Electronics and Communication Engineering (ECE)

The current 12 for the circuit shown below is______________ mA •
    Correct answer is '7'. Can you explain this answer?

    Srinidhi Akella answered  •  12 hours ago
    Just apply nodal analysis
    let the nodal voltage be V
    (V-30)/2k + V/1k = 9mA
    i.e V-30+2V=18. i.e V=16volts
    so I2=(30-V)/2k= 7mA

    The process of transmitting two or more information signals simultaneously over the same channel is called
    • a)
      multiplexing
    • b)
      telemetry
    • c)
      detection
    • d)
      modulation
    Correct answer is option 'A'. Can you explain this answer?

    Priya Tanwar answered  •  14 hours ago
    Multiplexing may be defined as the process of combining several message signals together and send them over the same communication channel, i.e. FDM, TDM and CDM.

    The state diagram of a finite state machine (FSM) designed to detect an overlapping sequence of three bits is shown in the figure. The FSM has an input ‘In’ and an output ‘Out’. The initial state of the FSM is S0.
      Correct answer is '4 to 4'. Can you explain this answer?

      Shilpa Jaiswal answered  •  14 hours ago
      From the state diagram, let us obtain the transition of states and out when IN channel.
      Initial state is So, the input sea is 10101101001101


      → The ticketed mark now corresponding to output = 1.
      So output will be 1 ‘4’ times.

      A single tone signal 14Cos(40π x103t) is used to modulate a carrier Accoswct. Then determine the number of channels available in very high frequency (VHF) band for this signal, if amplitude modulation and frequency modulation scheme employs respectively {Assume sensitivity of FM modulator = 10KHz/V}
      • a)
        33,750 and 4218                               
      • b)
        3375 and 421
      • c)
        67,500 and 8437
      • d)
        6,750 and 844
      Correct answer is option 'D'. Can you explain this answer?

      Srinidhi Akella answered  •  21 hours ago
      The VHF band is 30M-300Mhz
      now if am modulation is done...the bw of each signal is 2fm=2(20khz)=40khz
      total bw of VHF band is (300-30)MHz=270Mhz
      assuming guard band to be zero, the number of signals each with bw 40khz occupying VHF band is
      270Mhz/40khz=6750
      similarly for FM, md=(Kf)(Am)/fm=10k(14)/(20k)=7
      so bw of each signal is 2(mf+1)fm=2(8)(20k)=320khz
      so numb
      ... more

      The Theven's equivalent resistance to the left of AB in figure given below is given by
      • a)
        1/2  Ω
      • b)
        1  Ω
      • c)
        3/2  Ω
      • d)
        None of these
      Correct answer is option 'A'. Can you explain this answer?

      Shiwan Gijai Deep answered  •  2 days ago
      For finding the Thevenin’s equivalent resistance, 8 A current source will be open circuited while V volt voltage source will be short circuited.
      Hence

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