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Thevenin’s and Norton’s theorems
Page 2


Thevenin’s and Norton’s theorems
Flow of presentation
ØStatement of Thevnin’s theorem
ØExamples of Thevnin’s theorem
ØStatement of Norton’s theorem
ØExamples of Norton’s theorem
Page 3


Thevenin’s and Norton’s theorems
Flow of presentation
ØStatement of Thevnin’s theorem
ØExamples of Thevnin’s theorem
ØStatement of Norton’s theorem
ØExamples of Norton’s theorem
THEVENIN’S THEOREM:
Consider the following:
Network
1
Network
2


A
B
Figure 1:  Coupled networks.
For purposes of discussion, at this point, we consider
that both networks are composed of resistors and
independent voltage and current sources
Page 4


Thevenin’s and Norton’s theorems
Flow of presentation
ØStatement of Thevnin’s theorem
ØExamples of Thevnin’s theorem
ØStatement of Norton’s theorem
ØExamples of Norton’s theorem
THEVENIN’S THEOREM:
Consider the following:
Network
1
Network
2


A
B
Figure 1:  Coupled networks.
For purposes of discussion, at this point, we consider
that both networks are composed of resistors and
independent voltage and current sources
THEVENIN’S THEOREM:
Suppose Network 2 is detached from Network 1 and
we focus temporarily only on Network 1.
Network
1


A
B
Figure 2:  Network 1, open-circuited.
Network 1 can be as complicated in structure as one
can imagine.  Maybe 45 meshes, 387 resistors, 91
voltage sources and 39 current sources.
Page 5


Thevenin’s and Norton’s theorems
Flow of presentation
ØStatement of Thevnin’s theorem
ØExamples of Thevnin’s theorem
ØStatement of Norton’s theorem
ØExamples of Norton’s theorem
THEVENIN’S THEOREM:
Consider the following:
Network
1
Network
2


A
B
Figure 1:  Coupled networks.
For purposes of discussion, at this point, we consider
that both networks are composed of resistors and
independent voltage and current sources
THEVENIN’S THEOREM:
Suppose Network 2 is detached from Network 1 and
we focus temporarily only on Network 1.
Network
1


A
B
Figure 2:  Network 1, open-circuited.
Network 1 can be as complicated in structure as one
can imagine.  Maybe 45 meshes, 387 resistors, 91
voltage sources and 39 current sources.
Network
1


A
B
THEVENIN’S THEOREM:
Now place a voltmeter across terminals A-B and
read the voltage.  We call this the open-circuit voltage.
No matter how complicated Network 1 is, we read one
voltage.  It is either positive at A, (with respect to B)
or negative at A.
We call this voltage V
os
and we also call it V
THEVENIN
= V
TH
Read More
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FAQs on PPT: Thevenin’s & Norton’s Theorems - Basic Electrical Technology - Electrical Engineering (EE)

1. What is Thevenin's theorem?
Ans. Thevenin's theorem states that any linear electrical network with voltage sources, current sources, and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor connected in series.
2. What is Norton's theorem?
Ans. Norton's theorem is similar to Thevenin's theorem but instead of a voltage source and a resistor, it states that any linear electrical network can be replaced by an equivalent circuit consisting of a single current source and a single resistor connected in parallel.
3. How do you calculate the Thevenin equivalent resistance?
Ans. To calculate the Thevenin equivalent resistance, we need to first remove all sources from the circuit and then calculate the total resistance seen from the load terminals. This is done by short-circuiting all voltage sources and open-circuiting all current sources, and then calculating the equivalent resistance using series and parallel resistor combinations.
4. How do you calculate the Thevenin equivalent voltage?
Ans. To calculate the Thevenin equivalent voltage, we need to determine the open-circuit voltage across the load terminals of the circuit. This can be done by removing the load resistor and calculating the voltage across its terminals. This voltage will be the Thevenin equivalent voltage.
5. How do you calculate the Norton equivalent current?
Ans. To calculate the Norton equivalent current, we need to determine the short-circuit current flowing through the load terminals of the circuit. This can be done by replacing the load resistor with a short circuit and calculating the current flowing through it. This current will be the Norton equivalent current.
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