JIPMER Entrance Exam Solved Paper - 2018

 Page 1


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
Page 2


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
Page 3


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
 
 
 
  
 
   
2. 
 
 
23
Br AlBr ?
? ? ? ? ? ?
 Br 
 
 Which is intermediate of above reaction :   
 (1) 
 Br 
H 
  (2) 
 
Br 
H 
  (3) 
 AlCl
3 
  (4) 
 
Br 
AlBr
3 
 
Ans. (2) 
Sol. Step 1 : Formation of a stronger electrophile. 
  
Br – :
: :
Br    +   FeBr 
3
: :
: Br – :
: :
Br – 
: :
?
?
FeBr 
3
:
?
?
 
 Step 2 : Electrophilic attack and formation of the sigma complex. 
          
Br – :
: :
Br  FeBr 
3
: :
:
+ H
H
H
H
H
H
? ? ? ? ? ? + FeBr
4
¯ 
 Step 3 : Loss of a proton gives the products. 
    
Br
H
H
H
H
H
bromobenzene
+ HBr + FeBr
3
        
 Other halogenating agents are ICl, HOCl etc.  
 order of effectiveness – Cl
2
 > BrCl > Br
2
 > ICl > I
2
 
 
3. Which of the following is substitution reaction -  
 (1) 
 R–C–OH 
O 
  
ROH/H
?
? ? ? ? ?
 R–C–OR 
O 
   (2) 
 OH 
 
H
?
?
? ? ? ? 
 
   
 (3) 
 R 
C=O 
R 
2
H O/H
?
? ? ? ? ?  
 R 
C 
R 
OH 
OH 
 
  (4) R–MgBr + CH3COOH —? R–H 
Ans. (1) 
Sol.  Reaction involving replacement of –OH group : 
   
 This is nucleophilic substitution reactions. 
 
Page 4


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
 
 
 
  
 
   
2. 
 
 
23
Br AlBr ?
? ? ? ? ? ?
 Br 
 
 Which is intermediate of above reaction :   
 (1) 
 Br 
H 
  (2) 
 
Br 
H 
  (3) 
 AlCl
3 
  (4) 
 
Br 
AlBr
3 
 
Ans. (2) 
Sol. Step 1 : Formation of a stronger electrophile. 
  
Br – :
: :
Br    +   FeBr 
3
: :
: Br – :
: :
Br – 
: :
?
?
FeBr 
3
:
?
?
 
 Step 2 : Electrophilic attack and formation of the sigma complex. 
          
Br – :
: :
Br  FeBr 
3
: :
:
+ H
H
H
H
H
H
? ? ? ? ? ? + FeBr
4
¯ 
 Step 3 : Loss of a proton gives the products. 
    
Br
H
H
H
H
H
bromobenzene
+ HBr + FeBr
3
        
 Other halogenating agents are ICl, HOCl etc.  
 order of effectiveness – Cl
2
 > BrCl > Br
2
 > ICl > I
2
 
 
3. Which of the following is substitution reaction -  
 (1) 
 R–C–OH 
O 
  
ROH/H
?
? ? ? ? ?
 R–C–OR 
O 
   (2) 
 OH 
 
H
?
?
? ? ? ? 
 
   
 (3) 
 R 
C=O 
R 
2
H O/H
?
? ? ? ? ?  
 R 
C 
R 
OH 
OH 
 
  (4) R–MgBr + CH3COOH —? R–H 
Ans. (1) 
Sol.  Reaction involving replacement of –OH group : 
   
 This is nucleophilic substitution reactions. 
 
 
 
 
  
 
   
4. Which is the following undergoes self oxidation and self reduction in same reaction  
 (1) C7H8O  (2) CH2O   (3) C3H7O  (4) C2H4O 
Ans. (2) 
Sol. Cannizzaro reaction :  
 Aldehydes which do not have an ?-hydrogen atom, undergo self oxidation and reduction 
(disproportionation) reaction on treatment with a concentrated alkali. 
       
 
5. Which of the following reaction produces ethylacetoacetate -  
 (1) Cannizaro reaaction    (2) Claisen reaction    
 (3) Reformatsky reaction   (4) Aldol reaction  
Ans. (2) 
Sol. 
 
CH
3
–C–CH
2
–C–O–C
2
H
5
 
O
 
O
 
(ethyl aceto acetate)
 
 
 This is a ?-keto ester which is form by clasinen ester condensation. 
 
6. 
 CH=O 
 
33
3
CH COOCOCH
CH COONa
? ? ? ? ? ? ? ? P ;  
 Major product of above reaction :  
 (1) C6H5–CH=CH–COOH    (2) C6H5–COOH   
 (3) C6H5–CH=CH–COOCH3    (4) C6H5–CH2–CHO 
Ans.  
Sol. Perkin reaction :  
 When aromatic aldehyde like benzaldehyde is treated with anhydride in the presence of sodium salt of 
acid from which anhydride is derived we get ? ? ? ?-unsaturated acid. 
     
 
7. Which of the following alcohol will react fastest with HCl    
 (1) 
 CH
3 
OH
 
  (2) 
 CH
2
OH 
  (3) 
 CH
3
 
OH 
  (4) 
 
H
3
C 
OH 
 
Ans. (4) 
 
Page 5


 
 
 
 
      
 
J JI IP PM ME ER R  M MB BB BS S  E EN NT TR RA AN NC CE E  T TE ES ST T  2 20 01 18 8    
E EX XA AM MI IN NA AT TI IO ON N  P PA AP PE ER R    
( (B BA AS SE ED D  O ON N  M ME EM MO OR RY Y  R RE ET TE EN NT TI IO ON N) )  
  
Date :  03-06-2018 (Sunday)    |     Time :  10.00 am - 12.30 pm    |    Morning Session    
 
 
NOTE:-  
1. Questions are collected from the appeared students.  
2. The solutions are prepared by the expert faculty team of Resonance Pre-Medical division, 
Kota.  
3. Questions may not be in the order or sequence as asked in the actual examination paper.  
4. The questions collected may not have all the options similar to the actual paper. Students 
are advised to see the question and answer / solutions.  
5.  Actual JIPMER Paper has 200 questions but we have included only those many 
     questions which have been collected from the students as per following table :-  
 
 
Subject  
No. of Question in Actual 
JIPMER Paper  
No. of Question in this Paper 
Chemistry 60  39 
Physics 60 45 
Biology 60 55 
English & 
Comprehension + 
Logical & 
Quantitative 
Reasoning 
20 07 
Total   200  146 
 
 
 
 
  
 
   
PART - A (CHEMISTRY)  
 
1. 
 OH 
 
–
3
CHCl OH ?
? ? ? ? ? ? ?
 OH 
CHO 
 
 Intermediate of above reaction is :   
 (1) :CCl2  (2) : CHCl   (3)
2
CHCl
?
  (4) 
3
CCl
?
 
Ans. (1) 
Sol. This is a Reimer-Tieman reaction  
 This is a electrophilic substitution reaction of phenol  
 ;g ,d jkbej fVeku vfHkfØ;k gS  
 ;g fQukWy dh bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gS 
 
 OH 
+ CHCl
3
 + NaOH 
O
–
Na
+
 
CHO 
 
 I : CHCl3 + NaOH –— ??
3
CCl
?
+ H2O  
         
 
–Cl
– 
CCl
2 
 
? ?  dichloro carbene (MkbZDyksjksdkchZu) 
? ??Incomplete octate (viw.kZ v"Vd) 
? ??6e
– 
? ??act as a electrophile  (bysDVªkWuLusgh dh rjg O;ogkj) 
 II :  
 
CCl
2 
ONa 
? ? 
+ 
Rds
?? ? ? 
O 
CCl
2 
+ 
? 
O 
H 
CCl
2 
? 
 
 III : 
 
CCl
2 
O 
? 
2
HO
?? ? ? 
OH 
OH 
OH 
 
? 
OH 
CHCl
2 
H
3
O
+ 
—CH 
OH 
—CH=O 
 
 
 
 
  
 
   
2. 
 
 
23
Br AlBr ?
? ? ? ? ? ?
 Br 
 
 Which is intermediate of above reaction :   
 (1) 
 Br 
H 
  (2) 
 
Br 
H 
  (3) 
 AlCl
3 
  (4) 
 
Br 
AlBr
3 
 
Ans. (2) 
Sol. Step 1 : Formation of a stronger electrophile. 
  
Br – :
: :
Br    +   FeBr 
3
: :
: Br – :
: :
Br – 
: :
?
?
FeBr 
3
:
?
?
 
 Step 2 : Electrophilic attack and formation of the sigma complex. 
          
Br – :
: :
Br  FeBr 
3
: :
:
+ H
H
H
H
H
H
? ? ? ? ? ? + FeBr
4
¯ 
 Step 3 : Loss of a proton gives the products. 
    
Br
H
H
H
H
H
bromobenzene
+ HBr + FeBr
3
        
 Other halogenating agents are ICl, HOCl etc.  
 order of effectiveness – Cl
2
 > BrCl > Br
2
 > ICl > I
2
 
 
3. Which of the following is substitution reaction -  
 (1) 
 R–C–OH 
O 
  
ROH/H
?
? ? ? ? ?
 R–C–OR 
O 
   (2) 
 OH 
 
H
?
?
? ? ? ? 
 
   
 (3) 
 R 
C=O 
R 
2
H O/H
?
? ? ? ? ?  
 R 
C 
R 
OH 
OH 
 
  (4) R–MgBr + CH3COOH —? R–H 
Ans. (1) 
Sol.  Reaction involving replacement of –OH group : 
   
 This is nucleophilic substitution reactions. 
 
 
 
 
  
 
   
4. Which is the following undergoes self oxidation and self reduction in same reaction  
 (1) C7H8O  (2) CH2O   (3) C3H7O  (4) C2H4O 
Ans. (2) 
Sol. Cannizzaro reaction :  
 Aldehydes which do not have an ?-hydrogen atom, undergo self oxidation and reduction 
(disproportionation) reaction on treatment with a concentrated alkali. 
       
 
5. Which of the following reaction produces ethylacetoacetate -  
 (1) Cannizaro reaaction    (2) Claisen reaction    
 (3) Reformatsky reaction   (4) Aldol reaction  
Ans. (2) 
Sol. 
 
CH
3
–C–CH
2
–C–O–C
2
H
5
 
O
 
O
 
(ethyl aceto acetate)
 
 
 This is a ?-keto ester which is form by clasinen ester condensation. 
 
6. 
 CH=O 
 
33
3
CH COOCOCH
CH COONa
? ? ? ? ? ? ? ? P ;  
 Major product of above reaction :  
 (1) C6H5–CH=CH–COOH    (2) C6H5–COOH   
 (3) C6H5–CH=CH–COOCH3    (4) C6H5–CH2–CHO 
Ans.  
Sol. Perkin reaction :  
 When aromatic aldehyde like benzaldehyde is treated with anhydride in the presence of sodium salt of 
acid from which anhydride is derived we get ? ? ? ?-unsaturated acid. 
     
 
7. Which of the following alcohol will react fastest with HCl    
 (1) 
 CH
3 
OH
 
  (2) 
 CH
2
OH 
  (3) 
 CH
3
 
OH 
  (4) 
 
H
3
C 
OH 
 
Ans. (4) 
 
 
 
 
  
 
   
8. Which is correct for cellulose – 
 (1) branched, ?(1,4) – glucose    (2) Unbranched, ?(1,6) – glucose   
 (3) Unbranched, ?(1,4) – glucose  (4) branched, ?(1,4) band ? (1, 6) 
Ans. (3) 
Sol.  
 
Polysaccharide Structure Monomeric unit 
linkage 
Amylose 
 
 
 
 
C1- ? ?D-Glucose + 
C4- ? ?D-Glucose + 
C1- ? ?D-Glucose + 
C4- ? ?D-Glucose... 
Amylopection 
 
 
 
C1- ? ?D-Glucose + 
C4- ? ?D-Glucose... 
Branching at  C1 
? ?D-Glucose + C6 
? ?D-Glucose…. 
Cellulose 
 
CH OH
2
CH OH
2
H
H
OH
OH
OH
OH
H
H
H
H
H
6
6
5
5
1
1
4
4
2
2
3
3
O
O
O
H
H O
n
Cellulose
H
? ? ? (1 4)
 
 
C1- ? ?D-Glucose + 
C4-??D-Glucose + 
C1- ? ?D-Glucose + 
C4-??D-Glucose... 
 
 Unbranched, ?(1,4) – glucose 
 
9. Which of the following is correct for Lactose 
 (1) It is nonreducing sugar   
 (2) Glycosidic bond [1,4] between glucose and galactose    
 (3) Glycosidic bond [1,4] between glucose and fructose   
 (4) Glycosidic bond [1,2] between glucose and galactose 
Ans. (2) 
Sol. Lactose = Glycosidic bond [1,4] between glucose and galactose 
 
10. 
 CH
3 
CH
3 Cl
 
H
 
H
 
H
 
 
and  
 CH
2
Cl 
H
 H
 
CH
3 
H H
 
 are :-  
 (1) Enantiomers  (2) Conformers  (3) Positional isomers (4) None of these  
Ans. (3) 
Sol. 
 CH
3 
CH
3 Cl
 
H
 
H
 
H
 
 
 CH
2
Cl 
H
 H
 
CH
3 
H H
 
 
 
 CH
3 
– CH
2
 – CH – CH
3 
Cl
 
2–Chlorobutane
 
CH
2 
– CH
2
 – CH
2
 – CH
3 
Cl
 
1–Chlorobutane
 
Position Isomer to each each other