JEE MAIN - Joint Entrance Exam
Subject wise Courses for JEE MAIN
Exam Name JEE MAIN (Joint Entrance Exam) | Exam Mode Online | Exam Frequency Twice in a Year |
Exam Duration 3 hours | Official Website |
Recommended Practice Quiz for JEE MAIN
- Test: Single Correct MCQs: Inverse Trigonometric Functions | JEE Advanced
- Test: Introduction To Sequences
- Test: General Properties Of d-Block Elements
- Test: Refraction By Plane Surfaces
- BITSAT Logical Reasoning Test - 2
- Part Test - 1 (JEE Advanced 2021)
- Test: Intermolecular Forces- States Of Matter
- Test: Relations
- Test: Introduction To Determinants
- Test: Electric Charge
- Test: Slope Of A Line
- Test: Single Correct MCQs: Sequences and Series | JEE Advanced
- Competition Level Test: Straight Lines- 2
- Test: Sets- 1
- Test: Number System- 1
Recommended Documents for JEE MAIN
- Work & Work Done by a Variable Force
- Important Definitions & Formulas: Real Numbers
- NCERT Textbook: Vector Algebra
- Introduction to Electric Charges
- NCERT Exemplar: Ray Optics and Optical Instruments
- JEE Main Previous year questions (2016-20): Vector Algebra and Three Dimensional Geometry
- Equilibrium: Equilibrium in Physical Process
- Subset, Power Set & Universal Set
- NCERT Solutions: Current Electricity
- Types of Mirrors, Mirror Formula and Magnification
- NCERT Solutions Exercise 3.1: Matrices
- Importance & Scope of Chemistry
- HC Verma Solutions: Introduction to Physics (Chapter 1)
- Introduction to Physical World
- NCERT Exemplars - Electric Charges and Fields
NTA JEE MAINS 2020
The National Testing Agency(NTA) has released the application form for the JEE Main 2020 April Session on 7th February. Candidates can now apply in the online mode till 6th March. However the last date for the payment of the application form is 7th March. Interested candidates can fill their application forms for JEE MainsPaper-1 ((BE/BTech), Paper-2 (BArch) and Paper-3 (BPlanning).
The Exam is conducted twice a year i.e. January and April. Candidates can appear for one or for both attempts depending on your convenience. Those Candidates who have already appeared in JEE (Main) January-2020 Examination can appear in JEE (Main) April2020 Examination for improvement, if they so wish. The candidates who could not appear in the January JEE (Main) 2020 Examination, may also appear in JEE(Main) April-2020 Examination. The candidate’s best of the two NTA scores will be considered for preparation of Merit List/Ranking. Candidates who’ll qualify the JEE Mains exam 2020 cutoff are eligible for JEE advanced 2020.
JEE Mains 2020 Exam Dates
Mathematics
Sets, relations and functions, Complex numbers and quadratic equations, Matrices and determinants, Mathematical reasoning, Mathematical induction, Permutations and combinations, Sequences and series, Limit, continuity and differentiability, Integral calculus, Differential equations, Binomial theorem and its simple applications, Three-dimensional geometry, Vector algebra, Coordinate geometry, Statistics and probability, Trigonometry.
2. Physics
Section A
Physics and measurement, Kinematics, Thermodynamics, Work, energy and power, Rotational motion, Gravitation, Laws of motion, Properties of solids and liquids, Electronic devices, Kinetic theory of gases, Oscillations and waves, Communication systems, Current electricity, Magnetic effects of current and magnetism, Electromagnetic induction and alternating currents, Electromagnetic waves, Optics, Dual nature of matter and radiation, Electrostatics, Atoms and nuclei.
Section B
Experimental skill
3. Chemistry
Physical Chemistry
Some basic concepts in chemistry, States of matter, Atomic structure, Chemical bonding and molecular structure, Chemical thermodynamics, Solutions, Equilibrium, Redox reactions and electrochemistry, Chemical kinetics, Surface chemistry.
Organic Chemistry
Purification and characterisation of organic compounds, Hydrocarbons, Chemistry in everyday life, Principles related to practical chemistry, Organic compounds containing halogens, Organic compounds containing oxygen, Organic compounds containing nitrogen, Polymers, Some basic principles, organic chemistry, Biomolecules.
Inorganic Chemistry
Classification of elements and periodicity in properties, Hydrogen, Block elements (alkali and alkaline earth metals), P Block elements group 13 to group 18 elements, d- and f - block elements, Coordination compounds Environmental chemistry, General principles and processes of isolation of metals.
The JEE Main eligibility criteria mentions all the terms and conditions that candidates should satisfy. Hence, to avoid the rejection in later stages, you should go through and understand the eligibility criteria before registering for the exam. We have given some of the points below:
Qualifying exam for JEE mains: candidate should have cleared Class XII Board exam/Intermediate Or equivalent examination as listed by NTA.
Age limit: There is no age limit for the candidate to appear in JEE Mains. But that student must note that IIT may set an age limit for admission.
Qualifying year of 10 2 level exam: Candidate passed QE in the year 2018, 2019 or appearing in 2020 and will be appearing in 2020 is eligible for JEE Mains 2020.
Subjects: Candidates should have studiedPhysics, Chemistry and Mathematics in their 10 2 qualification exam.
Number of attempts: Candidates can appear fo rJEE Mains for three consecutive years irrespective of the session attempts, two attempts in a year will be considered as one.
JEE Mains 2020 mock tests are essential for every non medical aspirant. They complete your preparation and ensure that you clear the examination with a good score. Candidates can also download the mock test which is now available and practise at home online.These mock tests of JEE Mains 2020 have been designed to be solved in under 3 hours, thus Using the released mock test, the candidates will be able to prepare well for the upcoming examination. The mock tests are available in the three languages- English, Hindi, Gujarati. Since the mock test will have the same structure as the JEE Main 2020 examination, the candidates will be familiar with the pattern and analyze their preparation. Time management can also be practiced using the mock test.
JEE Main exam pattern 2020 has been released on 3rd Sep, 2019. The exam will now be conducted for three papers separately (i.e BE/BTech, BArch and Bplan). JEE Main 2020 for BE/BTech courses will be held online(computer based mode) for 300markswhile the BArch will be conducted partly online ( mathematics and aptitude test) and partly offline (drawing test) for 400 marks. BPlan will be conducted separately carrying 100 MCQs for 400 marks.
JEE Mains is an entrance exam for students willing to pursue MBBS or BDS courses offered by the top medical colleges in India. Solving previous year questions papers are key to cracking the NEET exam. Thus, here we are providing you the NEET previous years question paper with solutions. From here you can download NEET question paper pdf to practise and understand the paper pattern.
Here are some solved past year question papers of JEE MAIN.
JEE Mains Application forms for the April session are available online from today i.e. 7th Feb onwards. Candidates will be able to fill and submit their application form till 6th March, 2019. The image correction window is open for all the candidates.
Register for JEE Main 2020- In this following step, candidates have to register via online mode with the basic details of the candidates.
Fill the online application form- Next, candidates have to fill information related to their personal, education, communication, parents/guardian details and about exam cite and paper preferences.
Uploading scanned images/documents- At this step, candidates have to upload photographs and signatures with the given specifications.
Pay JEE Main Application fee- after uploading the documents, candidates have to pay application fees of JEE Mains 2020 in online mode.
Printout of the confirmation page- After successfully paying the application fee, candidates have to take a printout of the application form and keep it safely for further references.
For January Session: December 6, 2019 || For April Session: March 16, 2020:
The admit card will be available online at nta.ac.in.
To download JEE Main Admit Card, enter Application Number and Password.
The exam is expected to be conducted in 258 cities across India and 10 international cities.
JEE Main exam center has to be chosen at the time of registration.
Steps to download JEE Main 2020 Admit Card:
Enter JEE Main Application Number, date of birth and security pin in the admit card window
Click on the “Submit” button.
Check the admit card on your computer screen.
Ensure all the details are correct before taking a print out.
JEE Main Exam Centers:
The examination will be conducted in major cities and towns across India as well as abroad.
Candidates must select one city while registering for the exam.
In case the candidate opts for Paper 1 in the city where JEE Main 2020 is conducted but also wants to appear in Paper 2, select four other centre cities.
However, if the number of candidates for online mode is less than 50 in a city on a particular date then all such candidates will be allotted the last day of the online mode exam in the same city.
JEE Main 2020 result for paper 2 and 3 has been released by the national testing Agency(NTA) on 23rd Jan. Earlier, the result for Paper 1result of JEE Main 2020 was declared on 17th Jan. to view JEE Main 2020 result and percentile score, candidates must enter their Application number and password/date of birth. NTA is not gonna send JEE Main 2020 scorecard through mail or post to aspirants who appeared for the exam.
JEE Main 2020 Result for April session will be announced by NTA on 30th April. The NTA score for JEE Main 2020 Paper-1, 2 and 3 for both the session(Jan and Apr) will be merged to compile the exam result and prepare the overall JEE Main 2020 merit list. The best of the two NTA scores will be considered for further processing for candidates who have appeared for the sessions.
JEE Main cut off is the minimum score required for qualifying the examination. Candidates who score above the JEE Main cut off percentile become eligible to participate in the admission process. The cut off of JEE Main varies for candidates belonging to reserved and unreserved categories.
The JEE Main cutoff 2020 will be released after the April exam. But you can get an idea by taking a look at past year cutoffs for JEE Main.
Q. When will the NTA release the JEE Main 2020 application form for April January session?
A. NTA has released the application form of JEE Main 2020 for April session for Paper 1 (BE/BTech), Paper 2 (BArch) and Paper 3 (BPlan) on February 7.
Q. When will the NTA conduct the JEE Main 2020 April exam?
A. JEE Main 2020 April exam is scheduled to be held on April 5, 7, 8, 9 and 11.
Q. What should i do if, While paying the application fee my transaction failed but money was deducted?
A. If something like this happens then the candidate must pay the application fees again. The money would be refunded in the account within 7 to 10 days if in case the balance is deducted due to network or technical problems.
Q. Can I edit the test centre after the submission of the application form of JEE Main 2020?
A. No. You will not be allowed to edit your test centre and examination mode after the submission of the JEE Main application form.
Q. For how many times a student can appear for JEE Main in one year?
A. JEE Main 2020 is conducted twice a year. The number of attempts for admission in a particular academic session is considered as one. The age eligibility as prescribed by the authority allows a candidate to appear in JEE Main for three consecutive years.
Q. Is it mandatory to appear for the exam twice or can I take just one of the attempts ?
A. No. There is no mandate to appear for both the exams. It depends on your choice. In case you appear for the exam, the better of the two scores will be used to rank in the merit list.
Q. Are there any changes done in the syllabus of JEE Main 2020?
A. No, there are no changes in the syllabus of JEE Main 2020 paper 1 and 2. However, the authority has released a seperate section for BPlan(Paper-3) of JEE Mains.
All Courses for JEE MAIN on EduRev
Recommended Question & Answers for JEE MAIN
- If cos a + 2cos b + cos c = 2 then a, b, c are in
- a)2b = a+c
- b)b2 = a x c
- c)a = b = c
- d)none of these
Correct answer is option 'A'. Can you explain this answer? - If one of the root of a quadratic equation with rational coefficients is rational, then other root must be
- a)Imaginary
- b)Irrational
- c)Rational
- d)None of these
Correct answer is option 'C'. Can you explain this answer? - How many geometrical isomers exist in 1,2,4-trichlorocyclopentane?Correct answer is '3'. Can you explain this answer?
- The equation
represents - a)circle
- b)ellipse
- c)pair of lines
- d)no real curve
Correct answer is option 'D'. Can you explain this answer? - Which of the following is not a possible ordered pair for a matrix with 6 elements?
- a)(2,3)
- b)(3,2)
- c)(1,6)
- d)(3,1)
Correct answer is option 'D'. Can you explain this answer? - If a×cos x + b × cos x = c, then the value of (a × sin x – b²cos x)² is
- a)a² + b² + c²
- b)a² - b² - c²
- c)a² - b² + c²
- d)a² + b² - c²
Correct answer is option 'D'. Can you explain this answer? - Is there any discount coupon for edurev infinity?
- The ratio of first to the last of n A.m.’s between 5 and 25 is 1 : 4. The value of n is
- a)9
- b)10
- c)11
- d)none of these
Correct answer is option 'D'. Can you explain this answer? - In a triangle ABC, tan A/2 = 5/6, tan B/2 = 20/37, then tan C/2 is equal to:
- a)2/5
- b)100/222
- c)34/37
- d)5/2
Correct answer is option 'A'. Can you explain this answer? - If 3 × tan(x – 15) = tan(x + 15), then the value of x is:
- a)30º
- b)45º
- c)60º
- d)90º
Correct answer is option 'B'. Can you explain this answer? - . If a 30 m length can be taped with a precision of ± 0.01 m, then the standard error of measuring 1.08 km with the same precision will be?
- If n (P) = 5, n(Q) = 12 and n(PUQ) = 14 then n(P∩Q) =
- a)3
- b)4
- c)5
- d)7
Correct answer is option 'A'. Can you explain this answer? - The S.D. of the observations 22,26,28,20,24,30 is
- a)3
- b)2.4
- c)3.42
- d)2
Correct answer is option 'C'. Can you explain this answer? - cos 68° cos 8° + sin 68° sin 8° = ?
- a)1/2
- b)1/4
- c)1
- d)0
Correct answer is option 'A'. Can you explain this answer? - The argument of the complex number 13−5i4−9i13−5i4−9i isOptions
- a)π/3
- b)π/4
- c)π/5
- d)π/6
Correct answer is option 'B'. Can you explain this answer?
