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RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.2                                                  PAGE NO: 18.6 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 
cm, AC = 4.5 cm and BD = 3.8 cm. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 
3.8 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 3.8cm with A as the center to mark that point as B. 
Step 3- Cut an arc of radius 3cm with C as the center to intersect with point B. 
Step 4- Cut an arc of radius 3.8cm with B as the center to mark that point as D. 
Step 5- Cut an arc of radius 2.3cm with A as the center to intersect with point D. 
Step 6- Now join AB, BD, AD and DC 
 
 
2. Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 
cm and BD = 10 cm. 
Solution: 
The given details are BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 6cm with A as the center to mark that point as D. 
Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D. 
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 7.5cm with C as the center to intersect at point B. 
Step 6- Now join AD, CD, DB and AB 
Page 2


 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.2                                                  PAGE NO: 18.6 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 
cm, AC = 4.5 cm and BD = 3.8 cm. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 
3.8 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 3.8cm with A as the center to mark that point as B. 
Step 3- Cut an arc of radius 3cm with C as the center to intersect with point B. 
Step 4- Cut an arc of radius 3.8cm with B as the center to mark that point as D. 
Step 5- Cut an arc of radius 2.3cm with A as the center to intersect with point D. 
Step 6- Now join AB, BD, AD and DC 
 
 
2. Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 
cm and BD = 10 cm. 
Solution: 
The given details are BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 6cm with A as the center to mark that point as D. 
Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D. 
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 7.5cm with C as the center to intersect at point B. 
Step 6- Now join AD, CD, DB and AB 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
 
3. Construct a quadrilateral ABCD when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 
8 cm and BD = 4 cm. 
Solution: 
The given details are AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm. 
Consider a triangle ABD from the given data, 
So, AB + BD = 3+4 = 7cm 
We know that sum of lengths of two sides of a triangle is always greater than the third 
side. 
? The construction is not possible. 
 
4. Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 
cm, AC = 7.3 cm and BD = 3.2 cm. 
Solution: 
The given details are AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 
3.2 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line CD = 4.1cm 
Step 2- Cut an arc of radius 7.3cm with C as the center to mark that point as A. 
Step 3- Cut an arc of radius 3.5cm with D as the center to intersect at point A. 
Step 4- Cut an arc of radius 3.2cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 2.5cm with C as the center to intersect at point B. 
Step 6- Now join CA, DA, DB, CB and AB 
Page 3


 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.2                                                  PAGE NO: 18.6 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 
cm, AC = 4.5 cm and BD = 3.8 cm. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 
3.8 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 3.8cm with A as the center to mark that point as B. 
Step 3- Cut an arc of radius 3cm with C as the center to intersect with point B. 
Step 4- Cut an arc of radius 3.8cm with B as the center to mark that point as D. 
Step 5- Cut an arc of radius 2.3cm with A as the center to intersect with point D. 
Step 6- Now join AB, BD, AD and DC 
 
 
2. Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 
cm and BD = 10 cm. 
Solution: 
The given details are BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 6cm with A as the center to mark that point as D. 
Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D. 
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 7.5cm with C as the center to intersect at point B. 
Step 6- Now join AD, CD, DB and AB 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
 
3. Construct a quadrilateral ABCD when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 
8 cm and BD = 4 cm. 
Solution: 
The given details are AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm. 
Consider a triangle ABD from the given data, 
So, AB + BD = 3+4 = 7cm 
We know that sum of lengths of two sides of a triangle is always greater than the third 
side. 
? The construction is not possible. 
 
4. Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 
cm, AC = 7.3 cm and BD = 3.2 cm. 
Solution: 
The given details are AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 
3.2 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line CD = 4.1cm 
Step 2- Cut an arc of radius 7.3cm with C as the center to mark that point as A. 
Step 3- Cut an arc of radius 3.5cm with D as the center to intersect at point A. 
Step 4- Cut an arc of radius 3.2cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 2.5cm with C as the center to intersect at point B. 
Step 6- Now join CA, DA, DB, CB and AB 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
5. Construct a quadrilateral ABCD given AD = 5 cm, AB = 5.5 cm, BC = 2.5 
cm, AC = 7.1 cm and BD = 8 cm. 
Solution: 
The given details are AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 
cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 5.5cm 
Step 2- Cut an arc of radius 2.5cm with B as the center to mark that point as C. 
Step 3- Cut an arc of radius 7.1cm with A as the center to intersect at point C. 
Step 4- Cut an arc of radius 8cm with B as the center to mark that point as D. 
Step 5- Cut an arc of radius 5cm with A as the center to intersect at point D. 
Step 6- Now join BC, AC, BD, AD and CD 
 
 
6. Construct a quadrilateral ABCD in which BC = 4 cm, CA = 5.6 cm, AD = 4.5 
cm, CD = 5 cm and BD = 6.5 cm. 
Page 4


 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.2                                                  PAGE NO: 18.6 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 
cm, AC = 4.5 cm and BD = 3.8 cm. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 
3.8 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 3.8cm with A as the center to mark that point as B. 
Step 3- Cut an arc of radius 3cm with C as the center to intersect with point B. 
Step 4- Cut an arc of radius 3.8cm with B as the center to mark that point as D. 
Step 5- Cut an arc of radius 2.3cm with A as the center to intersect with point D. 
Step 6- Now join AB, BD, AD and DC 
 
 
2. Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 
cm and BD = 10 cm. 
Solution: 
The given details are BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AC = 6cm. 
Step 2- Cut an arc of radius 6cm with A as the center to mark that point as D. 
Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D. 
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 7.5cm with C as the center to intersect at point B. 
Step 6- Now join AD, CD, DB and AB 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
 
3. Construct a quadrilateral ABCD when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 
8 cm and BD = 4 cm. 
Solution: 
The given details are AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm. 
Consider a triangle ABD from the given data, 
So, AB + BD = 3+4 = 7cm 
We know that sum of lengths of two sides of a triangle is always greater than the third 
side. 
? The construction is not possible. 
 
4. Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 
cm, AC = 7.3 cm and BD = 3.2 cm. 
Solution: 
The given details are AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 
3.2 cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line CD = 4.1cm 
Step 2- Cut an arc of radius 7.3cm with C as the center to mark that point as A. 
Step 3- Cut an arc of radius 3.5cm with D as the center to intersect at point A. 
Step 4- Cut an arc of radius 3.2cm with D as the center to mark that point as B. 
Step 5- Cut an arc of radius 2.5cm with C as the center to intersect at point B. 
Step 6- Now join CA, DA, DB, CB and AB 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
5. Construct a quadrilateral ABCD given AD = 5 cm, AB = 5.5 cm, BC = 2.5 
cm, AC = 7.1 cm and BD = 8 cm. 
Solution: 
The given details are AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 
cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 5.5cm 
Step 2- Cut an arc of radius 2.5cm with B as the center to mark that point as C. 
Step 3- Cut an arc of radius 7.1cm with A as the center to intersect at point C. 
Step 4- Cut an arc of radius 8cm with B as the center to mark that point as D. 
Step 5- Cut an arc of radius 5cm with A as the center to intersect at point D. 
Step 6- Now join BC, AC, BD, AD and CD 
 
 
6. Construct a quadrilateral ABCD in which BC = 4 cm, CA = 5.6 cm, AD = 4.5 
cm, CD = 5 cm and BD = 6.5 cm. 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
Solution: 
The given details are BC = 4 cm, CA = 5.6 cm, AD = 4.5 cm, CD = 5 cm and BD = 6.5 
cm. 
Steps to construct a quadrilateral: 
Step 1- Draw a line BC = 4cm 
Step 2- Cut an arc of radius 6.5cm with B as the center to mark that point as D. 
Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D. 
Step 4- Cut an arc of radius 5.6cm with C as the center to mark that point as A. 
Step 5- Cut an arc of radius 4.5cm with D as the center to intersect at point A. 
Step 6- Now join BD, CD, CA, DA and AB
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Document Description: Practical Geometry (Constructions) - EXERCISE 18.2 for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation. The notes and questions for Practical Geometry (Constructions) - EXERCISE 18.2 have been prepared according to the Class 8 exam syllabus. Information about Practical Geometry (Constructions) - EXERCISE 18.2 covers topics like and Practical Geometry (Constructions) - EXERCISE 18.2 Example, for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Practical Geometry (Constructions) - EXERCISE 18.2.
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