All India NEET Group
How to tolerate exam pressure?
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Bhakti Salpekar answered |
Start preparing from the day u start learning
A car covers the first half of the distance between two places at the speed of 40 km per hour and the second half at 60 km per hour. what is the average speed of the car?
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Juhe Shanofar answered |
Time taken in travelling the first distance x will be t1 =
x/40 and time taken in travelling the second distance x
will be t2 = x/60
Now the average velocity can be calculated as
V = total distance/total time
2x/t1+t2 = 2x/x/40 +x/60
= 48km/hr
x/40 and time taken in travelling the second distance x
will be t2 = x/60
Now the average velocity can be calculated as
V = total distance/total time
2x/t1+t2 = 2x/x/40 +x/60
= 48km/hr
The ignition powder in aluminothermite process contains a mixture of- a)Magnesium powder and BaO2
- b)Magnesium powder, aluminium and BaO2
- c)Magnesium and aluminium powder
- d)Magnesium and aluminium oxide
Correct answer is option 'A'. Can you explain this answer?
The ignition powder in aluminothermite process contains a mixture of
a)
Magnesium powder and BaO2
b)
Magnesium powder, aluminium and BaO2
c)
Magnesium and aluminium powder
d)
Magnesium and aluminium oxide
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EduRev JEE answered |
Alumino thermite process, contain oxides of Mn, Cr, that is not reduced by carbon due to very high melting point. They are reduced by Al. Its mixture consists of Mg powder along with BaO2 or KClO3.
A mixture of magnesium powder and BaO2 is used as ignition powder.
Roasting process is applied to which of the following ores?- a)Galena
- b)Iron pyrites
- c)Copper glance
- d)All of these
Correct answer is option 'D'. Can you explain this answer?
Roasting process is applied to which of the following ores?
a)
Galena
b)
Iron pyrites
c)
Copper glance
d)
All of these
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|
EduRev JEE answered |
Generally sulphide ores are subjected to roasting.
Galena: 2PbS+3O2 ⟶ 2PbO + 2SO2
Iron pyrites: 2FeS2 + 3O2 ⟶ 2FeO + 2SO2
Copper glance: 2Cu2S + 3O2 ⟶ 2Cu2O + 2SO2
Which is one of the following an acidic flux?- a)CuO
- b)SiO2
- c)Al2O3
- d)Fe2O3
Correct answer is option 'B'. Can you explain this answer?
Which is one of the following an acidic flux?
a)
CuO
b)
SiO2
c)
Al2O3
d)
Fe2O3
|
|
EduRev JEE answered |
An acidic flux is the chemical substance which removes the basic impurities
SiO2 + CaO → CaSiO3
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Thunga Deekshitha
asked a question
|
An interaction between non allelic genes in which an allele at one locus prevents expression of an allele at another locus, but not vice versa, is called- a)Dominance
- b)Collaboration
- c)Complementation
- d)Epistasis
Correct answer is option 'D'. Can you explain this answer?
An interaction between non allelic genes in which an
allele at one locus prevents expression of an allele at
another locus, but not vice versa, is called
a)
Dominance
b)
Collaboration
c)
Complementation
d)
Epistasis
The function of flux during smelting of ores is to- a)Make the ore porous
- b)Remove gangues
- c)Facilitate reduction
- d)Precipitate slag
Correct answer is option 'D'. Can you explain this answer?
The function of flux during smelting of ores is to
a)
Make the ore porous
b)
Remove gangues
c)
Facilitate reduction
d)
Precipitate slag
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|
EduRev JEE answered |
In the process of smelting of ores flux is added to promote fluidity and it also removes impurities by converting them into slag
Blister copper is refined by stirring molten impure metal with green logs of wood because such a wood liberates hydrocarbon gases (like CH4 ). This process X is called ________ and it is used to purify the metal that initially contain impurities of Y. Y is _______.- a)X = poling, Y = CuO2
- b)X = cupellation, Y = CuO
- c)X = cupellation, Y = ZnO
- d)X = poling, Y = Cu2O
Correct answer is option 'D'. Can you explain this answer?
Blister copper is refined by stirring molten impure metal with green logs of wood because such a wood liberates hydrocarbon gases (like CH4 ). This process X is called ________ and it is used to purify the metal that initially contain impurities of Y. Y is _______.
a)
X = poling, Y = CuO2
b)
X = cupellation, Y = CuO
c)
X = cupellation, Y = ZnO
d)
X = poling, Y = Cu2O
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|
EduRev JEE answered |
Poling is a purification process which is used for metals which contains their own oxide as impurity.
Number of possible isomers for the complex [Co(en)2Cl2]Cl will be (en = ethylenediamine)- a)1
- b)3
- c)4
- d)2
Correct answer is option 'B'. Can you explain this answer?
Number of possible isomers for the complex [Co(en)2Cl2]Cl will be (en = ethylenediamine)
a)
1
b)
3
c)
4
d)
2
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EduRev JEE answered |
Possible isomers of [Co(en)2Cl2]Cl
The name of complex ion, [Fe(CN)6]3− is- a)hexacyanitoferrate (III) ion
- b)tricyanoferrate (III) ion
- c)hexacyanidoferrate (III) ion
- d)hexacyanoiron (III) ion.
Correct answer is option 'C'. Can you explain this answer?
The name of complex ion, [Fe(CN)6]3− is
a)
hexacyanitoferrate (III) ion
b)
tricyanoferrate (III) ion
c)
hexacyanidoferrate (III) ion
d)
hexacyanoiron (III) ion.
|
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EduRev JEE answered |
The name of complex ion, [Fe(CN)6]3− is “hexacyanidoferrate (III) ion”
Which of the following has longest C−O bond length? (Free C−O bond length in CO is 1.128Å.)- a)[Fe(CO)4]2−
- b)[Mn(CO)6]+
- c)Ni(CO)4
- d)[Co(CO)4]−
Correct answer is option 'A'. Can you explain this answer?
Which of the following has longest C−O bond length? (Free C−O bond length in CO is 1.128Å.)
a)
[Fe(CO)4]2−
b)
[Mn(CO)6]+
c)
Ni(CO)4
d)
[Co(CO)4]−
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EduRev JEE answered |
The greater the negative charge on the carbonyl complex, the more easy it would be for the metal to permit its electrons to participate in the back bonding, the higher would be the M−C bond order and simultaneously there would be larger reduction in the C−O bond order. Thus, [Fe(CO)4]2− has the lowest C−O bond order means the longest bond length.
The correct increasing order of trans-effect of the following species is- a)NH3 > CN− >Br− > C6H5−
- b)CN− > C6H5− > Br− > NH3
- c)Br− > CN− > NH3 > C6H5−
- d)CN− > Br− > C6H5− > NH3
Correct answer is option 'B'. Can you explain this answer?
The correct increasing order of trans-effect of the following species is
a)
NH3 > CN− >Br− > C6H5−
b)
CN− > C6H5− > Br− > NH3
c)
Br− > CN− > NH3 > C6H5−
d)
CN− > Br− > C6H5− > NH3
|
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EduRev JEE answered |
The intensity of the trans-effect (as measured by the increase in rate of substitution of the trans ligand follows the sequence
CN− > C6H5− > Br− > NH3
The geometry and magnetic behaviour of the complex [Ni(CO)4] are- a)square planar geometry and diamagnetic
- b)tetrahedral geometry and diamagnetic
- c)square planar geometry and paramagnetic
- d)tetrahedral geometry and paramagnetic.
Correct answer is option 'B'. Can you explain this answer?
The geometry and magnetic behaviour of the complex [Ni(CO)4] are
a)
square planar geometry and diamagnetic
b)
tetrahedral geometry and diamagnetic
c)
square planar geometry and paramagnetic
d)
tetrahedral geometry and paramagnetic.
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EduRev JEE answered |
Ni(28):[Ar]3d84s2
∵ CO is a strong field ligand, so, unpaired electrons get paired.
Thus, the complex is sp3 hybridised with tetrahedral geometry and diamagnetic in nature.
An example of a sigma bonded organometallic compound is- a)Grignard's reagent
- b)ferrocene
- c)cobaltocene
- d)ruthenocene.
Correct answer is option 'A'. Can you explain this answer?
An example of a sigma bonded organometallic compound is
a)
Grignard's reagent
b)
ferrocene
c)
cobaltocene
d)
ruthenocene.
|
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EduRev JEE answered |
An example of a sigma bonded organometallic compound is grignard's reagent. Grignard's reagent is represented by R−MgX. An example is methyl magnesium iodide. A sigma bond is present between C atom and Mg atom.
Ethylene diamine tetraacetate (EDTA) ion is :- a)Hexadentate ligand with four "O" and two "N" donor atoms
- b)Unidentate ligand
- c)Bidentate ligand with two "N" donor atoms
- d)Tridentate ligand with three "N" donor atoms
Correct answer is option 'A'. Can you explain this answer?
Ethylene diamine tetraacetate (EDTA) ion is :
a)
Hexadentate ligand with four "O" and two "N" donor atoms
b)
Unidentate ligand
c)
Bidentate ligand with two "N" donor atoms
d)
Tridentate ligand with three "N" donor atoms
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|
EduRev JEE answered |
Ethylene diamine tetraacetate (EDTA) ion is a hexadented ligand having four donor oxygen atoms and two donor nitrogen atoms
Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?- a)SCN-< />− < />− < />2O42
- b)F− < />− < />2O42− < />−
- c)CN− < />2O42−
- d)SCN− < />− < />2O42− < />−
Correct answer is option 'D'. Can you explain this answer?
Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?
a)
SCN-< />− < />− < />2O42
b)
F− < />− < />2O42− < />−
c)
CN− < />2O42−
d)
SCN− < />− < />2O42− < />−
|
|
EduRev JEE answered |
According to spectrochemical series, the order of ligand field strength is
So, correct order is
SCN− < />− < />2O42− < />−
The IUPAC name of the complex- [Ag(H2O)2][Ag(CN)2] is:- a)dicyanidosilver(II) diaquaargentate(II)
- b)diaquasilver(II) dicyanidoargentate(II)
- c)dicyanidosilver(I) diaquaargentate(I)
- d)diaquasilver(I) dicyanidoargentate(I)
Correct answer is option 'D'. Can you explain this answer?
The IUPAC name of the complex- [Ag(H2O)2][Ag(CN)2] is:
a)
dicyanidosilver(II) diaquaargentate(II)
b)
diaquasilver(II) dicyanidoargentate(II)
c)
dicyanidosilver(I) diaquaargentate(I)
d)
diaquasilver(I) dicyanidoargentate(I)
|
|
EduRev JEE answered |
[Ag(H2O)2][Ag(CN)2]
IUPAC name : diaquasilver(I)dicyanidoargentate(I)
On heating a mixture of NH4Cl and KNO2, what is the gas obtained?- a)N2O2
- b)N2
- c)N2O
- d)NO
Correct answer is option 'B'. Can you explain this answer?
On heating a mixture of NH4Cl and KNO2, what is the gas obtained?
a)
N2O2
b)
N2
c)
N2O
d)
NO
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EduRev JEE answered |
Ammonium chloride reacts with potassium nitrite to produce nitrogen gas, potassium chloride and water.
The basicity of H3PO4 may be- a)1
- b)2
- c)3
- d)4
Correct answer is option 'C'. Can you explain this answer?
The basicity of H3PO4 may be
a)
1
b)
2
c)
3
d)
4
|
|
EduRev JEE answered |
The structure of H3PO4 is as
From the structure it is clear that it has 3 P - OH bonds which can produce three H+ ions per molecule of H3PO4 in aqueous solution. Hence, basicity is three.
Aluminium oxide is not reduced by chemical reactions since- a)Aluminium oxide is reactive
- b)Reducing agents contaminate
- c)Aluminium oxide is highly stable
- d)The process pollutes the environment
Correct answer is option 'C'. Can you explain this answer?
Aluminium oxide is not reduced by chemical reactions since
a)
Aluminium oxide is reactive
b)
Reducing agents contaminate
c)
Aluminium oxide is highly stable
d)
The process pollutes the environment
|
|
EduRev JEE answered |
Aluminium oxide is a highly stable oxide of aluminium. Thus, it is chemically inert. Metal oxides can be reduced to the corresponding metal by using a suitable reducing agent. But the choice of the reducing agent depends upon the reactivity of the metal. If the metal to be produced is a very reactive metal like alkali metals, alkaline earth metals and aluminium, then the reduction of the oxide can be done by only the electrolytic method.
The oxides of less reactive metals like zinc, iron etc. are reduced by a number of reducing agents like carbon or coke or carbon monoxide.
This is why aluminium is extracted from its ore bauxite by electrolytic reduction. The bauxite ore is first converted into alumina which is then converted into aluminium by the electrolysis of mixture of alumina and cryolite via the Hall and Heroult process.
|
Bimla Devi
asked a question
|
Light with an average flux of 20 W/cm2 falls on a non-reflecting surface at normal incidence having surface area 20 cm2. The energy received by the surface during time span of 1 minute is:- a)24 × 103 J
- b)48 × 103 J
- c)10 × 103 J
- d)12 × 103 J
Correct answer is option 'A'. Can you explain this answer?
Light with an average flux of 20 W/cm2 falls on a non-reflecting surface at normal incidence having surface area 20 cm2. The energy received by the surface during time span of 1 minute is:
a)
24 × 103 J
b)
48 × 103 J
c)
10 × 103 J
d)
12 × 103 J
Which of the following statements is correct with respect to the property of the elements with increase in atomic number in the carbon family?- a)Their metallic character decreases.
- b)The stability of +2 oxidation state increases.
- c)Their ionisation energy increases.
- d)Their atomic size decreases.
Correct answer is option 'B'. Can you explain this answer?
Which of the following statements is correct with respect to the property of the elements with increase in atomic number in the carbon family?
a)
Their metallic character decreases.
b)
The stability of +2 oxidation state increases.
c)
Their ionisation energy increases.
d)
Their atomic size decreases.
|
|
EduRev JEE answered |
Reluctance in tendency of s-electrons to participate in bonding is called inert pair effect and due to this stability of higher oxidation state increases down the group and that of lower oxidation state increases down the group. Lower oxidation state in carbon family is +2 while higher oxidation state is +4. Thus, stability of +2 oxidation state decreases while that of +4 oxidation state increases... more
Among the following which is the strongest oxidising agent?- a)Br2
- b)I2
- c)Cl2
- d)F2
Correct answer is option 'D'. Can you explain this answer?
Among the following which is the strongest oxidising agent?
a)
Br2
b)
I2
c)
Cl2
d)
F2
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|
EduRev JEE answered |
The halogen which has higher value of standard reduction potential will be the strongest oxidizing agent. Standard reduction potentials of halogens are positive and decrease from fluorine to iodine. So, F2 is the strongest oxidizing agent.
|
Gurjant Kaur
asked a question
|
Identify the wrong statement with reference to immunity: [2020]- a)Active immunity is quick and gives full response
- b)Foetus receives some antibodies from mother, it is an example for passive immunity
- c)When exposed to antigen (living or dead) antibodies are produced in the host’s body. It is called “Active immunity”
- d)When ready made antibodies are directly given, it is called “Passive immunity”.
Correct answer is option 'A'. Can you explain this answer?
Identify the wrong statement with reference to immunity: [2020]
a)
Active immunity is quick and gives full response
b)
Foetus receives some antibodies from mother, it is an example for passive immunity
c)
When exposed to antigen (living or dead) antibodies are produced in the host’s body. It is called “Active immunity”
d)
When ready made antibodies are directly given, it is called “Passive immunity”.
Which element is used in preparation of Pesticides?- a)Nitrogen
- b)Antimony
- c)Bismuth
- d)Arsenic
Correct answer is option 'A'. Can you explain this answer?
Which element is used in preparation of Pesticides?
a)
Nitrogen
b)
Antimony
c)
Bismuth
d)
Arsenic
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|
EduRev JEE answered |
Most pesticides contain elements, the type and number of which depend on the pesticide desired. Chlorine, oxygen, sulfur, phosphorus, nitrogen, and bromine are most common. Inert ingredients can be many substances, dependent on the type of pesticide. Liquid pesticides have traditionally used kerosene or some other petroleum distillate as a carrier, though water has recently begun to replace kerose... more
Aqueous solution of borax acts as a buffer because :- a)It contains weak acid and its salt with strong base
- b)It contains tribasic acid and strong base
- c)It contains number of neutral water molecules
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
Aqueous solution of borax acts as a buffer because :
a)
It contains weak acid and its salt with strong base
b)
It contains tribasic acid and strong base
c)
It contains number of neutral water molecules
d)
None of these
|
|
EduRev JEE answered |
A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.
Aqueous solution of borax tribasic acid (H3BO3) and strong base. It contains weak acid and its salt with strong base.Hence borax act as buffer.
The dissolution of Al(OH)3 by a solution of NaOH results in the formation of which of the following?- a)[Al(H2O)4 (OH)2]+
- b)[Al(H2O)3 (OH)3]
- c)[Al(H2O)2 (OH)4]−
- d)[Al(H2O)6 (OH)3]
Correct answer is option 'C'. Can you explain this answer?
The dissolution of Al(OH)3 by a solution of NaOH results in the formation of which of the following?
a)
[Al(H2O)4 (OH)2]+
b)
[Al(H2O)3 (OH)3]
c)
[Al(H2O)2 (OH)4]−
d)
[Al(H2O)6 (OH)3]
|
|
EduRev JEE answered |
Al(OH)3 dissolves in NaOH solution to give AlOH4- ion which is supposed to have the octahedral complex species [Al(H2O2)(OH)4]- in aqueous solution.
An example of covalent solid is- a)MgO
- b)Mg
- c)SiC
- d)CaF2
Correct answer is option 'C'. Can you explain this answer?
An example of covalent solid is
a)
MgO
b)
Mg
c)
SiC
d)
CaF2
|
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EduRev JEE answered |
SiC is covalent compound also known as carborundum. It has semiconducting properties.
HNO3 acts as- a)Acid
- b)Oxidising agent
- c)Reducing agent
- d)Both (acid) and (oxidising agent)
Correct answer is option 'D'. Can you explain this answer?
HNO3 acts as
a)
Acid
b)
Oxidising agent
c)
Reducing agent
d)
Both (acid) and (oxidising agent)
|
|
EduRev JEE answered |
HNO3 is a strong acid in which N-atom is in its maximum oxidation state +5, so it can act only as oxidising agent not as reducing agent.
Lead oxide (PbO) can be dissolved in- a)H2SO4
- b)HNO3
- c)HCl
- d)H3PO4
Correct answer is option 'B'. Can you explain this answer?
Lead oxide (PbO) can be dissolved in
a)
H2SO4
b)
HNO3
c)
HCl
d)
H3PO4
|
|
EduRev JEE answered |
PbO dissolves in HNO3 as it forms Pb(NO3)2 which is soluble.
Only Iodine forms Hepta-fluoride IF7, but Chlorine and Bromine give Penta-fluorides. The reason for this is :- a)Low electron affinity of Iodine
- b)Unusual pentagonal bipyramidal structure of IF7
- c)That the larger Iodine atom can accommodate more number of smaller Fluorine atom around it
- d)Low chemical reactivity of IF7
Correct answer is option 'C'. Can you explain this answer?
Only Iodine forms Hepta-fluoride IF7, but Chlorine and Bromine give Penta-fluorides. The reason for this is :
a)
Low electron affinity of Iodine
b)
Unusual pentagonal bipyramidal structure of IF7
c)
That the larger Iodine atom can accommodate more number of smaller Fluorine atom around it
d)
Low chemical reactivity of IF7
|
|
EduRev JEE answered |
Due to larger size of iodine atom, it can accommodate up to seven small fluorine atoms around, while due to smaller sizes of chlorine and bromine atoms cannot accommodate seven fluorine atoms, i.e., steric factor dominate in case of chlorine and bromine.
Assertion (A): Noble gases have very low boiling points.Reason (R): All noble gases have general electronic configuration of ns2 np6 (except He)- a)Both (A) and (R) are true but (R) is correct explanation of (A)
- b)(A) is false but (R) is true
- c)(A) is true but (R) is false
- d)Both (A) and (R) are true but (R) is not the correct explanation of (A)
Correct answer is option 'D'. Can you explain this answer?
Assertion (A): Noble gases have very low boiling points.
Reason (R): All noble gases have general electronic configuration of ns2 np6 (except He)
a)
Both (A) and (R) are true but (R) is correct explanation of (A)
b)
(A) is false but (R) is true
c)
(A) is true but (R) is false
d)
Both (A) and (R) are true but (R) is not the correct explanation of (A)
|
|
EduRev JEE answered |
Both (A) and (R) are true but (R) is not the correct explanation of (A)
The melting and boiling points of noble gases are very low in comparison to those of other substances of comparable atomic and molecular masses. This indicates that only weak van der Waals forces or weak London dispersion forces are present between the atoms of the noble gases in the liquid or the solid state.
The van der Waals force increases with the increase in the size of the atom, and therefore, in general, the boiling and melting points increase from He to Rn.
Helium boils at −269 ∘C. Argon has larger mass than helium and have larger dispersion forces. Because of larger size the outer electrons are less tightly held in the larger atoms so that instantaneous dipoles are more easily induced resulting in greater interaction between argon atoms. Therefore, its boiling point (−186 ∘C) is more than that of He.
Similarly, because of increased dispersion forces, the boiling and melting points of monoatomic noble gases increase from helium to radon.
Which of the following is not the function of the respiratory system?- a)Regulate blood pH.
- b)Helps in gaseous exchange.
- c)Contains receptors for the sense of smell.
- d)Protection against blood loss.
Correct answer is option 'D'. Can you explain this answer?
Which of the following is not the function of the respiratory system?
a)
Regulate blood pH.
b)
Helps in gaseous exchange.
c)
Contains receptors for the sense of smell.
d)
Protection against blood loss.
|
Vishal Pasi answered |
A) option is not correct why ? can anyone explain it
All viruses
(a) Contain protein
(b) Contain DNA
(c) Are susceptible to antibiotics
(d) Are intracellular- a)(b) & (c)
- b)(a) & (d)
- c)(a) & (b)
- d)(b) & (d)
Correct answer is option 'B'. Can you explain this answer?
All viruses
(a) Contain protein
(b) Contain DNA
(c) Are susceptible to antibiotics
(d) Are intracellular
(a) Contain protein
(b) Contain DNA
(c) Are susceptible to antibiotics
(d) Are intracellular
a)
(b) & (c)
b)
(a) & (d)
c)
(a) & (b)
d)
(b) & (d)
|
Sourabh Yadav answered |
Because all virus are made up og ptotinand contain either dna Or rnaand are obligete intracellilar parasites
|
Karam Singh
asked a question
|
Which of the following options is incorrect about the larynx (sound box)?- a)It is a bony box.
- b)Glottis is the opening into the larynx.
- c)During swallowing of food glottis is covered by epiglottis to prevent food entry into the larynx.
- d)All of these.
Correct answer is option 'A'. Can you explain this answer?
Which of the following options is incorrect about the larynx (sound box)?
a)
It is a bony box.
b)
Glottis is the opening into the larynx.
c)
During swallowing of food glottis is covered by epiglottis to prevent food entry into the larynx.
d)
All of these.
Chemical reaction: 2 H2 +O2 --> 2 H2O Find the incorrect statement. a) 10L H2 will react with 5L O2 at same T,P. b) 5L O2 will produce 10L H2O at same T,P. c) 10L H2 will produce 10L H2O at 200 'C , 1 atm. d) 5 mol O2 will pr... more
|
Army Lovers answered |
Ans.... is C.....plzz... give feedback right or wrong
An electric dipole of moment p is placed in the position of stable equilibrium in uniform electric field of intensity E. This is rotated through an angle theta from the initial position. The potential energy of the electric dipole in the final position is- a)− pEcosθ
- b)pE (1 − cosθ)
- c)pE cosθ
- d)pE sinθ
Correct answer is option 'B'. Can you explain this answer?
An electric dipole of moment p is placed in the position of stable equilibrium in uniform electric field of intensity E. This is rotated through an angle theta from the initial position. The potential energy of the electric dipole in the final position is
a)
− pEcosθ
b)
pE (1 − cosθ)
c)
pE cosθ
d)
pE sinθ
|
|
EduRev JEE answered |
To orient the dipole at any angle θ from its initial position, work has to be done on the dipole from θ = 0° to θ
∴ Potential energy = pE (1−cosθ)
The given figure gives electric lines of force due to two charges q1 and q2. What are the signs of the two charges?
- a)q1 is positive but q2 is negative
- b)q1 is negative but q2 is positive
- c)both are negative
- d)both are positive.
Correct answer is option 'C'. Can you explain this answer?
The given figure gives electric lines of force due to two charges q1 and q2. What are the signs of the two charges?
a)
q1 is positive but q2 is negative
b)
q1 is negative but q2 is positive
c)
both are negative
d)
both are positive.
|
|
EduRev JEE answered |
Electric lines of force start from the positive charge and end at the negative charge. since the electric lines for both the charges are ending, therefore both q1 and q2 are negative charges.
Point charges +4q,−q and +4q are kept on the X -axis at point x=0,x=a and x=2a respectively. Then- a)only −q is in stable equilibrium
- b)all the charges are in stable equilibrium
- c)all of the charges are in unstable equilibrium
- d)none of the charges is in equilibrium
Correct answer is option 'C'. Can you explain this answer?
Point charges +4q,−q and +4q are kept on the X -axis at point x=0,x=a and x=2a respectively. Then
a)
only −q is in stable equilibrium
b)
all the charges are in stable equilibrium
c)
all of the charges are in unstable equilibrium
d)
none of the charges is in equilibrium
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EduRev JEE answered |
Net force on each of the charge due to the other charges is zero. However, disturbance in any direction other than along the line on which the charges lie, will not make the charges return.
A diamagnetic material in a magnetic field moves- a)from stronger to the weaker parts of the field
- b)from weaker to the stronger parts of the field
- c)perpendicular to the field
- d)in none of the above directions
Correct answer is option 'A'. Can you explain this answer?
A diamagnetic material in a magnetic field moves
a)
from stronger to the weaker parts of the field
b)
from weaker to the stronger parts of the field
c)
perpendicular to the field
d)
in none of the above directions
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EduRev JEE answered |
A diamagnetic material in a magnetic field moves from stronger to the weaker parts of the field
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