Class 6 Exam > Class 6 Notes > Mathematics (Maths) Class 6 > RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4)
Ratio, Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions | Mathematics (Maths) Class 6 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1 Exercise 9.4 PAGE: 9.18 1. The price of 3 metres of cloth is Rs 79.50. Find the price of 15 metres of such cloth. Solution: It is given that Price of 3 m of cloth = Rs 79.50 We get Price of 1 m of cloth = 79.50/3 = Rs 26.5 So the price of 15 m of cloth = 26.5 (15) = Rs 397.50 Hence, the price of 15 m of such cloth is Rs 397.50. 2. The cost of 17 chairs is Rs 9605. Find the number of chairs that can be purchased in Rs 56500. Solution: No. of chairs purchased for Rs 9605 = 17 We get No. of chairs purchased for Rs 1 = 17/9605 So the number of chairs purchased for Rs 56500 = 17/9605 (56500) = 100 Hence, 100 chairs can be purchased in Rs 56500. 3. Three ferryloads are needed to carry 150 people across a river. How many people will be carried on 4 ferryloads? Solution: We know that No. of people required to carry 3 ferryloads = 150 We get No. of people required to carry 1 ferryload = 150/3 = 50 So the number of people required to carry 4 ferryloads = 4 (50) = 200 Hence, 200 people are required to carry 4 ferryloads. 4. If 9 kg of rice costs Rs 120.60, what will 50 kg of such a quality of rice cost? Solution: It is given that Cost of 9 kg rice = Rs 120.60 We know that Cost of 1 kg rice = 120.60/9 = Rs 13.4 So the cost of 50 kg rice = 13.4 (50) = Rs 670 Hence, 50 kg of such a quality of rice costs Rs 670. 5. A train runs 200 kilometres in 5 hours. How many kilometres does it run in 7 hours? Solution: Distance travelled by train in 5 hours = 200 km Page 2 Exercise 9.4 PAGE: 9.18 1. The price of 3 metres of cloth is Rs 79.50. Find the price of 15 metres of such cloth. Solution: It is given that Price of 3 m of cloth = Rs 79.50 We get Price of 1 m of cloth = 79.50/3 = Rs 26.5 So the price of 15 m of cloth = 26.5 (15) = Rs 397.50 Hence, the price of 15 m of such cloth is Rs 397.50. 2. The cost of 17 chairs is Rs 9605. Find the number of chairs that can be purchased in Rs 56500. Solution: No. of chairs purchased for Rs 9605 = 17 We get No. of chairs purchased for Rs 1 = 17/9605 So the number of chairs purchased for Rs 56500 = 17/9605 (56500) = 100 Hence, 100 chairs can be purchased in Rs 56500. 3. Three ferryloads are needed to carry 150 people across a river. How many people will be carried on 4 ferryloads? Solution: We know that No. of people required to carry 3 ferryloads = 150 We get No. of people required to carry 1 ferryload = 150/3 = 50 So the number of people required to carry 4 ferryloads = 4 (50) = 200 Hence, 200 people are required to carry 4 ferryloads. 4. If 9 kg of rice costs Rs 120.60, what will 50 kg of such a quality of rice cost? Solution: It is given that Cost of 9 kg rice = Rs 120.60 We know that Cost of 1 kg rice = 120.60/9 = Rs 13.4 So the cost of 50 kg rice = 13.4 (50) = Rs 670 Hence, 50 kg of such a quality of rice costs Rs 670. 5. A train runs 200 kilometres in 5 hours. How many kilometres does it run in 7 hours? Solution: Distance travelled by train in 5 hours = 200 km We know that Distance travelled by train in 1 hour = 200/5 = 40 km So the distance travelled by train in 7 hours = 40 (7) = 280 km Hence, the train runs 280 km in 7 hours. 6. 10 boys can dig a pitch in 12 hours. How long will 8 boys take to do it? Solution: It is given that 10 boys can dig a pitch in 12 hours We know that the time taken by one boy = 10 (12) = 120 hours So the time taken by 8 boys to dig the pitch = 120/8 = 15 hours Hence, 8 boys will take 15 hours to dig the pitch. 7. A man can work 8 hours daily and finishes a work in 12 days. If he works 6 hours daily, in how many days will the same work be finished? Solution: It is given that A man can work 8 hours daily and finishes a work in 12 days If he works for one hour, then the time taken to finish the work = 8 × 12 = 96 days If he works 6 hours daily, the days required to finish the work = 96/6 = 16 days Hence, the man requires 16 days to finish the same work. 8. Fifteen post cards cost Rs 2.25. What will be the cost of 36 post cards? How many postcards can be bought in Rs 45? Solution: It is given that Cost of fifteen post cards = Rs 2.25 We know that Cost of one post card = Rs 2.25/15 So the cost of 36 post cards = 2.25/15 (36) = Rs 5.40 We get No. of postcards that can be purchased in Rs 1 = 15/2.25 Number of postcards that can be bought in Rs 45 = 15/2.25 (45) = 300 Hence, the cost of 36 post cards is Rs 5.40 and 300 post cards can be bought in Rs 45. 9. A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost? Solution: It is given that Cost of rail journey of 75 km = Rs 215 We know that Cost of rail journey of 1 km = Rs 215/75 Page 3 Exercise 9.4 PAGE: 9.18 1. The price of 3 metres of cloth is Rs 79.50. Find the price of 15 metres of such cloth. Solution: It is given that Price of 3 m of cloth = Rs 79.50 We get Price of 1 m of cloth = 79.50/3 = Rs 26.5 So the price of 15 m of cloth = 26.5 (15) = Rs 397.50 Hence, the price of 15 m of such cloth is Rs 397.50. 2. The cost of 17 chairs is Rs 9605. Find the number of chairs that can be purchased in Rs 56500. Solution: No. of chairs purchased for Rs 9605 = 17 We get No. of chairs purchased for Rs 1 = 17/9605 So the number of chairs purchased for Rs 56500 = 17/9605 (56500) = 100 Hence, 100 chairs can be purchased in Rs 56500. 3. Three ferryloads are needed to carry 150 people across a river. How many people will be carried on 4 ferryloads? Solution: We know that No. of people required to carry 3 ferryloads = 150 We get No. of people required to carry 1 ferryload = 150/3 = 50 So the number of people required to carry 4 ferryloads = 4 (50) = 200 Hence, 200 people are required to carry 4 ferryloads. 4. If 9 kg of rice costs Rs 120.60, what will 50 kg of such a quality of rice cost? Solution: It is given that Cost of 9 kg rice = Rs 120.60 We know that Cost of 1 kg rice = 120.60/9 = Rs 13.4 So the cost of 50 kg rice = 13.4 (50) = Rs 670 Hence, 50 kg of such a quality of rice costs Rs 670. 5. A train runs 200 kilometres in 5 hours. How many kilometres does it run in 7 hours? Solution: Distance travelled by train in 5 hours = 200 km We know that Distance travelled by train in 1 hour = 200/5 = 40 km So the distance travelled by train in 7 hours = 40 (7) = 280 km Hence, the train runs 280 km in 7 hours. 6. 10 boys can dig a pitch in 12 hours. How long will 8 boys take to do it? Solution: It is given that 10 boys can dig a pitch in 12 hours We know that the time taken by one boy = 10 (12) = 120 hours So the time taken by 8 boys to dig the pitch = 120/8 = 15 hours Hence, 8 boys will take 15 hours to dig the pitch. 7. A man can work 8 hours daily and finishes a work in 12 days. If he works 6 hours daily, in how many days will the same work be finished? Solution: It is given that A man can work 8 hours daily and finishes a work in 12 days If he works for one hour, then the time taken to finish the work = 8 × 12 = 96 days If he works 6 hours daily, the days required to finish the work = 96/6 = 16 days Hence, the man requires 16 days to finish the same work. 8. Fifteen post cards cost Rs 2.25. What will be the cost of 36 post cards? How many postcards can be bought in Rs 45? Solution: It is given that Cost of fifteen post cards = Rs 2.25 We know that Cost of one post card = Rs 2.25/15 So the cost of 36 post cards = 2.25/15 (36) = Rs 5.40 We get No. of postcards that can be purchased in Rs 1 = 15/2.25 Number of postcards that can be bought in Rs 45 = 15/2.25 (45) = 300 Hence, the cost of 36 post cards is Rs 5.40 and 300 post cards can be bought in Rs 45. 9. A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost? Solution: It is given that Cost of rail journey of 75 km = Rs 215 We know that Cost of rail journey of 1 km = Rs 215/75 So the cost of rail journey of 120 km = 215/75 (120) = Rs 344 Hence, the cost of rail journey of 120 km is Rs 344. 10. If the sales tax on a purchase worth Rs 60 is Rs 4.20. What will be the sales tax on the purchase worth Rs 150? Solution: It is given that Sales tax on a purchase worth Rs 60 = Rs 4.20 We know that Sales tax on a purchase worth Rs 1 = Rs 4.20/60 So the sales tax on the purchase worth Rs 150 = 4.20/60 (150) = Rs 10.50 Hence, the sales tax on the purchase worth Rs 150 is Rs 10.50. 11. The cost of 17 chairs is Rs 19210. Find the number of such chairs that can be purchased in Rs 113000? Solution: It is given that No. of chairs purchased in Rs 19210 = 17 We know that No. of chairs purchased in Rs 1 = 17/19210 So the number of chairs that can be purchased in Rs 113000 = 17/19210 (113000) = 100 Hence, 100 chairs can be purchased in Rs 113000. 12. A car travels 165 km in 3 hours (i) How long will it take to travel 440 km? (ii) How far will it travel in 7 hours? Solution: Distance travelled by car = 165 km in 3 hours So the speed of car = Distance/ time = 165/3 = 55 km per hour (i) Time taken to travel 440 km = 440/55 = 8 hours (ii) Distance covered in 7 hours = 55 (7) = 385 km 13. 2 dozens of oranges cost Rs 60. Find the cost of 120 similar oranges? Solution: It is given that Cost of 2 dozens of oranges = Rs 60 We know that Cost of 1 orange = Rs 60/24 So the cost of 120 similar oranges = 60/24 (120) = Rs 300 Hence, the cost of 120 similar oranges is Rs 300. Page 4 Exercise 9.4 PAGE: 9.18 1. The price of 3 metres of cloth is Rs 79.50. Find the price of 15 metres of such cloth. Solution: It is given that Price of 3 m of cloth = Rs 79.50 We get Price of 1 m of cloth = 79.50/3 = Rs 26.5 So the price of 15 m of cloth = 26.5 (15) = Rs 397.50 Hence, the price of 15 m of such cloth is Rs 397.50. 2. The cost of 17 chairs is Rs 9605. Find the number of chairs that can be purchased in Rs 56500. Solution: No. of chairs purchased for Rs 9605 = 17 We get No. of chairs purchased for Rs 1 = 17/9605 So the number of chairs purchased for Rs 56500 = 17/9605 (56500) = 100 Hence, 100 chairs can be purchased in Rs 56500. 3. Three ferryloads are needed to carry 150 people across a river. How many people will be carried on 4 ferryloads? Solution: We know that No. of people required to carry 3 ferryloads = 150 We get No. of people required to carry 1 ferryload = 150/3 = 50 So the number of people required to carry 4 ferryloads = 4 (50) = 200 Hence, 200 people are required to carry 4 ferryloads. 4. If 9 kg of rice costs Rs 120.60, what will 50 kg of such a quality of rice cost? Solution: It is given that Cost of 9 kg rice = Rs 120.60 We know that Cost of 1 kg rice = 120.60/9 = Rs 13.4 So the cost of 50 kg rice = 13.4 (50) = Rs 670 Hence, 50 kg of such a quality of rice costs Rs 670. 5. A train runs 200 kilometres in 5 hours. How many kilometres does it run in 7 hours? Solution: Distance travelled by train in 5 hours = 200 km We know that Distance travelled by train in 1 hour = 200/5 = 40 km So the distance travelled by train in 7 hours = 40 (7) = 280 km Hence, the train runs 280 km in 7 hours. 6. 10 boys can dig a pitch in 12 hours. How long will 8 boys take to do it? Solution: It is given that 10 boys can dig a pitch in 12 hours We know that the time taken by one boy = 10 (12) = 120 hours So the time taken by 8 boys to dig the pitch = 120/8 = 15 hours Hence, 8 boys will take 15 hours to dig the pitch. 7. A man can work 8 hours daily and finishes a work in 12 days. If he works 6 hours daily, in how many days will the same work be finished? Solution: It is given that A man can work 8 hours daily and finishes a work in 12 days If he works for one hour, then the time taken to finish the work = 8 × 12 = 96 days If he works 6 hours daily, the days required to finish the work = 96/6 = 16 days Hence, the man requires 16 days to finish the same work. 8. Fifteen post cards cost Rs 2.25. What will be the cost of 36 post cards? How many postcards can be bought in Rs 45? Solution: It is given that Cost of fifteen post cards = Rs 2.25 We know that Cost of one post card = Rs 2.25/15 So the cost of 36 post cards = 2.25/15 (36) = Rs 5.40 We get No. of postcards that can be purchased in Rs 1 = 15/2.25 Number of postcards that can be bought in Rs 45 = 15/2.25 (45) = 300 Hence, the cost of 36 post cards is Rs 5.40 and 300 post cards can be bought in Rs 45. 9. A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost? Solution: It is given that Cost of rail journey of 75 km = Rs 215 We know that Cost of rail journey of 1 km = Rs 215/75 So the cost of rail journey of 120 km = 215/75 (120) = Rs 344 Hence, the cost of rail journey of 120 km is Rs 344. 10. If the sales tax on a purchase worth Rs 60 is Rs 4.20. What will be the sales tax on the purchase worth Rs 150? Solution: It is given that Sales tax on a purchase worth Rs 60 = Rs 4.20 We know that Sales tax on a purchase worth Rs 1 = Rs 4.20/60 So the sales tax on the purchase worth Rs 150 = 4.20/60 (150) = Rs 10.50 Hence, the sales tax on the purchase worth Rs 150 is Rs 10.50. 11. The cost of 17 chairs is Rs 19210. Find the number of such chairs that can be purchased in Rs 113000? Solution: It is given that No. of chairs purchased in Rs 19210 = 17 We know that No. of chairs purchased in Rs 1 = 17/19210 So the number of chairs that can be purchased in Rs 113000 = 17/19210 (113000) = 100 Hence, 100 chairs can be purchased in Rs 113000. 12. A car travels 165 km in 3 hours (i) How long will it take to travel 440 km? (ii) How far will it travel in 7 hours? Solution: Distance travelled by car = 165 km in 3 hours So the speed of car = Distance/ time = 165/3 = 55 km per hour (i) Time taken to travel 440 km = 440/55 = 8 hours (ii) Distance covered in 7 hours = 55 (7) = 385 km 13. 2 dozens of oranges cost Rs 60. Find the cost of 120 similar oranges? Solution: It is given that Cost of 2 dozens of oranges = Rs 60 We know that Cost of 1 orange = Rs 60/24 So the cost of 120 similar oranges = 60/24 (120) = Rs 300 Hence, the cost of 120 similar oranges is Rs 300. 14. A family of 4 members consumes 6 kg of sugar in a month. What will be the monthly consumption of sugar, if the number of family members becomes 6? Solution: It is given that Amount of sugar used by a 4 members family = 6 kg We know that Amount of sugar used by 1 member = 6/4 kg So the sugar consumed by 6 members of a family = 6/4 (6) = 9kg Hence, 9 kg is the monthly consumption of sugar, if the number of family members becomes 6. 15. The weight of 45 folding chairs is 18 kg. How many such chairs can be loaded on a truck having a capacity of carrying 4000 kg load? Solution: It is given that No. of folding chairs weighing 18 kg = 45 We know that No. of folding chairs weighing 1 kg = 45/18 So the number of folding chairs weighing 4000 kg = 45/18 (4000) = 10000 Hence, 10000 chairs can be loaded on a truck having a capacity of carrying 4000 kg load.Read More
|
94 videos|347 docs|54 tests
|
FAQs on Ratio, Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions - Mathematics (Maths) Class 6
| 1. What is the definition of ratio in mathematics? |  |
Ans. In mathematics, ratio is a way of comparing two or more quantities by division. It represents the quantitative relationship between the quantities and is expressed as a fraction, using a colon or as a quotient of two numbers.
| 2. How can we simplify ratios? | |
Ans. Ratios can be simplified by dividing both the numerator and denominator by their greatest common divisor. This process is known as simplifying or reducing the ratio to its simplest form.
| 3. What is the unitary method in mathematics? | |
Ans. The unitary method is a technique used in mathematics to solve problems related to ratios and proportions. It involves finding the value of a single unit and then using that information to determine the value of multiple units or quantities.
| 4. How can we solve problems based on proportions? | |
Ans. To solve problems based on proportions, we can use the concept of cross-multiplication. This involves multiplying the numerator of one ratio by the denominator of the other ratio and setting the two products equal to each other. By solving the resulting equation, we can find the unknown quantity.
| 5. Can you provide an example of a ratio and proportion problem? | |
Ans. Sure! Here's an example: If the ratio of boys to girls in a class is 3:5 and there are 15 girls, how many boys are there? To solve this proportion, we can set up the equation 3/5 = x/15, where x represents the number of boys. By cross-multiplying and solving for x, we find that there are 9 boys in the class.
Related Exams
About this Document
|
4.81/5 Rating |
|
Oct 24, 2024 Last updated |
Document Description: RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) for Class 6 2024 is part of Mathematics (Maths) Class 6 preparation.
The notes and questions for RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) have been prepared according to the Class 6 exam syllabus. Information about RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) covers topics
like and RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Example, for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4).
Introduction of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) in English is available as part of our Mathematics (Maths) Class 6
for Class 6 & RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) in Hindi for Mathematics (Maths) Class 6 course.
Download more important topics related with notes, lectures and mock test series for Class 6
Exam by signing up for free. Class 6: Ratio, Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions | Mathematics (Maths) Class 6
Description
Full syllabus notes, lecture & questions for Ratio, Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions | Mathematics (Maths) Class 6 - Class 6 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 6 | Best notes, free PDF download
Information about RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4)
In this doc you can find the meaning of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) defined & explained in the simplest way possible. Besides explaining types of
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) theory, EduRev gives you an ample number of questions to practice RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) tests, examples and also practice Class 6
tests
|
Explore Courses for Class 6 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
MCQs
,Important questions
,Summary
,Semester Notes
,mock tests for examination
,Previous Year Questions with Solutions
,study material
,Ratio
,Ratio
,Objective type Questions
,Exam
,Ratio
,ppt
,Sample Paper
,practice quizzes
,Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions | Mathematics (Maths) Class 6
,past year papers
,Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions | Mathematics (Maths) Class 6
,Free
,Viva Questions
,Proportion & Unitary Method (Exercise 9.4) RD Sharma Solutions | Mathematics (Maths) Class 6
,Extra Questions
,video lectures
,shortcuts and tricks
;
Additional Information about RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) for Class 6 Preparation
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Free PDF Download
The RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) is an invaluable resource that delves deep into the core of the Class 6 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) now and kickstart your journey towards success in the Class 6 exam.
Importance of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4)
The importance of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) cannot be overstated, especially for Class 6 aspirants.
This document holds the key to success in the Class 6 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Notes
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4).
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Notes on EduRev are your ultimate resource for success.
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Class 6 Questions
The "RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) Class 6 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 6 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) on the App
Students of Class 6 can study RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4),
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.4) is prepared as per the latest Class 6 syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup