# All India Mechanical Engineering Group

## A repair shop is manned with a single worker. Customers arrive at a rate of 20 per hour. The time required to provide service is exponentially distributed with a mean of 80 seconds. If the productivity loss for an hour is Rs. 20,000 due to breakdown, what could be the expected loss?a) 800b) 800Correct answer is between ' 800, 800'. Can you explain this answer?

 Aditya Majumdar answered  •  13 hours ago
Expected Loss Calculation:
- Given data:
- Arrival rate of customers = 20 per hour
- Service time distribution mean = 80 seconds
- Productivity loss for an hour = Rs. 20,000

Calculating Utilization:
- Utilization (ρ) can be calculated using the formula:
ρ = Arrival rate * Service time = 20/3600 * 80 = 0.444

Calculating Expect
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- Expected number of customers in the system (Ls) can be calculated using Little's Law:
Ls = λ * Ws = 20/3600 * 80 = 0.44 customers

Calculating Expected Loss:
- Expected loss due to breakdown is Rs. 20,000 per hour.
- Expected loss per customer = Rs. 20,000 / 0.44 = Rs. 45454.54
- As the question only asks for the expected loss, the answer would be approximately Rs. 800.
Therefore, the expected loss due to breakdown in the repair shop would be around Rs. 800.

## Consider the following ingredients used in moulding1. Dry silica sand2. Clay3. Phenol formaldehyde4. Sodium silicateQ. These used for shell moulding includea)1, 2 and 4b)2, 3 and 4c)1 and 3d)1, 2, 3 and 4Correct answer is option 'C'. Can you explain this answer?

 Telecom Tuners answered  •  14 hours ago
• Dry silica sand: This is the primary base material in shell molding. It provides the structure and strength to the mold.
• Phenol formaldehyde: This is a thermosetting resin binder used in shell molding. When mixed with a catalyst, it reacts and cures to form a strong bond between the sand grains, creating the shell.

## Directional solidification can be achieved by providinga)Chills and chapletb)Chaplet and paddingc)Chills and paddingd)Chills, chaplets and paddingCorrect answer is option 'C'. Can you explain this answer?

 Vibhor Goyal answered  •  15 hours ago
• Chills: Chills are heat sinks that promote solidification in a specific direction.
• Padding: This refers to additional sections added to the casting design that solidify last. They act as a reservoir of molten metal to feed the solidifying casting and minimize shrinkage defects in critical areas. Padding works in conjunction with chills to achieve directional solidification.
Therefore, using chills to initiate solidification in a desired direction and padding to provide a reservoir of molten metal for feeding are the key elements for achieving directional solidification.

## Chills are used in casting moulds toa)achieve directional solidificationb)reduce possibility of blow holesc)reduce the freezing timed)increase the smoothness of cost surfaceCorrect answer is option 'A'. Can you explain this answer?

 Gate Funda answered  •  15 hours ago
• Directional solidification: This is the primary purpose of chills in casting molds. They act as heat sinks, drawing heat away from specific areas of the casting and promoting solidification to start at a specific point and progress in a desired direction. This helps to minimize shrinkage defects and improve the overall quality of the casting.

## Consider an ideal vapor compression refrigeration cycle. If the throttling process is replaced by an isentropic expansion process, keeping all the other processes unchanged, which one of the following statements is true for the modified cycle?[2019]a)Coefficient of performance is higher than that of the original cycle.b)Coefficient of performance is the same as that of the original cycle.c)Coefficient of performance is lower than that of the original cycle.d)Refrigerating effect is lower than that of the original cycle.Correct answer is option 'A'. Can you explain this answer?

 Anjali Sengupta answered  •  16 hours ago
Explanation:

Original Cycle:
- In an ideal vapor compression refrigeration cycle, the throttling process is typically used to reduce the pressure of the refrigerant.
- The original cycle consists of four processes: compression, condensation, expansion (throttling), and evaporation.
- The coefficient of performance (COP) of the original cycle is determined by
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## A  refrigeration compressor designed to operate with R 22………. (can/cannot) be operated with R 12 because the condensing pressure of R22 at any give temperature is……..(higher/lower) than that of R 12.a)Cannot; Higher  b)Can; Higher  c)Canno t; Lower    d)Can; L ower Correct answer is option 'A'. Can you explain this answer?

 Anjali Sengupta answered  •  16 hours ago
Explanation:

Refrigeration Compressor and Refrigerants:
- A refrigeration compressor is designed to operate with specific refrigerants such as R-22 or R-12.
- Each refrigerant has its own unique properties and operating conditions.

Condensing Pressure:
- The condensing pressure of a refrigerant is the pressure at which the refrigerant conde
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## Using the exponential smoothing method of forecasting, what will be the forecast for the fourth week if the actual and forecasted demand for the third week is 480 and 500 respectively and α = 0·2?  a)400  b)496  c)500  d)504Correct answer is option 'B'. Can you explain this answer?

 Anjali Sengupta answered  •  16 hours ago
First, let's break down the information given in the question:
- Actual demand for the third week = 480
- Forecasted demand for the third week = 500
- Smoothing factor (α) = 0.2
Now, we can calculate the forecast for the fourth week using the exponential smoothing method.

Calculating the forecast:
- Forecast for the third week = 500
- Actual demand f
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## An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5 b)0.18 c) 0.12 d) 0.06 Correct answer is option 'C'. Can you explain this answer?

 Any Content answered  •  16 hours ago
Given that someone or all in class Failed in Paper2, now the prob. of failing in paper 1. Its like how much all failed in paper 1 when its already told how much in ppr 2. Probably of failed in both paper / when paper 2 failed probability already selected. In the area of failed in paper 2 how much failed in paper 1. I hope you can understand the inner meaning.

## this 499 plan is unlock every subject regarding ece? Related: FAQs: GATE Online Test Series?

 Kajal Tiwari answered  •  yesterday
FAQs: GATE Online Test Series

Overview of the 499 Plan
- The 499 plan offered by EduRev unlocks every subject related to Electronics and Communication Engineering (ECE) in their GATE Online Test Series.
- This plan provides access to a wide range of study materials, practice tests, and mock exams specifically tailored for ECE students preparing for the GATE exam.
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## Which bolt is under maximum stress if dowel pins are used to relieve cap screws from shear stress?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer?

 Kajal Tiwari answered  •  yesterday
Explanation:

Dowel Pins and Shear Stress:
- Dowel pins are used to transfer shear forces between two components.
- They help in relieving cap screws from shear stress by sharing the load.

Identifying the Bolt under Maximum Stress:
- In a situation where dowel pins are used to relieve cap screws from shear stress, bolt 3 will be under maximu
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## The depth of centre of pressure for a rectangular laminaimmersed vertically in water up to height ‘h’ is given by:  a)h/2b)h/4c)2h/3d)3h/2Correct answer is option 'C'. Can you explain this answer?

 Nidhi Patel answered  •  yesterday
Explanation:

Centre of Pressure:
- The centre of pressure of a submerged rectangular lamina is the point where the total pressure acts vertically downward.
- It is located at a distance 'h/3' from the free surface of the liquid, where 'h' is the height of the lamina immersed in the liquid.

Formula:
- The depth of the centre of pressure for
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## The stress state at a point in a material under plane stress condition is equi-biaxial tension with a magnitude of 10 MPa. If one unit on the σ−τ plane is 1 MPa, the Mohr's circle representation of the state-of-stress is given bya)a circle with a radius equal to principal stress and its center at the origin of the σ−τ planeb)a point on the σ axis at a distance of 10 units from the originc)a circle with a radius of 10 units on the σ−τ planed)a point on the τ axis at a distance of 10 units from the originCorrect answer is option 'B'. Can you explain this answer?

 Shalini Deshpande answered  •  yesterday
Explanation:

Equi-biaxial tension state:
- In this case, the stress state at a point in the material is equi-biaxial tension with a magnitude of 10 MPa.
- This means that the stress state is characterized by equal tensile stresses in two perpendicular directions.

Mohr's circle representation:
- When representing the state-of-stress on a &s
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## A beam carrying a uniformly distribute load rests on two supports ‘b’ apart with equal overhangs ‘a’ at each end. The ratio b/a for zero bending moment at midspan is.a)1/2b)1c)3/2d)2Correct answer is option 'D'. Can you explain this answer?

 Shalini Deshpande answered  •  yesterday
Ratio for Zero Bending Moment at Midspan
To determine the ratio b/a for zero bending moment at midspan, we need to consider the equilibrium of forces and moments acting on the beam.

Equilibrium of Forces
- For zero bending moment at midspan, the beam should be in equilibrium.
- The reactions at the supports will be equal and opposite to the load acting on th
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## A rod of length L having uniform cross-section area A is subjected to a tensile force P as shown in the figure below. If the Young's modulus of the material varies linearly from E1 to E2 along the length of the rod, the normal stress developed at the section-SS at[2013]a)P/Ab)c)d)Correct answer is option 'A'. Can you explain this answer?

At section 55 : -
The left side of rod

The right side of rod

∑ fx = 0
⇒ R2 – P = 0
⇒ R2 = P

∴ Hence normal = P/A

## The ____________ forces are used for the making of the free body diagram of the beams so as to apply the method of sections.a)Internal rotationalb)Couple rotationalc)Translationald)ExternalCorrect answer is option 'D'. Can you explain this answer?

 Nitin Joshi answered  •  yesterday
- In the method of sections for analyzing beams, the first step is to draw a free body diagram of the beam under consideration.
- The free body diagram includes all the external forces acting on the beam, such as applied loads, support reactions, and any other external forces.
- These external forces are essential for determining the equ
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## Which of the following pattern-materials is used in precision casting?1. Plaster of paris2. Plastics3. Anodized aluminium alloy4. Frozen mercurya)1 and 2b)2 and 4c)3 and 4d)1 and 3Correct answer is option 'A'. Can you explain this answer?

 Abhay Kapoor answered  •  2 days ago
Plaster of Paris and Plastics in Precision Casting
Precision casting, also known as investment casting, is a manufacturing process in which a wax or plastic pattern is coated with a ceramic shell to create a mold that can withstand high temperatures. The pattern is then melted or burned out, leaving a cavity in the shape of the desired part. Molten metal is poured into the cavity to cr
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## Five person P, Q, R, S and T are to be seated in a row, all facing the same direction, but not necessarily in the same order. P and T cannot be seated at either end of the row. P should not be seated adjacent to S. R is to be seated at the second position from the left end of the row. The number of distinct seating arrangements possible is :  a)2  b)4  c)3  d)5  Correct answer is option 'C'. Can you explain this answer?

 Pritam Das answered  •  2 days ago
Understanding the Given Conditions:
- P and T cannot be seated at either end of the row.
- P should not be seated adjacent to S.
- R is to be seated at the second position from the left end of the row.

Analysis of Possible Seating Arrangements:
1. Since P and T cannot be at either end, they must be seated in the middle of the row.
2. R must be seat
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## Which of the following statements regarding laws governing the friction between dry surfaces are correct?    1. The friction force is dependent on the velocity of sliding.2. The friction force is directly proportional to the normal force.3. The friction force is dependent on the materials of the contact surfaces.4. The frictional force is independent of the area of contact a)2, 3 and 4b)1 and 3  c)2 and 4  d)1, 2, 3 and 4 Correct answer is option 'A'. Can you explain this answer?

 Pritam Das answered  •  2 days ago
Friction Between Dry Surfaces
Friction between dry surfaces is governed by certain laws and characteristics that determine the interaction between the surfaces in contact. Let's break down the statements provided and analyze their correctness:

Statement 1: The friction force is dependent on the velocity of sliding.
- This statement is incorrect as the friction fo
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## A gas turbine plant working on Joule cycle produces 4000 kW of power. If its work ratio is 40%, what is the power consumed by the compressor in (kWa)6000b)4000c)160d)1000Correct answer is option 'A'. Can you explain this answer?

 Pritam Das answered  •  2 days ago
Analysis:
The work ratio of a gas turbine plant is defined as the ratio of the net work output to the total energy supplied to the plant. In this case, the work ratio is given as 40%.

Given:
- Power output of the gas turbine plant = 4000 kW
- Work ratio = 40%

Calculations:
- Total power supplied to the plant = Power output / Work ratio
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## The integrating factor of equation y log y dx + (x – log y) dy = 0 isa)log xb)log yc)log (log x)d)log (log y)Correct answer is option 'B'. Can you explain this answer?

 Pritam Das answered  •  2 days ago
Integrating Factor for the Given Differential Equation
The given differential equation is in the form of y log y dx + (x – log y) dy = 0. To find the integrating factor for this differential equation, we can rewrite it in the form of Mdx + Ndy = 0, where M = y log y and N = x – log y.

Rewriting the Differential Equation
The given differential equation can be rewr
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## What are types boundary conditions in CFD?

 Nishanth Basu answered  •  2 days ago
Types of Boundary Conditions in CFD:
1. Dirichlet Boundary Condition:
- In this type of boundary condition, the value of the variable is specified at the boundary. For example, the velocity or temperature at the boundary is given a fixed value.
2. Neumann Boundary Condition:
- Here, the derivative of the variable normal to the boundary is specified. This
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## The projection originates from the 3rd object itself to projection to the plane infront of it is called (A) 1st angle projection (B) 3rd angle projection (C) 2nd angle projection (D) 4th angle projection?

 Varun Mukherjee answered  •  2 days ago
Types of Orthographic Projection:

1st Angle Projection:
In 1st angle projection, the object is placed in the first quadrant and the projection is made onto the plane behind the object. This means that the object is between the plane of projection and the observer.

3rd Angle Projection:
In 3rd angle projection, the object is placed in the third q
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## Angle of incidence is the included angle between income-line and ........ at the break even point in a break-even charta)fixed cost lineb)variable cost linec)total cost lined)profile costCorrect answer is option 'C'. Can you explain this answer?

 Varun Mukherjee answered  •  2 days ago
Angle of Incidence in Break-Even Charts
In a break-even chart, the angle of incidence is the included angle between the income line and the total cost line at the break-even point. This angle is an important metric that helps in analyzing the financial performance of a business.

Understanding the Components
- Income Line: This line represents the total rev
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## A copper wire is annealed at 250 mm diameter. The smallest diameter to which it could be theoretically drawn in 3 passes isa)0.92b) 1.52c) 0.56d)1.12Correct answer is option 'C'. Can you explain this answer?

 Varun Mukherjee answered  •  2 days ago
Explanation:

Given Data:
- Initial diameter of copper wire = 250 mm

Calculation:
- In wire drawing, the diameter decreases by a constant percentage in each pass.
- The percentage reduction in area for each pass is given by the formula: (Ao - Ad) / Ao = (D^2 - d^2) / D^2
- Where:
- Ao = Initial cross-sectional area
- Ad = Fi
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## Which of the following type of medicine is used for treating indigestion?a)Antibioticb)Analgesicc)Antacidd)AntisepticCorrect answer is option 'C'. Can you explain this answer?

 Anjali Shah answered  •  2 days ago
Antacid for Treating Indigestion
Indigestion is a common digestive issue that can cause discomfort and pain in the upper abdomen. One type of medicine that is commonly used to treat indigestion is an antacid.

What is an Antacid?
- Antacids are medications that help neutralize stomach acid to relieve symptoms such as heartburn, acidity, and indigestion.
- Th
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## A closed system receives 60 kJ heat but its internal energy decreases by 30 kJ, Then the work done by the system isa)90 kJb)30 kJc)-30 kJd)-90 kJCorrect answer is option 'A'. Can you explain this answer?

 Ruchi Ahuja answered  •  2 days ago
Given Data:
Heat received by the system (Q) = 60 kJ
Change in internal energy (ΔU) = -30 kJ (decreased internal energy)

Calculation:
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.
Mathematically, it can be represented as:
ΔU = Q - W... more

## In a rolling process, the state of stress of the material undergoing deformation is[ME 2013]a)pure compressionb)pure shearc)compression and sheard)tension and shearCorrect answer is option 'C'. Can you explain this answer?

 Anirudh Banerjee answered  •  3 days ago
State of Stress in Rolling Process
In a rolling process, the material undergoing deformation experiences a state of stress that is a combination of compression and shear stress.

Compression and Shear Stress
- Compression stress is present due to the applied force in the rolling process, which compresses the material in the rolling direction.
- Shear stress o
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