Overview of IIT JAM 2020

Exam Name Indian Institute of technology Joint Admission Test for MSc | Mode Online | Exam Level All India level |

Exam Duration 3 hours | Exam Frequency Once in a Year | Conducted By IIT Kanpur |

Accepting Colleges 43 Colleges | Official Website |

- Test: Periodic Properties- 1
- Test: Chemical Bonding- 1
- Test: General Organic Chemistry- 1
- Test: Solid State- 1
- Chemistry - 2019 Past Year Paper
- Test: Gaseous State - 4
- Test: Conductance- 1
- Test: Gaseous State- 1
- Work, Power And Energy MCQ Level - 1
- Test: Colligative Properties- 1
- Test: Chemical Equilibrium- 1

- Introduction to Reaction Mechanism -Reaction Mechanism Chemistry
- Introduction to Organometallic & 18 Electron Rule - Organometallic Chemistry
- Organometallic Chemistry Introduction - Organometallic Chemistry
- Ideal Gas Laws - Gaseous
- Introduction to Electrochemistry - Electrochemistry
- Faraday's First Law of Electrolysis - Electrochemistry
- Colligative Properties (Part-1)
- Series Reaction - Chemical Kinetics
- Integrated Rate Law Expression Of Zero Order - Chemical Kinetics
- Introduction to Chemical Kinetics - Chemical Kinetics
- Integrated Rate Law Expression Of Zero Order - Chemical Kinetics
- Bond Order from Lewis Dot Structure - Chemical Bonding
- Revision Notes - Some Basic Concepts in Chemistry
- Octet Rule - Chemical Bonding
- Hyperconjugation

IIT JAM 2020: Important Dates [Official], Application, Eligibility, Syllabus, Exam Pattern & Result

What is IIT JAM

Joint Admission Test for MSc (JAM) is an all India level online entrance exam conducted by Indian Institute of Technology (IITs) every year on a rotational basis on behalf of ministry of human Resources development (MHRD), government of India. Candidates are informed that the biometric system of identification verification (finger - print) will be used for the JAM 2020exam as well as admission.

Till last year, the IIT JAM exam was conducted for seven subjects of science in order to provide admission to candidates in MSc and other post - bachelors courses offered at IITs and integrated Ph.D. courses offered at indian Institute of Science (IISc), Bangalore. Several National Institute of Technology (NITs) and centrally funded technical Institute (CFTIs) also accept JAM Score for MSc admission.

IIT JAM 2020 Exam dates and other events

IIT JAM 2020 Syllabus

Syllabus for Chemistry

Physical Chemistry- Basic Mathematical concepts, atomic and Molecular Structure, Theory of gases, Solid State, Chemical Thermodynamics, Chemical and phase equilibria, Electrochemistry, Chemical Kinetics, Adsorptions, Spectroscopy.

Organic Chemistry - Basic Concepts in Organic Chemistry and Stereochemistry, Organic Reaction Mechanism and synthetic Application, Qualitative Organic Analysis, Natural Product Chemistry, Aromatic and Heterocyclic Chemistry.

Inorganic Chemistry- Periodic table, Chemical Bonding and Shape of compounds, main groupsElements (s and p blocks), Transition Metals(d block), Bioinorganic Chemistry, Instrumental Method of Analysis, Analytical Chemistry.

Syllabus for Physics - Mathematical Methods, Mechanics and General Properties of Matter, Oscillations, Waves and Optic, Electricity and Magnetism, Kinetic theory, Thermodynamics, Modern Physics, Solid State Physics, Devices and Electronics

Syllabus for Mathematics - Sequences and Series of Real Numbers, Functions of One Real Variable, Functions of Two or Three Real Variables, Integral Calculus, Differential Equations, Vector Calculus, Group Theory, Linear Algebra, Real Analysis.

Syllabus for Geology -The Planet Earth, Geomorphology, Structural Geology, Paleontology, Stratography, Mineralogy, Petrology, Economic Geology, Applied Geology

Syllabus for Mathematics Statistics

Mathematics- Sequences and Series, Differential Calculus, Integral Calculus, Matrices.

Statistics- Probability, Random Variables, Standard Distributions, Joint Distributions, Sampling distributions, Limit Theorems, Estimation, Testing of Hypotheses

Syllabus for biotechnology

Biology (10 2 3 level) - General Biology, Biochemistry and Physiology, Basic Biotechnology, Molecular Biology, Cell Biology, Microbiology.

Chemistry(10 2 3 level)

Mathematics (10 2 level)

Physics (10 2 level)

IIT JAM 2020 Eligibility

In order to fulfill IIT JAM 2020 eligibility criteria, candidates should hold a bachelor’s degree with at laest 55% aggregate marks (50% for SC/ ST/ PwD category candidates). It may be noted that the aggregate marks should be without rounding off and take into account all the subjects, including languages and submission, all years combined, informs the official website.

Candidates who have appeared or will appear for their graduation exams in 2020 are also eligible to apply.

Age limit: There is no age limit to appear for the IIT JAM 2020 Exam.

IIT JAM 2020 Eligibility Criteria: Minimum Educational Qualification

IIT JAM Mock Test 2020

IIT JAM Mock test 2020 is essential for everyone. They complete your preparation and ensure that you clear the examination with a good score. Candidates can also download the IIT JAM mock test which is now available and practise at home offline.These mock tests of IIT JAM 2020 have been designed to be solved in under 2 hours, thus Using the released IIT JAM mock test, the candidates will be able to prepare well for the upcoming examination. Since the mock test will have the same structure as the IIT JAM 2020 examination, the candidates will be familiar with the pattern and analyze their preparation. Time management can also be practiced using the IIT JAM 2020 mock test.

IIT JAM Exam Pattern

The IIT JAM 2020Exam pattern is such that candidates need to complete their respective test paper in three hours. In the exam, candidates need to attempt 60 questions which are of 100 Marks weightage. These 60 questions are divided into three sections- A,B and C. All these sections are compulsory and candidats need to attempt questions from all the sections. The medium of instruction for JAM test paper is English.the detailed IIT JAM exam pattern 2020 is mentioned in the table below:

Negative marking is only in section A. For each one marks questions, 1/3 marks will be deducted. On the other hand, for each wrong answer to two marks questions, 2/3 marks will be deducted. There is no negative marking for any question left unanswered.

No negative marking is there in section B and C.

IIT JAM Question Papers

JEE Mains is an entrance exam for students willing to pursue MSc courses offered by the IITs. Solving previous year questions papers are key to cracking the IIT JAM exam. Thus, here we are providing you the IIT JAM previous years question paper with solutions. From here you can download IIT JAM question papers pdf to practise and understand the paper pattern.

Here are some solved past year question papers.

IIT JAM 2020 Application Form

Candidates need to apply online for the IIT JAM 2020 registrations. Candidates need to visit the JAM Online Application Processing System (JOAPS) link which is present on the official website of the Exam and fill the IIT JAM 2020 application form there. The IIT JAM 2020 application fee also needs to be paid online only via net banking/ debit card/ credit card. Please note that candidates can apply for a maximum of two test papers at a time. But for appearing for the second test paper, candidates need to pay an additional application fee.

Note :

If you are applying for two Test papers, then make sure that both the exams are conducted in different sessions.

After the payment is done, a fee payment number will be generated, which must be saved by the candidate for later use.

Official II JAM website states that “An application once submitted cannot be changed or rectified.”

IIT JAM Admit Card 2020

Candidates can follow the following steps to download their Admit cards for IIT JAM 2020 Exam.

Step 1: open IIT JAM 2020 official website(http://jam.iitk.ac.in/)

Step 2: Click on ‘JOAPS Admit Card’ link

Step 3: Enter enrollment/ Email ID and password

Step 4: Solve the given arithmetic expression

Step 5: Click on ‘Submit’ button

Step 6: check the declaration box

Step 7: Click on ‘Download Admit Card’ button

Step 8: View and take print out of IIT JAM 2020 Admit Card

After downloading the JAM 2020 admit card, candidates need to take a print out of it and carry it to the allotted exam centre along with a valid ID proof (original). Those candidates who will not be carrying their admit card and ID proof might not be allowed to appear for the JAM 2020 Exam.

IIT JAM Result 2020

IIT JAM 2020 result will be declared on the official website of the exam.

Candidates are given an All India Rank (AIR) on each test paper in IIT JAM 2020. On the basis of AIR, an All India Merit List is prepared. Candidates whose names and roll numbers appear in the merit list are then eligible for admission in MSc courses offered at IITs and integrated Ph.D. programmes offered at IISc.

Frequently Asked Questions for IIT JAM (FAQs)

Q. What is IIT JAM?

A. IIT JAM is a national level exam that is conducted to shortlist students for admission in MSc and integrated MSc courses offered at colleges accepting IIT JAM scores for admission. IIT JAM is jointly conducted by the IITs and Indian Institute of Science (IISC). IIT JAM is conducted on a rotational basis by the colleges participating in exams. The IIT JAM 2020 is being conducted by IIT Kanpur.

Q. What is the eligibility for IIT JAM 2020?

A. Candidates are eligible to appear for IIT JAM exam 2020 if they have a bachelor’s degree with minimum 55% aggregate marks if they belong to the General category. For Students from SC/ ST/ PwD category the minimum marks to meet IIT JAM eligibility criteria is 50%. Candidates who have appeared or will be appearing for their graduation exams in 2020 are also eligible to apply.

Age Limit Criteria: There is no age limit to appear for IIT JAM 2020 exam.

Q. How many times can I appear for IIT JAM?

A. There is no restriction on the number of times an aspirant can take the IIT JAM exam. Candidates can give the JAM exam only if they fulfill the eligibility criteria of the science entrance test.

Q. Is IIT JAM difficult?

A. Experts share that the IIT JAM exam is difficult to clear. This is not because the difficulty level of the questions asked is very high because the selection ratio through IIT JAM exam is low. However, this does not mean that the questions asked in the exam will be easy.

Q. How to predict your IIT JAM 2020 score?

A.You are able to predict your score based on the number of correct and incorrect answers. For this you need to match your answers from the answer key. Add marks for every correct answer and deduct for an incorrect answer. Ensure that you follow the same marking scheme as given.

Q. What is the benefit/advantage of IIT JAM?

A. IIT JAM is a national level science entrance exam that is conducted on a rotational basis by the participating IITs and IISc. IIT JAM is the means through which candidates can secure admission in MSc and other post-bachelor courses offered at IITs and integrated PhD courses offered at IISc Bangalore.

Mock Test Series for IIT JAM Mathematics

Mathematics for IIT JAM, CSIR NET, UGC NET

Past Year Papers of IIT JAM Mathematics

Modern Physics for IIT JAM

Inorganic Chemistry

IIT JAM Biotechnology Past Year Papers

Mock Test Series of IIT JAM Biotechnology

Topic-wise Tests & Solved Examples for IIT JAM Mathematics

Topic wise Tests for IIT JAM Physics

Additional Topics for IIT JAM Mathematics

Algebra for IIT JAM Mathematics

Physics for IIT JAM, UGC - NET, CSIR NET

Basic Physics for IIT JAM

Organic Chemistry

IIT JAM Physics Past Year Papers

Mock Test Series for IIT JAM Physics

MOCK Test Series for IIT JAM Chemistry

IIT JAM Past Year Papers and Model Test Paper (All Branches)

Calculus for IIT JAM Mathematics

IIT JAM Chemistry Past Year Papers

Physical Chemistry

- The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:
- a)15.16 JK
^{–1}mol^{–1} - b)– 15.16 JK
^{–1}mol^{–1} - c)– 5.05 JK
^{–1}mol^{–1} - d)5.05 JK
^{–1}mol^{–1}

Correct answer is option 'D'. Can you explain this answer? - Correct statement(s) is/are:
- a)Product have double bond equivalent = 1
- b)Two products will form
- c)Product have double bond equivalent
- d)Number of carbon + number of hydrogen in product = 15

Correct answer is option 'B,C'. Can you explain this answer? - Consider the following P–V diagram for an ideal gas that follows the diagonal path from A to B: The work done (in atm–L) on the gas in the process is:
- a)9.5
- b)99.75
- c)190
- d)10 ln 20

Correct answer is option 'D'. Can you explain this answer? - The number of IR bands will be obtain in M(CO)
_{5}- a)1
- b)2
- c)3
- d)5

Correct answer is option 'B'. Can you explain this answer? - A compound with molecule formula C
_{4}H_{6}O_{2}shows band at 1170 cm^{–1}in IR spectrum and peaks at 178, 68, 28 and 22 ppm in^{13}C NMR spectrum. The correct structure of the compound is:- a)
- b)
- c)
- d)

Correct answer is option 'C'. Can you explain this answer? - Let S be the set of all limit points of the set be the set of all positive

rational numbers. Then- a)
- b)
- c)
- d)

Correct answer is option 'C'. Can you explain this answer? - Hybridization state of boron and oxygen in boric acid is:
- a)sp
^{3}, sp^{2} - b)sp
^{2}, sp^{3} - c)sp
^{2}, sp^{2} - d)sp
^{3}, sp^{3}

Correct answer is option 'C'. Can you explain this answer? - Total number of delocalized lone pairs (combined) in [Adenine & Guanine]:Correct answer is '4'. Can you explain this answer?
- The number of metal-metal bonds in [W
_{2}(OPh)_{6}] is:- a)1
- b)2
- c)3
- d)4

Correct answer is option 'C'. Can you explain this answer? - Let Let V be the subspace of defined byThen the dimension of V is
- a)pn − rank(T)
- b)mn − p rank(T)
- c)p(m − rank(T))
- d)p(n − rank(T))

Correct answer is option 'D'. Can you explain this answer? - A hydrogen electrode placed in a buffer solution of CH
_{3}COONa and acetic acid in the ratio’s x : y and y : x has electrode potential values E_{1}volts and E_{2}volts respectively at 25°C. The pK_{a}values of acetic acid is (E_{1}and E_{2}are oxidation potential)- a)
- b)
- c)
- d)

Correct answer is option 'A'. Can you explain this answer? - For which one of the following values of k, the equation 2x
^{3}+ 3x^{2}− 12x − k = 0 has three distinct real roots?- a)20
- b)16
- c)26
- d)31

Correct answer is option 'B'. Can you explain this answer? - The equation of the tangent plane to the surface at the point (2, 0, 1) is
- a)2x + z = 5
- b)3x - z = 10
- c)3x + 4z = 10
- d)7x - 4z = 10

Correct answer is option 'C'. Can you explain this answer? - The value of the integral is
- a)2π
- b)1/2π
- c)π/2
- d)2/π

Correct answer is option 'B'. Can you explain this answer? - If y(x) is the solution of the initial value problem then y(ln 2) is (round off to 2 decimal places) equal to ____________Correct answer is between '1.12,1.25'. Can you explain this answer?