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The Solid State Practice Questions - DPP for NEET

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1. (b)
= 4
? It has fcc unit cell.
2. (a) Wurtzite has face centred cubic structure in which each Zn
2+
 ion is
attached to four S
2– 
ions and each S
2–
 ion remains in contact with
four Zn
2+
 ions.  Hence coordination number of each ion is 4.
3. (c) The increase in pressure results in decrease in size of ions (more in
case of anion than cation), the  increases and the
coordination number also increase.
4. (a) ratio is  Hence LiF has NaCl structure with CN
= 6.
5. (a) Diamond is like ZnS. In diamond cubic unit cell, there are eight
corner atoms, six face centered atoms and four more atoms inside
the structure.
Number of atoms present in a diamond cubic cell
=  = 8
(corners) (face centered) (inside body)
6. (a) Fraction of unoccupied sites in NaCl crystal
 = 5.96 × 10
–3
7. (a) MnO
2
Page 2


1. (b)
= 4
? It has fcc unit cell.
2. (a) Wurtzite has face centred cubic structure in which each Zn
2+
 ion is
attached to four S
2– 
ions and each S
2–
 ion remains in contact with
four Zn
2+
 ions.  Hence coordination number of each ion is 4.
3. (c) The increase in pressure results in decrease in size of ions (more in
case of anion than cation), the  increases and the
coordination number also increase.
4. (a) ratio is  Hence LiF has NaCl structure with CN
= 6.
5. (a) Diamond is like ZnS. In diamond cubic unit cell, there are eight
corner atoms, six face centered atoms and four more atoms inside
the structure.
Number of atoms present in a diamond cubic cell
=  = 8
(corners) (face centered) (inside body)
6. (a) Fraction of unoccupied sites in NaCl crystal
 = 5.96 × 10
–3
7. (a) MnO
2
8. (c) I
2
 (s)
9. (a)
10. (b) It is the property of liquid crystal.
11. (d) Calculate the  ratio to get the limiting ratio value and consult
the table. All are correct.
12. (a) = 
Hence 
13. (c) For cubic geometry the limiting ratio is
 i.e., (c)
14. (a) Statement (a) is correct.
15. (a) For bcc lattice body diagonal = .
The distance between the two oppositely charged ions  = 
16. (d) Number of formulas in cube shaped crystals 
since in NaCl type of structure 4 formula units form 'a' cell
units cells  = 2.57 × 10
21
 unit cells.
17. (c) As CsCl is body-centred, 
18. (c) AB is just like NaCl. Thus twelve A
+
 are at edges and 1 within
body of fcc i.e. in octahedral voids and six B
–
 at faces and 8 at
corner.
19. (b) Among the given crystals, only silicon exists as a covalent solid. It
has diamond like structure.
20. (c) The p.f. for body centred cube = 0.68.
Page 3


1. (b)
= 4
? It has fcc unit cell.
2. (a) Wurtzite has face centred cubic structure in which each Zn
2+
 ion is
attached to four S
2– 
ions and each S
2–
 ion remains in contact with
four Zn
2+
 ions.  Hence coordination number of each ion is 4.
3. (c) The increase in pressure results in decrease in size of ions (more in
case of anion than cation), the  increases and the
coordination number also increase.
4. (a) ratio is  Hence LiF has NaCl structure with CN
= 6.
5. (a) Diamond is like ZnS. In diamond cubic unit cell, there are eight
corner atoms, six face centered atoms and four more atoms inside
the structure.
Number of atoms present in a diamond cubic cell
=  = 8
(corners) (face centered) (inside body)
6. (a) Fraction of unoccupied sites in NaCl crystal
 = 5.96 × 10
–3
7. (a) MnO
2
8. (c) I
2
 (s)
9. (a)
10. (b) It is the property of liquid crystal.
11. (d) Calculate the  ratio to get the limiting ratio value and consult
the table. All are correct.
12. (a) = 
Hence 
13. (c) For cubic geometry the limiting ratio is
 i.e., (c)
14. (a) Statement (a) is correct.
15. (a) For bcc lattice body diagonal = .
The distance between the two oppositely charged ions  = 
16. (d) Number of formulas in cube shaped crystals 
since in NaCl type of structure 4 formula units form 'a' cell
units cells  = 2.57 × 10
21
 unit cells.
17. (c) As CsCl is body-centred, 
18. (c) AB is just like NaCl. Thus twelve A
+
 are at edges and 1 within
body of fcc i.e. in octahedral voids and six B
–
 at faces and 8 at
corner.
19. (b) Among the given crystals, only silicon exists as a covalent solid. It
has diamond like structure.
20. (c) The p.f. for body centred cube = 0.68.
21. (1.46)
22. (5) To get a n – type semiconductor from silicon, it should be doped
with a substance with valency 5.
e.g., silicon is doped with phosphorus to form a n – type semiconductor.
23. (1.432) = 
2.7 =  Z = 4
Hence it is face centred cubic unit lattice.
Again 4r =  = 5.727 Å
 r = 1.432 Å
24. (4) In Na
2
O there is antifluorite structure. Here negative ions form the
ccp arrangement so that each positive ion is surrounded by 4
negative ions and each negative ion is surrounded by 8 positive
ions. So coordination no. of Na
+
 is 4.
25. (1.15) ;
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FAQs on The Solid State Practice Questions - DPP for NEET

1. What is the meaning of NEET?
Ans. NEET stands for National Eligibility cum Entrance Test. It is a national-level entrance exam conducted in India for students who wish to pursue undergraduate medical and dental courses in government or private medical colleges in India.
2. What is the significance of Daily Practice Problems (DPP) for NEET?
Ans. Daily Practice Problems (DPP) for NEET are an important tool for NEET aspirants to enhance their preparation. These daily practice problems provide regular practice, help in improving time management skills, and boost confidence by familiarizing students with the exam pattern and types of questions asked in the NEET exam.
3. What is the topic covered in Chapter "The Solid State"?
Ans. The chapter "The Solid State" covers the fundamental concepts related to the solid state of matter in chemistry. It includes topics such as classification of solids, crystal lattice, unit cell, packing in solids, and various types of crystal structures.
4. How can I prepare for the chapter "The Solid State" for NEET?
Ans. To prepare for the chapter "The Solid State" for NEET, you can follow these steps: - Start by understanding the basic concepts and definitions related to the solid state of matter. - Read the chapter thoroughly from your textbook and make notes of important points. - Practice solving numerical problems and questions from previous year NEET question papers related to the solid state. - Refer to reliable study materials and online resources for additional practice and clarification of doubts. - Revise regularly and attempt mock tests to assess your understanding and improve your speed and accuracy.
5. What are some common mistakes to avoid while studying the chapter "The Solid State" for NEET?
Ans. Some common mistakes to avoid while studying the chapter "The Solid State" for NEET include: - Neglecting to understand the basic concepts and definitions, which are essential for solving problems related to the solid state. - Relying solely on memorization instead of understanding the underlying principles and their applications. - Skipping the practice of numerical problems and relying only on theoretical knowledge. - Not revising the chapter regularly, leading to forgetting important concepts and equations. - Not seeking help or clarification for doubts from teachers or online resources, which can hinder proper understanding of the topic.
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