Mechanical Engineering
A single point cutting tool with a nose radius of 0.4 mm was used to turn a component in a lathe employing feed rate of 0.3 mm/rev. If the feed rate is doubled, the ideal surface roughness (peak-to-valley height) produced on the components will increase by a factor of[PI 2003]- a)2
- b)4
- c)8
- d)16
Correct answer is option 'B'. Can you explain this answer?
A single point cutting tool with a nose radius of 0.4 mm was used to turn a component in a lathe employing feed rate of 0.3 mm/rev. If the feed rate is doubled, the ideal surface roughness (peak-to-valley height) produced on the components will increase by a factor of
[PI 2003]
a)
2
b)
4
c)
8
d)
16
Constructing Careers answered • 4 hours ago
After introducing slack variables s and t, the initial basic feasible solution is represented by the table below (basic variables are s = 6 and t = 6, and the objective function value is 0).
After some simplex iterations, the following table is obtained
From this, one can conclude that[2008]- a)the LP has a unique optimal solution
- b)the LP has an optimal solution that is not unique
- c)the LP is infeasible
- d)the LP is unbounded
Correct answer is option 'B'. Can you explain this answer?
After introducing slack variables s and t, the initial basic feasible solution is represented by the table below (basic variables are s = 6 and t = 6, and the objective function value is 0).
After some simplex iterations, the following table is obtained
From this, one can conclude that
After some simplex iterations, the following table is obtained
From this, one can conclude that
[2008]
a)
the LP has a unique optimal solution
b)
the LP has an optimal solution that is not unique
c)
the LP is infeasible
d)
the LP is unbounded
Constructing Careers answered • 4 hours agoz = 4x + 6y
3x + 2y ≤ 6
2x + 3y ≤ 6
x, y > 0
3x + 2y ≤ 6
2x + 3y ≤ 6
x, y > 0
Feasible region (O–A–B–C–0) Since, Slope of objective function is equal to the slope of constraint Hence LPP has multiple optimal solution
At B (6/5, 6/5)
Z = 12
At C (0,2)
Z = 12
At B (6/5, 6/5)
Z = 12
At C (0,2)
Z = 12
Sandeep Prajapati asked • 1 minute agoTwo shafts A and B under pure torsion are of identical length and identical weight and are made of the same material. The shaft A is solid and the shaft B is hollow. We can say that- a)shaft B is better than shaft A
- b)shaft A is better than shaft B
- c)both the shafts are equally good
Correct answer is option 'A'. Can you explain this answer?
Two shafts A and B under pure torsion are of identical length and identical weight and are made of the same material. The shaft A is solid and the shaft B is hollow. We can say that
a)
shaft B is better than shaft A
b)
shaft A is better than shaft B
c)
both the shafts are equally good
Assertion (A): A diamond tool is used for USM of glass workpiece.
Reason (R): Diamond is harder than glass[PI 1990]- a)Both A and R are true and R is the correct explanation of A
- b)Both A and R are true but R is not a correct explanation of A
- c)A is true but R is false
- d)A is false but R is true
Correct answer is option 'D'. Can you explain this answer?
Assertion (A): A diamond tool is used for USM of glass workpiece.
Reason (R): Diamond is harder than glass
Reason (R): Diamond is harder than glass
[PI 1990]
a)
Both A and R are true and R is the correct explanation of A
b)
Both A and R are true but R is not a correct explanation of A
c)
A is true but R is false
d)
A is false but R is true
Gate Funda answered • 4 hours agoSoft tool material must be used in order to avoid tool wear.
In orthogonal turning of a cylindrical tube of wall thickness 5 mm, the axial and the tangential cutting forces were measured at 1259 N and 1601 N, respectively. The measured chip thickness after machining was found to be 0.3 mm. The rake angle was 10° and the axial feed was 100 mm/min. The rotational speed of the spindle was 1000 rpm. Assuming the material to be perfectly plastic and merchant’s first solution, the shear strength of the martial is closest to[ME 2019,Set-1]- a)875 M Pa
- b)200 M Pa
- c)722 M Pa
- d)920 M Pa
Correct answer is option 'C'. Can you explain this answer?
In orthogonal turning of a cylindrical tube of wall thickness 5 mm, the axial and the tangential cutting forces were measured at 1259 N and 1601 N, respectively. The measured chip thickness after machining was found to be 0.3 mm. The rake angle was 10° and the axial feed was 100 mm/min. The rotational speed of the spindle was 1000 rpm. Assuming the material to be perfectly plastic and merchant’s first solution, the shear strength of the martial is closest to
[ME 2019,Set-1]
a)
875 M Pa
b)
200 M Pa
c)
722 M Pa
d)
920 M Pa
Gate Funda answered • 4 hours agoFor, orthogonal turning,
λ = 90°, Fc = 1601 N
Chip thickness 'tc' = 0.3,
Ft = 1259 N.
N = 1000 r pm , α = 10 m
= 1601 x cos19.19° - 1259 sin 19.19
= 1098.20 N
λ = 90°, Fc = 1601 N
Chip thickness 'tc' = 0.3,
Ft = 1259 N.
N = 1000 r pm , α = 10 m
= 1601 x cos19.19° - 1259 sin 19.19
= 1098.20 N
A manufacturer produces two types of products, 1 and 2, at production levels of x1 and x2 respectively. The profit is given is 2x1 + 5x2. The production constraints are:
x1 + 3x2 < 40
3x1 + x2 < 24
x1 + x2 < 10
x1 > 0 x2 > 0
The maximum profit which can meet the constraints is[2003]- a)29
- b)38
- c)44
- d)75
Correct answer is option 'C'. Can you explain this answer?
A manufacturer produces two types of products, 1 and 2, at production levels of x1 and x2 respectively. The profit is given is 2x1 + 5x2. The production constraints are:
x1 + 3x2 < 40
3x1 + x2 < 24
x1 + x2 < 10
x1 > 0 x2 > 0
The maximum profit which can meet the constraints is
x1 + 3x2 < 40
3x1 + x2 < 24
x1 + x2 < 10
x1 > 0 x2 > 0
The maximum profit which can meet the constraints is
[2003]
a)
29
b)
38
c)
44
d)
75
Pioneer Academy answered • 4 hours ago
Feasible Region (0– A – B – C– 0) At point (A) 0, 10) Z = 2 (0) + 5 (10) = 50
At point B (7,3) Z = 2(7) + 5(3) = 2y At point C (8, 0) Z = 2(16) + 5(0) = (16) 2
⇒32
Hence maximum profit is Zmax = 50
No correct option is given.
At point B (7,3) Z = 2(7) + 5(3) = 2y At point C (8, 0) Z = 2(16) + 5(0) = (16) 2
⇒32
Hence maximum profit is Zmax = 50
No correct option is given.
Consider the radiation heat exchange inside an annulus between two very long concentric cylinders. The radius of the outer cylinder is R0 and that of the inner cylinder is Ri. The radiation view factor of the outer cylinder onto itself is[2016]- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
Consider the radiation heat exchange inside an annulus between two very long concentric cylinders. The radius of the outer cylinder is R0 and that of the inner cylinder is Ri. The radiation view factor of the outer cylinder onto itself is
[2016]
a)
b)
c)
d)
Pioneer Academy answered • 4 hours ago
View factor
F1– 1 = 0
F1– 2 = 1
Reciprocacy theorem
A 2F 2– 1 = A 1F 1– 2
⇒
F2– 1 + F2– 2 = 1
∴ F2– 2 = 1 – F2– 1 = 1 - Ri/Ro
Details pertaining to an orthogonal metal cutting process are given below:
Chip thickness ratio 0.4
Undeformed thickness 0.6 mm
Rake angle +10°
Cutting speed 2.5 m/s
Mean thickness of primary shear zone 25 microns
The shear strain rate in s-1 during the process is[PI 2012]- a)0.1781 × 105
- b)0.7754 × 105
- c)1.0104 × 105
- d)4.397 × 105
Correct answer is option 'C'. Can you explain this answer?
Details pertaining to an orthogonal metal cutting process are given below:
Chip thickness ratio 0.4
Undeformed thickness 0.6 mm
Rake angle +10°
Cutting speed 2.5 m/s
Mean thickness of primary shear zone 25 microns
The shear strain rate in s-1 during the process is
Chip thickness ratio 0.4
Undeformed thickness 0.6 mm
Rake angle +10°
Cutting speed 2.5 m/s
Mean thickness of primary shear zone 25 microns
The shear strain rate in s-1 during the process is
[PI 2012]
a)
0.1781 × 105
b)
0.7754 × 105
c)
1.0104 × 105
d)
4.397 × 105
Manish Aggarwal answered • 4 hours ago
Feed rate in slab milling operation is equal to[ME 2018,Set-2]- a)rotation per minute (rpm)
- b)product of rpm and number of teeth in the cutter
- c)product of rpm, feed per tooth and number of teeth in the cutter
- d)product of rpm, feed per tooth and number of teeth in contact
Correct answer is option 'C'. Can you explain this answer?
Feed rate in slab milling operation is equal to
[ME 2018,Set-2]
a)
rotation per minute (rpm)
b)
product of rpm and number of teeth in the cutter
c)
product of rpm, feed per tooth and number of teeth in the cutter
d)
product of rpm, feed per tooth and number of teeth in contact
Manish Aggarwal answered • 4 hours agoTable feed or Feed rate
In a typical metal cutting operation, using a cutting tool a positive rake a = 10°, it is as observed that the shear angle was 20°. The friction angle is[ME 1997]- a)45°
- b)30°
- c)60°
- d)40°
Correct answer is option 'C'. Can you explain this answer?
In a typical metal cutting operation, using a cutting tool a positive rake a = 10°, it is as observed that the shear angle was 20°. The friction angle is
[ME 1997]
a)
45°
b)
30°
c)
60°
d)
40°
Pathways Academy answered • 4 hours agoα = 10°, ϕ= 20°
Ernest & Merchants' theory
2ϕ + β - α = 90°
2 × 20 + β - 10 = 90°
40 + β - 10 = 90°
β = 60°
Ernest & Merchants' theory
2ϕ + β - α = 90°
2 × 20 + β - 10 = 90°
40 + β - 10 = 90°
β = 60°
In a counterflow heat exchanger, hot fluid enters at 60°C and cold fluid leaves at 30°C. Mass flow rate of the hot fluid is 1 kg/s and that the cold fluid is 2 kg/s. Specific heat of the hot fluid is 10 kJ/kgK and that of the cold fluid is 5 kJ/kgK. The Log Mean Temperature Difference (LMTD) for the heat exchanger in °C is[2007]- a)15
- b)30
- c)35
- d)45
Correct answer is option 'B'. Can you explain this answer?
In a counterflow heat exchanger, hot fluid enters at 60°C and cold fluid leaves at 30°C. Mass flow rate of the hot fluid is 1 kg/s and that the cold fluid is 2 kg/s. Specific heat of the hot fluid is 10 kJ/kgK and that of the cold fluid is 5 kJ/kgK. The Log Mean Temperature Difference (LMTD) for the heat exchanger in °C is
[2007]
a)
15
b)
30
c)
35
d)
45
Pathways Academy answered • 4 hours agoHeat capacity of hot fluid
= 1 × 10 = 10 kJ / k – s
Heat capacity of cold fluid
= 2 × 5 = 10 kJ / k – s
Since heat capacity is same, so LMTD is difference of temperature at either end
i.e. LMTD = 60º – 30º = 30º C
= 1 × 10 = 10 kJ / k – s
Heat capacity of cold fluid
= 2 × 5 = 10 kJ / k – s
Since heat capacity is same, so LMTD is difference of temperature at either end
i.e. LMTD = 60º – 30º = 30º C
Abhishek Govil asked • 26 minutes agoIn the design of shafts made of ductile materials subjected to twisting moment and bendingmoment, the recommended theory of failure is- a)maximum principal stress theory
- b)maximum principal strain theory
- c)maximum shear stress theory
- d)maximum strain – energy theory
Correct answer is option 'C'. Can you explain this answer?
In the design of shafts made of ductile materials subjected to twisting moment and bendingmoment, the recommended theory of failure is
a)
maximum principal stress theory
b)
maximum principal strain theory
c)
maximum shear stress theory
d)
maximum strain – energy theory
Ankur Pandey asked • 44 minutes agoWhich one of the following loadings is considered for design of axles ?
- a) Bending moment only
- b) Twisting moment only
- c) Combined bending moment and torsion
- d) Combined action of bending moment, twisting moment and axial thrust
Correct answer is option 'A'. Can you explain this answer?
Which one of the following loadings is considered for design of axles ?
a)
Bending moment onlyb)
Twisting moment onlyc)
Combined bending moment and torsiond)
Combined action of bending moment, twisting moment and axial thrust 
Daniyal Zahid asked • 2 hours agoFor the double long shoe, external drum brake illustrated in the figure (All dimensions are in mm), the face width of the shoes is 30 mm. the coefficient of friction between the shoe and the drum can be taken as 0.28.
Q.Determine the actuation load on the left-had shoe when the pressure on the brake lining does not exceed 1.4 MPa- a) 3961 N
- b) 3266 N
- c) 1243 N
- d) 2004 N
Correct answer is option 'D'. Can you explain this answer?
For the double long shoe, external drum brake illustrated in the figure (All dimensions are in mm), the face width of the shoes is 30 mm. the coefficient of friction between the shoe and the drum can be taken as 0.28.
Q.
Determine the actuation load on the left-had shoe when the pressure on the brake lining does not exceed 1.4 MPa
a)
3961 N
b)
3266 N
c)
1243 N
d)
2004 N
Mantu Das asked • 2 hours agoA medium carbon steel workpiece is turned on a lath at 50 m/ min cutting speed, 0.8 mm/ revfeed and 1.5 mm depth of cut, what is the rate of metal removal- a)100 mm3/ min
- b)20000 mm3/min
- c)60000 mm3/ min
- d)Can not be calculated with the given data
Correct answer is option 'C'. Can you explain this answer?
A medium carbon steel workpiece is turned on a lath at 50 m/ min cutting speed, 0.8 mm/ revfeed and 1.5 mm depth of cut, what is the rate of metal removal
a)
100 mm3/ min
b)
20000 mm3/min
c)
60000 mm3/ min
d)
Can not be calculated with the given data
Shivam Saxena asked • 2 hours agoConsider the following statements: 1. The degree of freedom for lower kinematic pairs is always equal to one.
2. A ball-and-socket joint has 3 degrees of freedom and is a higher kinematic pair
3.Oldham's coupling mechanism has two prismatic pairs and two revolute pairs.Which of the statements given above is/are correct?[IES-2005]- a)1, 2 and 3
- b)1 only
- c)2 and 3
- d)3 only
Correct answer is option 'A'. Can you explain this answer?
Consider the following statements:
1. The degree of freedom for lower kinematic pairs is always equal to one.
2. A ball-and-socket joint has 3 degrees of freedom and is a higher kinematic pair
3.Oldham's coupling mechanism has two prismatic pairs and two revolute pairs.
2. A ball-and-socket joint has 3 degrees of freedom and is a higher kinematic pair
3.Oldham's coupling mechanism has two prismatic pairs and two revolute pairs.
Which of the statements given above is/are correct?
[IES-2005]
a)
1, 2 and 3
b)
1 only
c)
2 and 3
d)
3 only
Aadarsh Vikram asked • 3 hours agoConsider the following two processes:a. A heat source at 1200 K loses 2500 kJ of heat to sink at 800 Kb. A heat source at 800 K loses 2000 kJ of heat to sink at 500 KWhich of the following statements is TRUE?- a)Process I is more irreversible than Process II
- b)Process II is more irreversible than Process I
- c)Irreversibility associated in both the processes is equal
- d)Both the processes are reversible
Correct answer is option 'B'. Can you explain this answer?
Consider the following two processes:
a. A heat source at 1200 K loses 2500 kJ of heat to sink at 800 K
b. A heat source at 800 K loses 2000 kJ of heat to sink at 500 K
Which of the following statements is TRUE?
a)
Process I is more irreversible than Process II
b)
Process II is more irreversible than Process I
c)
Irreversibility associated in both the processes is equal
d)
Both the processes are reversible
SATYA KUMARI asked • 3 hours agoTwo plates of the same metal having equal thickness are to be butt welded with electric arc.When the plate thickness changes, welding is achieved by[ME 2002]- a)Adjusting the current
- b)Adjusting the duration of the current
- c)Changing the electrode size
- d)Changing the electrode coating
Correct answer is option 'A'. Can you explain this answer?
Two plates of the same metal having equal thickness are to be butt welded with electric arc.When the plate thickness changes, welding is achieved by
[ME 2002]
a)
Adjusting the current
b)
Adjusting the duration of the current
c)
Changing the electrode size
d)
Changing the electrode coating
SINGH AMIT asked • 3 hours agoThe strength of a brazed joint[ME 2005]- a)decreases with increase in gap between the two joining surfaces
- b)increases with increase in gap between the two joining surfaces
- c)decreases up to certain gap between the two joining surfaces beyond which it increases
- d)increases up to certain gap between the two joining surfaces beyond which it decreases
Correct answer is option 'D'. Can you explain this answer?
The strength of a brazed joint
[ME 2005]
a)
decreases with increase in gap between the two joining surfaces
b)
increases with increase in gap between the two joining surfaces
c)
decreases up to certain gap between the two joining surfaces beyond which it increases
d)
increases up to certain gap between the two joining surfaces beyond which it decreases
PREM DEVI asked • 3 hours agoPenetration is increased by[ME 1990]- a)Increasing welding current and welding speed
- b)Increasing welding current and decreasing welding speed
- c)Decreasing welding current and welding speed
- d)Decreasing welding current and increasing welding speed
Correct answer is option 'B'. Can you explain this answer?
Penetration is increased by
[ME 1990]
a)
Increasing welding current and welding speed
b)
Increasing welding current and decreasing welding speed
c)
Decreasing welding current and welding speed
d)
Decreasing welding current and increasing welding speed
ASIF HABIB asked • 3 hours agoIn an arc welding process, the voltage and current are 25 V and 300 A respectively. The arc heat transfer efficiency is 0.85 and welding speed is 8 mm/s. The net heat input (in J/mm) is[ME 2006]- a)64
- b)797
- c)1103
- d)79700
Correct answer is option 'B'. Can you explain this answer?
In an arc welding process, the voltage and current are 25 V and 300 A respectively. The arc heat transfer efficiency is 0.85 and welding speed is 8 mm/s. The net heat input (in J/mm) is
[ME 2006]
a)
64
b)
797
c)
1103
d)
79700
DEBARSHI HALDER asked • 3 hours agoIn an arc welding process, welding speed is doubled. Assuming all other process parameters to be constant, the cross sectional area of the weld bead will[ME 2017,Set-1]- a)increase by 25%
- b)increase by 50%
- c)reduce by 25%
- d)reduce by 50%
Correct answer is option 'D'. Can you explain this answer?
In an arc welding process, welding speed is doubled. Assuming all other process parameters to be constant, the cross sectional area of the weld bead will
[ME 2017,Set-1]
a)
increase by 25%
b)
increase by 50%
c)
reduce by 25%
d)
reduce by 50%
PRIYANKA KAPOOR asked • 3 hours agoDuring a steady gas metal arc welding with direct current electrode positive polarity, the welding current, voltage and weld speed are 150 A, 30 V and 6 m/min respectively. A metallic wire electrode of diameter 1.2 mm is being fed at a constant rate of 12 m/min. The density, specific heat and melting temp of the wire electrode are 7000 kg/m3, 500 J/kg and 1530°C respectively.
Assume the ambient temp to be 30°C and neglect the latent heat of melting. Further consider that 2/3rd of the total electrical power is available for melting of the wire electrode. The melting efficiency (in percentage) of the wire electrode is[PI 2010]- a)39.58
- b)45.25
- c)49.38
- d)54.98
Correct answer is option 'A'. Can you explain this answer?
During a steady gas metal arc welding with direct current electrode positive polarity, the welding current, voltage and weld speed are 150 A, 30 V and 6 m/min respectively. A metallic wire electrode of diameter 1.2 mm is being fed at a constant rate of 12 m/min. The density, specific heat and melting temp of the wire electrode are 7000 kg/m3, 500 J/kg and 1530°C respectively.
Assume the ambient temp to be 30°C and neglect the latent heat of melting. Further consider that 2/3rd of the total electrical power is available for melting of the wire electrode. The melting efficiency (in percentage) of the wire electrode is
Assume the ambient temp to be 30°C and neglect the latent heat of melting. Further consider that 2/3rd of the total electrical power is available for melting of the wire electrode. The melting efficiency (in percentage) of the wire electrode is
[PI 2010]
a)
39.58
b)
45.25
c)
49.38
d)
54.98
KANCHAN KUMARI asked • 3 hours agoFor butt welding 40 mm thick steel plates, when the expected quantity of such jobs is 5000 per month over a period of 10 years, choose the best suitable welding process out of the following available alternatives.[ME 1999]- a)SAW
- b)Oxyacetylene gas welding
- c)EBM
- d)MIG
Correct answer is option 'A'. Can you explain this answer?
For butt welding 40 mm thick steel plates, when the expected quantity of such jobs is 5000 per month over a period of 10 years, choose the best suitable welding process out of the following available alternatives.
[ME 1999]
a)
SAW
b)
Oxyacetylene gas welding
c)
EBM
d)
MIG
PRABAL RATHOUR asked • 3 hours agoIn a DC arc welding operation, the voltage-arc length characteristic was obtained as Varc = 20 + 5l where the arc length l was varied between 5 mm and 7 mm. Here Varc denotes the arc voltage in Volts. The arc current was varied from 400 A to 500 A. Assuming linear power source characteristic, the open circuit voltage and the short circuit current for the welding operation are[ME 2012]- a)45 V, 450 A
- b)75 V, 750 A
- c)95 V, 950 A
- d)150 V, 1500 A
Correct answer is option 'C'. Can you explain this answer?
In a DC arc welding operation, the voltage-arc length characteristic was obtained as Varc = 20 + 5l where the arc length l was varied between 5 mm and 7 mm. Here Varc denotes the arc voltage in Volts. The arc current was varied from 400 A to 500 A. Assuming linear power source characteristic, the open circuit voltage and the short circuit current for the welding operation are
[ME 2012]
a)
45 V, 450 A
b)
75 V, 750 A
c)
95 V, 950 A
d)
150 V, 1500 A
SHAWETA KUMARI asked • 3 hours agoWhich of the following process can be used for welding of Aluminum alloys?
P. Submerged arc welding
Q. Gas metal arc welding
R. Electroslag welding
S. Gas tungsten arc welding[PI 2003]- a)P and Q
- b)Q and S
- c)Q and R
- d)R and S
Correct answer is option 'B'. Can you explain this answer?
Which of the following process can be used for welding of Aluminum alloys?
P. Submerged arc welding
Q. Gas metal arc welding
R. Electroslag welding
S. Gas tungsten arc welding
P. Submerged arc welding
Q. Gas metal arc welding
R. Electroslag welding
S. Gas tungsten arc welding
[PI 2003]
a)
P and Q
b)
Q and S
c)
Q and R
d)
R and S
Mayur Chawla asked • 3 hours agoTo restore stable operating condition in a hydrodynamic journal bearing, when it encounters higher magnitude loads, - a)Oil viscosity is to be decreased
- b)oil viscosity is to be increased
- c)Oil viscosity index is to be increased
- d)oil viscosity index is to be decreased
Correct answer is option 'B'. Can you explain this answer?
To restore stable operating condition in a hydrodynamic journal bearing, when it encounters higher magnitude loads,
a)
Oil viscosity is to be decreased
b)
oil viscosity is to be increased
c)
Oil viscosity index is to be increased
d)
oil viscosity index is to be decreased
Rubi Kumari asked • 4 hours agoThe practice to use steam on the shell side and water on the tube side in condensers of steam power plant is because[1994]- a)to increase overall HT coefficient, water side velocity can be increased if water is on the tube side
- b)condenser can act as a Storage unit for condensed steam
- c)rate of condensation of steam is invariably smaller than the mass flow rate of cooling water
- d)it is easier to maintain vacuum on the shell side than on the tube side
Correct answer is option 'D'. Can you explain this answer?
The practice to use steam on the shell side and water on the tube side in condensers of steam power plant is because
[1994]
a)
to increase overall HT coefficient, water side velocity can be increased if water is on the tube side
b)
condenser can act as a Storage unit for condensed steam
c)
rate of condensation of steam is invariably smaller than the mass flow rate of cooling water
d)
it is easier to maintain vacuum on the shell side than on the tube side
Gokul Krishnan asked • 5 hours agoConsider the following operations involved in forging a hexagonal bolt from a round bar stock, whose diameter is equal to the bolt diameter:
1. Flattening 2. Upsetting 3. Swaging 4. CamberingQ.The correct sequence of these operations is- a)1, 2, 3, 4
- b)2, 3, 4, 1
- c)2, 1, 3, 4
- d)3, 2, 1, 4
Correct answer is option 'A'. Can you explain this answer?
Consider the following operations involved in forging a hexagonal bolt from a round bar stock, whose diameter is equal to the bolt diameter:
1. Flattening 2. Upsetting 3. Swaging 4. Cambering
1. Flattening 2. Upsetting 3. Swaging 4. Cambering
Q.
The correct sequence of these operations is
a)
1, 2, 3, 4
b)
2, 3, 4, 1
c)
2, 1, 3, 4
d)
3, 2, 1, 4
Amulya Das asked • 5 hours agoThe COP of a heat pump can be increased either by decreasing TH by ΔT or by increasing TL by ΔT. The new COP of the heat pump is- a)same in both the cases
- b)highest if TH is decreased
- c)highest it TL in in increased
- d)independent of change in TH and TL
Correct answer is option 'C'. Can you explain this answer?
The COP of a heat pump can be increased either by decreasing TH by ΔT or by increasing TL by ΔT. The new COP of the heat pump is
a)
same in both the cases
b)
highest if TH is decreased
c)
highest it TL in in increased
d)
independent of change in TH and TL
aravinth chinnadurai asked • 5 hours agoConsider the following parameter:
1. Oil pressure
2. Bearing metal temperature
3. Drain oil temperature
4. Bearing vibration
5. Friction coefficienWhich of the above should be monitored for determining safe operation of journal bearing?- a)1,2 and 3
- b)1,2, 3 and 4
- c)1, 2, 3 and 5
- d)All of the above
Correct answer is option 'B'. Can you explain this answer?
Consider the following parameter:
1. Oil pressure
2. Bearing metal temperature
3. Drain oil temperature
4. Bearing vibration
5. Friction coefficien
1. Oil pressure
2. Bearing metal temperature
3. Drain oil temperature
4. Bearing vibration
5. Friction coefficien
Which of the above should be monitored for determining safe operation of journal bearing?
a)
1,2 and 3
b)
1,2, 3 and 4
c)
1, 2, 3 and 5
d)
All of the above
ANKIT KUMAR asked • 6 hours agoA component can be produced by any of the four processes I, II, III and IV. The fixed cost and the variable cost for each of the processes are listed below. The most economical process for producing a batch of 100 pieces is[2014]- a)I
- b)II
- c)III
- d)IV
Correct answer is option 'B'. Can you explain this answer?
A component can be produced by any of the four processes I, II, III and IV. The fixed cost and the variable cost for each of the processes are listed below. The most economical process for producing a batch of 100 pieces is
[2014]
a)
I
b)
II
c)
III
d)
IV
ANSHAD M asked • 6 hours ago When the annual demand of a product is 24000 units, the EOQ (Economic Order Quantity) is 2000 units. If the annual demand is 48000 units the most appropriate EOQ will be[1991]- a)1000 units
- b)2000 units
- c)2800 units
- d)4000 units
Correct answer is option 'D'. Can you explain this answer?
When the annual demand of a product is 24000 units, the EOQ (Economic Order Quantity) is 2000 units. If the annual demand is 48000 units the most appropriate EOQ will be
[1991]
a)
1000 units
b)
2000 units
c)
2800 units
d)
4000 units
MANENDRA KUMAR asked • 6 hours agoIn machine shop, pins of 15 mm diameter are produced at a rate of 1000 per month and the same is consumed at a rate of 500 per month.The production and consumption continue simultaneously till the maximum inventory is reached. Then inventory is allowed to reduce to zero due to consumption. The lot size of production is 1000. If backlog is not allowed, the maximum inventory level is[2007]- a)400
- b)500
- c)600
- d)700
Correct answer is option 'B'. Can you explain this answer?
In machine shop, pins of 15 mm diameter are produced at a rate of 1000 per month and the same is consumed at a rate of 500 per month.The production and consumption continue simultaneously till the maximum inventory is reached. Then inventory is allowed to reduce to zero due to consumption. The lot size of production is 1000. If backlog is not allowed, the maximum inventory level is
[2007]
a)
400
b)
500
c)
600
d)
700
KARISHMA THAKUR asked • 6 hours agoThe diameter and rotational speed of a job are 100 m and 500 rpm respectively. The high spots (chatter marks) are found at a spacing of 30 deg on the job surface. The chatter frequency is[PI 1990]- a)5 Hz
- b)12 Hz
- c)100 Hz
- d)500 Hz
Correct answer is option 'C'. Can you explain this answer?
The diameter and rotational speed of a job are 100 m and 500 rpm respectively. The high spots (chatter marks) are found at a spacing of 30 deg on the job surface. The chatter frequency is
[PI 1990]
a)
5 Hz
b)
12 Hz
c)
100 Hz
d)
500 Hz
SANDEEP MAHARANA asked • 6 hours agoA 60 deg symmetrical V tool is used in shaping at workpiece with a depth of cut of 0.1 mm and feed of 0.1 mm/stroke. The theoretical peak to valley height, in mm, of the surface produced is[PI 1995]- a)0.043
- b)0.067
- c)0.086
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
A 60 deg symmetrical V tool is used in shaping at workpiece with a depth of cut of 0.1 mm and feed of 0.1 mm/stroke. The theoretical peak to valley height, in mm, of the surface produced is
[PI 1995]
a)
0.043
b)
0.067
c)
0.086
d)
None of these
POOJA KUMARI asked • 6 hours agoA job of the shape shown in the figure below is to be machined on a lathe. The tool best suited for machining of this job must have
[PI 2004]- a)positive side rake angle
- b)positive back rake angle
- c)positive cutting edge inclination angle
- d)negative cutting edge inclination angle
Correct answer is option 'A'. Can you explain this answer?
A job of the shape shown in the figure below is to be machined on a lathe. The tool best suited for machining of this job must have
[PI 2004]
a)
positive side rake angle
b)
positive back rake angle
c)
positive cutting edge inclination angle
d)
negative cutting edge inclination angle
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