CBSE Class 8 > Class 8 Notes > ML Aggarwal: Simple & Compound Interest - 1
ML Aggarwal: Simple & Compound Interest - 1
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Page 1
1. Find the simple interest on Rs 4000 at 7.5% p.a. for 3 years 3
months. Also, find the amount.
Solution:
Here
Principal (P) = Rs 4000
Rate of interest (R) = 7.5% p.a.
=
% p.a.
Time (T) = 3 years 3 months
= 3
years
= 3
years
=
years
Hence,
Simple Interest (I) =
×
×
= Rs
×
×
= Rs
× ×
× ×
On simplification, we get,
= Rs 5 × 15 × 13
Page 2
1. Find the simple interest on Rs 4000 at 7.5% p.a. for 3 years 3
months. Also, find the amount.
Solution:
Here
Principal (P) = Rs 4000
Rate of interest (R) = 7.5% p.a.
=
% p.a.
Time (T) = 3 years 3 months
= 3
years
= 3
years
=
years
Hence,
Simple Interest (I) =
×
×
= Rs
×
×
= Rs
× ×
× ×
On simplification, we get,
= Rs 5 × 15 × 13
= Rs 975
Therefore,
Amount = P + I
= Rs 14000 + Rs 975
= RS 14, 975
2. What sum of money will yield Rs 170.10 as simple interest in 2 years
3 months at 6% per annum?
Solution:
Here
I = Rs 170.10
T = 2 years 3 months
= 2
years
= 2
years
=
years
R = 6%
Hence,
P =
×
×
= Rs
. ×
×
On calculating further, we get,
= Rs
. × ×
×
Page 3
1. Find the simple interest on Rs 4000 at 7.5% p.a. for 3 years 3
months. Also, find the amount.
Solution:
Here
Principal (P) = Rs 4000
Rate of interest (R) = 7.5% p.a.
=
% p.a.
Time (T) = 3 years 3 months
= 3
years
= 3
years
=
years
Hence,
Simple Interest (I) =
×
×
= Rs
×
×
= Rs
× ×
× ×
On simplification, we get,
= Rs 5 × 15 × 13
= Rs 975
Therefore,
Amount = P + I
= Rs 14000 + Rs 975
= RS 14, 975
2. What sum of money will yield Rs 170.10 as simple interest in 2 years
3 months at 6% per annum?
Solution:
Here
I = Rs 170.10
T = 2 years 3 months
= 2
years
= 2
years
=
years
R = 6%
Hence,
P =
×
×
= Rs
. ×
×
On calculating further, we get,
= Rs
. × ×
×
= Rs
×
×
= Rs
×
×
= Rs
= Rs 1260
3. Find the rate of interest when Rs 800 fetches Rs 130 as a simple
interest in 2 years 6 months.
Solution:
Here
P = Rs 800
T = 2 years 6 months
= 2
years
= 2
years
=
years
Hence,
R =
×
! ×
=
×
" ×
% p.a.
On simplification, we get,
=
× ×
" ×
% p.a.
Page 4
1. Find the simple interest on Rs 4000 at 7.5% p.a. for 3 years 3
months. Also, find the amount.
Solution:
Here
Principal (P) = Rs 4000
Rate of interest (R) = 7.5% p.a.
=
% p.a.
Time (T) = 3 years 3 months
= 3
years
= 3
years
=
years
Hence,
Simple Interest (I) =
×
×
= Rs
×
×
= Rs
× ×
× ×
On simplification, we get,
= Rs 5 × 15 × 13
= Rs 975
Therefore,
Amount = P + I
= Rs 14000 + Rs 975
= RS 14, 975
2. What sum of money will yield Rs 170.10 as simple interest in 2 years
3 months at 6% per annum?
Solution:
Here
I = Rs 170.10
T = 2 years 3 months
= 2
years
= 2
years
=
years
R = 6%
Hence,
P =
×
×
= Rs
. ×
×
On calculating further, we get,
= Rs
. × ×
×
= Rs
×
×
= Rs
×
×
= Rs
= Rs 1260
3. Find the rate of interest when Rs 800 fetches Rs 130 as a simple
interest in 2 years 6 months.
Solution:
Here
P = Rs 800
T = 2 years 6 months
= 2
years
= 2
years
=
years
Hence,
R =
×
! ×
=
×
" ×
% p.a.
On simplification, we get,
=
× ×
" ×
% p.a.
=
×
%
=
% p.a.
=
%
= 6.5% p.a.
Therefore, the required rate of interest is 6.5% p.a.
4. Find the time when simple interest on Rs 3.3 lakhs at 6.5% per
annum is Rs 75075.
Solution:
Here,
P = 3.3 lakhs
= Rs 3.3 × 100000
= Rs 330000
R = 6.5% per annum
I = Rs 75075
Hence,
T =
$ ×
×
=
×
× .
years
=
× ×
×
years
On further calculation, we get,
=
×
years
Page 5
1. Find the simple interest on Rs 4000 at 7.5% p.a. for 3 years 3
months. Also, find the amount.
Solution:
Here
Principal (P) = Rs 4000
Rate of interest (R) = 7.5% p.a.
=
% p.a.
Time (T) = 3 years 3 months
= 3
years
= 3
years
=
years
Hence,
Simple Interest (I) =
×
×
= Rs
×
×
= Rs
× ×
× ×
On simplification, we get,
= Rs 5 × 15 × 13
= Rs 975
Therefore,
Amount = P + I
= Rs 14000 + Rs 975
= RS 14, 975
2. What sum of money will yield Rs 170.10 as simple interest in 2 years
3 months at 6% per annum?
Solution:
Here
I = Rs 170.10
T = 2 years 3 months
= 2
years
= 2
years
=
years
R = 6%
Hence,
P =
×
×
= Rs
. ×
×
On calculating further, we get,
= Rs
. × ×
×
= Rs
×
×
= Rs
×
×
= Rs
= Rs 1260
3. Find the rate of interest when Rs 800 fetches Rs 130 as a simple
interest in 2 years 6 months.
Solution:
Here
P = Rs 800
T = 2 years 6 months
= 2
years
= 2
years
=
years
Hence,
R =
×
! ×
=
×
" ×
% p.a.
On simplification, we get,
=
× ×
" ×
% p.a.
=
×
%
=
% p.a.
=
%
= 6.5% p.a.
Therefore, the required rate of interest is 6.5% p.a.
4. Find the time when simple interest on Rs 3.3 lakhs at 6.5% per
annum is Rs 75075.
Solution:
Here,
P = 3.3 lakhs
= Rs 3.3 × 100000
= Rs 330000
R = 6.5% per annum
I = Rs 75075
Hence,
T =
$ ×
×
=
×
× .
years
=
× ×
×
years
On further calculation, we get,
=
×
years
=
years
We get,
=
years
= 3
years
5. Find the sum of money when
(i) Simple interest at %
&
'
% p.a. for years is Rs 2356.25
(ii) The final amount is Rs 11300 at 4% p.a. for 3 years 3 months.
Solution:
(i) Here,
I = Rs 2356.25
R = 7
% p.a.
=
% p.a.
T = 2
years
=
years
Hence,
P = (I × 100) / (R × T)
= Rs
. ×
)
×
*
On further calculation, we get,
= Rs
. × × ×
×
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Apr 26, 2026 Last updated
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