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 Page 1


 
 
 
 
1 
 
Solutions 
1. Ans. A.  
98 = 17 + 81  
26 = 98 – 72  
89 = 26 + 63  
35 = 89 – 54  
? = 35 + 45, i.e. ? = 80 
2. Ans. D.  
17 = 2 x 6 + 5  
89 = 17 x 5 + 4  
359 = 89 x 4 + 3  
1079 = 359 x 3 + 2  
? = 1079 x 2 + 1, i.e. ? = 2159 
3. Ans. B.  
5 = 3 + (1
3
 + 1)  
15 = 5 + (2
3
 + 2)  
45 = 15 + (3
3
 + 3)  
113 = 45 + (4
3
 + 4)  
? = 113 + (5
3
 + 5), i.e. ? = 243 
4. Ans. A.  
4.5 = 7 x 0.5 + 1  
5.5 = 4.5 x 1 + 1  
12 = 5.5 x 2 + 1  
49 = 12 x 4 + 1  
? = 49 x 8 + 1, i.e. ? = 393 
5. Ans. C.  
540 = 3240/6  
108 = 540/5  
27 = 108/4  
? = 27/3, i.e. ? = 9  
4.5 = 9/2 
6. Ans. E.  
Approximating the values:  
(v81 - v25) × (v121 + v16) = ?  
(9 - 5) × (11 + 4) = ?  
4 × 15 = ?  
? = 60 
7. Ans. B.  
53 - 345 ÷ 23 = 2 ×(?)  
53 - 15 = 2 ×(?)  
38 = 2 ×(?)  
? = 19 
8. Ans. C.  
(184 - 6) × 30 = ?  
178 × 30 = ?  
? = 5340 
9. Ans. A.  
v(3100 ÷ 62 + 14) = ?  
v(50 + 14) = ?  
v64 = ?  
? = 8 
10. Ans. C.  
112 × 5 ÷ 14 = 11 + ?  
112 × 5 ÷ 14 = 11 + ?  
560 ÷ 14 = 11 + ?  
40 = 11 + ?  
? = 40 - 11 = 29 
11. Ans. A.  
25% of 84 ÷ 7 = ?  
[(25 × 84)/100]÷ 7 = ?  
21÷ 7 = ?  
? = 3 
12. Ans. B.  
Approximate average number of books sold by 
Shop B during all the days together 
= (15+10+22+22.5+25+17.5)*100/ 6 = 11200/6 
= 1866.66, i.e. approximately 1867  
13. Ans. C.  
Books sold by Shop A on all days 
=(12.5+15+22.5+20+22.5+15)*100 = 10750 
Books sold by Shop B on all days = 
(15+10+22+22.5+25+17.5)*100 = 11200 
Total number of books sold by both Shop A and B 
on all the days together = 11200 + 10750 = 21950 
Number of books sold by Shop B on Friday= 25 × 
100 = 2500 
Required percentage = (2500/21950)*100 = 11% 
(Approx) 
14. Ans. E.  
Number of books sold by Shop A on Thursday = 20 
× 100 = 2000 
number of books sold by Shop B on Monday = 15 × 
100 = 1500 
Required ratio = 2000 : 1500 = 4 : 3 
15. Ans. D.  
Total number of books sold on Friday = (22.5 + 25) 
× 100 = 4750 
Total number of books sold on Thursday = (20 + 
22.5) × 100 
= 4250 
Required percentage = 4750 : 4250 
= 19 : 17 
16. Ans. D.  
The total books sold by Shop B on all days 
excluding Wednesday = (15 + 10 + 22.5 + 25 + 
17.5) = 90 
Total number of books sold on Thursday, Friday and 
Saturday together =65 
Required % = 90/65*100 = 
138.5%, approximately 
 
Page 2


 
 
 
 
1 
 
Solutions 
1. Ans. A.  
98 = 17 + 81  
26 = 98 – 72  
89 = 26 + 63  
35 = 89 – 54  
? = 35 + 45, i.e. ? = 80 
2. Ans. D.  
17 = 2 x 6 + 5  
89 = 17 x 5 + 4  
359 = 89 x 4 + 3  
1079 = 359 x 3 + 2  
? = 1079 x 2 + 1, i.e. ? = 2159 
3. Ans. B.  
5 = 3 + (1
3
 + 1)  
15 = 5 + (2
3
 + 2)  
45 = 15 + (3
3
 + 3)  
113 = 45 + (4
3
 + 4)  
? = 113 + (5
3
 + 5), i.e. ? = 243 
4. Ans. A.  
4.5 = 7 x 0.5 + 1  
5.5 = 4.5 x 1 + 1  
12 = 5.5 x 2 + 1  
49 = 12 x 4 + 1  
? = 49 x 8 + 1, i.e. ? = 393 
5. Ans. C.  
540 = 3240/6  
108 = 540/5  
27 = 108/4  
? = 27/3, i.e. ? = 9  
4.5 = 9/2 
6. Ans. E.  
Approximating the values:  
(v81 - v25) × (v121 + v16) = ?  
(9 - 5) × (11 + 4) = ?  
4 × 15 = ?  
? = 60 
7. Ans. B.  
53 - 345 ÷ 23 = 2 ×(?)  
53 - 15 = 2 ×(?)  
38 = 2 ×(?)  
? = 19 
8. Ans. C.  
(184 - 6) × 30 = ?  
178 × 30 = ?  
? = 5340 
9. Ans. A.  
v(3100 ÷ 62 + 14) = ?  
v(50 + 14) = ?  
v64 = ?  
? = 8 
10. Ans. C.  
112 × 5 ÷ 14 = 11 + ?  
112 × 5 ÷ 14 = 11 + ?  
560 ÷ 14 = 11 + ?  
40 = 11 + ?  
? = 40 - 11 = 29 
11. Ans. A.  
25% of 84 ÷ 7 = ?  
[(25 × 84)/100]÷ 7 = ?  
21÷ 7 = ?  
? = 3 
12. Ans. B.  
Approximate average number of books sold by 
Shop B during all the days together 
= (15+10+22+22.5+25+17.5)*100/ 6 = 11200/6 
= 1866.66, i.e. approximately 1867  
13. Ans. C.  
Books sold by Shop A on all days 
=(12.5+15+22.5+20+22.5+15)*100 = 10750 
Books sold by Shop B on all days = 
(15+10+22+22.5+25+17.5)*100 = 11200 
Total number of books sold by both Shop A and B 
on all the days together = 11200 + 10750 = 21950 
Number of books sold by Shop B on Friday= 25 × 
100 = 2500 
Required percentage = (2500/21950)*100 = 11% 
(Approx) 
14. Ans. E.  
Number of books sold by Shop A on Thursday = 20 
× 100 = 2000 
number of books sold by Shop B on Monday = 15 × 
100 = 1500 
Required ratio = 2000 : 1500 = 4 : 3 
15. Ans. D.  
Total number of books sold on Friday = (22.5 + 25) 
× 100 = 4750 
Total number of books sold on Thursday = (20 + 
22.5) × 100 
= 4250 
Required percentage = 4750 : 4250 
= 19 : 17 
16. Ans. D.  
The total books sold by Shop B on all days 
excluding Wednesday = (15 + 10 + 22.5 + 25 + 
17.5) = 90 
Total number of books sold on Thursday, Friday and 
Saturday together =65 
Required % = 90/65*100 = 
138.5%, approximately 
 
 
 
 
 
2 
 
17. Ans. B.  
Students who take part in group activities from 
class  
VII = (280-210) = 70  
VIII = (310-220) = 90  
X = (220 - 160) = 60  
Average = (70+90+60)/3 = 73.33, i.e. 
approximately 73 
18. Ans. D.  
Students who participate in group singing from 
class VIII = (310-220)* 4/5 = 72  
Students who participate in quiz from IX class = 
(185-95)*2/5 = 36  
Required Ratio = 72:36, i.e. 2:1 
19. Ans. A.  
Number of students who take part in quiz from VII 
& VIII classes together = (70*2/7) + 90*1/5 = 20 
+ 18 = 38  
total students who take part in any activity from 
Class IX = 185-95 = 90  
Required Difference = 90 - 38 = 52 
20. Ans. B.  
Students who take part in group singing from VIII 
and X together = (90*4/5) + (60*7/10) = 72 + 42 
= 114  
Students who take part in quiz from VII = 70*2/7 
= 20  
Required percent = 20/114*100 = 17.54%, i.e. 
approximately 17% 
21. Ans. E.  
Total students who take part in quiz from all the 
classes together =  
(70*2/7) + (90*1/5) + (90*2/5) + (60*3/10)  
= 20 + 18 + 36 + 18 = 92 
22. Ans. C.  
Total students who take part in any activity from 
class VII, VIII & IX = 70 + 90 + 90 = 250  
Total students who do not take part in any activity 
from class IX = 95  
Required % = 95/250 * 100 = 38 
23. Ans. C.  
Given that length of first train + length of second 
train = 660  
Speed of first train : Speed of second train = 5:8 = 
5x : 8x  
Time taken to cross the poll by two trains = 4:3 = 
4y:3y  
Now ,  
(5x*4y) + (8x*3y) = 660  
44xy = 660  
xy = 15  
L1 - L2 = 24xy -20xy = 4xy = 60 m 
 
24. Ans. D.  
Currently :  
A+B+C+D = 76  
According to ques , after 7 years  
A+B+C+D = 7x+6x+5x+8x = 76+7*4  
26x = 76 + 28  
X = 104/26  
x = 4  
C’s present age  
= 5x – 7 =  
20 – 7  
= 13 
25. Ans. C.  
Let 4 consecutive even numbers are  
x, x+ 2, x+ 4, x+ 6  
According to the question -  
1/x + 1/x+2 = 11/60  
x+2+x/ x(x+2) = 11/60  
2(x+1)/x^2 + 2x = 11/60  
120x + 120 = 11x ² + 22x  
11x ² - 98x – 120 = 0  
So ,  
X = -24/22 , 10  
X = -12/11 , 10  
So, the numbers will be 10,12,14,16. 
Hence, 
Third largest number = 14 
Reciprocal of third number = 1/14 
26. Ans. B.  
Let digit = xyz  
Given y = 3  
According to the question =  
(100z+10y+x) - (100x+10y+z) = 396x  
99z-99x = 396  
Z-x = 4  
Also, Z+ x = 14  
Solving (i) & (ii)  
Z = 9 , x= 5  
The original number is 539 
27. Ans. B.  
According to the question ,  
Marked Price = 1600 + Cost price - (i)  
MP – 500 = 125/100 * CP - (ii)  
MP = 5/4 CP + 500 - (ii)  
4MP = 5CP + 2000 -(ii)  
Solving (i) and (ii)  
Cost Price = 4400  
Now , the selling price  
= 130/100 * 4400  
= 5720 
Page 3


 
 
 
 
1 
 
Solutions 
1. Ans. A.  
98 = 17 + 81  
26 = 98 – 72  
89 = 26 + 63  
35 = 89 – 54  
? = 35 + 45, i.e. ? = 80 
2. Ans. D.  
17 = 2 x 6 + 5  
89 = 17 x 5 + 4  
359 = 89 x 4 + 3  
1079 = 359 x 3 + 2  
? = 1079 x 2 + 1, i.e. ? = 2159 
3. Ans. B.  
5 = 3 + (1
3
 + 1)  
15 = 5 + (2
3
 + 2)  
45 = 15 + (3
3
 + 3)  
113 = 45 + (4
3
 + 4)  
? = 113 + (5
3
 + 5), i.e. ? = 243 
4. Ans. A.  
4.5 = 7 x 0.5 + 1  
5.5 = 4.5 x 1 + 1  
12 = 5.5 x 2 + 1  
49 = 12 x 4 + 1  
? = 49 x 8 + 1, i.e. ? = 393 
5. Ans. C.  
540 = 3240/6  
108 = 540/5  
27 = 108/4  
? = 27/3, i.e. ? = 9  
4.5 = 9/2 
6. Ans. E.  
Approximating the values:  
(v81 - v25) × (v121 + v16) = ?  
(9 - 5) × (11 + 4) = ?  
4 × 15 = ?  
? = 60 
7. Ans. B.  
53 - 345 ÷ 23 = 2 ×(?)  
53 - 15 = 2 ×(?)  
38 = 2 ×(?)  
? = 19 
8. Ans. C.  
(184 - 6) × 30 = ?  
178 × 30 = ?  
? = 5340 
9. Ans. A.  
v(3100 ÷ 62 + 14) = ?  
v(50 + 14) = ?  
v64 = ?  
? = 8 
10. Ans. C.  
112 × 5 ÷ 14 = 11 + ?  
112 × 5 ÷ 14 = 11 + ?  
560 ÷ 14 = 11 + ?  
40 = 11 + ?  
? = 40 - 11 = 29 
11. Ans. A.  
25% of 84 ÷ 7 = ?  
[(25 × 84)/100]÷ 7 = ?  
21÷ 7 = ?  
? = 3 
12. Ans. B.  
Approximate average number of books sold by 
Shop B during all the days together 
= (15+10+22+22.5+25+17.5)*100/ 6 = 11200/6 
= 1866.66, i.e. approximately 1867  
13. Ans. C.  
Books sold by Shop A on all days 
=(12.5+15+22.5+20+22.5+15)*100 = 10750 
Books sold by Shop B on all days = 
(15+10+22+22.5+25+17.5)*100 = 11200 
Total number of books sold by both Shop A and B 
on all the days together = 11200 + 10750 = 21950 
Number of books sold by Shop B on Friday= 25 × 
100 = 2500 
Required percentage = (2500/21950)*100 = 11% 
(Approx) 
14. Ans. E.  
Number of books sold by Shop A on Thursday = 20 
× 100 = 2000 
number of books sold by Shop B on Monday = 15 × 
100 = 1500 
Required ratio = 2000 : 1500 = 4 : 3 
15. Ans. D.  
Total number of books sold on Friday = (22.5 + 25) 
× 100 = 4750 
Total number of books sold on Thursday = (20 + 
22.5) × 100 
= 4250 
Required percentage = 4750 : 4250 
= 19 : 17 
16. Ans. D.  
The total books sold by Shop B on all days 
excluding Wednesday = (15 + 10 + 22.5 + 25 + 
17.5) = 90 
Total number of books sold on Thursday, Friday and 
Saturday together =65 
Required % = 90/65*100 = 
138.5%, approximately 
 
 
 
 
 
2 
 
17. Ans. B.  
Students who take part in group activities from 
class  
VII = (280-210) = 70  
VIII = (310-220) = 90  
X = (220 - 160) = 60  
Average = (70+90+60)/3 = 73.33, i.e. 
approximately 73 
18. Ans. D.  
Students who participate in group singing from 
class VIII = (310-220)* 4/5 = 72  
Students who participate in quiz from IX class = 
(185-95)*2/5 = 36  
Required Ratio = 72:36, i.e. 2:1 
19. Ans. A.  
Number of students who take part in quiz from VII 
& VIII classes together = (70*2/7) + 90*1/5 = 20 
+ 18 = 38  
total students who take part in any activity from 
Class IX = 185-95 = 90  
Required Difference = 90 - 38 = 52 
20. Ans. B.  
Students who take part in group singing from VIII 
and X together = (90*4/5) + (60*7/10) = 72 + 42 
= 114  
Students who take part in quiz from VII = 70*2/7 
= 20  
Required percent = 20/114*100 = 17.54%, i.e. 
approximately 17% 
21. Ans. E.  
Total students who take part in quiz from all the 
classes together =  
(70*2/7) + (90*1/5) + (90*2/5) + (60*3/10)  
= 20 + 18 + 36 + 18 = 92 
22. Ans. C.  
Total students who take part in any activity from 
class VII, VIII & IX = 70 + 90 + 90 = 250  
Total students who do not take part in any activity 
from class IX = 95  
Required % = 95/250 * 100 = 38 
23. Ans. C.  
Given that length of first train + length of second 
train = 660  
Speed of first train : Speed of second train = 5:8 = 
5x : 8x  
Time taken to cross the poll by two trains = 4:3 = 
4y:3y  
Now ,  
(5x*4y) + (8x*3y) = 660  
44xy = 660  
xy = 15  
L1 - L2 = 24xy -20xy = 4xy = 60 m 
 
24. Ans. D.  
Currently :  
A+B+C+D = 76  
According to ques , after 7 years  
A+B+C+D = 7x+6x+5x+8x = 76+7*4  
26x = 76 + 28  
X = 104/26  
x = 4  
C’s present age  
= 5x – 7 =  
20 – 7  
= 13 
25. Ans. C.  
Let 4 consecutive even numbers are  
x, x+ 2, x+ 4, x+ 6  
According to the question -  
1/x + 1/x+2 = 11/60  
x+2+x/ x(x+2) = 11/60  
2(x+1)/x^2 + 2x = 11/60  
120x + 120 = 11x ² + 22x  
11x ² - 98x – 120 = 0  
So ,  
X = -24/22 , 10  
X = -12/11 , 10  
So, the numbers will be 10,12,14,16. 
Hence, 
Third largest number = 14 
Reciprocal of third number = 1/14 
26. Ans. B.  
Let digit = xyz  
Given y = 3  
According to the question =  
(100z+10y+x) - (100x+10y+z) = 396x  
99z-99x = 396  
Z-x = 4  
Also, Z+ x = 14  
Solving (i) & (ii)  
Z = 9 , x= 5  
The original number is 539 
27. Ans. B.  
According to the question ,  
Marked Price = 1600 + Cost price - (i)  
MP – 500 = 125/100 * CP - (ii)  
MP = 5/4 CP + 500 - (ii)  
4MP = 5CP + 2000 -(ii)  
Solving (i) and (ii)  
Cost Price = 4400  
Now , the selling price  
= 130/100 * 4400  
= 5720 
 
 
 
 
3 
 
28. Ans. D.  
Time taken by A to complete a work alone - 24 
days  
Time taken by A in completing 1/3 of work = 
24*1/3= 8 Days  
8 day = time taken by B in completing 1/2 of work  
B alone can complete the work = 16 days  
The required time in completing the work if both A 
& B start working together?  
16*24 / 40  
= 48/5 Days 
29. Ans. C.  
Solution:-Distance covered by 1st train in 4 hours 
= 80*4 = 320 km  
Relative speed of 2nd train = 120-80 = 40 km  
It will overtake another train in 320/40 = 8 hours  
Distance between overtake point and station A = 
8*120 = 960 km 
30. Ans. A.  
Let B’s investment = x rs.  
? A’s investment =( x + 1200) rs.  
Ratio of the profits of A and B = 
(x+1200)*(15+4):x*15  
= {19(x+1200)}:15x  
Now,let the total profit of A =y  
? total profit of B = (y-280)  
But total profit = 1240  
?y+(y-280)=1240  
?2y=1520  
?y= 760  
?profit of A = 760rs.  
Profit of B = 760-280=480 rs.  
Ratio of profits= 760:480 = 19:12  
According to the question,  
 =   
?  
?3x = 14400  
?x = 4800 rs.  
?investment of A = 4800+1200  
= 6000 rs. 
31. Ans. A.  
Suppose the two liquids A and B are 7x litres and 
5x litres respectively  
Now, when 9 litres of mixture are taken out,  
  
Now, when 9 liters of liquid B are added 
 
32. Ans. B.  
Let the principal amount be Rs. x  
Calculating SI:  
SI for 1 year at 12% rate is Rs (12/100)*x. For 3 
years it will be Rs (36/100)*x ------ (1)  
Calculating CI:  
For 1
st
 year, Interest = (12/100)*x  
For 2
nd
 year, interest = (12/100)*x + (12/100)*x + 
(144/10000)*x  
For 3
rd
 year, interest = (12/100)*x + (12/100)*x + 
(12/100)*x + (144/10000)*x + (144/10000)*x + 
(1728/1000000)*x. ------ (2)  
Subtracting equation 2 and 1 and solving further,  
312*144*x/1000000 = 112.32  
X = Rs 2500. 
Alternative way:     Using formula for Difference 
between CI and SI for 3 years  
 
we can also use the above formula to find the value 
of P. 
33. Ans. B.  
Let radius of the base and height of the cone be ‘r’ 
& ‘h’ respectively.  
Then volume of cone = pr
2
h/3  
For cylinder, radius is reduced by 4 times = r/4  
And, height is increased by 8 folds = 8h  
Volume of cylinder = pR
2
H = p(r/4)
2
(8h) = 
(16/8)pr
2
h = pr
2
h/2  
Ratio of volume of cone to volume of cylinder = 
(pr
2
h/3) : (pr
2
h/2)  
Or, Ratio = 2 : 3. 
 
Page 4


 
 
 
 
1 
 
Solutions 
1. Ans. A.  
98 = 17 + 81  
26 = 98 – 72  
89 = 26 + 63  
35 = 89 – 54  
? = 35 + 45, i.e. ? = 80 
2. Ans. D.  
17 = 2 x 6 + 5  
89 = 17 x 5 + 4  
359 = 89 x 4 + 3  
1079 = 359 x 3 + 2  
? = 1079 x 2 + 1, i.e. ? = 2159 
3. Ans. B.  
5 = 3 + (1
3
 + 1)  
15 = 5 + (2
3
 + 2)  
45 = 15 + (3
3
 + 3)  
113 = 45 + (4
3
 + 4)  
? = 113 + (5
3
 + 5), i.e. ? = 243 
4. Ans. A.  
4.5 = 7 x 0.5 + 1  
5.5 = 4.5 x 1 + 1  
12 = 5.5 x 2 + 1  
49 = 12 x 4 + 1  
? = 49 x 8 + 1, i.e. ? = 393 
5. Ans. C.  
540 = 3240/6  
108 = 540/5  
27 = 108/4  
? = 27/3, i.e. ? = 9  
4.5 = 9/2 
6. Ans. E.  
Approximating the values:  
(v81 - v25) × (v121 + v16) = ?  
(9 - 5) × (11 + 4) = ?  
4 × 15 = ?  
? = 60 
7. Ans. B.  
53 - 345 ÷ 23 = 2 ×(?)  
53 - 15 = 2 ×(?)  
38 = 2 ×(?)  
? = 19 
8. Ans. C.  
(184 - 6) × 30 = ?  
178 × 30 = ?  
? = 5340 
9. Ans. A.  
v(3100 ÷ 62 + 14) = ?  
v(50 + 14) = ?  
v64 = ?  
? = 8 
10. Ans. C.  
112 × 5 ÷ 14 = 11 + ?  
112 × 5 ÷ 14 = 11 + ?  
560 ÷ 14 = 11 + ?  
40 = 11 + ?  
? = 40 - 11 = 29 
11. Ans. A.  
25% of 84 ÷ 7 = ?  
[(25 × 84)/100]÷ 7 = ?  
21÷ 7 = ?  
? = 3 
12. Ans. B.  
Approximate average number of books sold by 
Shop B during all the days together 
= (15+10+22+22.5+25+17.5)*100/ 6 = 11200/6 
= 1866.66, i.e. approximately 1867  
13. Ans. C.  
Books sold by Shop A on all days 
=(12.5+15+22.5+20+22.5+15)*100 = 10750 
Books sold by Shop B on all days = 
(15+10+22+22.5+25+17.5)*100 = 11200 
Total number of books sold by both Shop A and B 
on all the days together = 11200 + 10750 = 21950 
Number of books sold by Shop B on Friday= 25 × 
100 = 2500 
Required percentage = (2500/21950)*100 = 11% 
(Approx) 
14. Ans. E.  
Number of books sold by Shop A on Thursday = 20 
× 100 = 2000 
number of books sold by Shop B on Monday = 15 × 
100 = 1500 
Required ratio = 2000 : 1500 = 4 : 3 
15. Ans. D.  
Total number of books sold on Friday = (22.5 + 25) 
× 100 = 4750 
Total number of books sold on Thursday = (20 + 
22.5) × 100 
= 4250 
Required percentage = 4750 : 4250 
= 19 : 17 
16. Ans. D.  
The total books sold by Shop B on all days 
excluding Wednesday = (15 + 10 + 22.5 + 25 + 
17.5) = 90 
Total number of books sold on Thursday, Friday and 
Saturday together =65 
Required % = 90/65*100 = 
138.5%, approximately 
 
 
 
 
 
2 
 
17. Ans. B.  
Students who take part in group activities from 
class  
VII = (280-210) = 70  
VIII = (310-220) = 90  
X = (220 - 160) = 60  
Average = (70+90+60)/3 = 73.33, i.e. 
approximately 73 
18. Ans. D.  
Students who participate in group singing from 
class VIII = (310-220)* 4/5 = 72  
Students who participate in quiz from IX class = 
(185-95)*2/5 = 36  
Required Ratio = 72:36, i.e. 2:1 
19. Ans. A.  
Number of students who take part in quiz from VII 
& VIII classes together = (70*2/7) + 90*1/5 = 20 
+ 18 = 38  
total students who take part in any activity from 
Class IX = 185-95 = 90  
Required Difference = 90 - 38 = 52 
20. Ans. B.  
Students who take part in group singing from VIII 
and X together = (90*4/5) + (60*7/10) = 72 + 42 
= 114  
Students who take part in quiz from VII = 70*2/7 
= 20  
Required percent = 20/114*100 = 17.54%, i.e. 
approximately 17% 
21. Ans. E.  
Total students who take part in quiz from all the 
classes together =  
(70*2/7) + (90*1/5) + (90*2/5) + (60*3/10)  
= 20 + 18 + 36 + 18 = 92 
22. Ans. C.  
Total students who take part in any activity from 
class VII, VIII & IX = 70 + 90 + 90 = 250  
Total students who do not take part in any activity 
from class IX = 95  
Required % = 95/250 * 100 = 38 
23. Ans. C.  
Given that length of first train + length of second 
train = 660  
Speed of first train : Speed of second train = 5:8 = 
5x : 8x  
Time taken to cross the poll by two trains = 4:3 = 
4y:3y  
Now ,  
(5x*4y) + (8x*3y) = 660  
44xy = 660  
xy = 15  
L1 - L2 = 24xy -20xy = 4xy = 60 m 
 
24. Ans. D.  
Currently :  
A+B+C+D = 76  
According to ques , after 7 years  
A+B+C+D = 7x+6x+5x+8x = 76+7*4  
26x = 76 + 28  
X = 104/26  
x = 4  
C’s present age  
= 5x – 7 =  
20 – 7  
= 13 
25. Ans. C.  
Let 4 consecutive even numbers are  
x, x+ 2, x+ 4, x+ 6  
According to the question -  
1/x + 1/x+2 = 11/60  
x+2+x/ x(x+2) = 11/60  
2(x+1)/x^2 + 2x = 11/60  
120x + 120 = 11x ² + 22x  
11x ² - 98x – 120 = 0  
So ,  
X = -24/22 , 10  
X = -12/11 , 10  
So, the numbers will be 10,12,14,16. 
Hence, 
Third largest number = 14 
Reciprocal of third number = 1/14 
26. Ans. B.  
Let digit = xyz  
Given y = 3  
According to the question =  
(100z+10y+x) - (100x+10y+z) = 396x  
99z-99x = 396  
Z-x = 4  
Also, Z+ x = 14  
Solving (i) & (ii)  
Z = 9 , x= 5  
The original number is 539 
27. Ans. B.  
According to the question ,  
Marked Price = 1600 + Cost price - (i)  
MP – 500 = 125/100 * CP - (ii)  
MP = 5/4 CP + 500 - (ii)  
4MP = 5CP + 2000 -(ii)  
Solving (i) and (ii)  
Cost Price = 4400  
Now , the selling price  
= 130/100 * 4400  
= 5720 
 
 
 
 
3 
 
28. Ans. D.  
Time taken by A to complete a work alone - 24 
days  
Time taken by A in completing 1/3 of work = 
24*1/3= 8 Days  
8 day = time taken by B in completing 1/2 of work  
B alone can complete the work = 16 days  
The required time in completing the work if both A 
& B start working together?  
16*24 / 40  
= 48/5 Days 
29. Ans. C.  
Solution:-Distance covered by 1st train in 4 hours 
= 80*4 = 320 km  
Relative speed of 2nd train = 120-80 = 40 km  
It will overtake another train in 320/40 = 8 hours  
Distance between overtake point and station A = 
8*120 = 960 km 
30. Ans. A.  
Let B’s investment = x rs.  
? A’s investment =( x + 1200) rs.  
Ratio of the profits of A and B = 
(x+1200)*(15+4):x*15  
= {19(x+1200)}:15x  
Now,let the total profit of A =y  
? total profit of B = (y-280)  
But total profit = 1240  
?y+(y-280)=1240  
?2y=1520  
?y= 760  
?profit of A = 760rs.  
Profit of B = 760-280=480 rs.  
Ratio of profits= 760:480 = 19:12  
According to the question,  
 =   
?  
?3x = 14400  
?x = 4800 rs.  
?investment of A = 4800+1200  
= 6000 rs. 
31. Ans. A.  
Suppose the two liquids A and B are 7x litres and 
5x litres respectively  
Now, when 9 litres of mixture are taken out,  
  
Now, when 9 liters of liquid B are added 
 
32. Ans. B.  
Let the principal amount be Rs. x  
Calculating SI:  
SI for 1 year at 12% rate is Rs (12/100)*x. For 3 
years it will be Rs (36/100)*x ------ (1)  
Calculating CI:  
For 1
st
 year, Interest = (12/100)*x  
For 2
nd
 year, interest = (12/100)*x + (12/100)*x + 
(144/10000)*x  
For 3
rd
 year, interest = (12/100)*x + (12/100)*x + 
(12/100)*x + (144/10000)*x + (144/10000)*x + 
(1728/1000000)*x. ------ (2)  
Subtracting equation 2 and 1 and solving further,  
312*144*x/1000000 = 112.32  
X = Rs 2500. 
Alternative way:     Using formula for Difference 
between CI and SI for 3 years  
 
we can also use the above formula to find the value 
of P. 
33. Ans. B.  
Let radius of the base and height of the cone be ‘r’ 
& ‘h’ respectively.  
Then volume of cone = pr
2
h/3  
For cylinder, radius is reduced by 4 times = r/4  
And, height is increased by 8 folds = 8h  
Volume of cylinder = pR
2
H = p(r/4)
2
(8h) = 
(16/8)pr
2
h = pr
2
h/2  
Ratio of volume of cone to volume of cylinder = 
(pr
2
h/3) : (pr
2
h/2)  
Or, Ratio = 2 : 3. 
 
 
 
 
 
4 
 
34. Ans. E.  
Suppose the speed of boat in still water is x km/h 
and speed of stream is y km/h  
Speed of boat in downstream = (x + y) km/h  
 x + y = 32 …(i)  
Speed of boat in upstream = (x – y) km/h  
 x – y = 28 …(ii)  
Add. Eqs. (i) and (ii), we get  
2x = 60  
x = 30 km/h 
35. Ans. D.  
CP of mixture = {(40*3+60*2)/2+3} = 48  
SP of the mixture = 1.1 48 =52.8 
36. Ans. D.  
In option D, ‘apart’ is incorrect after ‘to drain 
water’. 
37. Ans. C.  
In option C, ‘has’ is incorrectly used since the 
sentence is in past tense. Moreover, the subject is 
cities, which is plural. 
38. Ans. D.  
Option D: ‘Documentation of the seasonality in 
native people’ doesn’t make sense. 
39. Ans. E.  
Options A, C and E in the absence of a proper 
subject add the ‘bag’ automatically to the verb 
‘racing for the bus’. So, it does not make any sense 
as it would mean that the bag is racing for the bus. 
Option B is incorrect because of the fragment 
‘making the documents lose’. Option D doesn't 
convey a proper meaning. 
40. Ans. D.  
We have to find the incorrect statement. All the 
sentences except D have been correctly structured. 
In option D, the phrase ‘complied into by’ is 
incorrect. You "comply with" a rule or a law and not 
by cities. 
41. Ans. E.  
Option A: ‘legally state-issued currencies’ is 
incorrect. The word describes the state-issued 
currencies; hence it should be an adjective and not 
an adverb.  
Option B: ‘state-issues’ is incorrect and should be 
replaced by ‘state-issued’.  
Option C: ‘carry in’ is grammatically incorrect.  
Option D: ‘to carrying out’ is grammatically 
incorrect. 
42. Ans. E.  
Triptych means a set of three associated artistic, 
literary, or musical works intended to be 
appreciated together.  
 
Triptychal doesn’t make sense, hence options A, B 
and C can be eliminated.  
Sentence D doesn’t convey any meaning. 
43. Ans. B.  
Option B- ‘stations of numerical small nations’ is 
incorrect. 
The other statements make complete sense, hence 
are correct.  
44. Ans. E.  
In the given sentences, boiled down is the phrasal 
verb that should have been used which means 
summarizing something, to reduce or simplify 
(something) to the most basic, essential, or 
fundamental element(s). In this context it means 
that the one who had more power, succeeded. 
'Boiled down' should be followed by 'to' and not 
'for', hence option D is incorrect.  
45. Ans. D.  
Solution: In the given sentences banking upon is 
the correct phrasal verb which means basing hopes 
on someone/something or depending on someone 
for something. 
Option D is incorrect because bank of does not have 
any relevant meaning in the given context. 
46. Ans. A.  
The answer is 'give me a ballpark figure of how 
much this event is going to cost.' A ballpark figure 
is a rough numerical estimate or approximation. 
47. Ans. C.  
The statement is in general sense and doesn’t talk 
in past or future context specifically. Therefore one 
must use the present tense of the verb. Thus, 
'provide' is the correct answer. 
48. Ans. B.  
‘to stick to one’s guns’ means refuse to compromise 
or change, despite criticism. It is a phrasal verb 
hence we can’t make any changes in the 
prepositions used. The sentence is in past tense, 
hence stick should be replaced by stuck. 
49. Ans. B.  
The correct form of verb to be used after 'will' is 
'help.' Verbs are not needed in infinitive or 
participle form here since the effect of the disposal 
of assets will be seen in the future. So option B is 
the correct answer. 
50. Ans. B.  
The correct preposition here would be 'by'.  
By follows 'represented' when something takes the 
place of and refers to something bigger.  
With follows 'represented' when an attribute with 
which something or someone is depicted.  
A contract is not represented in a policy but stated 
in a policy. 
Page 5


 
 
 
 
1 
 
Solutions 
1. Ans. A.  
98 = 17 + 81  
26 = 98 – 72  
89 = 26 + 63  
35 = 89 – 54  
? = 35 + 45, i.e. ? = 80 
2. Ans. D.  
17 = 2 x 6 + 5  
89 = 17 x 5 + 4  
359 = 89 x 4 + 3  
1079 = 359 x 3 + 2  
? = 1079 x 2 + 1, i.e. ? = 2159 
3. Ans. B.  
5 = 3 + (1
3
 + 1)  
15 = 5 + (2
3
 + 2)  
45 = 15 + (3
3
 + 3)  
113 = 45 + (4
3
 + 4)  
? = 113 + (5
3
 + 5), i.e. ? = 243 
4. Ans. A.  
4.5 = 7 x 0.5 + 1  
5.5 = 4.5 x 1 + 1  
12 = 5.5 x 2 + 1  
49 = 12 x 4 + 1  
? = 49 x 8 + 1, i.e. ? = 393 
5. Ans. C.  
540 = 3240/6  
108 = 540/5  
27 = 108/4  
? = 27/3, i.e. ? = 9  
4.5 = 9/2 
6. Ans. E.  
Approximating the values:  
(v81 - v25) × (v121 + v16) = ?  
(9 - 5) × (11 + 4) = ?  
4 × 15 = ?  
? = 60 
7. Ans. B.  
53 - 345 ÷ 23 = 2 ×(?)  
53 - 15 = 2 ×(?)  
38 = 2 ×(?)  
? = 19 
8. Ans. C.  
(184 - 6) × 30 = ?  
178 × 30 = ?  
? = 5340 
9. Ans. A.  
v(3100 ÷ 62 + 14) = ?  
v(50 + 14) = ?  
v64 = ?  
? = 8 
10. Ans. C.  
112 × 5 ÷ 14 = 11 + ?  
112 × 5 ÷ 14 = 11 + ?  
560 ÷ 14 = 11 + ?  
40 = 11 + ?  
? = 40 - 11 = 29 
11. Ans. A.  
25% of 84 ÷ 7 = ?  
[(25 × 84)/100]÷ 7 = ?  
21÷ 7 = ?  
? = 3 
12. Ans. B.  
Approximate average number of books sold by 
Shop B during all the days together 
= (15+10+22+22.5+25+17.5)*100/ 6 = 11200/6 
= 1866.66, i.e. approximately 1867  
13. Ans. C.  
Books sold by Shop A on all days 
=(12.5+15+22.5+20+22.5+15)*100 = 10750 
Books sold by Shop B on all days = 
(15+10+22+22.5+25+17.5)*100 = 11200 
Total number of books sold by both Shop A and B 
on all the days together = 11200 + 10750 = 21950 
Number of books sold by Shop B on Friday= 25 × 
100 = 2500 
Required percentage = (2500/21950)*100 = 11% 
(Approx) 
14. Ans. E.  
Number of books sold by Shop A on Thursday = 20 
× 100 = 2000 
number of books sold by Shop B on Monday = 15 × 
100 = 1500 
Required ratio = 2000 : 1500 = 4 : 3 
15. Ans. D.  
Total number of books sold on Friday = (22.5 + 25) 
× 100 = 4750 
Total number of books sold on Thursday = (20 + 
22.5) × 100 
= 4250 
Required percentage = 4750 : 4250 
= 19 : 17 
16. Ans. D.  
The total books sold by Shop B on all days 
excluding Wednesday = (15 + 10 + 22.5 + 25 + 
17.5) = 90 
Total number of books sold on Thursday, Friday and 
Saturday together =65 
Required % = 90/65*100 = 
138.5%, approximately 
 
 
 
 
 
2 
 
17. Ans. B.  
Students who take part in group activities from 
class  
VII = (280-210) = 70  
VIII = (310-220) = 90  
X = (220 - 160) = 60  
Average = (70+90+60)/3 = 73.33, i.e. 
approximately 73 
18. Ans. D.  
Students who participate in group singing from 
class VIII = (310-220)* 4/5 = 72  
Students who participate in quiz from IX class = 
(185-95)*2/5 = 36  
Required Ratio = 72:36, i.e. 2:1 
19. Ans. A.  
Number of students who take part in quiz from VII 
& VIII classes together = (70*2/7) + 90*1/5 = 20 
+ 18 = 38  
total students who take part in any activity from 
Class IX = 185-95 = 90  
Required Difference = 90 - 38 = 52 
20. Ans. B.  
Students who take part in group singing from VIII 
and X together = (90*4/5) + (60*7/10) = 72 + 42 
= 114  
Students who take part in quiz from VII = 70*2/7 
= 20  
Required percent = 20/114*100 = 17.54%, i.e. 
approximately 17% 
21. Ans. E.  
Total students who take part in quiz from all the 
classes together =  
(70*2/7) + (90*1/5) + (90*2/5) + (60*3/10)  
= 20 + 18 + 36 + 18 = 92 
22. Ans. C.  
Total students who take part in any activity from 
class VII, VIII & IX = 70 + 90 + 90 = 250  
Total students who do not take part in any activity 
from class IX = 95  
Required % = 95/250 * 100 = 38 
23. Ans. C.  
Given that length of first train + length of second 
train = 660  
Speed of first train : Speed of second train = 5:8 = 
5x : 8x  
Time taken to cross the poll by two trains = 4:3 = 
4y:3y  
Now ,  
(5x*4y) + (8x*3y) = 660  
44xy = 660  
xy = 15  
L1 - L2 = 24xy -20xy = 4xy = 60 m 
 
24. Ans. D.  
Currently :  
A+B+C+D = 76  
According to ques , after 7 years  
A+B+C+D = 7x+6x+5x+8x = 76+7*4  
26x = 76 + 28  
X = 104/26  
x = 4  
C’s present age  
= 5x – 7 =  
20 – 7  
= 13 
25. Ans. C.  
Let 4 consecutive even numbers are  
x, x+ 2, x+ 4, x+ 6  
According to the question -  
1/x + 1/x+2 = 11/60  
x+2+x/ x(x+2) = 11/60  
2(x+1)/x^2 + 2x = 11/60  
120x + 120 = 11x ² + 22x  
11x ² - 98x – 120 = 0  
So ,  
X = -24/22 , 10  
X = -12/11 , 10  
So, the numbers will be 10,12,14,16. 
Hence, 
Third largest number = 14 
Reciprocal of third number = 1/14 
26. Ans. B.  
Let digit = xyz  
Given y = 3  
According to the question =  
(100z+10y+x) - (100x+10y+z) = 396x  
99z-99x = 396  
Z-x = 4  
Also, Z+ x = 14  
Solving (i) & (ii)  
Z = 9 , x= 5  
The original number is 539 
27. Ans. B.  
According to the question ,  
Marked Price = 1600 + Cost price - (i)  
MP – 500 = 125/100 * CP - (ii)  
MP = 5/4 CP + 500 - (ii)  
4MP = 5CP + 2000 -(ii)  
Solving (i) and (ii)  
Cost Price = 4400  
Now , the selling price  
= 130/100 * 4400  
= 5720 
 
 
 
 
3 
 
28. Ans. D.  
Time taken by A to complete a work alone - 24 
days  
Time taken by A in completing 1/3 of work = 
24*1/3= 8 Days  
8 day = time taken by B in completing 1/2 of work  
B alone can complete the work = 16 days  
The required time in completing the work if both A 
& B start working together?  
16*24 / 40  
= 48/5 Days 
29. Ans. C.  
Solution:-Distance covered by 1st train in 4 hours 
= 80*4 = 320 km  
Relative speed of 2nd train = 120-80 = 40 km  
It will overtake another train in 320/40 = 8 hours  
Distance between overtake point and station A = 
8*120 = 960 km 
30. Ans. A.  
Let B’s investment = x rs.  
? A’s investment =( x + 1200) rs.  
Ratio of the profits of A and B = 
(x+1200)*(15+4):x*15  
= {19(x+1200)}:15x  
Now,let the total profit of A =y  
? total profit of B = (y-280)  
But total profit = 1240  
?y+(y-280)=1240  
?2y=1520  
?y= 760  
?profit of A = 760rs.  
Profit of B = 760-280=480 rs.  
Ratio of profits= 760:480 = 19:12  
According to the question,  
 =   
?  
?3x = 14400  
?x = 4800 rs.  
?investment of A = 4800+1200  
= 6000 rs. 
31. Ans. A.  
Suppose the two liquids A and B are 7x litres and 
5x litres respectively  
Now, when 9 litres of mixture are taken out,  
  
Now, when 9 liters of liquid B are added 
 
32. Ans. B.  
Let the principal amount be Rs. x  
Calculating SI:  
SI for 1 year at 12% rate is Rs (12/100)*x. For 3 
years it will be Rs (36/100)*x ------ (1)  
Calculating CI:  
For 1
st
 year, Interest = (12/100)*x  
For 2
nd
 year, interest = (12/100)*x + (12/100)*x + 
(144/10000)*x  
For 3
rd
 year, interest = (12/100)*x + (12/100)*x + 
(12/100)*x + (144/10000)*x + (144/10000)*x + 
(1728/1000000)*x. ------ (2)  
Subtracting equation 2 and 1 and solving further,  
312*144*x/1000000 = 112.32  
X = Rs 2500. 
Alternative way:     Using formula for Difference 
between CI and SI for 3 years  
 
we can also use the above formula to find the value 
of P. 
33. Ans. B.  
Let radius of the base and height of the cone be ‘r’ 
& ‘h’ respectively.  
Then volume of cone = pr
2
h/3  
For cylinder, radius is reduced by 4 times = r/4  
And, height is increased by 8 folds = 8h  
Volume of cylinder = pR
2
H = p(r/4)
2
(8h) = 
(16/8)pr
2
h = pr
2
h/2  
Ratio of volume of cone to volume of cylinder = 
(pr
2
h/3) : (pr
2
h/2)  
Or, Ratio = 2 : 3. 
 
 
 
 
 
4 
 
34. Ans. E.  
Suppose the speed of boat in still water is x km/h 
and speed of stream is y km/h  
Speed of boat in downstream = (x + y) km/h  
 x + y = 32 …(i)  
Speed of boat in upstream = (x – y) km/h  
 x – y = 28 …(ii)  
Add. Eqs. (i) and (ii), we get  
2x = 60  
x = 30 km/h 
35. Ans. D.  
CP of mixture = {(40*3+60*2)/2+3} = 48  
SP of the mixture = 1.1 48 =52.8 
36. Ans. D.  
In option D, ‘apart’ is incorrect after ‘to drain 
water’. 
37. Ans. C.  
In option C, ‘has’ is incorrectly used since the 
sentence is in past tense. Moreover, the subject is 
cities, which is plural. 
38. Ans. D.  
Option D: ‘Documentation of the seasonality in 
native people’ doesn’t make sense. 
39. Ans. E.  
Options A, C and E in the absence of a proper 
subject add the ‘bag’ automatically to the verb 
‘racing for the bus’. So, it does not make any sense 
as it would mean that the bag is racing for the bus. 
Option B is incorrect because of the fragment 
‘making the documents lose’. Option D doesn't 
convey a proper meaning. 
40. Ans. D.  
We have to find the incorrect statement. All the 
sentences except D have been correctly structured. 
In option D, the phrase ‘complied into by’ is 
incorrect. You "comply with" a rule or a law and not 
by cities. 
41. Ans. E.  
Option A: ‘legally state-issued currencies’ is 
incorrect. The word describes the state-issued 
currencies; hence it should be an adjective and not 
an adverb.  
Option B: ‘state-issues’ is incorrect and should be 
replaced by ‘state-issued’.  
Option C: ‘carry in’ is grammatically incorrect.  
Option D: ‘to carrying out’ is grammatically 
incorrect. 
42. Ans. E.  
Triptych means a set of three associated artistic, 
literary, or musical works intended to be 
appreciated together.  
 
Triptychal doesn’t make sense, hence options A, B 
and C can be eliminated.  
Sentence D doesn’t convey any meaning. 
43. Ans. B.  
Option B- ‘stations of numerical small nations’ is 
incorrect. 
The other statements make complete sense, hence 
are correct.  
44. Ans. E.  
In the given sentences, boiled down is the phrasal 
verb that should have been used which means 
summarizing something, to reduce or simplify 
(something) to the most basic, essential, or 
fundamental element(s). In this context it means 
that the one who had more power, succeeded. 
'Boiled down' should be followed by 'to' and not 
'for', hence option D is incorrect.  
45. Ans. D.  
Solution: In the given sentences banking upon is 
the correct phrasal verb which means basing hopes 
on someone/something or depending on someone 
for something. 
Option D is incorrect because bank of does not have 
any relevant meaning in the given context. 
46. Ans. A.  
The answer is 'give me a ballpark figure of how 
much this event is going to cost.' A ballpark figure 
is a rough numerical estimate or approximation. 
47. Ans. C.  
The statement is in general sense and doesn’t talk 
in past or future context specifically. Therefore one 
must use the present tense of the verb. Thus, 
'provide' is the correct answer. 
48. Ans. B.  
‘to stick to one’s guns’ means refuse to compromise 
or change, despite criticism. It is a phrasal verb 
hence we can’t make any changes in the 
prepositions used. The sentence is in past tense, 
hence stick should be replaced by stuck. 
49. Ans. B.  
The correct form of verb to be used after 'will' is 
'help.' Verbs are not needed in infinitive or 
participle form here since the effect of the disposal 
of assets will be seen in the future. So option B is 
the correct answer. 
50. Ans. B.  
The correct preposition here would be 'by'.  
By follows 'represented' when something takes the 
place of and refers to something bigger.  
With follows 'represented' when an attribute with 
which something or someone is depicted.  
A contract is not represented in a policy but stated 
in a policy. 
 
 
 
 
5 
 
51. Ans. C.  
The answer is the ‘vilest thing that can be done by 
a person.' Vile/vilest means extremely unpleasant.  
Option A: A singular thing is being talked about 
(indicated by ‘is’) hence, things can’t be used.  
Option B: ‘is’ indicates singular activity, hence 
things can’t be used.  
Option C: It makes the sentence grammatically and 
structurally correct. 
52. Ans. B.  
A- The subject is ‘trees’, which is plural, so the use 
of ‘has’ is incorrect as a helping verb. 
B- The fragment makes the sentence structurally 
and grammatically correct. 
D- The subject is plural and therefore ‘its’ can’t be 
used to address the subject. 
53. Ans. A.  
‘in to’ is the wrong usage of preposition.  
ii- ‘onto’ is the wrong usage of preposition. 
iii- ‘Who’ is a redundant word and distorts the 
meaning of the statement. .  
‘puts at’ makes the sentence correct. 
54. Ans. E.  
i. is incorrect because of the incorrect use of open”. 
ii. is incorrect because of the incorrect use of 
“opened” hopefully represents future while opened 
represents past. This makes the sentence 
structurally incorrect. 
C is correct because of the correct use of “would 
open” and delivers correct meaning to the 
sentence. 'would' is used to refer to the possibility 
in the future which is supported by the use of the 
word 'hopefully'. 
iii. is incorrect because of the incorrect use of “is 
opening”. 
55. Ans. E.  
i- ‘that things’ is incorrect. 
ii- This is wrong because it is not unprofitable for 
the professionals but the political masters of health 
care. 
iii-It is structurally incorrect. It should be has not 
been. 
56. Ans. D.  
This can be interpreted from these lines, “Second, 
reforms to the tax system were carried out, giving 
the central government an increasing share of the 
total fiscal revenue and thereby enhancing its 
dominance over the allocation of resources. This 
has seriously threatened marketization reform and, 
arguably, has even damaged the market 
mechanism and competition.” Hence, option D is 
the correct answer. 
 
57. Ans. D.  
In the given passage, the author has explained all 
the factors that contributed to the imbalance in the 
Chinese economy. Further, the implications of such 
factors on the trade, finance and economy have 
also been dealt with. Hence, the correct answer is 
option D. 
58. Ans. D.  
Statement (i) can be interpreted from these lines, 
“… the government retained its monopoly of 
lucrative services such as telecommunication and 
financial services while discarding the burden of 
some public services.” Statement (ii) can be 
interpreted from these lines, “The early 1990s 
marked a turning point in the Chinese economy, 
which had been gradually evolving since the late 
1970s when the policy of reform and opening was 
adopted.” Statement (iii) is incorrect, rather the 
policy of reforms exacerbated the unbalanced 
situation which can be interpreted from these lines, 
“As the significant changes got underway in the 
early 1990s, they had the effect of enhancing, or of 
continuously exacerbating, an already unbalanced 
situation.” 
59. Ans. B.  
The government expenditure and government 
investment policies proved detrimental to 
investment and household expenditure which can 
be interpreted from these lines, “The third and 
fourth developments since the early 1990s 
(outlined above) mean that, in effect, government 
expenditure is squeezing out household 
expenditure, and government investment policies 
(via SOEs and SOBs) are discouraging and even 
forcing out private investment.” Hence, option B is 
the correct answer. 
60. Ans. A.  
Sluggish means dull or slow moving, torpid means 
the same. 
Torpid - mentally or physically inactive; lethargic. 
Active - engaging or ready to engage in physically 
energetic pursuits. 
Spirited - full of energy, enthusiasm, and 
determination. 
Squally - related to weather 
61. Ans. A.  
Exacerbate means to make worse. Contrary to it, 
'aid' which means to help is the most suitable 
response. 
 
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FAQs on IBPS PO Prelims Question Paper Solution-2017 - IBPS PO Prelims & Mains - Documents, Videos & Tests - Bank Exams

1. What is the IBPS PO Prelims exam?
Ans. The IBPS PO Prelims exam is a banking exam conducted by the Institute of Banking Personnel Selection (IBPS) to recruit probationary officers (PO) in various public sector banks in India. It is the first stage of the selection process.
2. What is the pattern of the IBPS PO Prelims exam?
Ans. The IBPS PO Prelims exam consists of three sections: English Language, Quantitative Aptitude, and Reasoning Ability. Each section has a specific number of questions and a time limit. The exam is conducted online and is objective in nature.
3. How can I prepare for the IBPS PO Prelims exam?
Ans. To prepare for the IBPS PO Prelims exam, you can follow these steps: - Understand the exam pattern and syllabus. - Create a study plan and schedule. - Study and practice each section thoroughly. - Solve previous year question papers and mock tests. - Stay updated with current affairs and banking awareness. - Analyze your performance and work on weak areas.
4. What is the eligibility criteria for the IBPS PO Prelims exam?
Ans. The eligibility criteria for the IBPS PO Prelims exam are as follows: - Nationality: Must be a citizen of India or a subject of Nepal/Bhutan. - Age: Must be between 20 to 30 years. - Educational Qualification: Must have a degree (graduation) in any discipline from a recognized university.
5. What is the selection process for the IBPS PO exam?
Ans. The selection process for the IBPS PO exam consists of three stages: - Preliminary Exam: It is the first stage and acts as a screening test. - Main Exam: Candidates who qualify the Prelims are eligible for the Main exam, which is the second stage. - Interview: Candidates who clear the Main exam are called for the interview, which is the final stage of the selection process.
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