Open App

Class 6 Exam > Class 6 Notes > Mathematics (Maths) Class 6 > RD Sharma Solutions: Fractions (Exercise 6.9)

Fractions (Exercise 6.9) RD Sharma Solutions | Mathematics (Maths) Class 6 PDF Download

Download, print and study this document offline

Please wait while the PDF view is loading

 Page 1


 
 
 
 
 
 
Exercise 6.9                                                                               page: 6.35 
1. Add: 
(i) 3/4 and 5/6 
(ii) 7/10 and 2/15 
(iii) 8/13 and 2/3 
(iv) 4/5 and 7/15 
Solution: 
 
(i) 3/4 and 5/6 
It can be written as 
3/4 + 5/6 
We know that the LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] + [(5 × 2)/ (6 × 2)] 
On further calculation 
= 9/12 + 10/ 12 
We get 
= (9 + 10)/ 12 = 19/12 
 
(ii) 7/10 and 2/15 
It can be written as 
7/10 + 2/15 
We know that the LCM of 10 and 15 is 30 
In order to convert fraction into equivalent fraction having 30 as denominator 
= [(7 × 3)/ (10 × 3)] + [(2 × 2)/ (15 × 2)] 
On further calculation 
= 21/30 + 4/ 30 
We get 
= (21 + 4)/ 30 = 25/30 = 5/6 
 
(iii) 8/13 and 2/3 
It can be written as 
8/13 + 2/3 
We know that the LCM of 13 and 3 is 39 
In order to convert fraction into equivalent fraction having 39 as denominator 
= [(8 × 3)/ (13 × 3)] + [(2 × 13)/ (3 × 13)] 
On further calculation 
= 24/39 + 26/39 
We get 
= (24 + 26)/ 39 = 50/39 
 
(iv) 4/5 and 7/15 
It can be written as 
4/5 + 7/15 
We know that the LCM of 5 and 15 is 1 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(4 × 3)/ (5 × 3)] + [(7 × 1)/ (15 × 1)] 
On further calculation 
= 12/15 + 7/ 15 
Page 2


 
 
 
 
 
 
Exercise 6.9                                                                               page: 6.35 
1. Add: 
(i) 3/4 and 5/6 
(ii) 7/10 and 2/15 
(iii) 8/13 and 2/3 
(iv) 4/5 and 7/15 
Solution: 
 
(i) 3/4 and 5/6 
It can be written as 
3/4 + 5/6 
We know that the LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] + [(5 × 2)/ (6 × 2)] 
On further calculation 
= 9/12 + 10/ 12 
We get 
= (9 + 10)/ 12 = 19/12 
 
(ii) 7/10 and 2/15 
It can be written as 
7/10 + 2/15 
We know that the LCM of 10 and 15 is 30 
In order to convert fraction into equivalent fraction having 30 as denominator 
= [(7 × 3)/ (10 × 3)] + [(2 × 2)/ (15 × 2)] 
On further calculation 
= 21/30 + 4/ 30 
We get 
= (21 + 4)/ 30 = 25/30 = 5/6 
 
(iii) 8/13 and 2/3 
It can be written as 
8/13 + 2/3 
We know that the LCM of 13 and 3 is 39 
In order to convert fraction into equivalent fraction having 39 as denominator 
= [(8 × 3)/ (13 × 3)] + [(2 × 13)/ (3 × 13)] 
On further calculation 
= 24/39 + 26/39 
We get 
= (24 + 26)/ 39 = 50/39 
 
(iv) 4/5 and 7/15 
It can be written as 
4/5 + 7/15 
We know that the LCM of 5 and 15 is 1 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(4 × 3)/ (5 × 3)] + [(7 × 1)/ (15 × 1)] 
On further calculation 
= 12/15 + 7/ 15 
 
 
 
 
 
 
We get 
= (12 + 7)/ 15 = 19/15 
 
2. Subtract: 
(i) 2/7 from 19/21 
(ii) 21/25 from 18/20 
(iii) 7/16 from 2 
(iv) 4/15 from 2 1/5 
Solution: 
 
(i) 2/7 from 19/21 
It can be written as 
19/21 – 2/7 
We know that LCM of 21 and 7 is 21 
In order to convert fraction into equivalent fraction having 21 as denominator 
= [(19 × 1)/ (21 × 1)] - [(2 × 3)/ (7 × 3)] 
On further calculation 
= 19/21 - 6/21 
We get 
= (19 - 6)/21 = 13/21 
 
(ii) 21/25 from 18/20 
It can be written as 
18/20 – 21/25 
We know that LCM of 20 and 25 is 100 
In order to convert fraction into equivalent fraction having 100 as denominator 
= [(18 × 5)/ (20 × 5)] - [(21 × 4)/ (25 × 4)] 
On further calculation 
= 90/100 - 84/100 
We get 
= (90 - 84)/100 = 6/100 = 3/50 
 
(iii) 7/16 from 2 
It can be written as 
2/1 – 7/16 
We know that LCM of 1 and 16 is 16 
In order to convert fraction into equivalent fraction having 16 as denominator 
= [(16 × 2)/ (16 × 1)] - [(7 × 1)/ (16 × 1)] 
On further calculation 
= 32/16 - 7/16 
We get 
= (32 - 7)/16 = 25/16 
 
(iv) 4/15 from 2 1/5 
It can be written as 
11/5 – 4/15  
We know that LCM of 5 and 15 is 15 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(11 × 3)/ (5 × 3)] - [(4 × 1)/ (15 × 1)] 
Page 3


 
 
 
 
 
 
Exercise 6.9                                                                               page: 6.35 
1. Add: 
(i) 3/4 and 5/6 
(ii) 7/10 and 2/15 
(iii) 8/13 and 2/3 
(iv) 4/5 and 7/15 
Solution: 
 
(i) 3/4 and 5/6 
It can be written as 
3/4 + 5/6 
We know that the LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] + [(5 × 2)/ (6 × 2)] 
On further calculation 
= 9/12 + 10/ 12 
We get 
= (9 + 10)/ 12 = 19/12 
 
(ii) 7/10 and 2/15 
It can be written as 
7/10 + 2/15 
We know that the LCM of 10 and 15 is 30 
In order to convert fraction into equivalent fraction having 30 as denominator 
= [(7 × 3)/ (10 × 3)] + [(2 × 2)/ (15 × 2)] 
On further calculation 
= 21/30 + 4/ 30 
We get 
= (21 + 4)/ 30 = 25/30 = 5/6 
 
(iii) 8/13 and 2/3 
It can be written as 
8/13 + 2/3 
We know that the LCM of 13 and 3 is 39 
In order to convert fraction into equivalent fraction having 39 as denominator 
= [(8 × 3)/ (13 × 3)] + [(2 × 13)/ (3 × 13)] 
On further calculation 
= 24/39 + 26/39 
We get 
= (24 + 26)/ 39 = 50/39 
 
(iv) 4/5 and 7/15 
It can be written as 
4/5 + 7/15 
We know that the LCM of 5 and 15 is 1 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(4 × 3)/ (5 × 3)] + [(7 × 1)/ (15 × 1)] 
On further calculation 
= 12/15 + 7/ 15 
 
 
 
 
 
 
We get 
= (12 + 7)/ 15 = 19/15 
 
2. Subtract: 
(i) 2/7 from 19/21 
(ii) 21/25 from 18/20 
(iii) 7/16 from 2 
(iv) 4/15 from 2 1/5 
Solution: 
 
(i) 2/7 from 19/21 
It can be written as 
19/21 – 2/7 
We know that LCM of 21 and 7 is 21 
In order to convert fraction into equivalent fraction having 21 as denominator 
= [(19 × 1)/ (21 × 1)] - [(2 × 3)/ (7 × 3)] 
On further calculation 
= 19/21 - 6/21 
We get 
= (19 - 6)/21 = 13/21 
 
(ii) 21/25 from 18/20 
It can be written as 
18/20 – 21/25 
We know that LCM of 20 and 25 is 100 
In order to convert fraction into equivalent fraction having 100 as denominator 
= [(18 × 5)/ (20 × 5)] - [(21 × 4)/ (25 × 4)] 
On further calculation 
= 90/100 - 84/100 
We get 
= (90 - 84)/100 = 6/100 = 3/50 
 
(iii) 7/16 from 2 
It can be written as 
2/1 – 7/16 
We know that LCM of 1 and 16 is 16 
In order to convert fraction into equivalent fraction having 16 as denominator 
= [(16 × 2)/ (16 × 1)] - [(7 × 1)/ (16 × 1)] 
On further calculation 
= 32/16 - 7/16 
We get 
= (32 - 7)/16 = 25/16 
 
(iv) 4/15 from 2 1/5 
It can be written as 
11/5 – 4/15  
We know that LCM of 5 and 15 is 15 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(11 × 3)/ (5 × 3)] - [(4 × 1)/ (15 × 1)] 
 
 
 
 
 
 
On further calculation 
= 33/15 - 4/15 
We get 
= (33 - 4)/15 = 29/15 
 
3. Find the difference of: 
(i) 13/24 and 7/16 
(ii) 5/18 and 4/15 
(iii) 1/12 and 3/4 
(iv) 2/3 and 6/7 
Solution: 
 
(i) 13/24 and 7/16 
It can be written as 
13/24 – 7/16 
We know that LCM of 24 and 16 is 48 
In order to convert fraction into equivalent fraction having 48 as denominator 
= [(13 × 2)/ (24 × 2)] - [(7 × 3)/ (16 × 3)] 
On further calculation 
= 26/48 - 21/48 
We get 
= (26 - 21)/48 = 5/48 
 
(ii) 5/18 and 4/15 
It can be written as 
5/18 – 4/15 
We know that LCM of 18 and 15 is 90 
In order to convert fraction into equivalent fraction having 90 as denominator 
= [(5 × 5)/ (18 × 5)] - [(4 × 6)/ (15 × 6)] 
On further calculation 
= 25/90 - 24/90 
We get 
= (25 - 24)/90 = 1/90 
 
(iii) 1/12 and 3/4 
It can be written as 
3/4 – 1/12 
We know that LCM of 4 and 12 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] - [(1 × 1)/ (12 × 1)] 
On further calculation 
= 9/12 - 1/12 
We get 
= (9 - 1)/12 = 8/12 = 2/3 
 
(iv) 2/3 and 6/7 
It can be written as 
6/7 – 2/3 
We know that LCM of 7 and 3 is 21 
In order to convert fraction into equivalent fraction having 48 as denominator 
Page 4


 
 
 
 
 
 
Exercise 6.9                                                                               page: 6.35 
1. Add: 
(i) 3/4 and 5/6 
(ii) 7/10 and 2/15 
(iii) 8/13 and 2/3 
(iv) 4/5 and 7/15 
Solution: 
 
(i) 3/4 and 5/6 
It can be written as 
3/4 + 5/6 
We know that the LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] + [(5 × 2)/ (6 × 2)] 
On further calculation 
= 9/12 + 10/ 12 
We get 
= (9 + 10)/ 12 = 19/12 
 
(ii) 7/10 and 2/15 
It can be written as 
7/10 + 2/15 
We know that the LCM of 10 and 15 is 30 
In order to convert fraction into equivalent fraction having 30 as denominator 
= [(7 × 3)/ (10 × 3)] + [(2 × 2)/ (15 × 2)] 
On further calculation 
= 21/30 + 4/ 30 
We get 
= (21 + 4)/ 30 = 25/30 = 5/6 
 
(iii) 8/13 and 2/3 
It can be written as 
8/13 + 2/3 
We know that the LCM of 13 and 3 is 39 
In order to convert fraction into equivalent fraction having 39 as denominator 
= [(8 × 3)/ (13 × 3)] + [(2 × 13)/ (3 × 13)] 
On further calculation 
= 24/39 + 26/39 
We get 
= (24 + 26)/ 39 = 50/39 
 
(iv) 4/5 and 7/15 
It can be written as 
4/5 + 7/15 
We know that the LCM of 5 and 15 is 1 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(4 × 3)/ (5 × 3)] + [(7 × 1)/ (15 × 1)] 
On further calculation 
= 12/15 + 7/ 15 
 
 
 
 
 
 
We get 
= (12 + 7)/ 15 = 19/15 
 
2. Subtract: 
(i) 2/7 from 19/21 
(ii) 21/25 from 18/20 
(iii) 7/16 from 2 
(iv) 4/15 from 2 1/5 
Solution: 
 
(i) 2/7 from 19/21 
It can be written as 
19/21 – 2/7 
We know that LCM of 21 and 7 is 21 
In order to convert fraction into equivalent fraction having 21 as denominator 
= [(19 × 1)/ (21 × 1)] - [(2 × 3)/ (7 × 3)] 
On further calculation 
= 19/21 - 6/21 
We get 
= (19 - 6)/21 = 13/21 
 
(ii) 21/25 from 18/20 
It can be written as 
18/20 – 21/25 
We know that LCM of 20 and 25 is 100 
In order to convert fraction into equivalent fraction having 100 as denominator 
= [(18 × 5)/ (20 × 5)] - [(21 × 4)/ (25 × 4)] 
On further calculation 
= 90/100 - 84/100 
We get 
= (90 - 84)/100 = 6/100 = 3/50 
 
(iii) 7/16 from 2 
It can be written as 
2/1 – 7/16 
We know that LCM of 1 and 16 is 16 
In order to convert fraction into equivalent fraction having 16 as denominator 
= [(16 × 2)/ (16 × 1)] - [(7 × 1)/ (16 × 1)] 
On further calculation 
= 32/16 - 7/16 
We get 
= (32 - 7)/16 = 25/16 
 
(iv) 4/15 from 2 1/5 
It can be written as 
11/5 – 4/15  
We know that LCM of 5 and 15 is 15 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(11 × 3)/ (5 × 3)] - [(4 × 1)/ (15 × 1)] 
 
 
 
 
 
 
On further calculation 
= 33/15 - 4/15 
We get 
= (33 - 4)/15 = 29/15 
 
3. Find the difference of: 
(i) 13/24 and 7/16 
(ii) 5/18 and 4/15 
(iii) 1/12 and 3/4 
(iv) 2/3 and 6/7 
Solution: 
 
(i) 13/24 and 7/16 
It can be written as 
13/24 – 7/16 
We know that LCM of 24 and 16 is 48 
In order to convert fraction into equivalent fraction having 48 as denominator 
= [(13 × 2)/ (24 × 2)] - [(7 × 3)/ (16 × 3)] 
On further calculation 
= 26/48 - 21/48 
We get 
= (26 - 21)/48 = 5/48 
 
(ii) 5/18 and 4/15 
It can be written as 
5/18 – 4/15 
We know that LCM of 18 and 15 is 90 
In order to convert fraction into equivalent fraction having 90 as denominator 
= [(5 × 5)/ (18 × 5)] - [(4 × 6)/ (15 × 6)] 
On further calculation 
= 25/90 - 24/90 
We get 
= (25 - 24)/90 = 1/90 
 
(iii) 1/12 and 3/4 
It can be written as 
3/4 – 1/12 
We know that LCM of 4 and 12 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] - [(1 × 1)/ (12 × 1)] 
On further calculation 
= 9/12 - 1/12 
We get 
= (9 - 1)/12 = 8/12 = 2/3 
 
(iv) 2/3 and 6/7 
It can be written as 
6/7 – 2/3 
We know that LCM of 7 and 3 is 21 
In order to convert fraction into equivalent fraction having 48 as denominator 
 
 
 
 
 
 
= [(6 × 3)/ (7 × 3)] - [(2 × 7)/ (3 × 7)] 
On further calculation 
= 18/21 - 14/21 
We get 
= (18 - 14)/21 = 4/21 
 
4. Subtract as indicated: 
(i) 8/3 – 5/9 
(ii) 4 2/5 – 2 1/5 
(iii) 5 6/7 – 2 2/3 
(iv) 4 3/4 – 2 1/6 
Solution: 
 
(i) 8/3 – 5/9 
It can be written as 
8/3 – 5/9 
We know that LCM of 3 and 9 is 9 
In order to convert fraction into equivalent fraction having 9 as denominator 
= [(8 × 3)/ (3 × 3)] - [(5 × 1)/ (9 × 1)] 
On further calculation 
= 24/9 - 5/9 
We get 
= (24 - 5)/9 = 19/9  
 
(ii) 4 2/5 – 2 1/5 
It can be written as 
22/5 – 11/5 
We get 
= (22 - 11)/5 = 11/5  
 
(iii) 5 6/7 – 2 2/3 
It can be written as 
41/7 – 8/3 
We know that LCM of 7 and 3 is 21 
In order to convert fraction into equivalent fraction having 21 as denominator 
= [(41 × 3)/ (7 × 3)] - [(8 × 7)/ (3 × 7)] 
On further calculation 
= 123/21 - 56/21 
We get 
= (123 - 56)/21 = 67/21  
 
(iv) 4 3/4 – 2 1/6 
It can be written as 
19/4 – 13/6 
We know that LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(19 × 3)/ (4 × 3)] - [(13 × 2)/ (6 × 2)] 
Page 5


 
 
 
 
 
 
Exercise 6.9                                                                               page: 6.35 
1. Add: 
(i) 3/4 and 5/6 
(ii) 7/10 and 2/15 
(iii) 8/13 and 2/3 
(iv) 4/5 and 7/15 
Solution: 
 
(i) 3/4 and 5/6 
It can be written as 
3/4 + 5/6 
We know that the LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] + [(5 × 2)/ (6 × 2)] 
On further calculation 
= 9/12 + 10/ 12 
We get 
= (9 + 10)/ 12 = 19/12 
 
(ii) 7/10 and 2/15 
It can be written as 
7/10 + 2/15 
We know that the LCM of 10 and 15 is 30 
In order to convert fraction into equivalent fraction having 30 as denominator 
= [(7 × 3)/ (10 × 3)] + [(2 × 2)/ (15 × 2)] 
On further calculation 
= 21/30 + 4/ 30 
We get 
= (21 + 4)/ 30 = 25/30 = 5/6 
 
(iii) 8/13 and 2/3 
It can be written as 
8/13 + 2/3 
We know that the LCM of 13 and 3 is 39 
In order to convert fraction into equivalent fraction having 39 as denominator 
= [(8 × 3)/ (13 × 3)] + [(2 × 13)/ (3 × 13)] 
On further calculation 
= 24/39 + 26/39 
We get 
= (24 + 26)/ 39 = 50/39 
 
(iv) 4/5 and 7/15 
It can be written as 
4/5 + 7/15 
We know that the LCM of 5 and 15 is 1 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(4 × 3)/ (5 × 3)] + [(7 × 1)/ (15 × 1)] 
On further calculation 
= 12/15 + 7/ 15 
 
 
 
 
 
 
We get 
= (12 + 7)/ 15 = 19/15 
 
2. Subtract: 
(i) 2/7 from 19/21 
(ii) 21/25 from 18/20 
(iii) 7/16 from 2 
(iv) 4/15 from 2 1/5 
Solution: 
 
(i) 2/7 from 19/21 
It can be written as 
19/21 – 2/7 
We know that LCM of 21 and 7 is 21 
In order to convert fraction into equivalent fraction having 21 as denominator 
= [(19 × 1)/ (21 × 1)] - [(2 × 3)/ (7 × 3)] 
On further calculation 
= 19/21 - 6/21 
We get 
= (19 - 6)/21 = 13/21 
 
(ii) 21/25 from 18/20 
It can be written as 
18/20 – 21/25 
We know that LCM of 20 and 25 is 100 
In order to convert fraction into equivalent fraction having 100 as denominator 
= [(18 × 5)/ (20 × 5)] - [(21 × 4)/ (25 × 4)] 
On further calculation 
= 90/100 - 84/100 
We get 
= (90 - 84)/100 = 6/100 = 3/50 
 
(iii) 7/16 from 2 
It can be written as 
2/1 – 7/16 
We know that LCM of 1 and 16 is 16 
In order to convert fraction into equivalent fraction having 16 as denominator 
= [(16 × 2)/ (16 × 1)] - [(7 × 1)/ (16 × 1)] 
On further calculation 
= 32/16 - 7/16 
We get 
= (32 - 7)/16 = 25/16 
 
(iv) 4/15 from 2 1/5 
It can be written as 
11/5 – 4/15  
We know that LCM of 5 and 15 is 15 
In order to convert fraction into equivalent fraction having 15 as denominator 
= [(11 × 3)/ (5 × 3)] - [(4 × 1)/ (15 × 1)] 
 
 
 
 
 
 
On further calculation 
= 33/15 - 4/15 
We get 
= (33 - 4)/15 = 29/15 
 
3. Find the difference of: 
(i) 13/24 and 7/16 
(ii) 5/18 and 4/15 
(iii) 1/12 and 3/4 
(iv) 2/3 and 6/7 
Solution: 
 
(i) 13/24 and 7/16 
It can be written as 
13/24 – 7/16 
We know that LCM of 24 and 16 is 48 
In order to convert fraction into equivalent fraction having 48 as denominator 
= [(13 × 2)/ (24 × 2)] - [(7 × 3)/ (16 × 3)] 
On further calculation 
= 26/48 - 21/48 
We get 
= (26 - 21)/48 = 5/48 
 
(ii) 5/18 and 4/15 
It can be written as 
5/18 – 4/15 
We know that LCM of 18 and 15 is 90 
In order to convert fraction into equivalent fraction having 90 as denominator 
= [(5 × 5)/ (18 × 5)] - [(4 × 6)/ (15 × 6)] 
On further calculation 
= 25/90 - 24/90 
We get 
= (25 - 24)/90 = 1/90 
 
(iii) 1/12 and 3/4 
It can be written as 
3/4 – 1/12 
We know that LCM of 4 and 12 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(3 × 3)/ (4 × 3)] - [(1 × 1)/ (12 × 1)] 
On further calculation 
= 9/12 - 1/12 
We get 
= (9 - 1)/12 = 8/12 = 2/3 
 
(iv) 2/3 and 6/7 
It can be written as 
6/7 – 2/3 
We know that LCM of 7 and 3 is 21 
In order to convert fraction into equivalent fraction having 48 as denominator 
 
 
 
 
 
 
= [(6 × 3)/ (7 × 3)] - [(2 × 7)/ (3 × 7)] 
On further calculation 
= 18/21 - 14/21 
We get 
= (18 - 14)/21 = 4/21 
 
4. Subtract as indicated: 
(i) 8/3 – 5/9 
(ii) 4 2/5 – 2 1/5 
(iii) 5 6/7 – 2 2/3 
(iv) 4 3/4 – 2 1/6 
Solution: 
 
(i) 8/3 – 5/9 
It can be written as 
8/3 – 5/9 
We know that LCM of 3 and 9 is 9 
In order to convert fraction into equivalent fraction having 9 as denominator 
= [(8 × 3)/ (3 × 3)] - [(5 × 1)/ (9 × 1)] 
On further calculation 
= 24/9 - 5/9 
We get 
= (24 - 5)/9 = 19/9  
 
(ii) 4 2/5 – 2 1/5 
It can be written as 
22/5 – 11/5 
We get 
= (22 - 11)/5 = 11/5  
 
(iii) 5 6/7 – 2 2/3 
It can be written as 
41/7 – 8/3 
We know that LCM of 7 and 3 is 21 
In order to convert fraction into equivalent fraction having 21 as denominator 
= [(41 × 3)/ (7 × 3)] - [(8 × 7)/ (3 × 7)] 
On further calculation 
= 123/21 - 56/21 
We get 
= (123 - 56)/21 = 67/21  
 
(iv) 4 3/4 – 2 1/6 
It can be written as 
19/4 – 13/6 
We know that LCM of 4 and 6 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(19 × 3)/ (4 × 3)] - [(13 × 2)/ (6 × 2)] 
 
 
 
 
 
 
On further calculation 
= 57/12 - 26/12 
We get 
= (57 - 26)/12 = 31/12  
 
5. Simplify: 
(i) 2/3 + 3/4 + 1/2 
(ii) 5/8 + 2/5 + 3/4 
(iii) 3/10 + 7/15 + 3/5 
(iv) 3/4 + 7/16 + 5/8 
(v) 4 2/3 + 3 1/4 + 7 1/2 
(vi) 7 1/3 + 3 2/3 + 5 1/6 
(vii) 7 + 7/4 + 5 1/6 
(viii) 5/6 + 3 + 3/4 
(ix) 7/18 + 5/6 + 1 1/12 
Solution: 
 
(i) 2/3 + 3/4 + 1/2 
We know that the LCM of 3, 4 and 2 is 12 
In order to convert fraction into equivalent fraction having 12 as denominator 
= [(2 × 4)/ (3 × 4)] + [(3 × 3)/ (4 × 3)] + [(1 × 6)/ (2 × 6)] 
On further calculation 
= 8/12+ 9/12 + 6/12 
We get 
= (8 + 9 + 6)/ 12 = 23/12 
 
(ii) 5/8 + 2/5 + 3/4 
We know that the LCM of 8, 5 and 4 is 40 
In order to convert fraction into equivalent fraction having 40 as denominator 
= [(5 × 5)/ (8 × 5)] + [(2 × 8)/ (5 × 8)] + [(3 × 10)/ (4 × 10)] 
On further calculation 
= 25/40 + 16/40 + 30/40 
We get 
= (25 + 16 + 30)/ 40 = 71/40 
 
(iii) 3/10 + 7/15 + 3/5 
We know that the LCM of 10, 15 and 5 is 30 
In order to convert fraction into equivalent fraction having 30 as denominator 
= [(3 × 3)/ (10 × 3)] + [(7 × 2)/ (15 × 2)] + [(3 × 6)/ (5 × 6)] 
On further calculation 
= 9/30+ 14/30 + 18/30 
We get 
= (9 + 14 + 18)/ 30 = 41/30 
 
(iv) 3/4 + 7/16 + 5/8 
We know that the LCM of 4, 16 and 8 is 16 
In order to convert fraction into equivalent fraction having 16 as denominator 
= [(3 × 4)/ (4 × 4)] + [(7 × 1)/ (16 × 1)] + [(5 × 2)/ (8 × 2)]

	Mathematics (Maths) Class 6 94 videos\|347 docs\|54 tests

Mathematics (Maths) Class 6

94 videos|347 docs|54 tests

Join Course for Free

Top Courses for Class 6

View all

Related Exams

Class 6

About this Document

	4.77/5 Rating
	Nov 21, 2024 Last updated

Document Description: RD Sharma Solutions: Fractions (Exercise 6.9) for Class 6 2024 is part of Mathematics (Maths) Class 6 preparation. The notes and questions for RD Sharma Solutions: Fractions (Exercise 6.9) have been prepared according to the Class 6 exam syllabus. Information about RD Sharma Solutions: Fractions (Exercise 6.9) covers topics like and RD Sharma Solutions: Fractions (Exercise 6.9) Example, for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Solutions: Fractions (Exercise 6.9).

Introduction of RD Sharma Solutions: Fractions (Exercise 6.9) in English is available as part of our Mathematics (Maths) Class 6 for Class 6 & RD Sharma Solutions: Fractions (Exercise 6.9) in Hindi for Mathematics (Maths) Class 6 course. Download more important topics related with notes, lectures and mock test series for Class 6 Exam by signing up for free. Class 6: Fractions (Exercise 6.9) RD Sharma Solutions | Mathematics (Maths) Class 6

Description

Full syllabus notes, lecture & questions for Fractions (Exercise 6.9) RD Sharma Solutions | Mathematics (Maths) Class 6 - Class 6 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 6 | Best notes, free PDF download

Information about RD Sharma Solutions: Fractions (Exercise 6.9)

In this doc you can find the meaning of RD Sharma Solutions: Fractions (Exercise 6.9) defined & explained in the simplest way possible. Besides explaining types of RD Sharma Solutions: Fractions (Exercise 6.9) theory, EduRev gives you an ample number of questions to practice RD Sharma Solutions: Fractions (Exercise 6.9) tests, examples and also practice Class 6 tests

	Mathematics (Maths) Class 6 94 videos\|347 docs\|54 tests

Mathematics (Maths) Class 6

94 videos|347 docs|54 tests

Join Course for Free

Download as PDF

Explore Courses for Class 6 exam

Top Courses for Class 6

Explore Courses

Signup for Free!

Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.

Start learning for Free

10M+ students study on EduRev

video lectures

ppt

Previous Year Questions with Solutions

Fractions (Exercise 6.9) RD Sharma Solutions | Mathematics (Maths) Class 6

Extra Questions

Objective type Questions

Viva Questions

study material

Sample Paper

pdf

shortcuts and tricks

Fractions (Exercise 6.9) RD Sharma Solutions | Mathematics (Maths) Class 6

Free

MCQs

practice quizzes

Semester Notes

Important questions

past year papers

Summary

mock tests for examination

Fractions (Exercise 6.9) RD Sharma Solutions | Mathematics (Maths) Class 6

Exam

;

Additional Information about RD Sharma Solutions: Fractions (Exercise 6.9) for Class 6 Preparation

RD Sharma Solutions: Fractions (Exercise 6.9) Free PDF Download

The RD Sharma Solutions: Fractions (Exercise 6.9) is an invaluable resource that delves deep into the core of the Class 6 exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the RD Sharma Solutions: Fractions (Exercise 6.9) now and kickstart your journey towards success in the Class 6 exam.

Importance of RD Sharma Solutions: Fractions (Exercise 6.9)

The importance of RD Sharma Solutions: Fractions (Exercise 6.9) cannot be overstated, especially for Class 6 aspirants. This document holds the key to success in the Class 6 exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

RD Sharma Solutions: Fractions (Exercise 6.9) Notes

RD Sharma Solutions: Fractions (Exercise 6.9) Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to RD Sharma Solutions: Fractions (Exercise 6.9). It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, RD Sharma Solutions: Fractions (Exercise 6.9) Notes on EduRev are your ultimate resource for success.

RD Sharma Solutions: Fractions (Exercise 6.9) Class 6 Questions

The "RD Sharma Solutions: Fractions (Exercise 6.9) Class 6 Questions" guide is a valuable resource for all aspiring students preparing for the Class 6 exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study RD Sharma Solutions: Fractions (Exercise 6.9) on the App

Students of Class 6 can study RD Sharma Solutions: Fractions (Exercise 6.9) alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the RD Sharma Solutions: Fractions (Exercise 6.9), students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of RD Sharma Solutions: Fractions (Exercise 6.9) is prepared as per the latest Class 6 syllabus.

Education Revolution