CBSE Class 8 > Class 8 Notes > ML Aggarwal: Percentage - 2
ML Aggarwal: Percentage - 2
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Page 1 1. Find the profit or loss percentage, when: (i) C.P. = ? 400, S.P. = ? 468 (ii) C.P. = ? 13600, S.P. = ? 12104 Solution: (i) It is given that C.P. = ? 400, S.P. = ? 468 Profit = S.P. – C.P. Substituting the values = 468 – 400 = ? 68 Here Profit % = ;#BDA@ × E.;. Substituting the values = × = 17 % (ii) It is given that C.P. = ? 13600, S.P. = ? 12104 Loss = C.P. – S.P. Substituting the values = 13600 – 12104 Page 2 1. Find the profit or loss percentage, when: (i) C.P. = ? 400, S.P. = ? 468 (ii) C.P. = ? 13600, S.P. = ? 12104 Solution: (i) It is given that C.P. = ? 400, S.P. = ? 468 Profit = S.P. – C.P. Substituting the values = 468 – 400 = ? 68 Here Profit % = ;#BDA@ × E.;. Substituting the values = × = 17 % (ii) It is given that C.P. = ? 13600, S.P. = ? 12104 Loss = C.P. – S.P. Substituting the values = 13600 – 12104 = ? 1496 Here Loss % = ! FBGG E.;. × 100( % Substituting the values = ! × 100( % So we get = % = 11 % 2. By selling an article for ? 1636.25, a dealer gains ? 96.25. Find his gain per cent. Solution: It is given that S.P. of an article = ? 1636.25 Gain = ? 96.25 So the C.P. = S.P. – Gain Substituting the values = 1636.25 – 96.25 = ? 1540 We know that Gain % = ! H$AC E.;. × 100( % Substituting the values Page 3 1. Find the profit or loss percentage, when: (i) C.P. = ? 400, S.P. = ? 468 (ii) C.P. = ? 13600, S.P. = ? 12104 Solution: (i) It is given that C.P. = ? 400, S.P. = ? 468 Profit = S.P. – C.P. Substituting the values = 468 – 400 = ? 68 Here Profit % = ;#BDA@ × E.;. Substituting the values = × = 17 % (ii) It is given that C.P. = ? 13600, S.P. = ? 12104 Loss = C.P. – S.P. Substituting the values = 13600 – 12104 = ? 1496 Here Loss % = ! FBGG E.;. × 100( % Substituting the values = ! × 100( % So we get = % = 11 % 2. By selling an article for ? 1636.25, a dealer gains ? 96.25. Find his gain per cent. Solution: It is given that S.P. of an article = ? 1636.25 Gain = ? 96.25 So the C.P. = S.P. – Gain Substituting the values = 1636.25 – 96.25 = ? 1540 We know that Gain % = ! H$AC E.;. × 100( % Substituting the values = ! . × 100( % By further calculation = % = % So we get = % = 6 % 3. By selling an article for ? 770, a man incurs a loss of ? 110. Find his loss percentage. Solution: It is given that S.P. of an article = ? 770 Loss = ? 110 We know that C.P. = S.P. + Loss Substituting the values = 770 + 110 = ? 880 Here Loss % = ! FBGG E.;. × 100( % Page 4 1. Find the profit or loss percentage, when: (i) C.P. = ? 400, S.P. = ? 468 (ii) C.P. = ? 13600, S.P. = ? 12104 Solution: (i) It is given that C.P. = ? 400, S.P. = ? 468 Profit = S.P. – C.P. Substituting the values = 468 – 400 = ? 68 Here Profit % = ;#BDA@ × E.;. Substituting the values = × = 17 % (ii) It is given that C.P. = ? 13600, S.P. = ? 12104 Loss = C.P. – S.P. Substituting the values = 13600 – 12104 = ? 1496 Here Loss % = ! FBGG E.;. × 100( % Substituting the values = ! × 100( % So we get = % = 11 % 2. By selling an article for ? 1636.25, a dealer gains ? 96.25. Find his gain per cent. Solution: It is given that S.P. of an article = ? 1636.25 Gain = ? 96.25 So the C.P. = S.P. – Gain Substituting the values = 1636.25 – 96.25 = ? 1540 We know that Gain % = ! H$AC E.;. × 100( % Substituting the values = ! . × 100( % By further calculation = % = % So we get = % = 6 % 3. By selling an article for ? 770, a man incurs a loss of ? 110. Find his loss percentage. Solution: It is given that S.P. of an article = ? 770 Loss = ? 110 We know that C.P. = S.P. + Loss Substituting the values = 770 + 110 = ? 880 Here Loss % = ! FBGG E.;. × 100( % Substituting the values = ! × 100( % By further calculation = % So we get = % = 12.5 % 4. Rashida bought 25 dozen eggs at the rate of ? 9.60 per dozen. 30 eggs were broken in the transaction and she sold the remaining eggs at one rupee each. Find her gain or loss percentage. Solution: It is given that C.P. of one dozen eggs = ? 9.60 C.P. of 25 dozen eggs = 25 × 9.60 = ? 240 No. of eggs = 25 dozen = 25 × 12 = 300 No. of eggs broken in transaction = 30 No. of remaining eggs = 300 – 30 = 270 We know that S.P. of one egg = ? 1 S.P. of 270 eggs = 1 × 270 = ? 270 So the profit = S.P. – C.P. Substituting the values Page 5 1. Find the profit or loss percentage, when: (i) C.P. = ? 400, S.P. = ? 468 (ii) C.P. = ? 13600, S.P. = ? 12104 Solution: (i) It is given that C.P. = ? 400, S.P. = ? 468 Profit = S.P. – C.P. Substituting the values = 468 – 400 = ? 68 Here Profit % = ;#BDA@ × E.;. Substituting the values = × = 17 % (ii) It is given that C.P. = ? 13600, S.P. = ? 12104 Loss = C.P. – S.P. Substituting the values = 13600 – 12104 = ? 1496 Here Loss % = ! FBGG E.;. × 100( % Substituting the values = ! × 100( % So we get = % = 11 % 2. By selling an article for ? 1636.25, a dealer gains ? 96.25. Find his gain per cent. Solution: It is given that S.P. of an article = ? 1636.25 Gain = ? 96.25 So the C.P. = S.P. – Gain Substituting the values = 1636.25 – 96.25 = ? 1540 We know that Gain % = ! H$AC E.;. × 100( % Substituting the values = ! . × 100( % By further calculation = % = % So we get = % = 6 % 3. By selling an article for ? 770, a man incurs a loss of ? 110. Find his loss percentage. Solution: It is given that S.P. of an article = ? 770 Loss = ? 110 We know that C.P. = S.P. + Loss Substituting the values = 770 + 110 = ? 880 Here Loss % = ! FBGG E.;. × 100( % Substituting the values = ! × 100( % By further calculation = % So we get = % = 12.5 % 4. Rashida bought 25 dozen eggs at the rate of ? 9.60 per dozen. 30 eggs were broken in the transaction and she sold the remaining eggs at one rupee each. Find her gain or loss percentage. Solution: It is given that C.P. of one dozen eggs = ? 9.60 C.P. of 25 dozen eggs = 25 × 9.60 = ? 240 No. of eggs = 25 dozen = 25 × 12 = 300 No. of eggs broken in transaction = 30 No. of remaining eggs = 300 – 30 = 270 We know that S.P. of one egg = ? 1 S.P. of 270 eggs = 1 × 270 = ? 270 So the profit = S.P. – C.P. Substituting the values = 270 – 240 = ? 30 Here Profit % = ! ;#BDA@ E.;. × 100( % Substituting the values = ! × 100( % So we get = % = % = 12.5 % 5. The cost of an article was ? 20000 and ? 1400 were spent on its repairs. If it is sold for a profit of 20 %, find the selling price of the article. Solution: It is given that Cost of an article = ? 20000 Cost of its repair = ? 1400 So the total cost = 20000 + 1400 = ? 21400 Profit = 20 % We know that S.P. = -E.;.× 3 ;#BDA@ % .Read More
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Apr 25, 2026 Last updated
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