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RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.3                                                  PAGE NO: 18.8 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 
cm, AD = 5 cm and ?B = 80°. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ?B = 
80°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 3.8cm 
Step 2- Construct and angle of 80
o
 at B. 
Step 3- Cut an arc of radius 3.4cm with B as the center to mark that point as C.  
Step 4- Cut an arc of radius 5cm with A as the center to mark that point as D. 
Step 5- Cut an arc of radius 4.5cm with C as the center to intersect at point D. 
Step 6- Now join BC, AD and CD 
 
2. Construct a quadrilateral ABCD given that AB = 8 cm, BC = 8 cm, CD = 10 
cm, AD = 10 cm and ?A = 45°. 
Solution: 
The given details are AB = 8 cm, BC = 8 cm, CD = 10 cm, AD = 10 cm and ?A = 45°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 8cm 
Step 2- Construct and angle of 45
o
 at A. 
Step 3- Cut an arc of radius 10cm with A as the center to mark that point as D.  
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as C. 
Step 5- Cut an arc of radius 8cm with B as the center to intersect at point C. 
Step 6- Now join AD, DC and BC 
Page 2


 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.3                                                  PAGE NO: 18.8 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 
cm, AD = 5 cm and ?B = 80°. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ?B = 
80°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 3.8cm 
Step 2- Construct and angle of 80
o
 at B. 
Step 3- Cut an arc of radius 3.4cm with B as the center to mark that point as C.  
Step 4- Cut an arc of radius 5cm with A as the center to mark that point as D. 
Step 5- Cut an arc of radius 4.5cm with C as the center to intersect at point D. 
Step 6- Now join BC, AD and CD 
 
2. Construct a quadrilateral ABCD given that AB = 8 cm, BC = 8 cm, CD = 10 
cm, AD = 10 cm and ?A = 45°. 
Solution: 
The given details are AB = 8 cm, BC = 8 cm, CD = 10 cm, AD = 10 cm and ?A = 45°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 8cm 
Step 2- Construct and angle of 45
o
 at A. 
Step 3- Cut an arc of radius 10cm with A as the center to mark that point as D.  
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as C. 
Step 5- Cut an arc of radius 8cm with B as the center to intersect at point C. 
Step 6- Now join AD, DC and BC 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions)
3. Construct a quadrilateral ABCD in which AB = 7.7 cm, BC = 6.8 cm, CD = 5.1
cm, AS = 3.6 cm and ?C = 120°.
Solution:
The given details are AB = 7.7 cm, BC = 6.8 cm, CD = 5.1 cm, AS = 3.6 cm and ?C =
120°.
Steps to construct a quadrilateral:
Step 1- Draw a line DC = 5.1cm
Step 2- Construct and angle of 120
o
 at C.
Step 3- Cut an arc of radius 6.8cm with C as the center to mark that point as B.
Step 4- Cut an arc of radius 7.7cm with B as the center to mark that point as A.
Step 5- Cut an arc of radius 3.6cm with D as the center to intersect at point A.
Step 6- Now join CB, BA and DA
Page 3


 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.3                                                  PAGE NO: 18.8 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 
cm, AD = 5 cm and ?B = 80°. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ?B = 
80°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 3.8cm 
Step 2- Construct and angle of 80
o
 at B. 
Step 3- Cut an arc of radius 3.4cm with B as the center to mark that point as C.  
Step 4- Cut an arc of radius 5cm with A as the center to mark that point as D. 
Step 5- Cut an arc of radius 4.5cm with C as the center to intersect at point D. 
Step 6- Now join BC, AD and CD 
 
2. Construct a quadrilateral ABCD given that AB = 8 cm, BC = 8 cm, CD = 10 
cm, AD = 10 cm and ?A = 45°. 
Solution: 
The given details are AB = 8 cm, BC = 8 cm, CD = 10 cm, AD = 10 cm and ?A = 45°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 8cm 
Step 2- Construct and angle of 45
o
 at A. 
Step 3- Cut an arc of radius 10cm with A as the center to mark that point as D.  
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as C. 
Step 5- Cut an arc of radius 8cm with B as the center to intersect at point C. 
Step 6- Now join AD, DC and BC 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions)
3. Construct a quadrilateral ABCD in which AB = 7.7 cm, BC = 6.8 cm, CD = 5.1
cm, AS = 3.6 cm and ?C = 120°.
Solution:
The given details are AB = 7.7 cm, BC = 6.8 cm, CD = 5.1 cm, AS = 3.6 cm and ?C =
120°.
Steps to construct a quadrilateral:
Step 1- Draw a line DC = 5.1cm
Step 2- Construct and angle of 120
o
 at C.
Step 3- Cut an arc of radius 6.8cm with C as the center to mark that point as B.
Step 4- Cut an arc of radius 7.7cm with B as the center to mark that point as A.
Step 5- Cut an arc of radius 3.6cm with D as the center to intersect at point A.
Step 6- Now join CB, BA and DA
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
4. Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = CD = 5 cm 
and ?B = 120°. 
Solution: 
The given details are AB = BC = 3 cm, AD = CD = 5 cm and ?B = 120°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 3cm 
Step 2- Construct and angle of 120
o
 at B. 
Step 3- Cut an arc of radius 3cm with B as the center to mark that point as C.  
Step 4- Cut an arc of radius 5cm with C as the center to mark that point as D. 
Step 5- Cut an arc of radius 5cm with A as the center to intersect at point D. 
Step 6- Now join BC, CD and DA 
 
 
5. Construct a quadrilateral ABCD in which AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm 
and DA = 3.3 cm and ?A = 60°. 
Solution: 
The given details are AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm and DA = 3.3 cm 
and ?A = 60°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 2.8cm 
Step 2- Construct and angle of 60
o
 at A. 
Step 3- Cut an arc of radius 3.3cm with A as the center to mark that point as D.  
Step 4- Cut an arc of radius 2.6cm with D as the center to mark that point as C. 
Step 5- Cut an arc of radius 3.1cm with B as the center to intersect at point C. 
Step 6- Now join AD, DC and CB 
Page 4


 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
EXERCISE 18.3                                                  PAGE NO: 18.8 
 
1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 
cm, AD = 5 cm and ?B = 80°. 
Solution: 
The given details are AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ?B = 
80°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 3.8cm 
Step 2- Construct and angle of 80
o
 at B. 
Step 3- Cut an arc of radius 3.4cm with B as the center to mark that point as C.  
Step 4- Cut an arc of radius 5cm with A as the center to mark that point as D. 
Step 5- Cut an arc of radius 4.5cm with C as the center to intersect at point D. 
Step 6- Now join BC, AD and CD 
 
2. Construct a quadrilateral ABCD given that AB = 8 cm, BC = 8 cm, CD = 10 
cm, AD = 10 cm and ?A = 45°. 
Solution: 
The given details are AB = 8 cm, BC = 8 cm, CD = 10 cm, AD = 10 cm and ?A = 45°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 8cm 
Step 2- Construct and angle of 45
o
 at A. 
Step 3- Cut an arc of radius 10cm with A as the center to mark that point as D.  
Step 4- Cut an arc of radius 10cm with D as the center to mark that point as C. 
Step 5- Cut an arc of radius 8cm with B as the center to intersect at point C. 
Step 6- Now join AD, DC and BC 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions)
3. Construct a quadrilateral ABCD in which AB = 7.7 cm, BC = 6.8 cm, CD = 5.1
cm, AS = 3.6 cm and ?C = 120°.
Solution:
The given details are AB = 7.7 cm, BC = 6.8 cm, CD = 5.1 cm, AS = 3.6 cm and ?C =
120°.
Steps to construct a quadrilateral:
Step 1- Draw a line DC = 5.1cm
Step 2- Construct and angle of 120
o
 at C.
Step 3- Cut an arc of radius 6.8cm with C as the center to mark that point as B.
Step 4- Cut an arc of radius 7.7cm with B as the center to mark that point as A.
Step 5- Cut an arc of radius 3.6cm with D as the center to intersect at point A.
Step 6- Now join CB, BA and DA
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
4. Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = CD = 5 cm 
and ?B = 120°. 
Solution: 
The given details are AB = BC = 3 cm, AD = CD = 5 cm and ?B = 120°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 3cm 
Step 2- Construct and angle of 120
o
 at B. 
Step 3- Cut an arc of radius 3cm with B as the center to mark that point as C.  
Step 4- Cut an arc of radius 5cm with C as the center to mark that point as D. 
Step 5- Cut an arc of radius 5cm with A as the center to intersect at point D. 
Step 6- Now join BC, CD and DA 
 
 
5. Construct a quadrilateral ABCD in which AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm 
and DA = 3.3 cm and ?A = 60°. 
Solution: 
The given details are AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm and DA = 3.3 cm 
and ?A = 60°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 2.8cm 
Step 2- Construct and angle of 60
o
 at A. 
Step 3- Cut an arc of radius 3.3cm with A as the center to mark that point as D.  
Step 4- Cut an arc of radius 2.6cm with D as the center to mark that point as C. 
Step 5- Cut an arc of radius 3.1cm with B as the center to intersect at point C. 
Step 6- Now join AD, DC and CB 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 18 
– Practical Geometry (Constructions) 
 
 
6. Construct a quadrilateral ABCD in which AB = BC = 6 cm, AD = DC = 4.5 cm 
and ?B = 120°. 
Solution: 
The given details are AB = BC = 6 cm, AD = DC = 4.5 cm and ?B = 120°. 
Steps to construct a quadrilateral: 
Step 1- Draw a line AB = 6cm 
Step 2- Construct and angle of 120
o
 at B. 
Step 3- Cut an arc of radius 6cm with B as the center to mark that point as C.  
Here, AC is about 10.3cm in length which is greater than AD + CD = 4.5+4.5=9cm 
We know that sum of the two sides of a triangle is always greater than the third side. 
AD + CD < AC 
? Construction is not possible.
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Document Description: Practical Geometry (Constructions) - EXERCISE 18.3 for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation. The notes and questions for Practical Geometry (Constructions) - EXERCISE 18.3 have been prepared according to the Class 8 exam syllabus. Information about Practical Geometry (Constructions) - EXERCISE 18.3 covers topics like and Practical Geometry (Constructions) - EXERCISE 18.3 Example, for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Practical Geometry (Constructions) - EXERCISE 18.3.
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