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ML Aggarwal: Simple & Compound Interest - 2

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 Page 1


 
1. Calculate the compound interest on Rs 6000 at 10% per annum for 
two years. 
Solution: 
Given 
Rate of interest = 10% per annum 
Principal for the first year = Rs 6000 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 600 
Amount at the end of first year = Rs 6000 + Rs 600 
= Rs 6600 
Principal for the second year = Rs 6600 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 660 
Amount for the second year = Rs 6600 + Rs 660 
= Rs 7260 
Therefore, compound interest for 2 years = final amount – (original) 
Principal 
= Rs 7260 – Rs 6000 
We get, 
= Rs 1260 
Page 2


 
1. Calculate the compound interest on Rs 6000 at 10% per annum for 
two years. 
Solution: 
Given 
Rate of interest = 10% per annum 
Principal for the first year = Rs 6000 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 600 
Amount at the end of first year = Rs 6000 + Rs 600 
= Rs 6600 
Principal for the second year = Rs 6600 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 660 
Amount for the second year = Rs 6600 + Rs 660 
= Rs 7260 
Therefore, compound interest for 2 years = final amount – (original) 
Principal 
= Rs 7260 – Rs 6000 
We get, 
= Rs 1260 
2. Salma borrowed from Mahila Samiti a sum of Rs 1875 to purchase 
a sewing machine. If the rate of interest is 4% per annum, what is the 
compound interest that she has to pay after 2 years? 
Solution: 
Principal for the first year = Rs 1875 
Rate of interest = 4% p.a. 
Interest for the first year = Rs 
	" ×  × 

 
= 75 
Amount at the end of first year = Rs 1875 + Rs 75 
= Rs 1950 
Principal for the second year = Rs 1950 
Interest for the second year = Rs 
	 ×  × 

 
= 78 
Amount at the end of second year = Rs 1950 + Rs 78 
= Rs 2028 
Hence, 
Compound interest paid by Salma = Final amount – (original) Principal 
= Rs 2028 – Rs 1875 
= Rs 153 
 
3. Jacob invests Rs 12000 for 3 years at 10% per annum. Calculate 
the amount and the compound interest that Jacob will get after 3 
years. 
Solution: 
Page 3


 
1. Calculate the compound interest on Rs 6000 at 10% per annum for 
two years. 
Solution: 
Given 
Rate of interest = 10% per annum 
Principal for the first year = Rs 6000 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 600 
Amount at the end of first year = Rs 6000 + Rs 600 
= Rs 6600 
Principal for the second year = Rs 6600 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 660 
Amount for the second year = Rs 6600 + Rs 660 
= Rs 7260 
Therefore, compound interest for 2 years = final amount – (original) 
Principal 
= Rs 7260 – Rs 6000 
We get, 
= Rs 1260 
2. Salma borrowed from Mahila Samiti a sum of Rs 1875 to purchase 
a sewing machine. If the rate of interest is 4% per annum, what is the 
compound interest that she has to pay after 2 years? 
Solution: 
Principal for the first year = Rs 1875 
Rate of interest = 4% p.a. 
Interest for the first year = Rs 
	" ×  × 

 
= 75 
Amount at the end of first year = Rs 1875 + Rs 75 
= Rs 1950 
Principal for the second year = Rs 1950 
Interest for the second year = Rs 
	 ×  × 

 
= 78 
Amount at the end of second year = Rs 1950 + Rs 78 
= Rs 2028 
Hence, 
Compound interest paid by Salma = Final amount – (original) Principal 
= Rs 2028 – Rs 1875 
= Rs 153 
 
3. Jacob invests Rs 12000 for 3 years at 10% per annum. Calculate 
the amount and the compound interest that Jacob will get after 3 
years. 
Solution: 
Principal for the first year = Rs 12000 
Rate of interest = 10% p.a. 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 1200 
Amount at the end of first year = Rs 12000 + Rs 1200 
= 13200 
Principal for the second year = Rs 13200 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 1320 
Amount at the end of second year = Rs 13200 + Rs 1320 
= Rs 14520 
Principal for the third year = Rs 14520 
Interest for the third year = Rs 
	 ×  × 

 
= Rs 1452 
Amount at the end of third year = Rs 14520 + Rs 1452 
= Rs 15972 
Hence, 
Compound interest for 3 year = Final amount – (original) Principal 
= Rs 15972 – Rs 12000 
= Rs 3972 
 
Page 4


 
1. Calculate the compound interest on Rs 6000 at 10% per annum for 
two years. 
Solution: 
Given 
Rate of interest = 10% per annum 
Principal for the first year = Rs 6000 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 600 
Amount at the end of first year = Rs 6000 + Rs 600 
= Rs 6600 
Principal for the second year = Rs 6600 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 660 
Amount for the second year = Rs 6600 + Rs 660 
= Rs 7260 
Therefore, compound interest for 2 years = final amount – (original) 
Principal 
= Rs 7260 – Rs 6000 
We get, 
= Rs 1260 
2. Salma borrowed from Mahila Samiti a sum of Rs 1875 to purchase 
a sewing machine. If the rate of interest is 4% per annum, what is the 
compound interest that she has to pay after 2 years? 
Solution: 
Principal for the first year = Rs 1875 
Rate of interest = 4% p.a. 
Interest for the first year = Rs 
	" ×  × 

 
= 75 
Amount at the end of first year = Rs 1875 + Rs 75 
= Rs 1950 
Principal for the second year = Rs 1950 
Interest for the second year = Rs 
	 ×  × 

 
= 78 
Amount at the end of second year = Rs 1950 + Rs 78 
= Rs 2028 
Hence, 
Compound interest paid by Salma = Final amount – (original) Principal 
= Rs 2028 – Rs 1875 
= Rs 153 
 
3. Jacob invests Rs 12000 for 3 years at 10% per annum. Calculate 
the amount and the compound interest that Jacob will get after 3 
years. 
Solution: 
Principal for the first year = Rs 12000 
Rate of interest = 10% p.a. 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 1200 
Amount at the end of first year = Rs 12000 + Rs 1200 
= 13200 
Principal for the second year = Rs 13200 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 1320 
Amount at the end of second year = Rs 13200 + Rs 1320 
= Rs 14520 
Principal for the third year = Rs 14520 
Interest for the third year = Rs 
	 ×  × 

 
= Rs 1452 
Amount at the end of third year = Rs 14520 + Rs 1452 
= Rs 15972 
Hence, 
Compound interest for 3 year = Final amount – (original) Principal 
= Rs 15972 – Rs 12000 
= Rs 3972 
 
4. A man invests Rs 46875 at 4% per annum compound interest for 3 
years. 
Calculate: 
(i) the interest for the first year 
(ii) the amount standing to his credit at the end of second year 
(iii) the interest for the third year 
Solution: 
(i) Principal for the first year = Rs 46875 
Rate of interest = 4% per annum 
Therefore, 
Interest for the first year = Rs 
	" ×  × 

 
We get, 
= Rs 
"

 
= Rs 1875 
Hence, interest for the first year is Rs 1875 
(ii) Amount at the end of first year 
= Rs 46875 + Rs 1875 
We get, 
= Rs 48750 
Principal for the second year = Rs 48750 
Interest for the second year = Rs 
	" ×  × 

 
= Rs 
"

 
Page 5


 
1. Calculate the compound interest on Rs 6000 at 10% per annum for 
two years. 
Solution: 
Given 
Rate of interest = 10% per annum 
Principal for the first year = Rs 6000 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 600 
Amount at the end of first year = Rs 6000 + Rs 600 
= Rs 6600 
Principal for the second year = Rs 6600 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 660 
Amount for the second year = Rs 6600 + Rs 660 
= Rs 7260 
Therefore, compound interest for 2 years = final amount – (original) 
Principal 
= Rs 7260 – Rs 6000 
We get, 
= Rs 1260 
2. Salma borrowed from Mahila Samiti a sum of Rs 1875 to purchase 
a sewing machine. If the rate of interest is 4% per annum, what is the 
compound interest that she has to pay after 2 years? 
Solution: 
Principal for the first year = Rs 1875 
Rate of interest = 4% p.a. 
Interest for the first year = Rs 
	" ×  × 

 
= 75 
Amount at the end of first year = Rs 1875 + Rs 75 
= Rs 1950 
Principal for the second year = Rs 1950 
Interest for the second year = Rs 
	 ×  × 

 
= 78 
Amount at the end of second year = Rs 1950 + Rs 78 
= Rs 2028 
Hence, 
Compound interest paid by Salma = Final amount – (original) Principal 
= Rs 2028 – Rs 1875 
= Rs 153 
 
3. Jacob invests Rs 12000 for 3 years at 10% per annum. Calculate 
the amount and the compound interest that Jacob will get after 3 
years. 
Solution: 
Principal for the first year = Rs 12000 
Rate of interest = 10% p.a. 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 1200 
Amount at the end of first year = Rs 12000 + Rs 1200 
= 13200 
Principal for the second year = Rs 13200 
Interest for the second year = Rs 
	 ×  × 

 
= Rs 1320 
Amount at the end of second year = Rs 13200 + Rs 1320 
= Rs 14520 
Principal for the third year = Rs 14520 
Interest for the third year = Rs 
	 ×  × 

 
= Rs 1452 
Amount at the end of third year = Rs 14520 + Rs 1452 
= Rs 15972 
Hence, 
Compound interest for 3 year = Final amount – (original) Principal 
= Rs 15972 – Rs 12000 
= Rs 3972 
 
4. A man invests Rs 46875 at 4% per annum compound interest for 3 
years. 
Calculate: 
(i) the interest for the first year 
(ii) the amount standing to his credit at the end of second year 
(iii) the interest for the third year 
Solution: 
(i) Principal for the first year = Rs 46875 
Rate of interest = 4% per annum 
Therefore, 
Interest for the first year = Rs 
	" ×  × 

 
We get, 
= Rs 
"

 
= Rs 1875 
Hence, interest for the first year is Rs 1875 
(ii) Amount at the end of first year 
= Rs 46875 + Rs 1875 
We get, 
= Rs 48750 
Principal for the second year = Rs 48750 
Interest for the second year = Rs 
	" ×  × 

 
= Rs 
"

 
We get, 
= Rs 1950 
Amount at the end of second year = Rs 48750 + Rs 1950 
We get, 
= Rs 50700 
Hence, the amount at the end of second year is Rs 50700 
(iii) Principal for the third year = Rs 50700 
Interest for the third year = Rs 
	 ×  × 

 
We get, 
= Rs 507 × 4 
= Rs 2028 
Hence, the interest for the third year is Rs 2028 
 
5. Calculate the compound interest for the second year on Rs 6000 
invested for 3 years at 10% p.a. Also find the sum due at the end of 
third year. 
Solution: 
Principal for the first year = Rs 6000 
Rate of interest = 10% p.a. 
Interest for the first year = Rs 
	 ×  × 

 
= Rs 600 
Amount at the end of first year = Rs 6000 + Rs 600 
= Rs 6600 
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