (10 2 level)
In order to fulfill IIT JAM 2020 eligibility criteria, candidates should hold a bachelor’s degree with at laest 55% aggregate marks (50% for SC/ ST/ PwD category candidates). It may be noted that the aggregate marks should be without rounding off and take into account all the subjects, including languages and submission, all years combined, informs the official website.
Candidates who have appeared or will appear for their graduation exams in 2020 are also eligible to apply.
Age limit: There is no age limit to appear for the IIT JAM 2020 Exam.
IIT JAM 2020 Eligibility Criteria: Minimum Educational Qualification
IIT JAM Mock test 2020 is essential for everyone. They complete your preparation and ensure that you clear the examination with a good score. Candidates can also download the IIT JAM mock test which is now available and practise at home offline.These mock tests of IIT JAM 2020 have been designed to be solved in under 2 hours, thus Using the released IIT JAM mock test, the candidates will be able to prepare well for the upcoming examination. Since the mock test will have the same structure as the IIT JAM 2020 examination, the candidates will be familiar with the pattern and analyze their preparation. Time management can also be practiced using the IIT JAM 2020 mock test.
The IIT JAM 2020Exam pattern is such that candidates need to complete their respective test paper in three hours. In the exam, candidates need to attempt 60 questions which are of 100 Marks weightage. These 60 questions are divided into three sections- A,B and C. All these sections are compulsory and candidats need to attempt questions from all the sections. The medium of instruction for JAM test paper is English.the detailed IIT JAM exam pattern 2020 is mentioned in the table below:
Negative marking is only in section A. For each one marks questions, 1/3 marks will be deducted. On the other hand, for each wrong answer to two marks questions, 2/3 marks will be deducted. There is no negative marking for any question left unanswered.
No negative marking is there in section B and C.
JEE Mains is an entrance exam for students willing to pursue MSc courses offered by the IITs. Solving previous year questions papers are key to cracking the IIT JAM exam. Thus, here we are providing you the IIT JAM previous years question paper with solutions. From here you can download IIT JAM question papers pdf to practise and understand the paper pattern.
Here are some solved past year question papers.
Candidates need to apply online for the IIT JAM 2020 registrations. Candidates need to visit the JAM Online Application Processing System (JOAPS) link which is present on the official website of the Exam and fill the IIT JAM 2020 application form there. The IIT JAM 2020 application fee also needs to be paid online only via net banking/ debit card/ credit card. Please note that candidates can apply for a maximum of two test papers at a time. But for appearing for the second test paper, candidates need to pay an additional application fee.
Note :
If you are applying for two Test papers, then make sure that both the exams are conducted in different sessions.
After the payment is done, a fee payment number will be generated, which must be saved by the candidate for later use.
Official II JAM website states that “An application once submitted cannot be changed or rectified.”
Candidates can follow the following steps to download their Admit cards for IIT JAM 2020 Exam.
Step 1: open IIT JAM 2020 official website(http://jam.iitk.ac.in/)
Step 2: Click on ‘JOAPS Admit Card’ link
Step 3: Enter enrollment/ Email ID and password
Step 4: Solve the given arithmetic expression
Step 5: Click on ‘Submit’ button
Step 6: check the declaration box
Step 7: Click on ‘Download Admit Card’ button
Step 8: View and take print out of IIT JAM 2020 Admit Card
After downloading the JAM 2020 admit card, candidates need to take a print out of it and carry it to the allotted exam centre along with a valid ID proof (original). Those candidates who will not be carrying their admit card and ID proof might not be allowed to appear for the JAM 2020 Exam.
IIT JAM 2020 result will be declared on the official website of the exam.
Candidates are given an All India Rank (AIR) on each test paper in IIT JAM 2020. On the basis of AIR, an All India Merit List is prepared. Candidates whose names and roll numbers appear in the merit list are then eligible for admission in MSc courses offered at IITs and integrated Ph.D. programmes offered at IISc.
Q. What is IIT JAM?
A. IIT JAM is a national level exam that is conducted to shortlist students for admission in MSc and integrated MSc courses offered at colleges accepting IIT JAM scores for admission. IIT JAM is jointly conducted by the IITs and Indian Institute of Science (IISC). IIT JAM is conducted on a rotational basis by the colleges participating in exams. The IIT JAM 2020 is being conducted by IIT Kanpur.
Q. What is the eligibility for IIT JAM 2020?
A. Candidates are eligible to appear for IIT JAM exam 2020 if they have a bachelor’s degree with minimum 55% aggregate marks if they belong to the General category. For Students from SC/ ST/ PwD category the minimum marks to meet IIT JAM eligibility criteria is 50%. Candidates who have appeared or will be appearing for their graduation exams in 2020 are also eligible to apply.
Age Limit Criteria: There is no age limit to appear for IIT JAM 2020 exam.
Q. How many times can I appear for IIT JAM?
A. There is no restriction on the number of times an aspirant can take the IIT JAM exam. Candidates can give the JAM exam only if they fulfill the eligibility criteria of the science entrance test.
Q. Is IIT JAM difficult?
A. Experts share that the IIT JAM exam is difficult to clear. This is not because the difficulty level of the questions asked is very high because the selection ratio through IIT JAM exam is low. However, this does not mean that the questions asked in the exam will be easy.
Q. How to predict your IIT JAM 2020 score?
A.You are able to predict your score based on the number of correct and incorrect answers. For this you need to match your answers from the answer key. Add marks for every correct answer and deduct for an incorrect answer. Ensure that you follow the same marking scheme as given.
Q. What is the benefit/advantage of IIT JAM?
A. IIT JAM is a national level science entrance exam that is conducted on a rotational basis by the participating IITs and IISc. IIT JAM is the means through which candidates can secure admission in MSc and other post-bachelor courses offered at IITs and integrated PhD courses offered at IISc Bangalore.
All Courses for IIT JAM on EduRev
Recommended Question & Answers for IIT JAM
- The number of IR bands will be obtain in M(CO)5
- a)1
- b)2
- c)3
- d)5
Correct answer is option 'B'. Can you explain this answer? - Na crystallizes in fcc lattice having edge length 500 pm. Mass of the Na particle is 4.151 × 10– 23g. the density of the lattice is:
- a)1.33 g/cm3
- b)1.5 g cm3
- c)1.75 g/cm3
- d)2.00 g cm3
Correct answer is option 'A'. Can you explain this answer? - The electrochemical cell shown below is a concentration cell.
M|M2+ (saturated solut ion of a sparingly so luble salt, MX2 || M2+ (0.001 mol dm–3)| M.
The emf of the cell depends on the difference in concentration of M2+ ions at the two electrodes. The emf of the cell at 298 is 0.059 V.Q.The solubility product (Ksp ; mol3 dm–9) of MX2 at 298 based on the informat ion available the given concentration cell is (take 2.303 × R × 298/F = 0.059 V)- a)1 × 10–15
- b)4 × 10–15
- c)1 × 10–12
- d)4 × 10–12
Correct answer is option 'B'. Can you explain this answer? - H2 and Br2 react to give HBr by the following steps:
The probable rate law for the above sequence is- a)
- b)Rate = k2 [H2][Br2]
- c)
- d)
Correct answer is option 'A'. Can you explain this answer? - T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L–1. Rate after 20 minute is:
- a)0.0693 mol L–1 min–1
- b)0.0693 x 2.5 mol L–1 min–1
- c)0.0693 x 5 mol L–1 min–1
- d)0.0693 x 10 mol L–1 min–1
Correct answer is option 'B'. Can you explain this answer? - For a reaction involving two steps given below:
Assume that the first step attains equilibrium rapidly. The rate of formation of P is proportional to- a)[G]1/2
- b)[G]
- c)[G]2
- d)[G]3/2
Correct answer is option 'D'. Can you explain this answer? - Which of the following is correct:
- a)θ1 = θ2
- b)θ1 > θ2
- c)θ1 < θ2
- d)None
Correct answer is option 'B'. Can you explain this answer? - Which one of the following plane will show allowed reflection for any FCC:
- a)(100)
- b)(110)
- c)(111)
- d)None of these
Correct answer is option 'C'. Can you explain this answer? - An element exists in two crystallographic modifications with FCC and BCC structures. The ratio of the densities of the FCC and BCC modifications in terms of the volumes of their unit cells (VFCC and VBCC) is:
- a)VBCC: VFCC
- b)2VBCC: VFCC
- c)VBCC: 2VFCC
- d)
Correct answer is option 'B'. Can you explain this answer? - Which of the following carbocations is the most stable?
- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer? - What is glycine?
- If the Aufbau principle had not been followed, Ca (Z = 20) would have been placed in the:a) s-blockb) p-blockc) d-blockd) f-blockThe correct answer is option 'C'. Can you explain this answer?
- If the rate of a reaction are R1 and R2 at concentrations C1 and C2 of a reactant respectively. The order of reaction, ‘n’ (assuming that the concentrations of all other reactants and T remain constant) with respect to that reactant is given by:
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer? - The Langmuir adsorption isotherm is deduced using the assumption:
- a)The heat of adsorption varies with coverage
- b)The adsorbed molecules interact with each other
- c)The adsorption takes place in multi layer
- d)The adsorption sites are equivalent in their ability to adsorb the particles.
Correct answer is option 'D'. Can you explain this answer? - The final product in the reaction[Mn (CO)6]- + MeLi → is :
- a)[Mn(CO)6]–Me
- b)[Mn(CO)5Me]
- c)[Mn(CO)6]
- d)[(MeCO)Mn(CO)5]
Correct answer is option 'B'. Can you explain this answer?
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