JEE Exam > JEE Notes > Mathematics (Maths) Class 12 > CBSE Past Year Paper Session (2015) Solutions, Math Class 12
CBSE Past Year Paper Session (2015) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
Page 2
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
Page 3
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
5. Consider the equation, y = mx, where m is the parameter.
Thus, the above equation represents the family of lines which pass through the origin.
y mx....(1)
y
m....(2)
x
?
??
Differentiating the above equation (1) with respect to x,
? ?
?
??
??
??
? ? ?
??
y mx
dy
m1
dx
dy
m
dx
dy y
from equation (2)
dx x
dy y
0
dx x
Thus we have eliminated the constant, m.
The required differential equation is
dy y
0
dx x
6. Consider the given differential equation:
dy
xlog x y 2log x
dx
Dividing the above equation by xlogx, we have,
xlog x dy y 2log x
xlog x dx xlog x xlog x
dy y 2
....(1)
dx xlog x x
Consider the general linear differential equation,
dy
Py Q,where P and Q are funct
dx
??
??
? ? ?
?? ions of x
? ? ? ?
Pdx
dx
Pdx
x log x
Comparing equation (1) and the general equation, we have,
12
P x and Q x
xlog x x
The integrating factor is given by the formula e
Thus,I.F. e e
??
?
?
?
??
Page 4
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
5. Consider the equation, y = mx, where m is the parameter.
Thus, the above equation represents the family of lines which pass through the origin.
y mx....(1)
y
m....(2)
x
?
??
Differentiating the above equation (1) with respect to x,
? ?
?
??
??
??
? ? ?
??
y mx
dy
m1
dx
dy
m
dx
dy y
from equation (2)
dx x
dy y
0
dx x
Thus we have eliminated the constant, m.
The required differential equation is
dy y
0
dx x
6. Consider the given differential equation:
dy
xlog x y 2log x
dx
Dividing the above equation by xlogx, we have,
xlog x dy y 2log x
xlog x dx xlog x xlog x
dy y 2
....(1)
dx xlog x x
Consider the general linear differential equation,
dy
Py Q,where P and Q are funct
dx
??
??
? ? ?
?? ions of x
? ? ? ?
Pdx
dx
Pdx
x log x
Comparing equation (1) and the general equation, we have,
12
P x and Q x
xlog x x
The integrating factor is given by the formula e
Thus,I.F. e e
??
?
?
?
??
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
? ? ? ?
? ?
?
??
?
? ? ?
?
?
dx
log log x
x log x
dx
Consider I=
xlog x
dx
Substituting logx=t; dt
x
dt
Thus I= log t log log x
t
Hence,I.F. e e log x
SECTION – B
7.
2
1 2 2
A 2 1 2
2 2 1
1 2 2 1 2 2
A 2 1 2 2 1 2
2 2 1 2 2 1
1 1 2 2 2 2 1 2 2 1 2 2 1 2 2 2 2 1
2 1 1 2 2 2 2 2 1 1 2 2 2 2 1 2 2 1
2 1 2 2 1 2 2 2 2 1 1 2 2 2 2 2 1 1
1 4 4 2 2 4 2 4 2
2 2 4 4 1 4 4 2 2
2 4 2 4 2 2 4 4 1
9 8 8
8 9 8
8 8 9
2
Consider A 4A 5I
9 8 8 1 2 2 1 0 0
8 9 8 4 2 1 2 5 0 1 0
8 8 9 2 2 1 0 0 1
9 8 8 4 8 8 5 0 0
8 9 8 8 4 8 0 5 0
8 8 9 8 8 4 0 0 5
9 9 8 8 8 8
8 8 9 9 8 8
8 8 8 8 9 9
Page 5
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
5. Consider the equation, y = mx, where m is the parameter.
Thus, the above equation represents the family of lines which pass through the origin.
y mx....(1)
y
m....(2)
x
?
??
Differentiating the above equation (1) with respect to x,
? ?
?
??
??
??
? ? ?
??
y mx
dy
m1
dx
dy
m
dx
dy y
from equation (2)
dx x
dy y
0
dx x
Thus we have eliminated the constant, m.
The required differential equation is
dy y
0
dx x
6. Consider the given differential equation:
dy
xlog x y 2log x
dx
Dividing the above equation by xlogx, we have,
xlog x dy y 2log x
xlog x dx xlog x xlog x
dy y 2
....(1)
dx xlog x x
Consider the general linear differential equation,
dy
Py Q,where P and Q are funct
dx
??
??
? ? ?
?? ions of x
? ? ? ?
Pdx
dx
Pdx
x log x
Comparing equation (1) and the general equation, we have,
12
P x and Q x
xlog x x
The integrating factor is given by the formula e
Thus,I.F. e e
??
?
?
?
??
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
? ? ? ?
? ?
?
??
?
? ? ?
?
?
dx
log log x
x log x
dx
Consider I=
xlog x
dx
Substituting logx=t; dt
x
dt
Thus I= log t log log x
t
Hence,I.F. e e log x
SECTION – B
7.
2
1 2 2
A 2 1 2
2 2 1
1 2 2 1 2 2
A 2 1 2 2 1 2
2 2 1 2 2 1
1 1 2 2 2 2 1 2 2 1 2 2 1 2 2 2 2 1
2 1 1 2 2 2 2 2 1 1 2 2 2 2 1 2 2 1
2 1 2 2 1 2 2 2 2 1 1 2 2 2 2 2 1 1
1 4 4 2 2 4 2 4 2
2 2 4 4 1 4 4 2 2
2 4 2 4 2 2 4 4 1
9 8 8
8 9 8
8 8 9
2
Consider A 4A 5I
9 8 8 1 2 2 1 0 0
8 9 8 4 2 1 2 5 0 1 0
8 8 9 2 2 1 0 0 1
9 8 8 4 8 8 5 0 0
8 9 8 8 4 8 0 5 0
8 8 9 8 8 4 0 0 5
9 9 8 8 8 8
8 8 9 9 8 8
8 8 8 8 9 9
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
000
000
000
2
2
2 1 1 1 1
1
1
Now
A 4A 5I 0
A 4A 5I
A A 4AA 5IA Postmultiply by A
A 4I 5A
1 2 2 4 0 0
2 1 2 0 4 0 5A
2 2 1 0 0 4
1
1
3 2 2
2 3 2 5A
2 2 3
3 2 2
555
2 3 2
A
555
2 2 3
555
OR
1
1
1
2 0 1
A 5 1 0
0 1 3
2 3 0 0 15 0 1 5 0
6 0 5
1
0
Hence A exists.
A A I
2 0 1 1 0 0
A 5 1 0 0 1 0
0 1 3 0 0 1
Read More
|
204 videos|288 docs|139 tests
|
FAQs on CBSE Past Year Paper Session (2015) Solutions, Math Class 12 - Mathematics (Maths) Class 12 - JEE
| 1. How can I access the CBSE past year paper solutions for the Math Class 12 exam held in 2015? |  |
Ans. You can access the CBSE past year paper solutions for the Math Class 12 exam held in 2015 by searching for them online. Many websites and educational platforms provide these solutions for free or for a nominal fee. You can also check the official CBSE website or refer to popular study material books for these solutions.
| 2. Are the CBSE past year paper solutions for Math Class 12 exam in 2015 helpful for exam preparation? | |
Ans. Yes, the CBSE past year paper solutions for the Math Class 12 exam held in 2015 are extremely helpful for exam preparation. These solutions provide a clear understanding of the paper pattern, important topics, and the level of difficulty of questions asked in the actual exam. By practicing these solutions, you can familiarize yourself with the exam format and improve your problem-solving skills.
| 3. How can solving CBSE past year paper solutions for Math Class 12 exam in 2015 benefit me? | |
Ans. Solving CBSE past year paper solutions for the Math Class 12 exam held in 2015 can benefit you in several ways. It helps you identify your strengths and weaknesses, understand the marking scheme, and improve time management skills. Additionally, it allows you to practice a wide range of questions and enhances your problem-solving abilities. By analyzing your performance in these past year papers, you can also gauge your preparedness for the actual exam.
| 4. Can I rely solely on CBSE past year paper solutions for Math Class 12 exam in 2015 for my exam preparation? | |
Ans. While CBSE past year paper solutions for the Math Class 12 exam held in 2015 are valuable resources for exam preparation, it is not advisable to rely solely on them. These solutions should be used in conjunction with other study materials, textbooks, and reference books. It is important to have a comprehensive understanding of the entire syllabus, practice different types of questions, and seek clarification from teachers or mentors when required.
| 5. Where can I find additional practice questions apart from CBSE past year paper solutions for Math Class 12 exam in 2015? | |
Ans. Apart from CBSE past year paper solutions for the Math Class 12 exam held in 2015, you can find additional practice questions in various study materials, textbooks, and reference books specifically designed for the Class 12 Math syllabus. Additionally, online platforms, educational websites, and mobile applications offer a wide range of practice questions, quizzes, and mock tests for Math Class 12. You can also join coaching institutes or attend online classes that provide additional practice material and question banks.
Related Exams
About this Document
|
4.83/5 Rating |
|
Nov 09, 2024 Last updated |
Document Description: CBSE Past Year Paper Session (2015) Solutions, Math Class 12 for JEE 2024 is part of Mathematics (Maths) Class 12 preparation.
The notes and questions for CBSE Past Year Paper Session (2015) Solutions, Math Class 12 have been prepared according to the JEE exam syllabus. Information about CBSE Past Year Paper Session (2015) Solutions, Math Class 12 covers topics
like and CBSE Past Year Paper Session (2015) Solutions, Math Class 12 Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for CBSE Past Year Paper Session (2015) Solutions, Math Class 12.
Introduction of CBSE Past Year Paper Session (2015) Solutions, Math Class 12 in English is available as part of our Mathematics (Maths) Class 12
for JEE & CBSE Past Year Paper Session (2015) Solutions, Math Class 12 in Hindi for Mathematics (Maths) Class 12 course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: CBSE Past Year Paper Session (2015) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE
Description
Full syllabus notes, lecture & questions for CBSE Past Year Paper Session (2015) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE - JEE | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 12 | Best notes, free PDF download
Information about CBSE Past Year Paper Session (2015) Solutions, Math Class 12
In this doc you can find the meaning of CBSE Past Year Paper Session (2015) Solutions, Math Class 12 defined & explained in the simplest way possible. Besides explaining types of
CBSE Past Year Paper Session (2015) Solutions, Math Class 12 theory, EduRev gives you an ample number of questions to practice CBSE Past Year Paper Session (2015) Solutions, Math Class 12 tests, examples and also practice JEE
tests
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Semester Notes
,mock tests for examination
,practice quizzes
,Summary
,Exam
,study material
,CBSE Past Year Paper Session (2015) Solutions
,video lectures
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,shortcuts and tricks
,Extra Questions
,past year papers
,Viva Questions
,CBSE Past Year Paper Session (2015) Solutions
,Free
,Important questions
,Sample Paper
,MCQs
,ppt
,CBSE Past Year Paper Session (2015) Solutions
,Objective type Questions
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,Previous Year Questions with Solutions
;
Additional Information about CBSE Past Year Paper Session (2015) Solutions, Math Class 12 for JEE Preparation
CBSE Past Year Paper Session (2015) Solutions, Math Class 12 Free PDF Download
The CBSE Past Year Paper Session (2015) Solutions, Math Class 12 is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the CBSE Past Year Paper Session (2015) Solutions, Math Class 12 now and kickstart your journey towards success in the JEE exam.
Importance of CBSE Past Year Paper Session (2015) Solutions, Math Class 12
The importance of CBSE Past Year Paper Session (2015) Solutions, Math Class 12 cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
CBSE Past Year Paper Session (2015) Solutions, Math Class 12 Notes
CBSE Past Year Paper Session (2015) Solutions, Math Class 12 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to CBSE Past Year Paper Session (2015) Solutions, Math Class 12.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, CBSE Past Year Paper Session (2015) Solutions, Math Class 12 Notes on EduRev are your ultimate resource for success.
CBSE Past Year Paper Session (2015) Solutions, Math Class 12 JEE Questions
The "CBSE Past Year Paper Session (2015) Solutions, Math Class 12 JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study CBSE Past Year Paper Session (2015) Solutions, Math Class 12 on the App
Students of JEE can study CBSE Past Year Paper Session (2015) Solutions, Math Class 12 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the CBSE Past Year Paper Session (2015) Solutions, Math Class 12,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of CBSE Past Year Paper Session (2015) Solutions, Math Class 12 is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup