Class 11
What is the referral code for edurev infinity?
Uphc Naharpurroopa answered • 14 minutes agoHow to see Ku referal code
Jagbiri Devi asked • 5 minutes agoA body sliding on a smooth inclined plane requires 4 seconds to reach the bottom starting from rest at the top. How much time does it take to cover one-fourth distance starting from rest at the top- a)1 s
- b)2 s
- c)4 s
- d)16 s
Correct answer is option 'B'. Can you explain this answer?
A body sliding on a smooth inclined plane requires 4 seconds to reach the bottom starting from rest at the top. How much time does it take to cover one-fourth distance starting from rest at the top
a)
1 s
b)
2 s
c)
4 s
d)
16 s
The solubility product expression for silver(I) sulphide, using x to represent the molar concentration of silver(I) and y to represent the molar concentration of sulphide, is formulated as:- a)x2y2
- b)xy3
- c)x2y
- d)xy2
Correct answer is option 'C'. Can you explain this answer?
The solubility product expression for silver(I) sulphide, using x to represent the molar concentration of silver(I) and y to represent the molar concentration of sulphide, is formulated as:
a)
x2y2
b)
xy3
c)
x2y
d)
xy2
Kruthika Kruthika answered • 2 hours ago
Punarth Jzy asked • 11 minutes agoTwo spherical planets P and Q have the same uniform density , masses Mpand MQ, and surface areas A and 4A, respectively. A spherical planet R also has uniform density and its mass is (MP + MQ). The escape velocities from the planets P, Q and R, are Vp, VQ and VR,respectively. Then [jee 2012]... more
Two spherical planets P and Q have the same uniform density , masses Mpand MQ, and surface areas A and 4A, respectively. A spherical planet R also has uniform density and its mass is (MP + MQ). The escape velocities from the planets P, Q and R, are Vp, VQ and VR,respectively. Then [jee 2012]
Value of rest potential in a polarized muscle fibre are?
Ramesh Chand answered • 4 hours ago-60 to -90mV...
Define Circinate vernation?
Ramesh Chand answered • 4 hours agoA form of vernation in which the leaf primordia are rolled in on themselves from the apex to the base, so that the apex is in the middle of the coil. It is seen in most ferns.
Yashwardhan Shinde asked • 19 minutes agoTwo masses m1 and m2 (m1 < m2) are released from rest from a finite distance. They start under their mutual gravitational attraction- a) Acceleration of m1 is more than that of m2
- b) Acceleration of m2 is more than that of m1
- c)Centre of mass of system will remain at rest in all the references frame
- d)Total energy of system remains constant
Correct answer is option 'A,D'. Can you explain this answer?
Two masses m1 and m2 (m1 < m2) are released from rest from a finite distance. They start under their mutual gravitational attraction
a)
Acceleration of m1 is more than that of m2
b)
Acceleration of m2 is more than that of m1
c)
Centre of mass of system will remain at rest in all the references frame
d)
Total energy of system remains constant
Valavan V asked • 42 minutes agoIs forbidden bands depend on structure of solids?? How?? Plz explain?
Dihsin. Rakkaht asked • 1 hour agoThree identical stars of mass M are located at the vertices of an equilateral triangle with slide L. The speed at which they will move if they all revolve under the influence of one another’s gravitational force in a circular orbit circumscribing the triangle while still preserving the equilateral triangle- a)
- b)
- c)
- d)Not possible at all
Correct answer is option 'B'. Can you explain this answer?
Three identical stars of mass M are located at the vertices of an equilateral triangle with slide L. The speed at which they will move if they all revolve under the influence of one another’s gravitational force in a circular orbit circumscribing the triangle while still preserving the equilateral triangle
a)
b)
c)
d)
Not possible at all
Rohan Bhalla asked • 1 hour agoBased on following figure,
- a)work done when gas expands isothermally against external pressure is - 167.2 J
- b)work done when gas expands isothermally and reversibly is larger than 167.2 J
- c)work done when gas expands under vacuum is zero
- d)work done when gas expands isothermally or isothermally reversibly is same
Correct answer is option 'A,B,C'. Can you explain this answer?
Based on following figure,
a)
work done when gas expands isothermally against external pressure is - 167.2 J
b)
work done when gas expands isothermally and reversibly is larger than 167.2 J
c)
work done when gas expands under vacuum is zero
d)
work done when gas expands isothermally or isothermally reversibly is same
Oppo Camera Phone asked • 2 hours agoFour particles, each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction. (Take that gravitational force between two point masses m1 and m2 separated by is 
The speed of each particle is- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
Four particles, each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction. (Take that gravitational force between two point masses m1 and m2 separated by is The speed of each particle is
The speed of each particle isa)
b)
c)
d)
Mrunmayee Jadhao asked • 2 hours ago Which is untrue about orbital velocity?- a)increases with the decrease in height of satellite
- b)depends on mass and radius of planet around which it revolves
- c)it is independent of mass of satellite
- d)decreases with an increase in radius of orbit
Correct answer is option 'A'. Can you explain this answer?
Which is untrue about orbital velocity?
a)
increases with the decrease in height of satellite
b)
depends on mass and radius of planet around which it revolves
c)
it is independent of mass of satellite
d)
decreases with an increase in radius of orbit
Mamta Phulia asked • 2 hours agoTwo containers X & Y are present with container X consisting of some mass of He at some temperature while container Y having double the volume as that of container X & kept at same temperature containing same mass of H2 gas as the mass of Helium gas. Based on this data & the following conditions answer the question that followsAssume sizes of H2 molecule & He atom to be same & size of H–atom to be half to that of He–atom & only bimolecular collisions to be occuring.Condition I: all except one atom of He are stationary in cont. X & all molecules of H2 are moving in container Y.Condition II: both containers contain all moving moleculesQ. Assuming condition II to be applicable, if temperature only of container Y is doubled to that of original (causing dissociation of all H2 gas into H gaseous atoms) then, if no. of total collisions per unit volume per unit time in container X is A then, no. of 'total collisions made by all molecules per unit volume in container Y would be... more
Two containers X & Y are present with container X consisting of some mass of He at some temperature while container Y having double the volume as that of container X & kept at same temperature containing same mass of H2 gas as the mass of Helium gas. Based on this data & the following conditions answer the question that follows
Assume sizes of H2 molecule & He atom to be same & size of H–atom to be half to that of He–atom & only bimolecular collisions to be occuring.
Condition I: all except one atom of He are stationary in cont. X & all molecules of H2 are moving in container Y.
Condition II: both containers contain all moving molecules
Q.
Assuming condition II to be applicable, if temperature only of container Y is doubled to that of original (causing dissociation of all H2 gas into H gaseous atoms) then, if no. of total collisions per unit volume per unit time in container X is A then, no. of 'total collisions made by all molecules per unit volume in container Y would be
Satyawati asked • 3 hours agoAt a certain place, the acceleration due to gravity is determined using a simple pendulum. The length of the pendulum is 25.0 cm and a stopwatch with least count is 1 s measures the time taken by the pendulum for 40 oscilations to be 50 s. the accuracy in the measurement of g is- a)4.40 %
- b)3.40 %
- c)2.40 %
- d)5.40 %
Correct answer is option 'A'. Can you explain this answer?
At a certain place, the acceleration due to gravity is determined using a simple pendulum. The length of the pendulum is 25.0 cm and a stopwatch with least count is 1 s measures the time taken by the pendulum for 40 oscilations to be 50 s. the accuracy in the measurement of g is
a)
4.40 %
b)
3.40 %
c)
2.40 %
d)
5.40 %
Anirban Saha asked • 3 hours agoImagine a situation in which the horizontal surface of block M0 is smooth and its vertical surface is rough with a coefficient of friction m 
Identify the correct statement(s)- a) If F=0, the blocks cannot remain stationary
- b)For one unique value of F, the blocks M and m remain stationary with respect to M0
- c)The limiting friction between m and M0 is independent of F
- d) There exist a value of F at which friction force is equal to zero.
Correct answer is option 'A,D'. Can you explain this answer?
Imagine a situation in which the horizontal surface of block M0 is smooth and its vertical surface is rough with a coefficient of friction m
Identify the correct statement(s)
a)
If F=0, the blocks cannot remain stationary
b)
For one unique value of F, the blocks M and m remain stationary with respect to M0
c)
The limiting friction between m and M0 is independent of F
d)
There exist a value of F at which friction force is equal to zero.
Prithvi V asked • 3 hours agoWhy does a flame always stand up even if a candle is placed upside down?
Neeraj Prajapati asked • 4 hours agoTwo bodies A & B rotate about an axis, such that angle qA (in radians) covered by first body is proportional to square of time, & qB (in radians) covered by second body varies linearly. At t = 0, qA = qB = 0. If A completes its first revolution in 
sec. & B needs 4p sec. to complete half revolution then; angular velocity wA : wB at t = 5 sec. are in the ratio- a)4 : 1
- b)80 : 1
- c) 20 : 1
- d)20 : 4
Correct answer is option 'C'. Can you explain this answer?
Two bodies A & B rotate about an axis, such that angle qA (in radians) covered by first body is proportional to square of time, & qB (in radians) covered by second body varies linearly. At t = 0, qA = qB = 0. If A completes its first revolution in sec. & B needs 4p sec. to complete half revolution then; angular velocity wA : wB at t = 5 sec. are in the ratio
sec. & B needs 4p sec. to complete half revolution then; angular velocity wA : wB at t = 5 sec. are in the ratioa)
4 : 1
b)
80 : 1
c)
20 : 1
d)
20 : 4
Raja Khan Rana asked • 4 hours agoCaryophyllene (C15H24) contain a six membered ring and on ozonolysis gives following product.
Q. If caryophyllene is treated with 1.0 mole of HCI, a ring closure reaction takes place to form monochloride. What is the most likely product of this reaction?- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
Caryophyllene (C15H24) contain a six membered ring and on ozonolysis gives following product.
Q. If caryophyllene is treated with 1.0 mole of HCI, a ring closure reaction takes place to form monochloride. What is the most likely product of this reaction?
a)
b)
c)
d)
Sangeeta Satish asked • 4 hours agoImportant Long answer question of nomadic empire class 11 history?
Ajith M asked • 5 hours agoHydrogen combines with oxygen to form two compounds namely, water and hydrogen peroxide.
Hydrogen + Oxygen →Water
Hydrogen + Oxygen →Hydrogen peroxide
Here, the masses of oxygen which combine with a fixed mass of hydrogen bear simple ratio, Will be- a)2 :1
- b)1:2
- c)3:4
- d)4:3
Correct answer is option 'B'. Can you explain this answer?
Hydrogen combines with oxygen to form two compounds namely, water and hydrogen peroxide.
Hydrogen + Oxygen →Water
Hydrogen + Oxygen →Hydrogen peroxide
Here, the masses of oxygen which combine with a fixed mass of hydrogen bear simple ratio, Will be
Hydrogen + Oxygen →Water
Hydrogen + Oxygen →Hydrogen peroxide
Here, the masses of oxygen which combine with a fixed mass of hydrogen bear simple ratio, Will be
a)
2 :1
b)
1:2
c)
3:4
d)
4:3
Puneet Goel asked • 6 hours agoEquilibrium constant for the given reaction is C = 1020 at temperature 300 KA(s) +2B(aq) 
2C (s) + D(aq.)K = 1020The equilibrium conc. of B starting with mixture of 1 mole of A and 1/3 mote/titre of B at 300 K is- a)-4 x 10-11
- b)-2 x 10-10
- c)-2 x 10-11
- d)-10-10
Correct answer is option 'A'. Can you explain this answer?
Equilibrium constant for the given reaction is C = 1020 at temperature 300 K
A(s) +2B(aq) 2C (s) + D(aq.)K = 1020
2C (s) + D(aq.)K = 1020The equilibrium conc. of B starting with mixture of 1 mole of A and 1/3 mote/titre of B at 300 K is
a)
-4 x 10-11
b)
-2 x 10-10
c)
-2 x 10-11
d)
-10-10
Rohit Raj asked • 6 hours agoDirection (Q. Nos. 12 and 13) This section contains a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given ptions (a),(b),(c),(d)A hypothetical electromagnetic wave is pictured here.
Q. Energy associated with this wave is... more
Direction (Q. Nos. 12 and 13) This section contains a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given ptions (a),(b),(c),(d)
A hypothetical electromagnetic wave is pictured here.
Q. Energy associated with this wave is
Renuka Devi asked • 7 hours agoIn a typical power station, amid a series of energy transfers and conversions, about 70% of the energy input gets wasted in the form of thermal energy, the efficiency of such a power station is about- a)0.3
- b)0.4
- c)0.7
- d)1
Correct answer is option 'A'. Can you explain this answer?
In a typical power station, amid a series of energy transfers and conversions, about 70% of the energy input gets wasted in the form of thermal energy, the efficiency of such a power station is about
a)
0.3
b)
0.4
c)
0.7
d)
1
Fetching relevant content for you
Ask a question
Related Courses
Follow Us
