Electronics and Communication Engineering (ECE)

• a)
  Positive and has a large value
• b)
  Negative and has a large value
• c)
  Positive and has a small value
• d)
  Negative and has a small value

• a)
  1 : 1
• b)
  1 : 2
• c)
  1 : 3
• d)
  1 : 4

• a)
  3.6 V
• b)
  9.8 V
• c)
  7.2 V
• d)
  12.3 V

• a) 
  62Ω
• b) 
  43Ω
• c) 
  72Ω
• d) 
  81Ω

• a)
   She is smart enough to take care of herself in Bombay
• b)
   She is enough smart to take care of oneself in Bombay
• c)
   She is enough smart to take care of herself in Bombay
• d)
   She is smart enough to take care of oneself in Bombay

• a)
  d.c. ground point
• b)
  must be floating
• c)
  The most negative voltage available in the circuit
• d)
  The most positive voltage available in the circuit

The curl of vector   is

• a)
  
• b)
  
• c)
  
• d)
  

• a)
  bandwidth of frequencies having output with in � 1 dB of the output at 1000 Hz
• b)
  bandwidth of frequencies having output with in � 3 dB of the output at 1000 Hz
• c)
  bandwidth of frequencies having output with in � 1 dB of the output at 500 Hz
• d)
  bandwidth of frequencies having output with in � 3 dB of the output at 500 Hz

• a)
  reciprocity theorem
• b)
  principle of maximum power transfer
• c)
  both (a) and (b)
• d)
  none of the above

• a)
   eclipses
• b)
   dominates
• c)
   overshadows
• d)
   subdues

• a)
  4.36
• b)
  9.8
• c)
  19
• d)
  3.13

• A:

  high only when A = 0, B = 0

• B:

  high only when A = 0, B = 1

• C:

  high only when A = 1, B = 0

• D:

  high for all values of A and B

The answer is A.

Consider the differential equation

The numerical value of  is

• a)
  -2
• b)
  -1
• c)
  0
• d)
  1

• a)
  Eddy current losses are higher
• b)
  Mass of moving system
  becomes higher
• c)
  The magnetic field produced by
  eddy currents introduce error
• d)
  Operating field is weak due to
  air cored.

• a)
  1,2,3
• b)
  1, 3
• c)
  1 only
• d)
  2, 3

Consider the system shown in figure . The average value of m(t) is zero and maximum value of
|m(t)| is M. The square-law device is defined by y(t) = 4x(t) +10 x(t).

Let W be the bandwidth of message signal m(t). AM signal would be recovered if

• a)
  f_c > W 
• b)
  f_c > 2W
• c)
  f_c ≥ 3W
• d)
  f_c > 4W

• a)
  (- 1)^k δ(k)                             
• b)
  δ(k) - (- 1)^k
• c)
  (-1)^k u(k)           
• d)
  u(k) - (- 1)^k

• a)
  1 time
• b)
  10 times
• c)
  11 times
• d)
  infinite times

In the circuit shown below, the voltage source has been connected for a long time enough for steady state condition to be reached. At time t=0, switch S is opened. Then open circuit voltage across AB is

• a)
  V.e ^{- (R / L)}
• b)
  V + V.e^-R/L
• c)
  V
• d)
  o

• A:

  38 kΩ

• B:

  17kΩ

• C:

  25 kΩ

• D:

  47 kΩ

The answer is b.

• a)
  2x
• b)
  −2x
• c)
  2|x|
• d)
  None of these

• a)
  TE₁₀ < TE₂₀ < TE₀₁ < TM₁₁
• b)
  TE₁₀ < TE_o1 < TE₂₀ < TM₁₁
• c)
  TE ₁₁ < TE₀₁ < TE₂₀ < TM ₁₀
• d)
  TE₀₁ < TE₁₀ < TE₂₀ < TM₁₁

• a)
  
• b)
  
• c)
  
• d)
  

• a)
  Equal to 1             
• b)
  Less than 1             
• c)
  Greater than 1         
• d)
  Equal to 5 ​

• a)
  10111
• b)
  10011
• c)
  10110
• d)
  10010

• a)
  slow and more reliable
• b)
  fast and more reliable
• c)
  fast and less reliable
• d)
  slow and less reliable

• a)
  more accurate but less stable
• b)
  less accurate but more stable
• c)
  more accurate as well as more stable
• d)
  less accurate as well as less stable

• a)
  
• b)
  exp (10s)
• c)
  
• d)
  exp (-10s)

Match the list
 

List-I
Material used
A. Maganin
B. Aluminium
C. Phosphor Bronze
D. Eureka

List-II
Purpose
1. Multiplier
2. Coils
3. Discs
4. Control spring
5. Shunt

• a)
  a
• b)
  b
• c)
  c
• d)
  d

• a)
  3
• b)
  2
• c)
  4
• d)
  Limit does not exist

The Eigen values of the matrix 

• a)
  1, 1, 2
• b)
  1, 2, 2
• c)
  1, 2, 3
• d)
  None of these

• a)
  1/21 rad
• b)
  1/15 rad
• c)
  1/3 rad
• d)
  1/8 rad

• a)
  1, 2, 3
• b)
  1, 2
• c)
  1 only
• d)
  2, 3

   then find 

• a)
  √3
• b)
  1 / 3
• c)
  3  
• d)
  None of these

• a)
  π/8
• b)
  π/64
• c)
  0
• d)
  π/4

  the third row of R^-1 is 

• a)
  [4 − 3 1]
• b)
  [1 1 1]
• c)
  [− 4 3 − 1]
• d)
  [− 1 1 − 1]

• a)
  a
• b)
  b
• c)
  c
• d)
  d

Given the transform pair below. Determine the time signal y(t) and choose correct option.

Que:  

• a)
  t cos 2(t - 3) u(t - 3)
• b)
  t cos 2(t - 3) u(t)
• c)
  -t cos 2(t - 3) u(t - 3)
• d)
  -t cos 2(t - 3) u(t)

• a)
  1 , 2 , 3 and 4
• b)
  1 ,3 and 4
• c)
  2, 3 and 4
• d)
  1,2 and 3

A circuit is given in fig. Find theThevenin equivalent as given in question.

As viewed from terminal y and y^' is

• a)
  8 V, 32 Ω
• b)
  4 V, 32 Ω
• c)
  5 V, 6 Ω
• d)
  7 V, 6 Ω

If wave form is given only for I period then

 

Q. Waveform x (t) is

 

• a)
  an even function with half wave symmetry.
• b)
  An odd function with half wave symmetry.
• c)
  an even function with no half wave symmetry.
• d)
  An odd function with no half wave symmetry.

• a)
   The potential biases has disappeared
• b)
  No. of holes diffusing from P-side to N-side equals the no. of electrons diffusing from N-side to P-side
• c)
  Total current crossing Junction from P-side to N-side equals the total current crossing Junction from N-side top-side
• d)
  No carriers cross the Junction

• a)
  aS²_g (ω) and a²P_g
• b)
  aS_g² (ω) and aP_g
• c)
  aS_g (ω) and a²P_g
• d)
  aS_g (ω) and aP_g

• a)
   0.5  
• b)
   0.6  
• c)
   0.7  
• d)
   None of these

• a)
  8
  
• b)
  12
• c)
  16
• d)
  24

• a)
  Zero initial condition
• b)
  Non-zero initial condition
• c)
  Zero final condition
• d)
  Non-zero final condition

• a)
  
• b)
  
• c)
  R
• d)
  -R

• a)
  0
• b)
  1
• c)
  ∞
• d)
  -1

• a)
  Free space
• b)
  Water
• c)
  Wires
• d)
  Fiber-optic cable