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A function is a relation that assigns exactly one output for each input. It can be represented as f(x), where 'f' is the function name and 'x' is the input variable. |
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To determine if a relation is a function, check if any input (x-value) corresponds to more than one output (y-value). If it does, it is not a function. The vertical line test can also be used: if a vertical line intersects the graph at more than one point, it is not a function. |
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The domain of a function is the set of all possible input values (x-values) for which the function is defined. For example, in f(x) = √x, the domain is x ≥ 0 because the square root of a negative number is not defined in the real number system. |
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The range of the function f(x) = x² is the set of all possible output values (y-values). Since x² is always non-negative, the range is y ≥ 0. |
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To find f(4), substitute 4 for x in the function: f(4) = 2(4) + 3 = 8 + 3 = 11. Therefore, f(4) = 11. |
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The composition of functions is given by (f o g)(x) = f(g(x)). For example, if f(x) = 2x and g(x) = x + 1, then (f o g)(x) = f(g(x)) = f(x + 1) = 2(x + 1) = 2x + 2. |
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An inverse function undoes the operation of the original function. If f(x) is a function, its inverse f⁻¹(x) satisfies f(f⁻¹(x)) = x for all x in the domain of f⁻¹. |
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If f(x) = x² - 4, what are the x-intercepts of the function? Solve for x when f(x) = 0. |
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To find the x-intercepts, set f(x) = 0: x² - 4 = 0. Solving gives x² = 4, hence x = ±2. The x-intercepts are x = 2 and x = -2. |
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The vertex form of a quadratic function is f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola. This form makes it easy to identify the vertex and the direction of the parabola. |
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If f(x) = 3x - 2 and g(x) = x², what is (f o g)(2)? First find g(2) and then apply f. |
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First, calculate g(2): g(2) = 2² = 4. Now apply f: f(g(2)) = f(4) = 3(4) - 2 = 12 - 2 = 10. Thus, (f o g)(2) = 10. |