DC Pandey Solutions: Electrostatics

DC Pandey Solutions: Electrostatics | Physics Class 12 - NEET PDF Download

``` Page 1

Introductory Exercise 21.1
Q.1. Is attraction a true test of electrification?
Ans. Due to induction effect, a charged body can attract a neutral body as shown
below.
Body-1 is positively charged and body-2 is neutral. But we can see that due to
distance factor attraction is more than the repulsion.
Q.2. What is the total charge, in coulombs, of all the electrons in a three-
gram mole of hydrogen atoms?
Ans. Number of atoms in 3 gram-mole of hydrogen atom = number of electrons in it
= 3N = (3 × 6.02 × 10 ) where
? Total charge
= - (1.6 × 10 ) (3 × 6.02 × 10 )
= -2.89 × 10 C
Introductory Exercise 21.2
0
23
0
-19 23
5
Page 2

Introductory Exercise 21.1
Q.1. Is attraction a true test of electrification?
Ans. Due to induction effect, a charged body can attract a neutral body as shown
below.
Body-1 is positively charged and body-2 is neutral. But we can see that due to
distance factor attraction is more than the repulsion.
Q.2. What is the total charge, in coulombs, of all the electrons in a three-
gram mole of hydrogen atoms?
Ans. Number of atoms in 3 gram-mole of hydrogen atom = number of electrons in it
= 3N = (3 × 6.02 × 10 ) where
? Total charge
= - (1.6 × 10 ) (3 × 6.02 × 10 )
= -2.89 × 10 C
Introductory Exercise 21.2
0
23
0
-19 23
5
Q.1. The mass of an electron is 9.11 × 10 kg, that of a proton is 1.67 × 10
kg. Find the ratio F /F of the electric force and the gravitational force
exerted by the proton on the electron,
Ans.
Q.2. Find the dimensions and units of ?0.
Ans.

Units and dimensions can be found by above equation.
Q.3. Three point charges q are placed at three vertices of an equilateral
triangle of side a. Find magnitude of electric force on any charge due to the
other two.
Ans.
F = Force between can two point charges
-31 -
27
e g
Page 3

Introductory Exercise 21.1
Q.1. Is attraction a true test of electrification?
Ans. Due to induction effect, a charged body can attract a neutral body as shown
below.
Body-1 is positively charged and body-2 is neutral. But we can see that due to
distance factor attraction is more than the repulsion.
Q.2. What is the total charge, in coulombs, of all the electrons in a three-
gram mole of hydrogen atoms?
Ans. Number of atoms in 3 gram-mole of hydrogen atom = number of electrons in it
= 3N = (3 × 6.02 × 10 ) where
? Total charge
= - (1.6 × 10 ) (3 × 6.02 × 10 )
= -2.89 × 10 C
Introductory Exercise 21.2
0
23
0
-19 23
5
Q.1. The mass of an electron is 9.11 × 10 kg, that of a proton is 1.67 × 10
kg. Find the ratio F /F of the electric force and the gravitational force
exerted by the proton on the electron,
Ans.
Q.2. Find the dimensions and units of ?0.
Ans.

Units and dimensions can be found by above equation.
Q.3. Three point charges q are placed at three vertices of an equilateral
triangle of side a. Find magnitude of electric force on any charge due to the
other two.
Ans.
F = Force between can two point charges
-31 -
27
e g
Q.4. Three point charges each of value +q are placed on three vertices of a
square of side a metre. What is the magnitude of the force on a point
charge of value-q coulomb placed at the centre of the square?
Ans.
Net force on -q from the charges at B and D is zero. So net force on - q is only due to
the charge at A.
where,
?
Q.5. Is there any lower limit to the electric force between two particles
placed at a certain distance?
Ans.
(q ) = (q )
1 min 2 min
Page 4

Introductory Exercise 21.1
Q.1. Is attraction a true test of electrification?
Ans. Due to induction effect, a charged body can attract a neutral body as shown
below.
Body-1 is positively charged and body-2 is neutral. But we can see that due to
distance factor attraction is more than the repulsion.
Q.2. What is the total charge, in coulombs, of all the electrons in a three-
gram mole of hydrogen atoms?
Ans. Number of atoms in 3 gram-mole of hydrogen atom = number of electrons in it
= 3N = (3 × 6.02 × 10 ) where
? Total charge
= - (1.6 × 10 ) (3 × 6.02 × 10 )
= -2.89 × 10 C
Introductory Exercise 21.2
0
23
0
-19 23
5
Q.1. The mass of an electron is 9.11 × 10 kg, that of a proton is 1.67 × 10
kg. Find the ratio F /F of the electric force and the gravitational force
exerted by the proton on the electron,
Ans.
Q.2. Find the dimensions and units of ?0.
Ans.

Units and dimensions can be found by above equation.
Q.3. Three point charges q are placed at three vertices of an equilateral
triangle of side a. Find magnitude of electric force on any charge due to the
other two.
Ans.
F = Force between can two point charges
-31 -
27
e g
Q.4. Three point charges each of value +q are placed on three vertices of a
square of side a metre. What is the magnitude of the force on a point
charge of value-q coulomb placed at the centre of the square?
Ans.
Net force on -q from the charges at B and D is zero. So net force on - q is only due to
the charge at A.
where,
?
Q.5. Is there any lower limit to the electric force between two particles
placed at a certain distance?
Ans.
(q ) = (q )
1 min 2 min
?
Q.6. The electric force on a charge q due to q is (4 i - 3 j) N. What is the
force on q due to q ?
Ans. Two forces are equal and opposite.
Introductory Exercise 21.3
Q.1: The electric field of a point charge is uniform. Is it true or false?
Ans. Electric field lines are not parallel and equidistant.
Q.2. Electric field lines are shown in Fig.. State whether the electric
potential is greater at A or B.
Ans. Electric lines flow higher potential to lower potential.
V > V
Q.3. A charged particle always move in the direct ion of electric field. Is this
statement true or false?
Ans. If charged particle is positive, and at rest. Electric field lines are straight then
only it will move in the direction of electric field.
Q.4. What is the charge per unit area in C/m , of an infinite plane sheet of
charge if the electric field produced by the sheet of charge has magnitude
3.0 N/C?
Ans.
? s= (2E e )
= 2 × 3.0 × 8.86 × 10 = 5.31 × 10 C/m
Q.5. The figure shows some of the electric field lines due to three-point
charges q , q and q of equal magnitude. What are the signs of each of
1 2
2 1
A B
2
0
-12 -11 2
1 2, 3
Page 5

Introductory Exercise 21.1
Q.1. Is attraction a true test of electrification?
Ans. Due to induction effect, a charged body can attract a neutral body as shown
below.
Body-1 is positively charged and body-2 is neutral. But we can see that due to
distance factor attraction is more than the repulsion.
Q.2. What is the total charge, in coulombs, of all the electrons in a three-
gram mole of hydrogen atoms?
Ans. Number of atoms in 3 gram-mole of hydrogen atom = number of electrons in it
= 3N = (3 × 6.02 × 10 ) where
? Total charge
= - (1.6 × 10 ) (3 × 6.02 × 10 )
= -2.89 × 10 C
Introductory Exercise 21.2
0
23
0
-19 23
5
Q.1. The mass of an electron is 9.11 × 10 kg, that of a proton is 1.67 × 10
kg. Find the ratio F /F of the electric force and the gravitational force
exerted by the proton on the electron,
Ans.
Q.2. Find the dimensions and units of ?0.
Ans.

Units and dimensions can be found by above equation.
Q.3. Three point charges q are placed at three vertices of an equilateral
triangle of side a. Find magnitude of electric force on any charge due to the
other two.
Ans.
F = Force between can two point charges
-31 -
27
e g
Q.4. Three point charges each of value +q are placed on three vertices of a
square of side a metre. What is the magnitude of the force on a point
charge of value-q coulomb placed at the centre of the square?
Ans.
Net force on -q from the charges at B and D is zero. So net force on - q is only due to
the charge at A.
where,
?
Q.5. Is there any lower limit to the electric force between two particles
placed at a certain distance?
Ans.
(q ) = (q )
1 min 2 min
?
Q.6. The electric force on a charge q due to q is (4 i - 3 j) N. What is the
force on q due to q ?
Ans. Two forces are equal and opposite.
Introductory Exercise 21.3
Q.1: The electric field of a point charge is uniform. Is it true or false?
Ans. Electric field lines are not parallel and equidistant.
Q.2. Electric field lines are shown in Fig.. State whether the electric
potential is greater at A or B.
Ans. Electric lines flow higher potential to lower potential.
V > V
Q.3. A charged particle always move in the direct ion of electric field. Is this
statement true or false?
Ans. If charged particle is positive, and at rest. Electric field lines are straight then
only it will move in the direction of electric field.
Q.4. What is the charge per unit area in C/m , of an infinite plane sheet of
charge if the electric field produced by the sheet of charge has magnitude
3.0 N/C?
Ans.
? s= (2E e )
= 2 × 3.0 × 8.86 × 10 = 5.31 × 10 C/m
Q.5. The figure shows some of the electric field lines due to three-point
charges q , q and q of equal magnitude. What are the signs of each of
1 2
2 1
A B
2
0
-12 -11 2
1 2, 3
the three charges?
Ans. Electric field lines start from positive charge and terminate on a negative
charge.
Q.6. Four particles each having a charge q, are placed on the four vertices
of a regular pentagon. The distance of each corner from the centre is a.
Find the electric field at the centre of the pentagon.
Ans. In case of five charges at five vert ices o f regular pentagon net electric field at
centre is zero. Because five vectors of equal magnitudes from a closed regular
pentagon at shown in figure (i).
Where one charge is removed. Then one vector
is deceased hence the net resultant is equal to magnitude of one vector
Q.7. A circular wire loop of radius R carries a total charge q distributed
uniformly over its length. A small length x( << R) of the wire is cut off. Find
the electric field at the centre due to the remaining wire.
Ans.
If loop is complete, then net electric field at centre C is zero. Because equal and
opposite pair of electric field vectors are canceled.
If PQ portion is removed as shown in figure, then electric field due to portion RS is
not cancelled. Hence electric field is only due to the option RS.
```

Physics Class 12

105 videos|425 docs|114 tests

FAQs on DC Pandey Solutions: Electrostatics - Physics Class 12 - NEET

 1. What is electrostatics?
Ans. Electrostatics is a branch of physics that deals with the study of electric charges at rest. It focuses on the behavior of stationary or static charges and the forces between them.
 2. What are the fundamental concepts of electrostatics?
Ans. The fundamental concepts of electrostatics include electric charge, electric field, electric potential, and electric potential energy. These concepts help in understanding the behavior and interaction of charges in electrostatic systems.
 3. How can we calculate the electric field due to a point charge?
Ans. The electric field due to a point charge can be calculated using Coulomb's law. The formula is given by E = k * (Q / r^2), where E is the electric field, k is the electrostatic constant, Q is the charge, and r is the distance from the charge.
 4. What is the principle of superposition in electrostatics?
Ans. The principle of superposition states that the total electric field at a point due to multiple charges is the vector sum of the electric fields produced by each individual charge. This principle allows us to calculate the net electric field at any point in an electrostatic system.
 5. How does Gauss's law help in solving electrostatic problems?
Ans. Gauss's law is a powerful tool in solving electrostatic problems, especially those involving symmetrical charge distributions. It relates the electric flux through a closed surface to the total charge enclosed by that surface. By using Gauss's law, we can determine the electric field or charge distribution in a system without having to integrate over the entire surface.

Physics Class 12

105 videos|425 docs|114 tests

Up next

 Explore Courses for NEET exam

How to Prepare for NEET

Read our guide to prepare for NEET which is created by Toppers & the best Teachers
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

;