Page 1
17
th
Mar. 2021 | Shift 2
SECTION – A
1. Two identical blocks A and B each of mass m resting on the smooth horizontal floor are
connected by a light spring of natural length L and spring constant K. A third block C of mass m
moving with a speed v along the line joining A and B collides with A. The maximum compression
in the spring is
C A B
m m
m
(1)
mv
2K
(2)
m
2K
(3)
mv
K
(4)
m
v
2K
Sol. (4)
C A ?V
1
B ?V
1
m m
m
v
From conservation of momentum
mv = mv
1
+ mv
1
V
1
=
V
2
A ?V/2 B ? V/2
m m
& from energy conservation
2
2 2
1 1 V 1
mv m 2 Kx
2 2 2 2
? ?
? ?
? ? ? ? ? ?
? ?
? ?
? ?
? ?
2 2
2
mv mv 1
kx
2 4 2
? ?
2
2
mv 1
kx
4 2
?
Then the maximum compression in the spring is
2
mv
x
2K
?
m
x v
2K
?
-
2. A sphere of mass 2 kg radius 0.5m is rolling with an initial speed of 1 ms
-1
goes up an inclined
plane which makes an angle of 30
0
with the horizontal plane, without slipping. How long will the
sphere take to return to the starting point A ?
30
0
A
(1) 0.80 s (2) 0.60 s (3) 0.52 s (4) 0.57 s
Sol. (4)
Page 2
17
th
Mar. 2021 | Shift 2
SECTION – A
1. Two identical blocks A and B each of mass m resting on the smooth horizontal floor are
connected by a light spring of natural length L and spring constant K. A third block C of mass m
moving with a speed v along the line joining A and B collides with A. The maximum compression
in the spring is
C A B
m m
m
(1)
mv
2K
(2)
m
2K
(3)
mv
K
(4)
m
v
2K
Sol. (4)
C A ?V
1
B ?V
1
m m
m
v
From conservation of momentum
mv = mv
1
+ mv
1
V
1
=
V
2
A ?V/2 B ? V/2
m m
& from energy conservation
2
2 2
1 1 V 1
mv m 2 Kx
2 2 2 2
? ?
? ?
? ? ? ? ? ?
? ?
? ?
? ?
? ?
2 2
2
mv mv 1
kx
2 4 2
? ?
2
2
mv 1
kx
4 2
?
Then the maximum compression in the spring is
2
mv
x
2K
?
m
x v
2K
?
-
2. A sphere of mass 2 kg radius 0.5m is rolling with an initial speed of 1 ms
-1
goes up an inclined
plane which makes an angle of 30
0
with the horizontal plane, without slipping. How long will the
sphere take to return to the starting point A ?
30
0
A
(1) 0.80 s (2) 0.60 s (3) 0.52 s (4) 0.57 s
Sol. (4)
mg sin ?
f
30
0
A
gsin
a
1 c
?
?
?
9.8sin30º
a
2
1
5
?
?
a = 3.5 m/sec
2
Time of accent
V = u + at
0 = 1 –3.5 t
t =
1
3.5
sec.
Time of decent
t =
1
3.5
sec.
Total time
2
T
3.5
? =0.57 sec.
3. If one mole of the polyatomic gas is having two vibrational modes and ? is the ratio of molar
specific heats for polyatomic gas p
v
C
C
? ?
? ?
? ?
? ?
then the value of ? is :
(1) 1.35 (2) 1.02 (3) 1.25 (4) 1.2
Sol. (NTA answer is 4) our answer is (3)
Degree of freedom of polyatomic gas
f = T + R + V
f = 3 + 3 + 2 = 8
? = 1 +
2
f
=
2
1
8
?
10 5
1.25
8 4
? ? ? ?
4. Two cells of emf 2E and E with internal resistance r
1
and r
2
respectively are connected in series
to an external resistor R (see figure). The value of R, at which the potential difference across
the terminals of the first cell becomes zero is
R
E 2E
(1)
1 2
r r ? (2)
1 2
r r ? (3)
1
2
r
r
2
? (4)
1
2
r
r
2
?
Page 3
17
th
Mar. 2021 | Shift 2
SECTION – A
1. Two identical blocks A and B each of mass m resting on the smooth horizontal floor are
connected by a light spring of natural length L and spring constant K. A third block C of mass m
moving with a speed v along the line joining A and B collides with A. The maximum compression
in the spring is
C A B
m m
m
(1)
mv
2K
(2)
m
2K
(3)
mv
K
(4)
m
v
2K
Sol. (4)
C A ?V
1
B ?V
1
m m
m
v
From conservation of momentum
mv = mv
1
+ mv
1
V
1
=
V
2
A ?V/2 B ? V/2
m m
& from energy conservation
2
2 2
1 1 V 1
mv m 2 Kx
2 2 2 2
? ?
? ?
? ? ? ? ? ?
? ?
? ?
? ?
? ?
2 2
2
mv mv 1
kx
2 4 2
? ?
2
2
mv 1
kx
4 2
?
Then the maximum compression in the spring is
2
mv
x
2K
?
m
x v
2K
?
-
2. A sphere of mass 2 kg radius 0.5m is rolling with an initial speed of 1 ms
-1
goes up an inclined
plane which makes an angle of 30
0
with the horizontal plane, without slipping. How long will the
sphere take to return to the starting point A ?
30
0
A
(1) 0.80 s (2) 0.60 s (3) 0.52 s (4) 0.57 s
Sol. (4)
mg sin ?
f
30
0
A
gsin
a
1 c
?
?
?
9.8sin30º
a
2
1
5
?
?
a = 3.5 m/sec
2
Time of accent
V = u + at
0 = 1 –3.5 t
t =
1
3.5
sec.
Time of decent
t =
1
3.5
sec.
Total time
2
T
3.5
? =0.57 sec.
3. If one mole of the polyatomic gas is having two vibrational modes and ? is the ratio of molar
specific heats for polyatomic gas p
v
C
C
? ?
? ?
? ?
? ?
then the value of ? is :
(1) 1.35 (2) 1.02 (3) 1.25 (4) 1.2
Sol. (NTA answer is 4) our answer is (3)
Degree of freedom of polyatomic gas
f = T + R + V
f = 3 + 3 + 2 = 8
? = 1 +
2
f
=
2
1
8
?
10 5
1.25
8 4
? ? ? ?
4. Two cells of emf 2E and E with internal resistance r
1
and r
2
respectively are connected in series
to an external resistor R (see figure). The value of R, at which the potential difference across
the terminals of the first cell becomes zero is
R
E 2E
(1)
1 2
r r ? (2)
1 2
r r ? (3)
1
2
r
r
2
? (4)
1
2
r
r
2
?
17
th
Mar. 2021 | Shift 2
Sol. (4)
R
E 2E
A B
r
2
r
1
1 2
3E
R r r
?
? ?
?
2E
r
1
B A
i
V
A
= V
B
2 E = i r
1
2E =
1 2
3E
R r r ? ?
r
1
2R + 2r
1
+ 2r
2
= 3r
1
R =
1
2
r
r
2
?
5. A sound wave of frequency 245 Hz travels with the speed of 300 ms
-1
along the positive x-axis.
Each point of the wave move to and fro through a total distance of 6 cm. What will be the
mathematical expression of the travelling wave ?
(1)
? ?
3
Y(x,t) 0.03 sin5.1x 0.2 10 t
? ?
? ? ?
? ?
(2)
? ?
3
Y(x,t) 0.06 sin5.1x 1.5 10 t
? ?
? ? ?
? ?
(3)
? ?
3
Y(x,t) 0.06 sin0.8x 0.5 10 t
? ?
? ? ?
? ?
(4)
? ?
3
Y(x,t) 0.03 sin5.1x 1.5 10 t
? ?
? ? ?
? ?
Sol. (4)
Y = A sin (kx - ?t)
A =
6
2
= 3cm = 0.03 m
? = 2 ? f = 2 ? ×245
? = 1.5 ×10
3
k =
3
1.5 10
v 300
? ?
?
k = 5.1
y = 0.03 sin (5.1x – 1.5 × 10
3
t)
Page 4
17
th
Mar. 2021 | Shift 2
SECTION – A
1. Two identical blocks A and B each of mass m resting on the smooth horizontal floor are
connected by a light spring of natural length L and spring constant K. A third block C of mass m
moving with a speed v along the line joining A and B collides with A. The maximum compression
in the spring is
C A B
m m
m
(1)
mv
2K
(2)
m
2K
(3)
mv
K
(4)
m
v
2K
Sol. (4)
C A ?V
1
B ?V
1
m m
m
v
From conservation of momentum
mv = mv
1
+ mv
1
V
1
=
V
2
A ?V/2 B ? V/2
m m
& from energy conservation
2
2 2
1 1 V 1
mv m 2 Kx
2 2 2 2
? ?
? ?
? ? ? ? ? ?
? ?
? ?
? ?
? ?
2 2
2
mv mv 1
kx
2 4 2
? ?
2
2
mv 1
kx
4 2
?
Then the maximum compression in the spring is
2
mv
x
2K
?
m
x v
2K
?
-
2. A sphere of mass 2 kg radius 0.5m is rolling with an initial speed of 1 ms
-1
goes up an inclined
plane which makes an angle of 30
0
with the horizontal plane, without slipping. How long will the
sphere take to return to the starting point A ?
30
0
A
(1) 0.80 s (2) 0.60 s (3) 0.52 s (4) 0.57 s
Sol. (4)
mg sin ?
f
30
0
A
gsin
a
1 c
?
?
?
9.8sin30º
a
2
1
5
?
?
a = 3.5 m/sec
2
Time of accent
V = u + at
0 = 1 –3.5 t
t =
1
3.5
sec.
Time of decent
t =
1
3.5
sec.
Total time
2
T
3.5
? =0.57 sec.
3. If one mole of the polyatomic gas is having two vibrational modes and ? is the ratio of molar
specific heats for polyatomic gas p
v
C
C
? ?
? ?
? ?
? ?
then the value of ? is :
(1) 1.35 (2) 1.02 (3) 1.25 (4) 1.2
Sol. (NTA answer is 4) our answer is (3)
Degree of freedom of polyatomic gas
f = T + R + V
f = 3 + 3 + 2 = 8
? = 1 +
2
f
=
2
1
8
?
10 5
1.25
8 4
? ? ? ?
4. Two cells of emf 2E and E with internal resistance r
1
and r
2
respectively are connected in series
to an external resistor R (see figure). The value of R, at which the potential difference across
the terminals of the first cell becomes zero is
R
E 2E
(1)
1 2
r r ? (2)
1 2
r r ? (3)
1
2
r
r
2
? (4)
1
2
r
r
2
?
17
th
Mar. 2021 | Shift 2
Sol. (4)
R
E 2E
A B
r
2
r
1
1 2
3E
R r r
?
? ?
?
2E
r
1
B A
i
V
A
= V
B
2 E = i r
1
2E =
1 2
3E
R r r ? ?
r
1
2R + 2r
1
+ 2r
2
= 3r
1
R =
1
2
r
r
2
?
5. A sound wave of frequency 245 Hz travels with the speed of 300 ms
-1
along the positive x-axis.
Each point of the wave move to and fro through a total distance of 6 cm. What will be the
mathematical expression of the travelling wave ?
(1)
? ?
3
Y(x,t) 0.03 sin5.1x 0.2 10 t
? ?
? ? ?
? ?
(2)
? ?
3
Y(x,t) 0.06 sin5.1x 1.5 10 t
? ?
? ? ?
? ?
(3)
? ?
3
Y(x,t) 0.06 sin0.8x 0.5 10 t
? ?
? ? ?
? ?
(4)
? ?
3
Y(x,t) 0.03 sin5.1x 1.5 10 t
? ?
? ? ?
? ?
Sol. (4)
Y = A sin (kx - ?t)
A =
6
2
= 3cm = 0.03 m
? = 2 ? f = 2 ? ×245
? = 1.5 ×10
3
k =
3
1.5 10
v 300
? ?
?
k = 5.1
y = 0.03 sin (5.1x – 1.5 × 10
3
t)
6. A carrier signal C(t) = 25 sin (2.512×10
10
t) is amplitude modulated by a message signal
m(t)=5 sin (1.57×10
8
t) and transmitted through an antenna. What will be bandwith of the
modulated signal ?
(1) 1987.5 MHz (2) 2.01 GHz (3) 50 MHz (4) 8 GHz
Sol. (3)
? = 2f
m(t)
? = 2×
8
1.57 10
2
?
?
? = 50 MHz
7. Two particles A and B of equal masses are suspended from two massless springs of spring
constants K
1
and K
2
respectively. If the maximum velocities during osciliations are equal, the
ratio of the amplitude of A and B is :
(1)
1
2
K
K
(2)
1
2
K
K
(3)
2
1
K
K
(4)
2
1
K
K
Sol. (3)
? V
max
= A ?
Given ?
1
A
1
= ?
2
A
2
We know that ? =
K
m
1 2
1 2
k k
A A
m m
?
1 2
2 1
A k
A k
?
8. Match List I with List II
List I List II
(a) Phase difference between current and voltage (i)
2
?
; current leads voltage
in a purely resistive AC circuit
(b) Phase difference between current and voltage in (ii) zero
a pure inductive AC circuit
(c) Phase difference between current and voltage in (iii)
2
?
; current lags voltage
a pure capacitive AC circuit
(d) Phase difference between current and voltage in (iv)
1 C L
X X
tan
R
?
? ? ?
? ?
? ?
an LCR series circuit
Choose the most appropriate answer from the options given below :
(1) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i) (2) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
(3) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i) (4) (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
Page 5
17
th
Mar. 2021 | Shift 2
SECTION – A
1. Two identical blocks A and B each of mass m resting on the smooth horizontal floor are
connected by a light spring of natural length L and spring constant K. A third block C of mass m
moving with a speed v along the line joining A and B collides with A. The maximum compression
in the spring is
C A B
m m
m
(1)
mv
2K
(2)
m
2K
(3)
mv
K
(4)
m
v
2K
Sol. (4)
C A ?V
1
B ?V
1
m m
m
v
From conservation of momentum
mv = mv
1
+ mv
1
V
1
=
V
2
A ?V/2 B ? V/2
m m
& from energy conservation
2
2 2
1 1 V 1
mv m 2 Kx
2 2 2 2
? ?
? ?
? ? ? ? ? ?
? ?
? ?
? ?
? ?
2 2
2
mv mv 1
kx
2 4 2
? ?
2
2
mv 1
kx
4 2
?
Then the maximum compression in the spring is
2
mv
x
2K
?
m
x v
2K
?
-
2. A sphere of mass 2 kg radius 0.5m is rolling with an initial speed of 1 ms
-1
goes up an inclined
plane which makes an angle of 30
0
with the horizontal plane, without slipping. How long will the
sphere take to return to the starting point A ?
30
0
A
(1) 0.80 s (2) 0.60 s (3) 0.52 s (4) 0.57 s
Sol. (4)
mg sin ?
f
30
0
A
gsin
a
1 c
?
?
?
9.8sin30º
a
2
1
5
?
?
a = 3.5 m/sec
2
Time of accent
V = u + at
0 = 1 –3.5 t
t =
1
3.5
sec.
Time of decent
t =
1
3.5
sec.
Total time
2
T
3.5
? =0.57 sec.
3. If one mole of the polyatomic gas is having two vibrational modes and ? is the ratio of molar
specific heats for polyatomic gas p
v
C
C
? ?
? ?
? ?
? ?
then the value of ? is :
(1) 1.35 (2) 1.02 (3) 1.25 (4) 1.2
Sol. (NTA answer is 4) our answer is (3)
Degree of freedom of polyatomic gas
f = T + R + V
f = 3 + 3 + 2 = 8
? = 1 +
2
f
=
2
1
8
?
10 5
1.25
8 4
? ? ? ?
4. Two cells of emf 2E and E with internal resistance r
1
and r
2
respectively are connected in series
to an external resistor R (see figure). The value of R, at which the potential difference across
the terminals of the first cell becomes zero is
R
E 2E
(1)
1 2
r r ? (2)
1 2
r r ? (3)
1
2
r
r
2
? (4)
1
2
r
r
2
?
17
th
Mar. 2021 | Shift 2
Sol. (4)
R
E 2E
A B
r
2
r
1
1 2
3E
R r r
?
? ?
?
2E
r
1
B A
i
V
A
= V
B
2 E = i r
1
2E =
1 2
3E
R r r ? ?
r
1
2R + 2r
1
+ 2r
2
= 3r
1
R =
1
2
r
r
2
?
5. A sound wave of frequency 245 Hz travels with the speed of 300 ms
-1
along the positive x-axis.
Each point of the wave move to and fro through a total distance of 6 cm. What will be the
mathematical expression of the travelling wave ?
(1)
? ?
3
Y(x,t) 0.03 sin5.1x 0.2 10 t
? ?
? ? ?
? ?
(2)
? ?
3
Y(x,t) 0.06 sin5.1x 1.5 10 t
? ?
? ? ?
? ?
(3)
? ?
3
Y(x,t) 0.06 sin0.8x 0.5 10 t
? ?
? ? ?
? ?
(4)
? ?
3
Y(x,t) 0.03 sin5.1x 1.5 10 t
? ?
? ? ?
? ?
Sol. (4)
Y = A sin (kx - ?t)
A =
6
2
= 3cm = 0.03 m
? = 2 ? f = 2 ? ×245
? = 1.5 ×10
3
k =
3
1.5 10
v 300
? ?
?
k = 5.1
y = 0.03 sin (5.1x – 1.5 × 10
3
t)
6. A carrier signal C(t) = 25 sin (2.512×10
10
t) is amplitude modulated by a message signal
m(t)=5 sin (1.57×10
8
t) and transmitted through an antenna. What will be bandwith of the
modulated signal ?
(1) 1987.5 MHz (2) 2.01 GHz (3) 50 MHz (4) 8 GHz
Sol. (3)
? = 2f
m(t)
? = 2×
8
1.57 10
2
?
?
? = 50 MHz
7. Two particles A and B of equal masses are suspended from two massless springs of spring
constants K
1
and K
2
respectively. If the maximum velocities during osciliations are equal, the
ratio of the amplitude of A and B is :
(1)
1
2
K
K
(2)
1
2
K
K
(3)
2
1
K
K
(4)
2
1
K
K
Sol. (3)
? V
max
= A ?
Given ?
1
A
1
= ?
2
A
2
We know that ? =
K
m
1 2
1 2
k k
A A
m m
?
1 2
2 1
A k
A k
?
8. Match List I with List II
List I List II
(a) Phase difference between current and voltage (i)
2
?
; current leads voltage
in a purely resistive AC circuit
(b) Phase difference between current and voltage in (ii) zero
a pure inductive AC circuit
(c) Phase difference between current and voltage in (iii)
2
?
; current lags voltage
a pure capacitive AC circuit
(d) Phase difference between current and voltage in (iv)
1 C L
X X
tan
R
?
? ? ?
? ?
? ?
an LCR series circuit
Choose the most appropriate answer from the options given below :
(1) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i) (2) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
(3) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i) (4) (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
17
th
Mar. 2021 | Shift 2
Sol. (4)
I
R
V
L
V
C
V
R
(a) phase difference b/w current & voltage in a purely resistive AC circuit is zero
(b) phase difference b/w current & voltage in a pure inductive AC circuit is
2
?
; current lags voltage.
(c) phase different b/w current & voltage in a pure capacitive AC circuit is
2
?
; current lead voltage.
(d) phase difference b/w current & voltage in an LCR series circuit is =
1 C L
X X
tan
R
?
? ? ?
? ?
? ?
9. A geostationary satellite is orbiting around an arbitary planet ‘P’ at a height of 11R above the
surface of ‘P’, R being the radius of ‘P’. The time period of another satellite in hours at a height
of 2R from the surface of ‘P’ is _____. ‘P’ has the time period of 24 hours.
(1)
6
2
(2) 3 (3) 6 2 (4) 5
Sol. (2)
2R
11R
R
R
From Kepler’s law
T
2
? R
3
2 3
24 12R
T 3R
? ? ? ?
?
? ? ? ?
? ? ? ?
T = 3 sec
10. The velocity of a particle is v=v
0
+gt+Ft
2
. Its position is x=0 at t=0; then its displacement after
time (t = 1) is :
(1)
0
g
v F
2
? ? (2) v
0
+2g+3F (3) v
0
+g+F (4)
0
g F
v
2 3
? ?
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