NEET Exam  >  NEET Notes  >  Chemistry Class 11  >  DPP for NEET: Daily Practice Problems, Ch: P-block Elements (Group 13 and 14)

P-block Elements (Group 13 and 14) Practice Questions - DPP for NEET

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


1. Boric acid is polymeric due to
(a) its acidic nature
(b) the presence of hydrogen bonds
(c) its monobasic nature
(d) its geometry
2. Which of the following statements about anhydrous aluminium chloride
is correct?
(a) It exists as AlCl
3
 molecules
(b) It is not easily hydrolysed
(c) It sublimes at 180ºC
(d) It is a strong Lewis base
3. The I.E
1
 among the group 13 member follows as
(a) B > Al < Ga < Tl
(b) B > Al > Ga > Tl
Page 2


1. Boric acid is polymeric due to
(a) its acidic nature
(b) the presence of hydrogen bonds
(c) its monobasic nature
(d) its geometry
2. Which of the following statements about anhydrous aluminium chloride
is correct?
(a) It exists as AlCl
3
 molecules
(b) It is not easily hydrolysed
(c) It sublimes at 180ºC
(d) It is a strong Lewis base
3. The I.E
1
 among the group 13 member follows as
(a) B > Al < Ga < Tl
(b) B > Al > Ga > Tl
(c) B > Ga > Al > Tl
(d) B > Ga < Al < Tl
4. Non-oxide ceramics can be
(a) B
4
C
(b) SiC
(c) Si
3
N
4
(d) All of these
5. Be
2
C and Al
4
C
3
 are called –
(a) ethanides
(b) methanides
(c) carbonides
(d) acetylides
6. Anhydrous AlCl
3
 cannot be obtained from which of the following
reactions ?
(a) Heating AlCl
3
.6H
2
O.
(b) By passing dry HCl over hot aluminium powder.
(c) By passing dry Cl
2
 over hot aluminium powder.
(d) By passing dry Cl
2
 over a hot mixture of alumina and coke.
7. Aluminium is extracted from alumina (Al
2
O
3
 ) by electrolysis of a
molten mixture of :
(a) Al
2
O
3
 + HF + NaAlF
4
(b) Al
2
O
3
 + CaF
2
 + NaAlF
4
(c) Al
2
O
3
 + Na
3
AlF
6
 + CaF
2
(d) Al
2
O
3
 + KF + Na
3
AlF
6
8. Alum helps in purifying water by
(a) forming Si complex with clay partiles
(b) sulphate part which combines with the dirt and removes it
Page 3


1. Boric acid is polymeric due to
(a) its acidic nature
(b) the presence of hydrogen bonds
(c) its monobasic nature
(d) its geometry
2. Which of the following statements about anhydrous aluminium chloride
is correct?
(a) It exists as AlCl
3
 molecules
(b) It is not easily hydrolysed
(c) It sublimes at 180ºC
(d) It is a strong Lewis base
3. The I.E
1
 among the group 13 member follows as
(a) B > Al < Ga < Tl
(b) B > Al > Ga > Tl
(c) B > Ga > Al > Tl
(d) B > Ga < Al < Tl
4. Non-oxide ceramics can be
(a) B
4
C
(b) SiC
(c) Si
3
N
4
(d) All of these
5. Be
2
C and Al
4
C
3
 are called –
(a) ethanides
(b) methanides
(c) carbonides
(d) acetylides
6. Anhydrous AlCl
3
 cannot be obtained from which of the following
reactions ?
(a) Heating AlCl
3
.6H
2
O.
(b) By passing dry HCl over hot aluminium powder.
(c) By passing dry Cl
2
 over hot aluminium powder.
(d) By passing dry Cl
2
 over a hot mixture of alumina and coke.
7. Aluminium is extracted from alumina (Al
2
O
3
 ) by electrolysis of a
molten mixture of :
(a) Al
2
O
3
 + HF + NaAlF
4
(b) Al
2
O
3
 + CaF
2
 + NaAlF
4
(c) Al
2
O
3
 + Na
3
AlF
6
 + CaF
2
(d) Al
2
O
3
 + KF + Na
3
AlF
6
8. Alum helps in purifying water by
(a) forming Si complex with clay partiles
(b) sulphate part which combines with the dirt and removes it
(c) coagulaing the mud particles
(d) making mud water soluble
9. Carbon and silicon belong to group 14. The maximum coordination
number of carbon in commonly occurring compounds is 4, whereas that
of silicon is 6. This is due to
(a) large size of silicon
(b) more electropositive nature of silicon
(c) availability of d-orbitals in silicon
(d) Both (a) and (b)
10. Soldiers of Napolean army while at Alps during freezing winter
suffered a serious problem as regards to the tin buttons of their
uniforms. White metallic tin buttons got converted to grey powder. This
transformation is related to
(a) a change in the partial pressure of oxygen in the air.
(b) a change in the crystalline structure of tin.
(c) an interaction with nitrogen of the air at very low temperatures.
(d) an interaction with water vapours contained in the humid air.
11. On adding ammonium hydroxide solution to Al
2
(SO
4
)
3 
(aq) :
(a) A precipitate is formed which does not dissolve in excess of ammonium
hydroxide
(b) A precipitate is formed which dissolves in excess of ammonia solution
(c) No precipitate is formed
(d) None of these
12. Gas A is bubbled through slaked lime when a white precipitate is
formed. On prolonged bubbling the precipitate is dissolved. On heating
the resultant solution, the white precipitate appears with evolution of
Page 4


1. Boric acid is polymeric due to
(a) its acidic nature
(b) the presence of hydrogen bonds
(c) its monobasic nature
(d) its geometry
2. Which of the following statements about anhydrous aluminium chloride
is correct?
(a) It exists as AlCl
3
 molecules
(b) It is not easily hydrolysed
(c) It sublimes at 180ºC
(d) It is a strong Lewis base
3. The I.E
1
 among the group 13 member follows as
(a) B > Al < Ga < Tl
(b) B > Al > Ga > Tl
(c) B > Ga > Al > Tl
(d) B > Ga < Al < Tl
4. Non-oxide ceramics can be
(a) B
4
C
(b) SiC
(c) Si
3
N
4
(d) All of these
5. Be
2
C and Al
4
C
3
 are called –
(a) ethanides
(b) methanides
(c) carbonides
(d) acetylides
6. Anhydrous AlCl
3
 cannot be obtained from which of the following
reactions ?
(a) Heating AlCl
3
.6H
2
O.
(b) By passing dry HCl over hot aluminium powder.
(c) By passing dry Cl
2
 over hot aluminium powder.
(d) By passing dry Cl
2
 over a hot mixture of alumina and coke.
7. Aluminium is extracted from alumina (Al
2
O
3
 ) by electrolysis of a
molten mixture of :
(a) Al
2
O
3
 + HF + NaAlF
4
(b) Al
2
O
3
 + CaF
2
 + NaAlF
4
(c) Al
2
O
3
 + Na
3
AlF
6
 + CaF
2
(d) Al
2
O
3
 + KF + Na
3
AlF
6
8. Alum helps in purifying water by
(a) forming Si complex with clay partiles
(b) sulphate part which combines with the dirt and removes it
(c) coagulaing the mud particles
(d) making mud water soluble
9. Carbon and silicon belong to group 14. The maximum coordination
number of carbon in commonly occurring compounds is 4, whereas that
of silicon is 6. This is due to
(a) large size of silicon
(b) more electropositive nature of silicon
(c) availability of d-orbitals in silicon
(d) Both (a) and (b)
10. Soldiers of Napolean army while at Alps during freezing winter
suffered a serious problem as regards to the tin buttons of their
uniforms. White metallic tin buttons got converted to grey powder. This
transformation is related to
(a) a change in the partial pressure of oxygen in the air.
(b) a change in the crystalline structure of tin.
(c) an interaction with nitrogen of the air at very low temperatures.
(d) an interaction with water vapours contained in the humid air.
11. On adding ammonium hydroxide solution to Al
2
(SO
4
)
3 
(aq) :
(a) A precipitate is formed which does not dissolve in excess of ammonium
hydroxide
(b) A precipitate is formed which dissolves in excess of ammonia solution
(c) No precipitate is formed
(d) None of these
12. Gas A is bubbled through slaked lime when a white precipitate is
formed. On prolonged bubbling the precipitate is dissolved. On heating
the resultant solution, the white precipitate appears with evolution of
gas B. The gases A and B respectively are
(a) CO and CO
(b) and CO
(c) CO and 
(d) and 
13. The straight chain polymer is formed by
(a) hydrolysis of CH
3
SiCl
3
 followed by condensation polymerisation
(b) hydrolysis of (CH
3
)
4
Si by addition polymerisation
(c) hydrolysis of (CH
3
)
2
SiCl
2
 followed by condensation polymerisation
(d) hydrolysis of (CH
3
)
3
SiCl followed by condensation polymerisation
14. It is because of inability of ns
2
 electrons of the valence shell to
participate in bonding that:-
(a) Sn
2+
 is oxidising while Pb
4+
 is reducing.
(b) Sn
2+
 and Pb
2+
 are both oxidising and reducing.
(c) Sn
4+
 is reducing while Pb
4+
 is oxidising.
(d) Sn
2+
 is reducing while Pb
4+
 is oxidising.
15. A group 14 element is oxidised to form corresponding oxide which is
gaseous in nature, when dissolved in water pH of the water decreases
further addition of group 2 hydroxides leads to precipitation. This oxide
can be
(a) GeO
2
(b) CO
(c) CO
2
(d) SnO
2
16. In borax bead test which compound is formed?
(a) Ortho-borate
(b) Meta-borate
(c) Double oxide
Page 5


1. Boric acid is polymeric due to
(a) its acidic nature
(b) the presence of hydrogen bonds
(c) its monobasic nature
(d) its geometry
2. Which of the following statements about anhydrous aluminium chloride
is correct?
(a) It exists as AlCl
3
 molecules
(b) It is not easily hydrolysed
(c) It sublimes at 180ºC
(d) It is a strong Lewis base
3. The I.E
1
 among the group 13 member follows as
(a) B > Al < Ga < Tl
(b) B > Al > Ga > Tl
(c) B > Ga > Al > Tl
(d) B > Ga < Al < Tl
4. Non-oxide ceramics can be
(a) B
4
C
(b) SiC
(c) Si
3
N
4
(d) All of these
5. Be
2
C and Al
4
C
3
 are called –
(a) ethanides
(b) methanides
(c) carbonides
(d) acetylides
6. Anhydrous AlCl
3
 cannot be obtained from which of the following
reactions ?
(a) Heating AlCl
3
.6H
2
O.
(b) By passing dry HCl over hot aluminium powder.
(c) By passing dry Cl
2
 over hot aluminium powder.
(d) By passing dry Cl
2
 over a hot mixture of alumina and coke.
7. Aluminium is extracted from alumina (Al
2
O
3
 ) by electrolysis of a
molten mixture of :
(a) Al
2
O
3
 + HF + NaAlF
4
(b) Al
2
O
3
 + CaF
2
 + NaAlF
4
(c) Al
2
O
3
 + Na
3
AlF
6
 + CaF
2
(d) Al
2
O
3
 + KF + Na
3
AlF
6
8. Alum helps in purifying water by
(a) forming Si complex with clay partiles
(b) sulphate part which combines with the dirt and removes it
(c) coagulaing the mud particles
(d) making mud water soluble
9. Carbon and silicon belong to group 14. The maximum coordination
number of carbon in commonly occurring compounds is 4, whereas that
of silicon is 6. This is due to
(a) large size of silicon
(b) more electropositive nature of silicon
(c) availability of d-orbitals in silicon
(d) Both (a) and (b)
10. Soldiers of Napolean army while at Alps during freezing winter
suffered a serious problem as regards to the tin buttons of their
uniforms. White metallic tin buttons got converted to grey powder. This
transformation is related to
(a) a change in the partial pressure of oxygen in the air.
(b) a change in the crystalline structure of tin.
(c) an interaction with nitrogen of the air at very low temperatures.
(d) an interaction with water vapours contained in the humid air.
11. On adding ammonium hydroxide solution to Al
2
(SO
4
)
3 
(aq) :
(a) A precipitate is formed which does not dissolve in excess of ammonium
hydroxide
(b) A precipitate is formed which dissolves in excess of ammonia solution
(c) No precipitate is formed
(d) None of these
12. Gas A is bubbled through slaked lime when a white precipitate is
formed. On prolonged bubbling the precipitate is dissolved. On heating
the resultant solution, the white precipitate appears with evolution of
gas B. The gases A and B respectively are
(a) CO and CO
(b) and CO
(c) CO and 
(d) and 
13. The straight chain polymer is formed by
(a) hydrolysis of CH
3
SiCl
3
 followed by condensation polymerisation
(b) hydrolysis of (CH
3
)
4
Si by addition polymerisation
(c) hydrolysis of (CH
3
)
2
SiCl
2
 followed by condensation polymerisation
(d) hydrolysis of (CH
3
)
3
SiCl followed by condensation polymerisation
14. It is because of inability of ns
2
 electrons of the valence shell to
participate in bonding that:-
(a) Sn
2+
 is oxidising while Pb
4+
 is reducing.
(b) Sn
2+
 and Pb
2+
 are both oxidising and reducing.
(c) Sn
4+
 is reducing while Pb
4+
 is oxidising.
(d) Sn
2+
 is reducing while Pb
4+
 is oxidising.
15. A group 14 element is oxidised to form corresponding oxide which is
gaseous in nature, when dissolved in water pH of the water decreases
further addition of group 2 hydroxides leads to precipitation. This oxide
can be
(a) GeO
2
(b) CO
(c) CO
2
(d) SnO
2
16. In borax bead test which compound is formed?
(a) Ortho-borate
(b) Meta-borate
(c) Double oxide
(d) Tetra-borate
17. Orthoboric acid when heated to red hot gives
(a) metaboric acid
(b) pyroboric acid
(c) boron and water
(d) boric anhydride
18. PbF
4
, PbCl
4
 exist but PbBr
4 
and PbI
4
 do not exist because of
(a) large size of Br
–
 and I
–
.
(b) strong oxidising character of Pb
4+
.
(c) strong  reducing character of Pb
4+
.
(d) low electronegativity of Br
–
 and I
–
.
19. In silicon dioxide
(a) there are double bonds between silicon and oxygen atoms.
(b) silicon atom is bonded to two oxygen atoms.
(c) each silicon atom is surrounded by two oxygen atoms and each oxygen
atom is bonded to two silicon atoms.
(d) each silicon atom is surrounded by four oxygen atoms and each oxygen
atom is bonded to two silicon atoms.
20. Graphite is a soft solid lubricant extremely difficult to melt. The reason
for this anomalous behaviour is that graphite
(a) is an allotropic form of diamond.
(b) has molecules of variable molecular masses like polymers.
(c) has carbon atoms arranged in large plates of rings of strongly bound
carbon atoms with weak interplate bonds.
(d) is a non-crystalline substance.
21. The gas evolved on heating CaF
2
 and SiO
2
 with concentrated H
2
SO
4
, on
hydrolysis gives a white gelatinous precipitate. The precipitate is:
(a) hydrofluosilicic acid
(b) silica gel
(c) silicic acid
Read More
172 videos|306 docs|152 tests

Top Courses for NEET

172 videos|306 docs|152 tests
Download as PDF
Explore Courses for NEET exam

Top Courses for NEET

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Viva Questions

,

Objective type Questions

,

Important questions

,

mock tests for examination

,

P-block Elements (Group 13 and 14) Practice Questions - DPP for NEET

,

pdf

,

Summary

,

P-block Elements (Group 13 and 14) Practice Questions - DPP for NEET

,

past year papers

,

Extra Questions

,

MCQs

,

video lectures

,

ppt

,

study material

,

Previous Year Questions with Solutions

,

P-block Elements (Group 13 and 14) Practice Questions - DPP for NEET

,

shortcuts and tricks

,

Sample Paper

,

Free

,

Exam

,

practice quizzes

,

Semester Notes

;