Class 6 Exam > Class 6 Notes > Mathematics (Maths) Class 6 > RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1)
Operations on Whole Numbers (Exercise 4.1) RD Sharma Solutions | Mathematics (Maths) Class 6 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1 Exercise 4.1 PAGE: 4.4 1. Fill in the blanks to make each of the following a true statement: (i) 359 + 476 = 476 + ….. (ii) …. + 1952 = 1952 + 2008 (iii) 90758 + 0 = …. (iv) 54321 + (489 + 699) = 489 + (54321 + …..) Solution: (i) 359 + 476 = 476 + 359 using commutativity (ii) 2008 + 1952 = 1952 + 2008 using commutativity (iii) 90758 + 0 = 90758 using the additive identity (iv) 54321 + (489 + 699) = 489 + (54321 + 699) using associativity 2. Add each of the following and check by reversing the order of addends: (i) 5628 + 39784 (ii) 923584 + 178 (iii) 15409 + 112 (iv) 2359 + 641 Solution: (i) We get 5628 + 39784 = 45412 By reversing the order of addends 39784 + 5628 = 45412 (ii) We get 923584 + 178 = 923762 By reversing the order of addends 178 + 923584 = 923762 (iii) We get 15409 + 112 = 15521 By reversing the order of addends 112 + 15409 = 15521 (iv) We get 2359 + 641 = 3000 By reversing the order of addends 641 + 2359 = 3000 3. Determine the sum by suitable rearrangements: (i) 953 + 407 + 647 (ii) 15409 + 178 + 591 + 322 (iii) 2359 + 10001 + 2641 + 9999 (iv) 1 + 2 + 3 + 4 + 1996 + 1997 + 1998 + 1999 (v) 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 Page 2 Exercise 4.1 PAGE: 4.4 1. Fill in the blanks to make each of the following a true statement: (i) 359 + 476 = 476 + ….. (ii) …. + 1952 = 1952 + 2008 (iii) 90758 + 0 = …. (iv) 54321 + (489 + 699) = 489 + (54321 + …..) Solution: (i) 359 + 476 = 476 + 359 using commutativity (ii) 2008 + 1952 = 1952 + 2008 using commutativity (iii) 90758 + 0 = 90758 using the additive identity (iv) 54321 + (489 + 699) = 489 + (54321 + 699) using associativity 2. Add each of the following and check by reversing the order of addends: (i) 5628 + 39784 (ii) 923584 + 178 (iii) 15409 + 112 (iv) 2359 + 641 Solution: (i) We get 5628 + 39784 = 45412 By reversing the order of addends 39784 + 5628 = 45412 (ii) We get 923584 + 178 = 923762 By reversing the order of addends 178 + 923584 = 923762 (iii) We get 15409 + 112 = 15521 By reversing the order of addends 112 + 15409 = 15521 (iv) We get 2359 + 641 = 3000 By reversing the order of addends 641 + 2359 = 3000 3. Determine the sum by suitable rearrangements: (i) 953 + 407 + 647 (ii) 15409 + 178 + 591 + 322 (iii) 2359 + 10001 + 2641 + 9999 (iv) 1 + 2 + 3 + 4 + 1996 + 1997 + 1998 + 1999 (v) 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 Solution: (i) 953 + 407 + 647 We know that 53 + 47 = 100 It can be written as (953 + 647) + 407 = 1600 + 407 On further calculation (953 + 647) + 407 = 2007 (ii) 15409 + 178 + 591 + 322 We know that 409 + 91 = 500 and 78 + 22 = 100 It can be written as (15409 + 591) + (178 + 322) = 16000 + 500 On further calculation (15409 + 591) + (178 + 322) = 16500 (iii) 2359 + 10001 + 2641 + 9999 We know that 59 + 41 = 100 and 99 + 01 = 100 It can be written as (2359 + 2641) + (10001 + 9999) = 5000 + 20000 On further calculation (2359 + 2641) + (10001 + 9999) = 25000 (iv) 1 + 2 + 3 + 4 + 1996 + 1997 + 1998 + 1999 We know that 99 + 1 = 100, 98 + 2 = 100, 97 + 3 = 100 and 96 + 4 = 100 It can be written as (1 + 1999) + (2 + 1998) + (3 + 1997) + (4 + 1996) = 2000 + 2000 + 2000 + 2000 On further calculation (1 + 1999) + (2 + 1998) + (3 + 1997) + (4 + 1996) = 8000 (v) 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 We know that 10 + 20 = 30, 1 + 9 = 10, 2 + 8 = 10, 3 + 7 = 10 and 4 + 6 = 10 It can be written as (10 + 20) + (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) = 30 + 30 + 30 + 30 + 30 + 15 On further calculation (10 + 20) + (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) = 150 + 15 = 165 4. Which of the following statements are true and which are false: (i) The sum of two odd numbers is an odd number. (ii) The sum of two odd numbers is an even number. (iii) The sum of two even numbers is an even number. (iv) The sum of two even numbers is an odd number. (v) The sum of an even number and an odd number is an odd number. (vi) The sum of an odd number and an even number is an even number. (vii) Every whole number is a natural number. Page 3 Exercise 4.1 PAGE: 4.4 1. Fill in the blanks to make each of the following a true statement: (i) 359 + 476 = 476 + ….. (ii) …. + 1952 = 1952 + 2008 (iii) 90758 + 0 = …. (iv) 54321 + (489 + 699) = 489 + (54321 + …..) Solution: (i) 359 + 476 = 476 + 359 using commutativity (ii) 2008 + 1952 = 1952 + 2008 using commutativity (iii) 90758 + 0 = 90758 using the additive identity (iv) 54321 + (489 + 699) = 489 + (54321 + 699) using associativity 2. Add each of the following and check by reversing the order of addends: (i) 5628 + 39784 (ii) 923584 + 178 (iii) 15409 + 112 (iv) 2359 + 641 Solution: (i) We get 5628 + 39784 = 45412 By reversing the order of addends 39784 + 5628 = 45412 (ii) We get 923584 + 178 = 923762 By reversing the order of addends 178 + 923584 = 923762 (iii) We get 15409 + 112 = 15521 By reversing the order of addends 112 + 15409 = 15521 (iv) We get 2359 + 641 = 3000 By reversing the order of addends 641 + 2359 = 3000 3. Determine the sum by suitable rearrangements: (i) 953 + 407 + 647 (ii) 15409 + 178 + 591 + 322 (iii) 2359 + 10001 + 2641 + 9999 (iv) 1 + 2 + 3 + 4 + 1996 + 1997 + 1998 + 1999 (v) 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 Solution: (i) 953 + 407 + 647 We know that 53 + 47 = 100 It can be written as (953 + 647) + 407 = 1600 + 407 On further calculation (953 + 647) + 407 = 2007 (ii) 15409 + 178 + 591 + 322 We know that 409 + 91 = 500 and 78 + 22 = 100 It can be written as (15409 + 591) + (178 + 322) = 16000 + 500 On further calculation (15409 + 591) + (178 + 322) = 16500 (iii) 2359 + 10001 + 2641 + 9999 We know that 59 + 41 = 100 and 99 + 01 = 100 It can be written as (2359 + 2641) + (10001 + 9999) = 5000 + 20000 On further calculation (2359 + 2641) + (10001 + 9999) = 25000 (iv) 1 + 2 + 3 + 4 + 1996 + 1997 + 1998 + 1999 We know that 99 + 1 = 100, 98 + 2 = 100, 97 + 3 = 100 and 96 + 4 = 100 It can be written as (1 + 1999) + (2 + 1998) + (3 + 1997) + (4 + 1996) = 2000 + 2000 + 2000 + 2000 On further calculation (1 + 1999) + (2 + 1998) + (3 + 1997) + (4 + 1996) = 8000 (v) 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 We know that 10 + 20 = 30, 1 + 9 = 10, 2 + 8 = 10, 3 + 7 = 10 and 4 + 6 = 10 It can be written as (10 + 20) + (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) = 30 + 30 + 30 + 30 + 30 + 15 On further calculation (10 + 20) + (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) = 150 + 15 = 165 4. Which of the following statements are true and which are false: (i) The sum of two odd numbers is an odd number. (ii) The sum of two odd numbers is an even number. (iii) The sum of two even numbers is an even number. (iv) The sum of two even numbers is an odd number. (v) The sum of an even number and an odd number is an odd number. (vi) The sum of an odd number and an even number is an even number. (vii) Every whole number is a natural number. (viii) Every natural number is a whole number. (ix) There is a whole number which when added to a whole number, gives that number. (x) There is a natural number which when added to a natural number, gives that number. (xi) Commutativity and associativity are properties of whole numbers. (xii) Commutativity and associativity are properties of addition of whole numbers. Solution: (i) False. We know that, 1 + 3 = 4 where 4 is an even number. (ii) True. We know that, 5 + 7 = 12 where 12 is an even number. (iii) True. We know that, 2 + 4 = 6 where 6 is an even number. (iv) False. We know that, 4 + 6 = 10 where 10 is an even number. (v) True. We know that, 2 + 1 = 3 where 3 is an odd number. (vi) False. We know that, 3 + 2 = 5 where 5 is an odd number. (vii) False. Whole number starts from 0 whereas natural numbers start from 1. (viii) True. All the natural numbers are also whole number. (ix) True. We know that, 1 + 0 = 1 where 1 is a whole number. (x) False. We know that 2 + 1 = 3 which is not that number. (xi) False. Commutativity and associativity are not properties of whole numbers. (xii) True. Commutativity and associativity are properties of addition of whole numbers.Read More
|
94 videos|347 docs|54 tests
|
Related Exams
About this Document
|
4.83/5 Rating |
|
Oct 24, 2024 Last updated |
Document Description: RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) for Class 6 2024 is part of Mathematics (Maths) Class 6 preparation.
The notes and questions for RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) have been prepared according to the Class 6 exam syllabus. Information about RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) covers topics
like and RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Example, for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1).
Introduction of RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) in English is available as part of our Mathematics (Maths) Class 6
for Class 6 & RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) in Hindi for Mathematics (Maths) Class 6 course.
Download more important topics related with notes, lectures and mock test series for Class 6
Exam by signing up for free. Class 6: Operations on Whole Numbers (Exercise 4.1) RD Sharma Solutions | Mathematics (Maths) Class 6
Description
Full syllabus notes, lecture & questions for Operations on Whole Numbers (Exercise 4.1) RD Sharma Solutions | Mathematics (Maths) Class 6 - Class 6 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 6 | Best notes, free PDF download
Information about RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1)
In this doc you can find the meaning of RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) defined & explained in the simplest way possible. Besides explaining types of
RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) theory, EduRev gives you an ample number of questions to practice RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) tests, examples and also practice Class 6
tests
|
Explore Courses for Class 6 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
practice quizzes
,Semester Notes
,Exam
,Summary
,Important questions
,study material
,MCQs
,shortcuts and tricks
,Previous Year Questions with Solutions
,Free
,Viva Questions
,ppt
,Sample Paper
,mock tests for examination
,video lectures
,Operations on Whole Numbers (Exercise 4.1) RD Sharma Solutions | Mathematics (Maths) Class 6
,Extra Questions
,Objective type Questions
,Operations on Whole Numbers (Exercise 4.1) RD Sharma Solutions | Mathematics (Maths) Class 6
,past year papers
,Operations on Whole Numbers (Exercise 4.1) RD Sharma Solutions | Mathematics (Maths) Class 6
;
Additional Information about RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) for Class 6 Preparation
RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Free PDF Download
The RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) is an invaluable resource that delves deep into the core of the Class 6 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) now and kickstart your journey towards success in the Class 6 exam.
Importance of RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1)
The importance of RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) cannot be overstated, especially for Class 6 aspirants.
This document holds the key to success in the Class 6 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Notes
RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1).
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Notes on EduRev are your ultimate resource for success.
RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Class 6 Questions
The "RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) Class 6 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 6 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) on the App
Students of Class 6 can study RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1),
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RD Sharma Solutions: Operations on Whole Numbers (Exercise 4.1) is prepared as per the latest Class 6 syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup