The nominal quiescent collector current of a transistor is 1.2 mA. If the range of β for this transistor is 80 ≤ β ≤ 120 and if the quiescent collector current changes by +_{-}10 percent, the range in value for r_{π} is

- a)1.73 kΩ < r
_{π}< 2.59 kΩ - b)1.93 kΩ < r
_{π}< 2.59 kΩ - c)1.73 kΩ < r
_{π }< 2.59 kΩ - d)1.56 kΩ < r
_{π}< 2.88 kΩ

Correct answer is option 'D'. Can you explain this answer?

Tanya Satija answered • 3 hours ago

to

- a)
- b)
- c)
- d)

Correct answer is option 'D'. Can you explain this answer?

Pooja Yadav answered • 3 hours ago

The circuit shown in the figure contains a dependent current source between A and B terminals. The theveninâ€™s equivalent resistance in kW between the terminals C and D is

- a)10 kW
- b)20 kW
- c)0 kW
- d)15 kW

Correct answer is option 'B'. Can you explain this answer?

Shoarib Quershi answered • 3 hours ago

Theveninâ€™s equivalent circuit is made by connecting 1A current source at the output and short circuiting the battery.

At node A,

At node A,

A frequency modulator has output . Where = 100 Hz/V and m (t) is shown in the figure. According Carsonâ€™s rule the bandwidth of s(t) is

- a)700 Hz
- b)1400 Hz
- c)2800 Hz
- d)200 Hz

Correct answer is option 'B'. Can you explain this answer?

Harshit Ahir answered • 3 hours ago

= 500 Hz,

So Bandwidth = 2

2(500 + 200)

= 1400 Hz

In a twin-wire transmission line in air, the adjacent voltage maxima are at 12 cm and 18 cm. The operating frequency is.

- a)2.5 GHz
- b)1.25 GHz
- c)5 GHz
- d)10 GHz

Correct answer is option 'A'. Can you explain this answer?

Md Shaik Junaid answered • 3 hours ago

Adjacent maxima appear with a distance of

f = 2.5 GHZ

f = 2.5 GHZ

The value of

- a)
- b)
- c)
- d)

Correct answer is option 'D'. Can you explain this answer?

Anamika Kadyan answered • 3 hours ago

The current 12 for the circuit shown below is______________ mA •

Correct answer is '7'. Can you explain this answer?

Srinidhi Akella answered • 12 hours ago

Just apply nodal analysis

let the nodal voltage be V

(V-30)/2k + V/1k = 9mA

i.e V-30+2V=18. i.e V=16volts

so I2=(30-V)/2k= 7mA

let the nodal voltage be V

(V-30)/2k + V/1k = 9mA

i.e V-30+2V=18. i.e V=16volts

so I2=(30-V)/2k= 7mA

The energy of a causal exponential pulse shown in figure is

- a)1/2α
- b)-α
- c)- 1/α
- d)2α

Correct answer is option 'A'. Can you explain this answer?

Geet Naman answered • 14 hours ago

Given,

∴ Normalized energy of given signal is

∴ Normalized energy of given signal is

The process of transmitting two or more information signals simultaneously over the same channel is called

- a)multiplexing
- b)telemetry
- c)detection
- d)modulation

Correct answer is option 'A'. Can you explain this answer?

Priya Tanwar answered • 14 hours ago

Multiplexing may be defined as the process of combining several message signals together and send them over the same communication channel, i.e. FDM, TDM and CDM.

Tanishka Rao asked • 22 hours ago

Delhi averages three murder per week and their occurrences follow a poission distribution.

Que:How many weeds per year (average) can the Delhi expect the number of murders per week to equal orexceed the average number per week ?

- a)15
- b)20
- c)25
- d)30

Correct answer is option 'D'. Can you explain this answer?

Direction flag is used with

- a)string instructions
- b)stack instructions
- c)arithmetic instructions
- d)branch instructions

Correct answer is option 'A'. Can you explain this answer?

Saryu Bakshi answered • 14 hours ago

Direction flag is used only with string instructions.

Ramya Srivalli asked • 22 hours ago

In an unbiased P-N Junction zero current implies that

- a)The potential biases has disappeared
- b)No. of holes diffusing from P-side to N-side equals the no. of electrons diffusing from N-side to P-side
- c)Total current crossing Junction from P-side to N-side equals the total current crossing Junction from N-side top-side
- d)No carriers cross the Junction

Correct answer is option 'C'. Can you explain this answer?

The amount of frequency shift in FM is

- a)directly proportional to amplitude of the modulating signal.
- b)inversely proportional to amplitude of the modulating signal.
- c)independent of amplitude of the modulating signal.
- d)proportional to frequency deviation.

Correct answer is option 'A'. Can you explain this answer?

Lakshmi Priya Ghildiyal answered • 14 hours ago

For FM, the frequency changes with the change in the amplitude of modulating signal value.

Anumala Krishna Vamsi asked • yesterday

A binary symmetric channel (BSC) has a transition probability of 1/8. If the

binary symbol X is such that P(X = 0) = 9/10, then the probability of error for

an optimum receiver will be

binary symbol X is such that P(X = 0) = 9/10, then the probability of error for

an optimum receiver will be

- a)a
- b)b
- c)c
- d)d

Correct answer is option 'A'. Can you explain this answer?

If in the next year, Crackle and Dairy Mill decided to join hands and increase their market share from their

combined existing share by 20%. What will be their combined production if the mark size remains the same?

combined existing share by 20%. What will be their combined production if the mark size remains the same?

- a)26251
- b)28520
- c)31780
- d)Indeterminable

Correct answer is option 'A'. Can you explain this answer?

Diya Ahuja answered • 14 hours ago

A linear time invariant (LTI) system with the transfer function

is connected in unity feedback configuration as shown in the figure.

For the closed loop system shown, the root locus for 0 < K < ∞ intersects the imaginary axis for K = 1.5. The closed loop system is stable for

is connected in unity feedback configuration as shown in the figure.

For the closed loop system shown, the root locus for 0 < K < ∞ intersects the imaginary axis for K = 1.5. The closed loop system is stable for

- a)K > 1.5
- b)1 < K < 1.5
- c)0 < K < 1
- d)no positive value of K

Correct answer is option 'A'. Can you explain this answer?

Rachita Sahoo answered • 14 hours ago

If closed loop system to be stable all coefficients to positive

The state diagram of a finite state machine (FSM) designed to detect an overlapping sequence of three bits is shown in the figure. The FSM has an input ‘In’ and an output ‘Out’. The initial state of the FSM is S_{0}.

Correct answer is '4 to 4'. Can you explain this answer?

Shilpa Jaiswal answered • 14 hours ago

From the state diagram, let us obtain the transition of states and out when IN channel.

Initial state is So, the input sea is 10101101001101

→ The ticketed mark now corresponding to output = 1.

So output will be 1 ‘4’ times.

Initial state is So, the input sea is 10101101001101

→ The ticketed mark now corresponding to output = 1.

So output will be 1 ‘4’ times.

For a (-)ve feedback second order control system in its step response, the maximum value of the output response in time domain form is given by

- a)0.84 per sec.
- b)0.45 per sec.
- c)4.2 per sec.
- d)5 per sec.

Correct answer is option 'C'. Can you explain this answer?

Sanjukta Pal answered • 14 hours ago

From the conventional approach we have,

Give that C(t)I_{max} = 1.75

∴ M_{p} = Maximum overshoot = 1.75 - 1.00 = 0.75

A single tone signal 14Cos(40π x10^{3}t) is used to modulate a carrier A_{c}cosw_{c}t. Then determine the number of channels available in very high frequency (VHF) band for this signal, if amplitude modulation and frequency modulation scheme employs respectively {Assume sensitivity of FM modulator = 10KHz/V}

- a)33,750 and 4218
- b)3375 and 421
- c)67,500 and 8437
- d)6,750 and 844

Correct answer is option 'D'. Can you explain this answer?

Srinidhi Akella answered • 21 hours ago

The VHF band is 30M-300Mhz

now if am modulation is done...the bw of each signal is 2fm=2(20khz)=40khz

total bw of VHF band is (300-30)MHz=270Mhz

assuming guard band to be zero, the number of signals each with bw 40khz occupying VHF band is

270Mhz/40khz=6750

similarly for FM, md=(Kf)(Am)/fm=10k(14)/(20k)=7

so bw of each signal is 2(mf+1)fm=2(8)(20k)=320khz

so numb... more

now if am modulation is done...the bw of each signal is 2fm=2(20khz)=40khz

total bw of VHF band is (300-30)MHz=270Mhz

assuming guard band to be zero, the number of signals each with bw 40khz occupying VHF band is

270Mhz/40khz=6750

similarly for FM, md=(Kf)(Am)/fm=10k(14)/(20k)=7

so bw of each signal is 2(mf+1)fm=2(8)(20k)=320khz

so numb... more

What will be sensitivity of modulator shown below, if its depth of modulation is

0.4 and x(t) = cos **(340nt) ?**

- a)0.68 KHz/V
- b)68 Hz/V
- c)36 Hz/V
- d)52 Hz/V

Correct answer is option 'B'. Can you explain this answer?

Srinidhi Akella answered • 21 hours ago

The modulation index for FM is md=(Kf)(Am)/fm

given x(t)=cos(340Ï€t). ...i.e Am=1volt and fm=170hz and given mf=0.4

so substituting we get 0.4=Kf(1)/170. i.e Kf=68hz/v

given x(t)=cos(340Ï€t). ...i.e Am=1volt and fm=170hz and given mf=0.4

so substituting we get 0.4=Kf(1)/170. i.e Kf=68hz/v

The open-loop transfer function of unity feedback system is G(s) = . Thes (s + 2) (s + 10)range of k for which closed-loop system is stable.

- a)k < 240
- b)k > 240
- c)k < 340
- d)k > 340

Correct answer is option 'A'. Can you explain this answer?

Shrinjini answered • yesterday

It is type-1 and order —3 system so the Nyquist plot is

For stability:

An EM wave travels in free space with the electric field component, E. = 100 e^{i(a866 +} ^{a5z)}a_{x} V/m and ω = 3 x 10^{8} rad/sec. The time average power in the wave is

- a)(1.33 a
_{y}- 2.3 a_{2}) W/m^{2} - b)(- 2.63 a
_{2}+ 5.6 a_{y}) W/m^{2} - c)(11.5 a
_{y}+ 6.6 a_{z}) W/m^{2} - d)(0.866 a
_{y}+ 0.5 a_{z}) W/m^{2}

Correct answer is option 'C'. Can you explain this answer?

Ashi Choudhary answered • yesterday

Consider a cascaded block of an LTI system

The impulse response of S_{1.} is h_{1.} t = δ **t -2 The impulse response of 5**_{2}** is h**_{2}** t = t.e**^{-r}**u t**

- a)
**W(t) will not be wide sense stationary so mean will not a be a constant.** - b)
- c)1
- d)2

Correct answer is option 'B'. Can you explain this answer?

Mridul Gupta answered • yesterday

then causal sequence f(n) is

- a)
- b)
- c)
- d)

Correct answer is option 'A'. Can you explain this answer?

Swati Srivastava answered • yesterday

On equating both sides we get. A 4- C = 3.

4A- 2B + C D = 5,

48 + D = 0

For the continuous signal x(t) shown in the fig draw The following signals

Q.

What is the signal x(-t)

- a)
- b)
- c)
- d)

Correct answer is option 'C'. Can you explain this answer?

Monika Singh answered • yesterday

The signal Is a folded signal. so

A circuit using an op - AMP is shown in the given figure it has

- a)Voltage series feed back
- b)Voltage shunt feed back
- c)Current shunt feed back
- d)Current series feed back

Correct answer is option 'B'. Can you explain this answer?

Shabhan Qurishi answered • yesterday

Since the feedback current is proportional to the output voltage, it is a voltage shunt feedback amplifier.

In a Vidicon camera tube

- a)grid G
_{1}accelerates electrons - b)grid G
_{2}accelerates electrons and grid G_{3}, slows down electrons - c)grid G
_{3}accelerates electrons and grid G_{2}slows down electrons - d)both grids G
_{2}and G_{3}accelerate electrons

Correct answer is option 'B'. Can you explain this answer?

Telecom Tuners answered • yesterday

Grid G_{2} accelerates the electrons. Grid G_{3}, is focus grid and slows the electrons so that they fall perpendicularly on the target at a low speed without causing secondary emission.

The received signal frequency at any time of a super-heterodyne receiver having IF = 456 kHz is 1 MHz. The corresponding image signal is

- a)within the medium band
- b)outside the medium band
- c)depend upon modulation index
- d)depends on Modulating frequency

Correct answer is option 'A'. Can you explain this answer?

Gate Funda answered • yesterday

Image signal frequency = Received signal frequency - 2 x Intermediate frequency.

= 1 MHz - 2 x 456kHz

1 MHz - 912 kHz 88 kHz

which lies in medium bond.

Consider the following

- Generation of SSB signals
- Design of minimum phase type filters
- Representation of band pass signals

- a)1 only
- b)1, 2 and 3
- c)1, 2 only
- d)1 and 3

Correct answer is option 'B'. Can you explain this answer?

L Narayan Reddy answered • yesterday

Hilbert transform is used in all the applications.

Yash Deep Singh asked • 2 days ago

The frequency response of a microphone means

- a)bandwidth of frequencies having output with in ± 1 dB of the output at 1000 Hz
- b)bandwidth of frequencies having output with in ± 3 dB of the output at 1000 Hz
- c)bandwidth of frequencies having output with in ± 1 dB of the output at 500 Hz
- d)bandwidth of frequencies having output with in ± 3 dB of the output at 500 Hz

Correct answer is option 'A'. Can you explain this answer?

Graphic equaliser system in stereophonic systems generally have

- a)3 or 4 bands
- b)1 band
- c)more than 8 bands
- d)large number of bands

Correct answer is option 'A'. Can you explain this answer?

Deepanshu answered • yesterday

Stereo systems have 3 or 4 bands at 300 Hz, 1000 Hz, 10000 Hz etc. in graphic equaliser system.

DAMANDEEP SINGH asked • 2 days ago

E = 4u_{x} -3 u_{y} + 5u_{z }in the neighborhood of point P(6, 2, -3). The incremental work done in moving 5 C charge a distance of 2 m in the direction u_{x} + u_{y} + u_{z} is

- a)-60 J
- b)34.64 J
- c)-34.64 J
- d)60 JJ

Correct answer is option 'C'. Can you explain this answer?

Consider the following

- A signal
*f*(*t*) and its Hilbert transform*f*(_{h}*t*) have the same energy density spectrum - A signal
*f*(*t*) and its Hilbert transform,*f*(_{h}*t*) have the same auto correlation function - A signal
*f*(*t*) and its Hilbert transform are mutually orthogonal

- a)1, 2 and 3
- b)1 and 2 only
- c)1 only
- d)2 and 3 only

Correct answer is option 'A'. Can you explain this answer?

Sachin Kaushal answered • yesterday

All are correct.

For the system shown in fig.the steady state error component due to unit step disturbance is 0.000012 and steady state error component due to unit ramp input is 0.003. The values of K_{1} and K_{2} are respectively

- a)16.4, 1684
- b)1250, 2.4
- c)125 x 10
^{3}, 0.016 - d)463, 3981

Correct answer is option 'C'. Can you explain this answer?

Piyush Vasuja answered • yesterday

If R (s) = 0

Error in output due to disturbance

Error due to ramp input

Error in output due to disturbance

Error due to ramp input

In the voltage doubler circuit shown in the figure, the switch ‘S’ is closed at t = 0. Assuming diodes D_{1} and D_{2} to be ideal, load resistance to be infinite and initial capacitor voltages to be zero, the steady state voltage across capacitors C_{1} and C_{2} will be

- a)v
_{c1}= 10V, v_{c2}= 5V - b)v
_{c1}= 10V, v_{c2}= –5V - c)v
_{c1}= 5V, v_{c2}= 10V - d)v
_{c1}= 5V, v_{c2}= –10V

Correct answer is option 'D'. Can you explain this answer?

Nitin Kumar answered • yesterday

Since R_{LOAD} is infinite, we can replace with open circuit

C_{1} will be charged in first +Ve half cycle

V_{C1} = +5v

C_{2} will be charged in first –Ve half cycle

V_{C2} = -10v

C

V

C

V

A uniformly doped npn bipolar transistor has following parameters:

N_{E} = 10^{18} cm^{-3} N_{B} = 5 x 10^{16} cm^{-3},

N_{c} = 2 x 10^{19} cm^{-3},

D_{E} = 8 cm^{2} /s , D_{B} = 15 cm^{2} /s , D_{c} = 14 cm^{2} /s

x_{E} = 0.8 μm, x_{B} = 0.7 μm

N

D

x

The emitter injection efficiency γ is

- a)0.999
- b)0.977
- c)0.982
- d)0.934

Correct answer is option 'B'. Can you explain this answer?

Zeba Ahmed answered • yesterday

A half wavelength dipole is kept in the x-y plane and oriented along 45° from the x-axis. Determine the direction of null in the radiation pattern for . Here the angle is measured from the z-axis, and the angle is measured from the x-axis in the x-y plane.

- a)
- b)
- c)
- d)

Correct answer is option 'A'. Can you explain this answer?

Santosh Kumar answered • yesterday

The null occurs along axis of the antenna which is

The following currents are measured in a uniformly doped npn bipolar transistor:

I_{nE} = 1.20 mA, I_{pE } = 0.10 mA, I_{nC} = 1.18 mA

I_{R} = 0.20 mA, I_{G} = 1 μA, I_{pC0} = 1 μA

I

The α is

- a)0.667
- b)0.733
- c)0.787
- d)0.8

Correct answer is option 'C'. Can you explain this answer?

Kunal Rauthan answered • 2 days ago

A silicon npn bipolar transistor has doping concentration of N_{E} = 2 x 10^{18}cm^{-3}, N_{B} =10^{17}cm^{-3} and N_{C } = 15 x 10^{16} cm^{-3}. The area is 10^{-3 } cm^{2} and neutral base width is 1 μm. The transistor is biased in the active region at V_{BE} = 0.5 V. The collector current is

(D_{B} = 20 cm^{2}/s)

(D

- a)9 μA
- b)17μA
- c)22 μA
- d)11 μA

Correct answer is option 'B'. Can you explain this answer?

N Ashish answered • 2 days ago

For the graph shown in fig.correct set is

- a)A
- b)B
- c)C
- d)D

Correct answer is option 'B'. Can you explain this answer?

Annu Nagar answered • 2 days ago

There are 4 node and 6 branches.

t = n - 1 = 3, l = b - n + 1 = 3

The time taken for the output to settle within 2% of step input for the control system represented by is given by:

- a)1.2 sec
- b)1.6 sec
- c)2 sec
- d)0.4 sec

Correct answer is option 'B'. Can you explain this answer?

M Satish answered • 2 days ago

Comparing the above transfer function with the standard second order transfer function

The value of Z_{22} (Ω) for the circuit shown below is

- a)4/11 Ω
- b)9/4 Ω
- c)4/9 Ω
- d)11/4 Ω

Correct answer is option 'A'. Can you explain this answer?

Yash Deep Singh answered • 2 days ago

Applying KVL, we get

Putting the value of V_{1} from equation (ii) into equation (i), we get

The Theven's equivalent resistance to the left of AB in figure given below is given by

- a)1/2 Ω
- b)1 Ω
- c)3/2 Ω
- d)None of these

Correct answer is option 'A'. Can you explain this answer?

Shiwan Gijai Deep answered • 2 days ago

For finding the Thevenin’s equivalent resistance, 8 A current source will be open circuited while V volt voltage source will be short circuited.

Hence

The initial state of the counter in the circuit shown below is 01, and resolution of DAC is 0.5 volt. Determine the output of DAC after three clock pulses.

- a)1.5 volt
- b)2 volt
- c)1 volt
- d)0 volt

Correct answer is option 'D'. Can you explain this answer?

V Nagaindraja answered • 2 days ago

The state diagram of counter

So, output of DAC = 0 volt

So, output of DAC = 0 volt

Two pipes can fill a tank in 15 minutes and 25 minutes respectively. Both the pipes are opened together and after some time, the first pipe is closed and the tank is completely full in 15 minutes. For how many minutes is the first pipe opened?

- a)5 minutes
- b)6 minutes
- c)7 minutes
- d)8 minutes

Correct answer is option 'B'. Can you explain this answer?

Dilpreet Singh answered • 2 days ago

t = 6 min.

Find the value of

- a)
- b)
- c)
- d)3

Correct answer is option 'D'. Can you explain this answer?

Gargi Sharma answered • 2 days ago

y(y-3) = 0

y = 3

Consider the audio signal with spectral components limited to the frequency band of 300 to 3300 Hz. A PCM signal is generated with a sampling rate of 8000 samples/sec. The required output signal to quantizing noise ratio is 30 dB. The minimum number of bits per sample needed is :

- a)4
- b)5
- c)6
- d)7

Correct answer is option 'B'. Can you explain this answer?

K Ragini Rao answered • 2 days ago

(SNR) in dB = 1.76 + 20 log L

Where L is the number of levels

So minimum number of levels are 26, and minimum number of bits are 5.

Where L is the number of levels

So minimum number of levels are 26, and minimum number of bits are 5.

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