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Solutions Practice Questions - DPP for NEET

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 Page 1


PART-I (Single Correct MCQs)
1. The solubility of a solid in a liquid is significantly affected by
temperature changes.
Solute + Solvent  Solution.
The  system being in a dynamic equilibrium must followLe-chatelier’s
principle. Considering the Le-chatelier’s principle which of the
following is correct?
(a) ??
sol
 > 0; solubility ; temperature
(b) ??
sol
 < 0; solubility ; temperature
(c) ??
sol
 > 0; solubility ; temperature
(d) ??
sol
 < 0; solubility ; temperature
2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and 
 = 0.4) and B (p°= 120 mm Hg and  = 0.6) is found to be 100
mm Hg. It shows that the solution exhibits
(a) positive deviation from ideal behaviour
Page 2


PART-I (Single Correct MCQs)
1. The solubility of a solid in a liquid is significantly affected by
temperature changes.
Solute + Solvent  Solution.
The  system being in a dynamic equilibrium must followLe-chatelier’s
principle. Considering the Le-chatelier’s principle which of the
following is correct?
(a) ??
sol
 > 0; solubility ; temperature
(b) ??
sol
 < 0; solubility ; temperature
(c) ??
sol
 > 0; solubility ; temperature
(d) ??
sol
 < 0; solubility ; temperature
2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and 
 = 0.4) and B (p°= 120 mm Hg and  = 0.6) is found to be 100
mm Hg. It shows that the solution exhibits
(a) positive deviation from ideal behaviour
(b) negative deviation from ideal behaviour
(c) ideal behaviour
(d) positive deviation for lower conc. and negative for higher conc.
3. Henry’s law constant of oxygen is 1.4 × 10
–3
 mol. lit
–1
. atm
–1
 at 298 K.
How much of oxygen is dissolved in 100 mL at 298 K when the partial
pressure of oxygen is 0.5 atm?
(a) 1.4 g
(b) 3.2 g
(c) 22.4 mg
(d) 2.24 mg
4. A solution containing components A and B follows Raoult’s law when
(a) A – B attraction force is greater than A – A and B – B
(b) A – B attraction force is less than A – A and B – B
(c) A – B attraction force remains same as A–A and B –B
(d) Volume of solution is different from sum of volume of solute and
solvent
5. Two 1-litre flask  A and B are connected to each other by a valve which
is closed. Flask A has benzene in equilibrium with its vapours at 30°C.
The flask B, is evacuated, and the valve is opened. Which of the
following is true. If temperature is kept constant.’
(a) Some of the benzene molecules would move to flask B from flask A.
(b) Vapour pressure will be half the initial value.
(c) The vapour pressure remains unchanged
(d) Some more of the liquid benzene in flask A would evaporate.
6. For a solution of two liquids A and B it was proved that 
. The resulting solution will be
(a) Non -ideal
(b) ideal
Page 3


PART-I (Single Correct MCQs)
1. The solubility of a solid in a liquid is significantly affected by
temperature changes.
Solute + Solvent  Solution.
The  system being in a dynamic equilibrium must followLe-chatelier’s
principle. Considering the Le-chatelier’s principle which of the
following is correct?
(a) ??
sol
 > 0; solubility ; temperature
(b) ??
sol
 < 0; solubility ; temperature
(c) ??
sol
 > 0; solubility ; temperature
(d) ??
sol
 < 0; solubility ; temperature
2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and 
 = 0.4) and B (p°= 120 mm Hg and  = 0.6) is found to be 100
mm Hg. It shows that the solution exhibits
(a) positive deviation from ideal behaviour
(b) negative deviation from ideal behaviour
(c) ideal behaviour
(d) positive deviation for lower conc. and negative for higher conc.
3. Henry’s law constant of oxygen is 1.4 × 10
–3
 mol. lit
–1
. atm
–1
 at 298 K.
How much of oxygen is dissolved in 100 mL at 298 K when the partial
pressure of oxygen is 0.5 atm?
(a) 1.4 g
(b) 3.2 g
(c) 22.4 mg
(d) 2.24 mg
4. A solution containing components A and B follows Raoult’s law when
(a) A – B attraction force is greater than A – A and B – B
(b) A – B attraction force is less than A – A and B – B
(c) A – B attraction force remains same as A–A and B –B
(d) Volume of solution is different from sum of volume of solute and
solvent
5. Two 1-litre flask  A and B are connected to each other by a valve which
is closed. Flask A has benzene in equilibrium with its vapours at 30°C.
The flask B, is evacuated, and the valve is opened. Which of the
following is true. If temperature is kept constant.’
(a) Some of the benzene molecules would move to flask B from flask A.
(b) Vapour pressure will be half the initial value.
(c) The vapour pressure remains unchanged
(d) Some more of the liquid benzene in flask A would evaporate.
6. For a solution of two liquids A and B it was proved that 
. The resulting solution will be
(a) Non -ideal
(b) ideal
(c) semi-ideal
(d) None of these
7. All form ideal solution except
(a) C
6
H
6
 and C
6
H
5
 CH
3
(b) C
2
H
6
 and C
2
H
5
I
(c) C
6
H
5
Cl and C
6
H
5
Br
(d) C
2
H
5 
I and C
2
H
5
 OH.
8. A binary liquid solution is prepared by mixing n-heptane and ethanol.
Which one of the following statements is correct regarding the
behaviour of the solution?
(a) The solution is non-ideal, showing – ve deviation from Raoult’s
Law.
(b) The solution is non-ideal, showing + ve deviation from Raoult’s
Law.
(c) n-heptane shows + ve deviation while ethanol shows– ve deviation from
Raoult’s Law.
(d) The solution formed is an ideal solution.
9. During depression of freezing point in a solution the following are in
equilibrium
(a) liquid solvent, solid solvent
(b) liquid solvent, solid solute
(c) liquid solute, solid solute
(d) liquid solute, solid solvent
10. Which of the following modes of expressing concentration is independent
of temperature ?
Page 4


PART-I (Single Correct MCQs)
1. The solubility of a solid in a liquid is significantly affected by
temperature changes.
Solute + Solvent  Solution.
The  system being in a dynamic equilibrium must followLe-chatelier’s
principle. Considering the Le-chatelier’s principle which of the
following is correct?
(a) ??
sol
 > 0; solubility ; temperature
(b) ??
sol
 < 0; solubility ; temperature
(c) ??
sol
 > 0; solubility ; temperature
(d) ??
sol
 < 0; solubility ; temperature
2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and 
 = 0.4) and B (p°= 120 mm Hg and  = 0.6) is found to be 100
mm Hg. It shows that the solution exhibits
(a) positive deviation from ideal behaviour
(b) negative deviation from ideal behaviour
(c) ideal behaviour
(d) positive deviation for lower conc. and negative for higher conc.
3. Henry’s law constant of oxygen is 1.4 × 10
–3
 mol. lit
–1
. atm
–1
 at 298 K.
How much of oxygen is dissolved in 100 mL at 298 K when the partial
pressure of oxygen is 0.5 atm?
(a) 1.4 g
(b) 3.2 g
(c) 22.4 mg
(d) 2.24 mg
4. A solution containing components A and B follows Raoult’s law when
(a) A – B attraction force is greater than A – A and B – B
(b) A – B attraction force is less than A – A and B – B
(c) A – B attraction force remains same as A–A and B –B
(d) Volume of solution is different from sum of volume of solute and
solvent
5. Two 1-litre flask  A and B are connected to each other by a valve which
is closed. Flask A has benzene in equilibrium with its vapours at 30°C.
The flask B, is evacuated, and the valve is opened. Which of the
following is true. If temperature is kept constant.’
(a) Some of the benzene molecules would move to flask B from flask A.
(b) Vapour pressure will be half the initial value.
(c) The vapour pressure remains unchanged
(d) Some more of the liquid benzene in flask A would evaporate.
6. For a solution of two liquids A and B it was proved that 
. The resulting solution will be
(a) Non -ideal
(b) ideal
(c) semi-ideal
(d) None of these
7. All form ideal solution except
(a) C
6
H
6
 and C
6
H
5
 CH
3
(b) C
2
H
6
 and C
2
H
5
I
(c) C
6
H
5
Cl and C
6
H
5
Br
(d) C
2
H
5 
I and C
2
H
5
 OH.
8. A binary liquid solution is prepared by mixing n-heptane and ethanol.
Which one of the following statements is correct regarding the
behaviour of the solution?
(a) The solution is non-ideal, showing – ve deviation from Raoult’s
Law.
(b) The solution is non-ideal, showing + ve deviation from Raoult’s
Law.
(c) n-heptane shows + ve deviation while ethanol shows– ve deviation from
Raoult’s Law.
(d) The solution formed is an ideal solution.
9. During depression of freezing point in a solution the following are in
equilibrium
(a) liquid solvent, solid solvent
(b) liquid solvent, solid solute
(c) liquid solute, solid solute
(d) liquid solute, solid solvent
10. Which of the following modes of expressing concentration is independent
of temperature ?
(a) Molarity
(b) Molality
(c) Formality
(d) Normality
11. How many grams of concentrated nitric acid solution should be used to
prepare 250 mL of 2.0M HNO
3
 ? The concentrated acid is 70% HNO
3
(a) 90.0 g conc. HNO
3
(b) 70.0 g conc. HNO
3
(c) 54.0 g conc. HNO
3
(d) 45.0 g conc. HNO
3
12. Which among the following will show maximum osmotic pressure?
(a) 1 M NaCl
(b) 1 M MgCl
2
(c) 1 M (NH
4
)
3
PO
4
(d) 1 M Na
2
SO
4
13. The boiling point of 0.2 mol kg
–1
 solution of X in water is greater than
equimolal solution of Y in water. Which one of the following
statements is true in this case ?
(a) Molecular mass of X is greater than the molecular mass of  Y.
(b) Molecular mass of X is less than the molecular mass of Y.
(c) Y is undergoing dissociation in water while X undergoes no change.
(d) X is undergoing dissociation in water.
14. Which of the following 0.10 m aqueous solutions will have the lowest
freezing point ?
(a) Al
2
(SO
4
)
3
(b) C
6
H
12
O
6
Page 5


PART-I (Single Correct MCQs)
1. The solubility of a solid in a liquid is significantly affected by
temperature changes.
Solute + Solvent  Solution.
The  system being in a dynamic equilibrium must followLe-chatelier’s
principle. Considering the Le-chatelier’s principle which of the
following is correct?
(a) ??
sol
 > 0; solubility ; temperature
(b) ??
sol
 < 0; solubility ; temperature
(c) ??
sol
 > 0; solubility ; temperature
(d) ??
sol
 < 0; solubility ; temperature
2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and 
 = 0.4) and B (p°= 120 mm Hg and  = 0.6) is found to be 100
mm Hg. It shows that the solution exhibits
(a) positive deviation from ideal behaviour
(b) negative deviation from ideal behaviour
(c) ideal behaviour
(d) positive deviation for lower conc. and negative for higher conc.
3. Henry’s law constant of oxygen is 1.4 × 10
–3
 mol. lit
–1
. atm
–1
 at 298 K.
How much of oxygen is dissolved in 100 mL at 298 K when the partial
pressure of oxygen is 0.5 atm?
(a) 1.4 g
(b) 3.2 g
(c) 22.4 mg
(d) 2.24 mg
4. A solution containing components A and B follows Raoult’s law when
(a) A – B attraction force is greater than A – A and B – B
(b) A – B attraction force is less than A – A and B – B
(c) A – B attraction force remains same as A–A and B –B
(d) Volume of solution is different from sum of volume of solute and
solvent
5. Two 1-litre flask  A and B are connected to each other by a valve which
is closed. Flask A has benzene in equilibrium with its vapours at 30°C.
The flask B, is evacuated, and the valve is opened. Which of the
following is true. If temperature is kept constant.’
(a) Some of the benzene molecules would move to flask B from flask A.
(b) Vapour pressure will be half the initial value.
(c) The vapour pressure remains unchanged
(d) Some more of the liquid benzene in flask A would evaporate.
6. For a solution of two liquids A and B it was proved that 
. The resulting solution will be
(a) Non -ideal
(b) ideal
(c) semi-ideal
(d) None of these
7. All form ideal solution except
(a) C
6
H
6
 and C
6
H
5
 CH
3
(b) C
2
H
6
 and C
2
H
5
I
(c) C
6
H
5
Cl and C
6
H
5
Br
(d) C
2
H
5 
I and C
2
H
5
 OH.
8. A binary liquid solution is prepared by mixing n-heptane and ethanol.
Which one of the following statements is correct regarding the
behaviour of the solution?
(a) The solution is non-ideal, showing – ve deviation from Raoult’s
Law.
(b) The solution is non-ideal, showing + ve deviation from Raoult’s
Law.
(c) n-heptane shows + ve deviation while ethanol shows– ve deviation from
Raoult’s Law.
(d) The solution formed is an ideal solution.
9. During depression of freezing point in a solution the following are in
equilibrium
(a) liquid solvent, solid solvent
(b) liquid solvent, solid solute
(c) liquid solute, solid solute
(d) liquid solute, solid solvent
10. Which of the following modes of expressing concentration is independent
of temperature ?
(a) Molarity
(b) Molality
(c) Formality
(d) Normality
11. How many grams of concentrated nitric acid solution should be used to
prepare 250 mL of 2.0M HNO
3
 ? The concentrated acid is 70% HNO
3
(a) 90.0 g conc. HNO
3
(b) 70.0 g conc. HNO
3
(c) 54.0 g conc. HNO
3
(d) 45.0 g conc. HNO
3
12. Which among the following will show maximum osmotic pressure?
(a) 1 M NaCl
(b) 1 M MgCl
2
(c) 1 M (NH
4
)
3
PO
4
(d) 1 M Na
2
SO
4
13. The boiling point of 0.2 mol kg
–1
 solution of X in water is greater than
equimolal solution of Y in water. Which one of the following
statements is true in this case ?
(a) Molecular mass of X is greater than the molecular mass of  Y.
(b) Molecular mass of X is less than the molecular mass of Y.
(c) Y is undergoing dissociation in water while X undergoes no change.
(d) X is undergoing dissociation in water.
14. Which of the following 0.10 m aqueous solutions will have the lowest
freezing point ?
(a) Al
2
(SO
4
)
3
(b) C
6
H
12
O
6
(c) KCl
(d) C
12
H
22
O
11
15. If sodium sulphate is considered to be completely dissociated into
cations and anions in aqueous solution, the change in freezing point of
water (?T
f
), when 0.01 mol of sodium sulphate is dissolved in 1 kg of
water, is  (K
f
 = 1.86 K kg mol
–1
)
(a) 0.372 K
(b) 0.0558 K
(c) 0.0744 K
(d) 0.0186 K
16. Which one of the following salts will have the same value of van’t Hoff
factor (i) as that of  K
4
[Fe(CN)
6
].
(a) Al
2
(SO
4
)
3
(b) NaCl
(c) Al(NO
3
)
3
(d) Na
2
SO
4
.
17. Mole fraction of the solute in a 1.00 molal aqueous solution is :
(a) 0.1770
(b) 0.0177
(c) 0.0344
(d) 1.7700
18. 25.3 g of sodium carbonate, is dissolved in enough water to
make 250 mL of solution. If sodium carbonate dissociates completely,
molar concentration of sodium ions,  and carbonate ions, 
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FAQs on DPP for NEET: Daily Practice Problems, Ch: Solutions

1. What are colligative properties and why do they only depend on the number of solute particles?
Ans. Colligative properties depend solely on the number of dissolved solute particles, not their chemical identity. These properties include vapour pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure. They arise because solute particles disrupt solvent interactions, affecting physical behaviour regardless of particle type. Understanding this distinction helps students solve NEET problems on solution behaviour accurately.
2. How do you calculate molarity and molality, and when should I use each one for NEET chemistry?
Ans. Molarity measures moles of solute per litre of solution and varies with temperature; molality measures moles per kilogram of solvent and remains constant. Use molarity for dilution problems and lab work; use molality for colligative property calculations. Grasping this difference prevents calculation errors in daily practice problems on solutions and boosts accuracy during NEET exams.
3. What's the difference between ideal and non-ideal solutions, and does it matter for my exam?
Ans. Ideal solutions follow Raoult's law perfectly with zero volume and heat changes upon mixing; non-ideal solutions deviate due to molecular interactions. Most NEET questions focus on ideal behaviour, but recognising deviations helps explain real-world phenomena. This conceptual clarity strengthens answers to multi-step solution problems on solubility and vapour pressure calculations.
4. Why does freezing point depression happen, and what's the formula I need to remember?
Ans. Freezing point depression occurs because solute particles disrupt solvent crystallisation, requiring lower temperatures to form solid. The formula is ΔTf = Kf × m, where Kf is the freezing point depression constant and m is molality. This concept directly appears in NEET daily practice problems testing understanding of colligative phenomena in solutions.
5. How do I solve osmotic pressure problems quickly without getting confused about units?
Ans. Osmotic pressure follows π = CRT (or π = (n/V)RT), where C is molarity, R is the gas constant, and T is absolute temperature. Use consistent SI units: pressure in pascals, volume in litres, temperature in Kelvin. Practice problems systematically using EduRev's MCQ tests and worksheets on solutions to master unit conversions and avoid exam mistakes.
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